2.4 Reasoning with Properties from Algebra Use properties of Algebra.

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2.4 Reasoning with 2.4 Reasoning with Properties from Properties from Algebra Algebra Use properties of Algebra Use properties of Algebra

Transcript of 2.4 Reasoning with Properties from Algebra Use properties of Algebra.

Page 1: 2.4 Reasoning with Properties from Algebra Use properties of Algebra.

2.4 Reasoning with 2.4 Reasoning with Properties from Properties from

AlgebraAlgebraUse properties of AlgebraUse properties of Algebra

Page 2: 2.4 Reasoning with Properties from Algebra Use properties of Algebra.

Properties of Algebra

Addition Property

If a = b, then a + c = b + c

If x – 4 = 20, then x – 4 + 4 = 20 + 4

Page 3: 2.4 Reasoning with Properties from Algebra Use properties of Algebra.

Properties of Algebra

Multiplication Property

If a = b, then a * c = b * c where c ≠ 0

If ⅛ x = 4, then 8 * ⅛ x = 4 * 8

Page 4: 2.4 Reasoning with Properties from Algebra Use properties of Algebra.

Other properties in Algebra

Reflexive Property x = x

Symmetric Property

If a = b, then b = a

Transitive Property

If a = b and b = c, then a = c

Page 5: 2.4 Reasoning with Properties from Algebra Use properties of Algebra.

More properties in Algebra

Substitution Property

If x = 4, then 3x + 2 = 3(4) + 2

Distributive Property

2(x + 4) = 2x + 2(4)

Page 6: 2.4 Reasoning with Properties from Algebra Use properties of Algebra.

Using the property of Algebra to solve an equation

3x + 12 = 8x – 18 Given

Page 7: 2.4 Reasoning with Properties from Algebra Use properties of Algebra.

Using the property of Algebra to solve an equation

3x + 12 = 8x – 18 Given

- 3x = - 3x Reflexive Property

Page 8: 2.4 Reasoning with Properties from Algebra Use properties of Algebra.

Using the property of Algebra to solve an equation

3x + 12 = 8x – 18 Given

- 3x = - 3x Reflexive Property

3x – 3x + 12 = 8x – 3x – 18Add. Property

Page 9: 2.4 Reasoning with Properties from Algebra Use properties of Algebra.

Using the property of Algebra to solve an equation

3x + 12 = 8x – 18 Given

- 3x = - 3x Reflexive Property

3x – 3x + 12 = 8x – 3x – 18Add. Property

12 = 5x -18 Simplified

Page 10: 2.4 Reasoning with Properties from Algebra Use properties of Algebra.

Using the property of Algebra to solve an equation

3x + 12 = 8x – 18 Given

- 3x = - 3x Reflexive Property

3x – 3x + 12 = 8x – 3x – 18Add. Property

12 = 5x -18 Simplified

18 = 18 Reflexive Property

Page 11: 2.4 Reasoning with Properties from Algebra Use properties of Algebra.

Using the property of Algebra to solve an equation

3x + 12 = 8x – 18 Given

- 3x = - 3x Reflexive Property

3x – 3x + 12 = 8x – 3x – 18 Add. Property

12 = 5x -18 Simplified

18 = 18 Reflexive Property

12 + 18 = 5x – 18 + 18 Add. Property

Page 12: 2.4 Reasoning with Properties from Algebra Use properties of Algebra.

Using the property of Algebra to solve an equation

3x + 12 = 8x – 18 Given - 3x = - 3x Reflexive Property

3x – 3x + 12 = 8x – 3x – 18Add. Property12 = 5x -18 Simplified18 = 18 Reflexive Property

12 + 18 = 5x – 18 + 18 Add. Property30 = 5x Simplified

Page 13: 2.4 Reasoning with Properties from Algebra Use properties of Algebra.

Using the property of Algebra to solve an equation

3x + 12 = 8x – 18 Given - 3x = - 3x Reflexive Property

3x – 3x + 12 = 8x – 3x – 18 Add. Property12 = 5x -18 Simplified18 = 18 Reflexive Property

12 + 18 = 5x – 18 + 18 Add. Property30 = 5x Simplified

1/5 = 1/5 Reflexive Property

Page 14: 2.4 Reasoning with Properties from Algebra Use properties of Algebra.

Using the property of Algebra to solve an equation

3x + 12 = 8x – 18 Given - 3x = - 3x Reflexive Property

3x – 3x + 12 = 8x – 3x – 18 Add. Property12 = 5x -18 Simplified18 = 18 Reflexive Property

12 + 18 = 5x – 18 + 18 Add. Property30 = 5x Simplified

1/5 = 1/5 Reflexive Property30 * 1/5 = 5x * 1/5 Mult. Property

Page 15: 2.4 Reasoning with Properties from Algebra Use properties of Algebra.

Using the property of Algebra to solve an equation

3x + 12 = 8x – 18 Given - 3x = - 3x Reflexive Property

3x – 3x + 12 = 8x – 3x – 18 Add. Property12 = 5x -18 Simplified18 = 18 Reflexive Property

12 + 18 = 5x – 18 + 18 Add. Property30 = 5x Simplified

1/5 = 1/5 Reflexive Property30 * 1/5 = 5x * 1/5 Mult. Property

6 = x Simplified

Page 16: 2.4 Reasoning with Properties from Algebra Use properties of Algebra.

Using the property of Algebra to solve an equation

3x + 12 = 8x – 18 Given - 3x = - 3x Reflexive Property

3x – 3x + 12 = 8x – 3x – 18 Add. Property12 = 5x -18 Simplified18 = 18 Reflexive Property

12 + 18 = 5x – 18 + 18 Add. Property30 = 5x Simplified

1/5 = 1/5 Reflexive Property30 * 1/5 = 5x * 1/5 Mult. Property

6 = x Simplifiedx = 6 Symmetric Property

Page 17: 2.4 Reasoning with Properties from Algebra Use properties of Algebra.

Since this is Geometry, we will show Geometry facts with Algebra

Given A B C D ;

AC = BD Verify that AB = CD

AC = BD Given

Page 18: 2.4 Reasoning with Properties from Algebra Use properties of Algebra.

Since this is Geometry, we will show Geometry facts with Algebra

Given A B C D ;

AC = BD Verify that AB = CD

AC = BD Given

AC = AB + BC

Page 19: 2.4 Reasoning with Properties from Algebra Use properties of Algebra.

Since this is Geometry, we will show Geometry facts with Algebra

Given A B C D ;

AC = BD Verify that AB = CD

AC = BD Given

AC = AB + BC Segment Addition

Page 20: 2.4 Reasoning with Properties from Algebra Use properties of Algebra.

Since this is Geometry, we will show Geometry facts with Algebra

Given A B C D ;

AC = BD Verify that AB = CD

AC = BD Given

AC = AB + BC Segment Addition

BD = BC + CD Segment Addition

Page 21: 2.4 Reasoning with Properties from Algebra Use properties of Algebra.

Since this is Geometry, we will show Geometry facts with Algebra

Given A B C D ;

AC = BD Verify that AB = CD

AC = BD Given

AC = AB + BC Segment Addition

BD = BC + CD Segment Addition

AB + BC = BC + CD

Page 22: 2.4 Reasoning with Properties from Algebra Use properties of Algebra.

Since this is Geometry, we will show Geometry facts with Algebra

Given A B C D ;

AC = BD Verify that AB = CD

AC = BD Given

AC = AB + BC Segment Addition

BD = BC + CD Segment Addition

AB + BC = BC + CD Substitution Prop.

Page 23: 2.4 Reasoning with Properties from Algebra Use properties of Algebra.

Since this is Geometry, we will show Geometry facts with Algebra

Given A B C D ; AC = BD Verify that AB = CD

AC = BD GivenAC = AB + BC Segment AdditionBD = BC + CD Segment AdditionAB + BC = BC + CD Substitution Prop.BC = BC Reflexive Prop.

Page 24: 2.4 Reasoning with Properties from Algebra Use properties of Algebra.

Since this is Geometry, we will show Geometry facts with Algebra

Given A B C D ; AC = BD Verify that AB = CD

AC = BD GivenAC = AB + BC Segment AdditionBD = BC + CD Segment AdditionAB + BC = BC + CD Substitution Prop.BC = BC Reflexive Prop.AB = CD Addition/ Subtraction

Prop.

Page 25: 2.4 Reasoning with Properties from Algebra Use properties of Algebra.

Given Find

#1. #1. Given

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mm

mmm

4m

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mmm

Page 26: 2.4 Reasoning with Properties from Algebra Use properties of Algebra.

Given Find

#1. #1. Given

#2. #2. Subst. Prop

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180321

mm

mm

mmm

4m

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mmm

43321 mmmmm

Page 27: 2.4 Reasoning with Properties from Algebra Use properties of Algebra.

Given Find

#1. #1. Given

#2. #2. Subst. Prop

#3. #3. Reflex Prop.

18043

9321

180321

mm

mm

mmm

4m

18043

180321

mm

mmm

43321 mmmmm

33 mm

Page 28: 2.4 Reasoning with Properties from Algebra Use properties of Algebra.

Given Find

#1. #1. Given

#2. #2. Subst. Prop

#3. #3. Reflex Prop.

#4. #4. Add./Subt Prop.

18043

9321

180321

mm

mm

mmm

4m

18043

180321

mm

mmm

43321 mmmmm

33 mm

421 mmm

Page 29: 2.4 Reasoning with Properties from Algebra Use properties of Algebra.

Given Find

#1. #1. Given

#2. #2. Subst. Prop

#3. #3. Reflex Prop.

#4. #4. Add./Subt. Prop.

#5. #5. Given

18043

9321

180321

mm

mm

mmm

4m

18043

180321

mm

mmm

43321 mmmmm

33 mm

421 mmm

9321 mm

Page 30: 2.4 Reasoning with Properties from Algebra Use properties of Algebra.

Given Find

#1. #1. Given

#2. #2. Subst. Prop

#3. #3. Reflex Prop.

#4. #4. Add./Subt. Prop.

#5. #5. Given

#6. #6. Substitution

18043

9321

180321

mm

mm

mmm

4m

18043

180321

mm

mmm

43321 mmmmm

33 mm

421 mmm

9321 mm

493 m

Page 31: 2.4 Reasoning with Properties from Algebra Use properties of Algebra.

HomeworkHomework

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