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The Straight Line
THE STRAIGHT LINE
GRADIENT m =12
12
X X
Y Y
−
−
Example Exercises
1) (1,2) and (3,4) 1) ( 2,1) and (4,3)
m =13
24
−
− =
2
2= 1
------------------------------------------------------------------------------------------------------------
2) (-1,2) and (3,4) 2) (- 2,1) and (4,3)
m=)1(3
24
−−
−=
4
2=
2
1
------------------------------------------------------------------------------------------------------------
3) (1,-2) and (3, 4) 4) (2,-1) and (4, 3)
------------------------------------------------------------------------------------------------------------
5) (-1,-2) and (3, 4) 6) (-2,-1) and (4, 3)
------------------------------------------------------------------------------------------------------------
7) (-1,-2) and (-3,-4) 8.) (-2,-1) and (-4,-3)
------------------------------------------------------------------------------------------------------------
9) (0,2
1) and ( 0,
2
3) 10) (-
2
1,2
3) and (
2
1,-
2
1)
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The Straight Line
INTERCEPT
X-intercept y = 0
Example Exercise
1) 42 += x y 1) 63 += x y
4200 +=⇒= x y
22
4
42
24
−=−
=
−=
=−
x
x
x
x- intercept = -2---------------------------------------------------------------------------------------------------------------------
2) 25 −= x y 2) 52 +−= x y
2500 −=⇒= x y
5
225
52
=
=
=
x
x
x
x-intercept =2
5
---------------------------------------------------------------------------------------------------------------------
3) 54 +−= x y 4.) 13 +−= x y
---------------------------------------------------------------------------------------------------------------------
5) 632 −= x y 6) 522 +−= x y
● y-intercept (x = 0)
●x-intercept (y = 0)
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The Straight Line
7) 63
2+−= x y 8) 4
5
2−−= x y
---------------------------------------------------------------------------------------------------------------------
9) 125
32 += x y 10) 3
9
13 −= x y
--------------------------------------------------------------------------------------------------------------------
11) 122 +=− x y 12) 233 −=− x y
y –intercept x = 0
Example Exersice
1) 62 += x y 1) 83 += x y
x = 0 , y = 2(0) + 6
y = 6y- intercept = 6
---------------------------------------------------------------------------------------------------------------------
2) 72 −= x y 3.) 93 −= x y
---------------------------------------------------------------------------------------------------------------------
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The Straight Line
4) 63
2+= x y 5) 6
2
1−= x y
---------------------------------------------------------------------------------------------------------------------
6) 73
2+−= x y 7) 10
5
2−−= x y
---------------------------------------------------------------------------------------------------------------------
Example
8) 125
32 += x y 9) 21
9
13 −= x y
X = 0, 2y =5
3(0) + 12
2y = 12y = 6
y – intercept = 6--------------------------------------------------------------------------------------------------------------------
10) 122 +=− x y 11) 233 −=− x y
……………………………………………………………………………………………………..
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The Straight Line
EQUATION OF A STRAIGHT LINE : y = mx + c
Gradient y-intercept
THE EQUATION OF A STRAIGHT LINE PASSING THROUGH THE POINTS AND
GRADIENT
Example Exercise A1) (2,7) and m = 3 1) (4,9) and m= -2
y = mx + c
7 = 3(2) + c7 = 6 + c7 – 6 = c
c = 1
Equation of a straight line , y = 3x + 1……………………………………………………………………………………………………….
2) (-3,5) and m = 4 2) (-1,7) and m = 5y = mx + c
5 = 4(-3) + c5 = -12 + c
C= 5 + 12=17
Equation of a straight line, y = 4x +17……………………………………………………………………………………………………….
3) (4,-9) and m =2
1 3) (-5,11) and m = -2
y = mx + c
-9 =2
1(4) + c
-9 = 2 + c-9 – 2 = c
c = -11
equation of a straight line, y = 2
1x - 11
……………………………………………………………………………………………………….
4) ( -3,-5) and m =3
2 5) (3,-7) and m = -
4
3
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The Straight Line
6) (-1,-4) and m =5
2 7) (-10,10) and m = -
5
4
…………………………………………………………………………………………….
8) (0,-3) and m =2
1 9) (-6,-2) and m =
3
4
The straight line can also be obtained by using the formula
y –k = m (x –h)
Example Exercise B
1) (2,7) and m = 3 1) (4,9) and m= -2
13
763
637)2(37
+=
+−=
−=−
−=−
x y
x y
x y x y
……………………………………………………………………………………………………….
2) (-3,-5) and m = 4 3) (-1,7) and m = 5
……………………………………………………………………………………………………….
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4) (4,-9) and m =2
1 5) (5,-11) and m = -2
……………………………………………………………………………
6) ( -4,-5) and m =3
2 7) (4,-7) and m = -
4
3
723
15823
82153
)4(2)5(3
)4(3
25
))4((32)5(
−=
−+=
+=+
+=+
+=+
−−=−−
x y
x y
x y
x y
x y
x y
…………………………………………………………………………………………………….
8 (-1,-4) and m =5
2 9) (10,10) and m = -
5
4
…………………………………………………………………………………………….
10) (0,-3) and m =2
1 11) (-5,-2) and m =
3
4
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The Straight Line
EQUATION OF A STRAIGHT LINE – THROUGH TWO POINTS
Step 1 : Find the gradientStep 2: Find the y- intercept
Step 3 : Write down the equation in a form of y = mx + c
Example Exercise
(-1,2) and (3,4) 1. (2,1) and (4,3)
m=)1(3
24
−−
−=
4
2=
2
1
y = mx + c
4 =2
1(3) + c
4 =2
3+ c
C= 4 -2
3
= 22
1
Equation of a straight line, y =2
1x +
2
5
Or 2y = x + 5---------------------------------------------------------------------------------------------------------------------
2) (-1,2) and (3,4) 3) (-2,1) and (4,3)
---------------------------------------------------------------------------------------------------------------------
4) (3,-5) and (-2,5) 5) (3,-7) and (-1,3)
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6) (0,-5) and (2,1) 7) (-1,5) and (-3,-7)
---------------------------------------------------------------------------------------------------------------------
8) ( 4,2
1) and (3,-6) 9) ( 5,
3
1) and ( 3,
3
1−− )
---------------------------------------------------------------------------------------------------------------------
EQUATION OF A STRAIGHT LINE PASSING THROUGH PARALLEL LINES
Lines which are parallel have the same gradient and vice versa.
Example Exercise
1) (1,2) and y = 3x – 4 1) (0,-3) and y = -2x + 5
3=⇒ m
13
233
332
)1(32
−=
+−=
−=−
−=−
x y
x y
x y
x y
………………………………………………………………………………………………2) (2,4) and y + x = 5 2) (0,6) and y = 5x -1
y = -x + 5
1−=⇒ m
.............................................................................................................................................................
6
42
24
)2(14
+−=
++−=
+−=−
−−=−
x y
x y
x y
x y
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3) (8,-5) and 5y + 20x = -2 3) (2,3) and 2x -5y = 125y = -20x -2
y = 5
220 −− x
y = - 4x -5
2
4−=⇒ m
374
5324
3245
)8(4)5(
−=
−−=
−=+
−=−−
x y
x y
x y
x y
………………………………………………………………………………………………
4) (5,2) and y = x -3 5) (1,8) and 3x + y =4
………………………………………………………………………………………………6) (3,4) and y = 2x -2 7) (0,-3) and 2x + y -5 = 0
………………………………………………………………………………………………8) (-1,3) and y = 3x + 1 9) (4,0) and y = 3x - 11
………………………………………………………………………………………………10) (4,-5) and y = -2x + 3 11) (3,4) and 4y – 2x = 3
8/21/2019 [Worksheet] Chapter 5 - The Straight Line
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The Straight Line
EXAMINATION FORMAT QUESTION
A(0,4)
B(2,2)
CO
Diagram 1
R O
P 0 6
Q(3,5)
Diagram 2
EXAMPLE 1
(i)
gradient AB= 12
2
20
24−=
−=
−
−
(ii) x-intercept for AB
0=⇒ y
the equation of AB ⇒
4
40
4
)0(14
=
−=−
−=−
−−=−
x
x
x y
x y
x-intercept = 4
(iii)
the equation of AC
102
02=
−
−== OB AC M M
4
4
)0(14
+=
=−
−=−
x y
x y
x y
EXERCISE1.Base on diagram 2
(i) gradient PQ
(ii) x-intercept for PQ
(iii) the equation of PR
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B(-3,3)C(5,4)
F
E
A(2,6)
Diagram 3
R
O P
Q(7,8)
3 In the diagram 4, 6=OP units.
(i) find the gradient of PR
(ii) find the y-intercept of PQ
Diagram 4
2 Base on diagram 3, find(i) the gradient of AB
(ii) the equation of ECF
(iii) x-intercept for ECF
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A
-6
O
B
4
4 The diagram 5, AB is a straight
line.
(i) state the y-intercept of AB
(ii) find the equation of of AB
Diagram 5
P(0,6)
QO
5. In diagram 6, the gradient of PQ
is2
3− . Line
RS is parallel to the line PQ and passes through a point (-5,3). Find
(i) the coordinate of Q.
ii) the equation of RS
Diagram 6
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6. In diagram 7, line DE is parallel to the line GF.
Given the equation of straight line DG is x + 3y = 14 and the gradient of GF is -2,
Find
(a) the value of h,(b) the coordinate F( c) the equation of straight line DE
[ 5 marks]
7. In diagram 8, the gradient of the straight line MN is3
2
Find(a) the value of p(b) the equation of straight line LN
8. In diagram 9, JKLM is a trapezium and JK is parallel to ML
Find
(i) the x-intercept for the straight line JK(ii) the equation of the straight line ML(iii) the coordinate M
y
x
D(-4,6)
G(h,4)
E O FDiagram 7
y
x
3
-5
● N(6, p)
Diagram 8
M
L
y K (2,5)
J(-4,2)
L(4,3)
M Ox
Diagram 9
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The Straight Line
SPM PAST YEAR QUESTIONS (PAPER 2)
1. SPM 2003
In Diagram 2, the graph shows that PQ, QR, and RS are straight lines. P is on the y-axis. OP isParallel to QR and PQ is parallel to RS.
The equation of PQ is 2x + y = 5(a) State the equation of the straight line QR(b) Find the equation of the straight line RS and hence, state its y-intercept.
[ 5 marks ]
2. SPM 2004
In Diagram 3, OPQR is parallelogram and O is the origin.
Find
(a) the equation of the straight line PQ,(b) the y-intercept of the straight line QR
[ 5 marks ]
O Q x
P●
● R
● (8, -7)
y
y
● R(4,12)
●Q
● P (3, -6)
0 x
Diagram 3
Diagram 2
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3. SPM 2005
In Diagram 2, O is the origin, point R lies on the x-axis and point P pies on the y-axis.
Straight line PU is parallel to the x-axis and straight line PR is parallel to straight line ST . Theequation of straight line PR is x + 2y = 14.
(a) State the equation of the straight line PU
(b) Find the equation of the straight line ST and hence , state its x-intercept
[ 5 marks]
4. SPM 2006( June)
In Diagram 3, O is the origin and PQRS is a trapezium. PS is parallel to QR. Straight line RS is
parallel to x-axis. Point Q and S lies on x-axis
Find
(a) Equation of a straight line QR(b) x-intercept of the straight line QR
[ 5 marks ]
●
R(4, -11)
yP (-1, 10)
●
xQ● ●S
Diagram 3
y
x●O R
P● ●U
x + 2y -14
S ●
●T(2, -5)
Diagram 2
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5. SPM 2006(Nov)
Diagram 5 shows a straight line PQ and a straight line RS drawn on a Cartesian plane. PQ is
parallel to RS.
Finda) the equation of the straight line PQ,
b) the x-intercept of the straight line PQ[ 5 marks ]
6. SPM 2007( June)
In Diagram 2, O is the origin . Point P and point R lie on the y-axis. PS is parallel to the x-axis
and straight line SR is parallel to straight line PQ .
Find(a) the equation of a straight line SR
(b) the x-intercept of the straight line SR[ 5 marks ]
Diagram 5
y
R (0, 4) ●
x
Q●O
P (0, 4)●
●
S (0, 4)
Diagram 2
y
xQ -4,0
S 8 , 3
R
P
O
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7. SPM 2007(Nov)
In Diagram 2, O is the origin .Straight line KL is parallel to straight line MN. The equation ofstraight line KL is 2x + y = 4. The points L and N lie on y-axis .
Findc) the equation of the straight line MN,
d) the x-intercept of the straight line MN[ 5 marks ]
8. SPM 2008( June)
In Diagram 5, PQRS is parallelogram and O is the origin . It is given that the equation of the
straight line PQ is 2y = x + 18.
Find(a) the equation of a straight line RS,
(b) the x-intercept of the straight line RS.[ 5 marks ]
y
M (-3, 7) ●
x
K●
●L
N●
O
Diagram 2
Diagram 5
y
x
R 7, 2
S
Q
P
O
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9. SPM 2008( Nov)
Diagram 6 show a trapezium PQRS drawn on a Cartesian plane. SR is parallel to PQ .
Find(a) the equation of a straight line SR
(b) the y-intercept of the straight line SR[ 5 marks ]
Diagram 6
y
xQ 11,1
S 8 , 9
RP (3 , 5)
O
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ANSWERS
Gradient
Exercise1) 1
2)3
1
3) 3 4) 25)
2
3
6)2
5
7) 1 8) 19)
3
1−
10) 2
Intercept
x-intercept
1. x = -2
2. x = 2
5
3. x = 4
5
4. x = 3
1
5. x = 2
6. x = 2
5
7. x = 9 8. x = 10 9. x = -20 10. x = -27 11. x = -1212.
3
2
y-intercept
1. y = 8 2. y = -7 3. y = -9 4 y = 6 5. y = -6 6. y = 7
7. y = -10 9. y = -7 10. y = -611. y =
3
2
Equation of a straight line – given the point and gradient
Exercise
1. y = -2x + 17 2. y = 5x +12 3. y = -2x + 14. y =
3
2x – 3 5. y = -
4
3x -19
6. y =5
2x -
5
18 7. y = -
5
4x + 2 8. y =
2
1x – 3 9. y =
3
4x - 1
The equation of a straight line passing through
two points
1. y = x – 12. y =
4
1x +
4
9
3. 3y = x + 5 4. y = -2x – 1 5. 2y = -5x + 1
6. y = 3x – 5 7. y = 6x + 11 8. y = -4x + 6 9. y = 12x + 1
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Equation of a straight line through parallel lines Exercise
1. 32 −−= x y 2. y = 5x + 6 3. y = 2x + 11 4. y = x – 3 5. y = -3x +11
6. y = 2x -2 7. y = -2x – 3 8. y = 3x + 6 9. y = 3x – 12 10. y = -2x + 3
11. 2y = x + 5
SPM Format Question
1. (i) -3
1 (ii) x = 18
2. (i)53 (ii) y =
53 x + 1 (iii) x = -
35
3. (i)3
4 (ii) y = 8x – 48
4. (i) -6 (ii) y =2
3x – 6
5. (i) Q = (4,0) (ii) 2y = -3x - 9
6. (i) x = 2 (ii) ( 4,0 ) (iii) y = -2x + 2
7. (a) p = 7 (b) y = 2x – 7
8. (a)2
1 (b) 2y = x + 2 (c) (-2,0)
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Past Years SPM Questions
1. SPM 2003 Q5
(a) x =2
5 (b) y-intercept =9
2. SPM 2004 Q6
(a) y = 3x – 15 (b) y-intercept =20
3. SPM 2005 Q5(a) y = 7 (b) 2y = -x - 8
x = 8
4. SPM 2006 ( June) Q7
(a) y = -2x -3 (b) x = -23
5. SPM 2006 ( Nov) Q10
(a) y = -2x + 11 (b) x –intercept =2
11
6. SPM 2007 ( June) Q7
(a) 34
3−= x y (b) x-intercept = 4
7. SPM 2007 ( Nov) Q5
(a) y = -2x + 1 (b) x –intercept =2
1
8. SPM 2008 ( June) Q7
(a)2
3
2
1−= x y (b) x-intercept = 3
9. SPM 2008 ( Nov) Q5
(a) 132
1+−= y (b) y –intercept = 13
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