2.4 Reasoning with Properties from Algebra

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2.4 Reasoning with Properties from Algebra. Use properties of Algebra. Properties of Algebra. Addition Property If a = b, then a + c = b + c If x – 4 = 20, then x – 4 + 4 = 20 + 4. Properties of Algebra. Multiplication Property If a = b, then a * c = b * c where c ≠ 0 - PowerPoint PPT Presentation

Transcript of 2.4 Reasoning with Properties from Algebra

2.4 Reasoning with 2.4 Reasoning with Properties from Properties from

AlgebraAlgebraUse properties of AlgebraUse properties of Algebra

Properties of Algebra

Addition Property

If a = b, then a + c = b + c

If x – 4 = 20, then x – 4 + 4 = 20 + 4

Properties of Algebra

Multiplication Property

If a = b, then a * c = b * c where c ≠ 0

If ⅛ x = 4, then 8 * ⅛ x = 4 * 8

Other properties in Algebra

Reflexive Property x = x

Symmetric Property

If a = b, then b = a

Transitive Property

If a = b and b = c, then a = c

More properties in Algebra

Substitution Property

If x = 4, then 3x + 2 = 3(4) + 2

Distributive Property

2(x + 4) = 2x + 2(4)

Using the property of Algebra to solve an equation

3x + 12 = 8x – 18 Given

Using the property of Algebra to solve an equation

3x + 12 = 8x – 18 Given

- 3x = - 3x Reflexive Property

Using the property of Algebra to solve an equation

3x + 12 = 8x – 18 Given

- 3x = - 3x Reflexive Property

3x – 3x + 12 = 8x – 3x – 18Add. Property

Using the property of Algebra to solve an equation

3x + 12 = 8x – 18 Given

- 3x = - 3x Reflexive Property

3x – 3x + 12 = 8x – 3x – 18Add. Property

12 = 5x -18 Simplified

Using the property of Algebra to solve an equation

3x + 12 = 8x – 18 Given

- 3x = - 3x Reflexive Property

3x – 3x + 12 = 8x – 3x – 18Add. Property

12 = 5x -18 Simplified

18 = 18 Reflexive Property

Using the property of Algebra to solve an equation

3x + 12 = 8x – 18 Given

- 3x = - 3x Reflexive Property

3x – 3x + 12 = 8x – 3x – 18 Add. Property

12 = 5x -18 Simplified

18 = 18 Reflexive Property

12 + 18 = 5x – 18 + 18 Add. Property

Using the property of Algebra to solve an equation

3x + 12 = 8x – 18 Given - 3x = - 3x Reflexive Property

3x – 3x + 12 = 8x – 3x – 18Add. Property12 = 5x -18 Simplified18 = 18 Reflexive Property

12 + 18 = 5x – 18 + 18 Add. Property30 = 5x Simplified

Using the property of Algebra to solve an equation

3x + 12 = 8x – 18 Given - 3x = - 3x Reflexive Property

3x – 3x + 12 = 8x – 3x – 18 Add. Property12 = 5x -18 Simplified18 = 18 Reflexive Property

12 + 18 = 5x – 18 + 18 Add. Property30 = 5x Simplified

1/5 = 1/5 Reflexive Property

Using the property of Algebra to solve an equation

3x + 12 = 8x – 18 Given - 3x = - 3x Reflexive Property

3x – 3x + 12 = 8x – 3x – 18 Add. Property12 = 5x -18 Simplified18 = 18 Reflexive Property

12 + 18 = 5x – 18 + 18 Add. Property30 = 5x Simplified

1/5 = 1/5 Reflexive Property30 * 1/5 = 5x * 1/5 Mult. Property

Using the property of Algebra to solve an equation

3x + 12 = 8x – 18 Given - 3x = - 3x Reflexive Property

3x – 3x + 12 = 8x – 3x – 18 Add. Property12 = 5x -18 Simplified18 = 18 Reflexive Property

12 + 18 = 5x – 18 + 18 Add. Property30 = 5x Simplified

1/5 = 1/5 Reflexive Property30 * 1/5 = 5x * 1/5 Mult. Property

6 = x Simplified

Using the property of Algebra to solve an equation

3x + 12 = 8x – 18 Given - 3x = - 3x Reflexive Property

3x – 3x + 12 = 8x – 3x – 18 Add. Property12 = 5x -18 Simplified18 = 18 Reflexive Property

12 + 18 = 5x – 18 + 18 Add. Property30 = 5x Simplified

1/5 = 1/5 Reflexive Property30 * 1/5 = 5x * 1/5 Mult. Property

6 = x Simplifiedx = 6 Symmetric Property

Since this is Geometry, we will show Geometry facts with Algebra

Given A B C D ;

AC = BD Verify that AB = CD

AC = BD Given

Since this is Geometry, we will show Geometry facts with Algebra

Given A B C D ;

AC = BD Verify that AB = CD

AC = BD Given

AC = AB + BC

Since this is Geometry, we will show Geometry facts with Algebra

Given A B C D ;

AC = BD Verify that AB = CD

AC = BD Given

AC = AB + BC Segment Addition

Since this is Geometry, we will show Geometry facts with Algebra

Given A B C D ;

AC = BD Verify that AB = CD

AC = BD Given

AC = AB + BC Segment Addition

BD = BC + CD Segment Addition

Since this is Geometry, we will show Geometry facts with Algebra

Given A B C D ;

AC = BD Verify that AB = CD

AC = BD Given

AC = AB + BC Segment Addition

BD = BC + CD Segment Addition

AB + BC = BC + CD

Since this is Geometry, we will show Geometry facts with Algebra

Given A B C D ;

AC = BD Verify that AB = CD

AC = BD Given

AC = AB + BC Segment Addition

BD = BC + CD Segment Addition

AB + BC = BC + CD Substitution Prop.

Since this is Geometry, we will show Geometry facts with Algebra

Given A B C D ; AC = BD Verify that AB = CD

AC = BD GivenAC = AB + BC Segment AdditionBD = BC + CD Segment AdditionAB + BC = BC + CD Substitution Prop.BC = BC Reflexive Prop.

Since this is Geometry, we will show Geometry facts with Algebra

Given A B C D ; AC = BD Verify that AB = CD

AC = BD GivenAC = AB + BC Segment AdditionBD = BC + CD Segment AdditionAB + BC = BC + CD Substitution Prop.BC = BC Reflexive Prop.AB = CD Addition/ Subtraction

Prop.

Given Find

#1. #1. Given

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Given Find

#1. #1. Given

#2. #2. Subst. Prop

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Given Find

#1. #1. Given

#2. #2. Subst. Prop

#3. #3. Reflex Prop.

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33 mm

Given Find

#1. #1. Given

#2. #2. Subst. Prop

#3. #3. Reflex Prop.

#4. #4. Add./Subt Prop.

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180321

mm

mm

mmm

4m

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43321 mmmmm

33 mm

421 mmm

Given Find

#1. #1. Given

#2. #2. Subst. Prop

#3. #3. Reflex Prop.

#4. #4. Add./Subt. Prop.

#5. #5. Given

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9321

180321

mm

mm

mmm

4m

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33 mm

421 mmm

9321 mm

Given Find

#1. #1. Given

#2. #2. Subst. Prop

#3. #3. Reflex Prop.

#4. #4. Add./Subt. Prop.

#5. #5. Given

#6. #6. Substitution

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180321

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4m

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43321 mmmmm

33 mm

421 mmm

9321 mm

493 m

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