Tentukan dengan Induksi Matematika Rumus dibawah inia. 1 + 2 + 3 + … + (2n + 3 ) = n2 + 4nb. 1 + 3 + 5 + … + (2n – 1 ) = n2
c. 6 + 10 + 14 + … + ( 4n + 2 ) = 2n2 + 4nd. 2 + 4 + 8 + … + 2n = 2n+1 – 2
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