PH = - log [H 3 O + ] [H 3 O + ] = 10 - pH mol/L For pure water at 25 o C pH = - log (1.0 x 10 -7 ) = 7.00 For a change in pH by 1, H 3 O + concentration.
![PH = - log [H 3 O + ] [H 3 O + ] = 10 - pH mol/L For pure water at 25 o C pH = - log (1.0 x 10 -7 ) = 7.00 For a change in pH by 1, H 3 O + concentration.](https://static.fdocuments.us/doc/330x215/56649d4c5503460f94a29c0c/ph-log-h-3-o-h-3-o-10-ph-moll-for-pure-water-at-25-o-c-ph.jpg)
