05. Material Properties of Metals (Lectured)
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Transcript of 05. Material Properties of Metals (Lectured)
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Engineering Materials H82 ENM
Spring 2013-14
Dr Joyce Tiong
05. Mechanical
Properties of Metals
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Introduction
H82ENM Chapter 5 - 2
Mechanical Properties
Stress
Strain
Elastic Deformation
Plastic Deformation
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There are 3 principal ways in which load may be applied:
Tension
Compression
Shear
Concepts of Stress & Strain
H82ENM Chapter 5 - 3
a. Tension b. Compression
c. Shear d. Torsion
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Concepts of Stress & Strain (cont.)
H82ENM Chapter 5 - 4
Simple tension: cable
Note: t = M/AcR here
o
s = F
A
o
t = F s
A
s s
M
M A o
2R
F s A c
Torsion (a form of shear): drive shaft
Ski lift (photo courtesy P.M. Anderson)
A o = cross sectional
area (when unloaded)
F F
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Concepts of Stress & Strain (cont.)
H82ENM Chapter 5 - 5
(photo courtesy P.M. Anderson) Canyon Bridge, Los Alamos, NM
o
s = F
A
Simple compression:
Note: compressive
structure member
(s < 0 here).
(photo courtesy P.M. Anderson)
A o
Balanced Rock, Arches National Park
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Concepts of Stress & Strain (cont.)
H82ENM Chapter 5 - 6
Bi-axial tension: Hydrostatic compression:
Pressurized tank
s < 0 h
(photo courtesy P.M. Anderson) (photo courtesy P.M. Anderson) Fish under water
s z > 0
s q
> 0
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Engineering Stress
H82ENM Chapter 5 - 7
Stress has units:
N/m2 or lbf/in2
Shear stress, t:
Area, A
F t
F t
F s
F
F
F s
t = F s
A o
Tensile stress, s:
original area
before loading
Area, A
F t
F t
s = F t
A o 2
f
2 m
N or
in
lb =
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Engineering Strain
H82ENM Chapter 5 - 8
Strain is always
dimensionless
Shear strain:
q
90
90 - q y
x
q g = x/y = tan
Adapted from Fig. 6.1(a) and (c), Callister & Rethwisch 8e.
Tensile strain: Lateral strain:
e = d L o
d /2
L o w o
- d e L = L w o
d L
/2
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Stress-Strain Testing
H82ENM Chapter 5 - 9
Typical tensile test machine
specimen extensometer
Typical tensile specimen
Adapted from Fig. 6.2, Callister & Rethwisch 8e.
gauge
length
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The Tensile Tester
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H82ENM Chapter 5 - 11
Elastic vs. Plastic Deformation
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H82ENM Chapter 5 - 12
Elastic vs. Plastic Deformation
(cont.)
Elastic means reversible!
Elastic Deformation
2. Small load
F
d
bonds
stretch
1. Initial 3. Unload
return to
initial
F
d
Linear- elastic
Non-Linear- elastic
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H82ENM Chapter 5 - 13
Elastic vs. Plastic Deformation
(cont.)
Plastic means permanent!
Plastic Deformation (Metals)
F
d linear elastic
linear elastic
d plastic
1. Initial 2. Small load 3. Unload
planes
still
sheared
F
d elastic + plastic
bonds
stretch
& planes
shear
d plastic
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Have a break, have a
(or maybe not)
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Elastic Deformation Linear Elastic Properties
H82ENM Chapter 5 - 15
Modulus of Elasticity, E:
(also known as Young's modulus)
Hooke's Law:
s = E e s
Linear-
elastic
E
e
F
F simple tension test
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Elastic Deformation (cont.)
H82ENM Chapter 5 - 16
Example:
A piece of Copper originally 305 mm long is pulled in tension with a stress of 276 MPa. If the deformation is entirely elastic, what will the resultant elongation? E = 110 Gpa
The deformation is elastic, thus strain is dependent on stress,
= =
=
=(276 MPa)(305 mm)
110x103 MPa= 0.77mm
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Elastic Deformation (cont.)
Elastic Properties
H82ENM Chapter 5 - 17
Poisson's ratio, n
- Negative ratio of transverse to axial strain:
Units:
E: [GPa] or [psi]
n: dimensionless
n > 0.50 density increases
n < 0.50 density decreases (voids form)
eL
e
-n
e n = - L
e
metals: n ~ 0.33
ceramics: n ~ 0.25
polymers: n ~ 0.40
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Elastic Deformation (cont.)
H82ENM Chapter 5 - 18
Example:
A tensile stress is to be applied along the long axis of a cylindrical brass rod that has a diameter of 10 mm.
Determine the magnitude of the load required to produce 2.5 x 10-3 mm change in diameter if the
deformation is entirely elastic. Given: The Poisson ratio value for Brass is 0.34. E = 97 GPa.
When force F is applied, the specimen will elongate in the z direction & contract in x direction.
For the strain in the x direction,
=
=2.5 x 103mm
10 mm= 2.5 x 104
(negative because the diameter is reduced)
Given the Poissons ratio, = 0.34
= =
2.5 x 104
0.34= 7.35 x 104
= = 7.35 x 104 97 x 103 MPa = 71.3 MPa
= = 2
2
= 71.3 x 106N
m210 x 103m
2
2
= 5600 N
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Elastic Deformation: Stress-Strain Behaviour
(cont.)
H82ENM Chapter 5 - 19
Slope of stress strain plot (which is proportional to the elastic
modulus) depends on bond strength of metal
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Elastic Deformation (cont.)
H82ENM Chapter 5 - 20
Elastic Shear modulus, G: t
G
g t = G g
Other Elastic Properties
simple
torsion
test
M
M
Special relations for isotropic materials:
2(1 + n)
E G = 3(1 - 2n)
E K =
Elastic Bulk modulus, K:
Pressure test: Init.
vol =Vo
Vol chg. = V
P
P P P = - K
V
V o
P
V
K V o
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Elastic Deformation (cont.)
H82ENM Chapter 5 - 21
Youngs Moduli: Comparison
Metals
Alloys
Graphite
Ceramics
Semicond
Polymers Composites
/fibers
E(GPa)
Composite data based on
reinforced epoxy with 60 vol%
of aligned
carbon (CFRE),
aramid (AFRE), or
glass (GFRE)
fibers.
109 Pa
0.2
8
0.6
1
Magnesium,
Aluminum
Platinum
Silver, Gold
Tantalum
Zinc, Ti
Steel, Ni
Molybdenum
G raphite
Si crystal
Glass - soda
Concrete
Si nitride Al oxide
PC
Wood( grain)
AFRE( fibers) *
CFRE *
GFRE*
Glass fibers only
Carbon fibers only
A ramid fibers only
Epoxy only
0.4
0.8
2
4
6
10
2 0
4 0
6 0 8 0
10 0
2 00
6 00 8 00
10 00 1200
4 00
Tin
Cu alloys
Tungsten
Si carbide
Diamond
PTF E
HDP E
LDPE
PP
Polyester
PS PET
C FRE( fibers) *
G FRE( fibers)*
G FRE(|| fibers)*
A FRE(|| fibers)*
C FRE(|| fibers)*
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Elastic Deformation (cont.)
H82ENM Chapter 5 - 22
Simple tension:
d = FL o
E A o
d L
= - n Fw o
E A o
Material, geometric, and loading parameters all contribute to deflection
Larger elastic moduli minimize elastic deflection.
Useful Linear Elastic Relationships
F
A o
d /2
d L
/2
Lo
w o
Simple torsion:
a = 2 ML o
r o 4 G
M = moment a = angle of twist
2ro
Lo
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Plastic Deformation
H82ENM Chapter 5 - 23
(at lower temperatures, i.e. T < Tmelt/3)
Plastic (Permanent) Deformation
Simple tension test:
engineering stress, s
engineering strain, e
Elastic+Plastic at larger stress
ep
plastic strain
Elastic initially
Adapted from Fig. 6.10(a), Callister
& Rethwisch 8e.
permanent (plastic) after load is removed
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Yield Strength, sy
H82ENM Chapter 5 - 24
Stress at which noticeable plastic deformation has
occurred.
when ep = 0.002
sy = yield strength
Note: for 2 inch sample
e = 0.002 = z/z
z = 0.004 in
Adapted from Fig. 6.10(a),
Callister & Rethwisch 8e.
tensile stress, s
engineering strain, e
sy
ep = 0.002
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Yield Strength : Comparison
H82ENM Chapter 5 - 25
Room temperature
values
Based on data in Table B.4,
Callister & Rethwisch 8e.
a = annealed
hr = hot rolled
ag = aged
cd = cold drawn
cw = cold worked
qt = quenched & tempered
Graphite/ Ceramics/ Semicond
Metals/ Alloys
Composites/ fibers
Polymers
Yie
ld s
trengt
h, s
y (M
Pa)
PVC
Har
d t
o m
eas
ure
,
since
in t
ensi
on, f
ract
ure
usu
ally
occ
urs
befo
re y
ield
.
Nylon 6,6
LDPE
70
20
40
60 50
100
10
30
200
300
400
500 600 700
1000
2000
Tin (pure)
Al (6061) a
Al (6061) ag
Cu (71500) hr Ta (pure) Ti (pure) a Steel (1020) hr
Steel (1020) cd Steel (4140) a
Steel (4140) qt
Ti (5Al-2.5Sn) a W (pure)
Mo (pure) Cu (71500) cw
Har
d t
o m
eas
ure
, in
cera
mic
mat
rix a
nd e
poxy
mat
rix c
om
posi
tes, s
ince
in t
ensi
on, f
ract
ure
usu
ally
occ
urs
befo
re y
ield
. H DPE PP
humid
dry
PC
PET
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Tensile Strength, TS
H82ENM Chapter 5 - 26
Metals: occurs when noticeable necking starts
Polymers: occurs when polymer backbone chains are
aligned and about to break
Adapted from Fig. 6.11,
Callister & Rethwisch 8e.
sy
strain
Typical response of a metal
F = fracture or
ultimate
strength
Neck acts as stress
concentrator
engi
neeri
ng
TS
str
ess
engineering strain
Maximum stress on engineering stress-strain curve.
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Tensile Strength: Comparison
H82ENM Chapter 5 - 27
Si crystal
Graphite/ Ceramics/ Semicond
Metals/ Alloys
Composites/ fibers
Polymers
Tensi
le
str
engt
h, T
S
(MPa)
PVC
Nylon 6,6
10
100
200
300
1000
Al (6061) a
Al (6061) ag
Cu (71500) hr
Ta (pure) Ti (pure) a
Steel (1020)
Steel (4140) a
Steel (4140) qt
Ti (5Al-2.5Sn) a W (pure)
Cu (71500) cw
L DPE
PP
PC PET
20
30 40
2000
3000
5000
Graphite
Al oxide
Concrete
Diamond
Glass-soda
Si nitride
H DPE
wood ( fiber)
wood(|| fiber)
1
GFRE (|| fiber)
GFRE ( fiber)
C FRE (|| fiber)
C FRE ( fiber)
A FRE (|| fiber)
A FRE( fiber)
E-glass fib
C fibers Aramid fib
Based on data in Table B.4,
Callister & Rethwisch 8e.
a = annealed
hr = hot rolled
ag = aged
cd = cold drawn
cw = cold worked
qt = quenched & tempered
AFRE, GFRE, & CFRE =
aramid, glass, & carbon
fiber-reinforced epoxy
composites, with 60 vol%
fibers.
Room temperature values
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Ductility
H82ENM Chapter 5 - 28
Plastic tensile strain at failure:
Another ductility measure: 100 x A
A A RA %
o
f o -
=
x 100 L
L L EL %
o
o f -
=
Engineering tensile strain, e
E ngineering
tensile
stress, s
smaller %EL
larger %EL Lf
Ao Af Lo
Reduction in Area
Elongation
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Resilience, Ur
H82ENM Chapter 5 - 29
Ability of a material to store energy
Energy stored best in elastic region
If we assume a linear stress-
strain curve this simplifies
to
y y r 2
1 U e s @
e
es=y
dUr 0
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Toughness
H82ENM Chapter 5 - 30
Energy to break a unit volume of material
Approximate by the area under the stress-strain curve
Brittle fracture: elastic energy
Ductile fracture: elastic + plastic energy
very small toughness (unreinforced polymers)
Engineering tensile strain, e
E ngineering
tensile
stress, s
small toughness (ceramics)
large toughness (metals)
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Question: Resilience vs Toughness
Define resilience and toughness.
State their difference(s).
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Engineering stress-strain vs True
stress-strain
Engineering stress-strain measures incorporate fixed
reference quantities.
Undeformed cross-sectional area is used.
True stress-strain measures account for changes in
cross-sectional area.
Instantaneous values for area is used.
Giving more accurate measurements.
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True Stress & Strain
H82ENM Chapter 5 - 33
Note: S.A. changes when sample stretched
True Stress
True Strain iT AF=s
oiT ln=e ee
ess
+=
+=
1
1
lnT
T
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Elastic Strain Recovery
H82ENM Chapter 5 - 34
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Hardness
H82ENM Chapter 5 - 35
Resistance to permanently indenting the surface
Large hardness means: --resistance to plastic deformation or cracking in compression
--better wear properties
e.g., 10 mm sphere
apply known force measure size of indent after removing load
d D Smaller indents mean larger hardness
increasing hardness
most plastics
brasses Al alloys
easy to machine steels file hard
cutting tools
nitrided steels diamond
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Hardness: Measurement
H82ENM Chapter 5 - 36
Rockwell
No major sample damage
Each scale runs to 130 but only useful in range 20-100
Minor load 10 kg
Major load 60 (A), 100 (B) & 150 (C) kg
A = diamond, B = 1/16 in. ball, C = diamond
HB = Brinell Hardness
TS (psia) = 500 x HB
TS (MPa) = 3.45 x HB
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H82ENM Chapter 5 - 37
Brinell (1)
Brinell (2)
Vickers
Knoop
Rockwell
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Rockwell Hardness Test
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Brinell Hardness Test
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Hardening
H82ENM Chapter 5 - 40
Curve fit to the stress-strain response:
s T = K e T
n
true stress (F/A) true strain: ln(L/Lo)
hardening exponent: n = 0.15 (some steels) to n = 0.5 (some coppers)
An increase in sy due to plastic deformation s
e
large hardening
small hardening s y 0
s y 1
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Variability in Material Properties
H82ENM Chapter 5 - 41
Elastic modulus is material property
Critical properties depend largely on sample flaws
(defects, etc.)
Large sample to sample variability
Statistics
Mean
Standard Deviation
2
1
2
1
-
-=
n
xxs i
n
n
xx n
n
=
(where n is the number of data points)
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Variability in Material Properties (cont.)
H82ENM Chapter 5 - 42
Example: The following tensile strengths were measured for four specimens of the same steel alloy. Compute: 1. The average tensile strength 2. Standard deviation
Average, = ()4=1
4
=520 + 512 + 515 + 522
4
= 517 MPa
Std. deviation, = () 24=1
4 1
2
=(520 517)2+(512 517)2+(515 517)2+(522 517)2
4 1
2
= 4.6 MPa
Sample number Tensile strength
(MPa)
1 520
2 512
3 515
4 522
Answer: 517 4.6 MPa
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Design or Safety Factors
H82ENM Chapter 5 - 43
Design uncertainties mean we do not push the limit.
Factor of safety, N
N
y
working
s=s
Often N is
between
1.2 and 4
Example: Calculate a diameter, d, to ensure that yield does not occur in the 1045 carbon steel rod below. Use a
factor of safety of 5.
40002202 /d
N,
5
N
y
working
s=s 1045 plain
carbon steel: s y = 310 MPa
TS = 565 MPa
F = 220,000N
d
L o
d = 0.067 m = 6.7 cm
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Summary
H82ENM Chapter 3 (2) -
44
Stress and strain: These are size-independent measures of load and
displacement, respectively
Elastic behaviour: This reversible behaviour often shows a linear
relation between stress and strain. To minimize deformation, select a
material with a large elastic modulus (E or G).
Plastic behaviour: This permanent deformation behaviour occurs
when the tensile (or compressive) uniaxial stress reaches sy
Toughness: The energy needed to break a unit volume of material
Ductility: The plastic strain at failure
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Homework:
Define elastic strain recovery with the aid of an
illustration.
Difference between Rockwell and Brinell hardness test
Coming up next:
Example Sheet 4