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Warm-Up 2/261.

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10 βˆ™22βˆ™23=10 βˆ™ 25=10 βˆ™32

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Rigor:You will learn how to find the real and complex

zeros of polynomial functions.

Relevance:You will be able to use graphs and equations of

polynomial functions to solve real world problems.

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2-4 Zeros of Polynomial Functions

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Example 1a: List possible rational zeros and determine which, if any are zeros.

𝑓 (π‘₯)=π‘₯3+2π‘₯+1

Step 1 Identify possible rational zeros.

and

Step 2 Test possible rational zeros to determine if they are rational zeros.

π‘π‘ž=Β± Factors 1

Factors 1=1π‘œπ‘Ÿβˆ’1

There are no rational zeros.

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Example 1b: List possible rational zeros and determine which, if any, are zeros.

𝑔 (π‘₯ )=π‘₯4+4 π‘₯3 βˆ’12π‘₯βˆ’ 9Step 1 Identify possible rational zeros.

Step 2 Test possible rational zeros to determine if they are rational zeros.

π‘π‘ž=Β± Factors 9

Factors 1=Β±1 , Β± 3 ,π‘œπ‘Ÿ Β± 9

There are two rational zeros at .

0

3

3

1 4 – 12

↓

– 9

– 1 – 3

– 31 – 9

9

0

– 1 – 3

9

0

1 3 – 9

↓ – 3 0

– 31 0

– 3

𝑔 (π‘₯)=(π‘₯+1) (π‘₯+3 )(π‘₯2βˆ’ 3)

π‘₯2βˆ’3=0π‘₯2=3π‘₯=±√3  

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Example 2: List possible rational zeros and determine which, if any, are zeros.

h (π‘₯ )=3 π‘₯3βˆ’ 7 π‘₯2 βˆ’2 2π‘₯+8Step 1 Identify possible rational zeros.

Step 2 Test possible rational zeros to determine if they are rational zeros.

π‘π‘ž=Β± Factors 8

Factors 3=Β±1 , Β± 2 , Β± 4 Β± 8 ,Β± 13 , Β± 2

3 , Β± 43 ,π‘œπ‘Ÿ Β± 8

3

There are 3 rational zeros at .

– 22

– 8

– 13

3 – 7 8

↓ – 6 26

43 0

– 2 4

– 1

3 – 13

↓ 12 – 4

03

4

h (π‘₯)=(π‘₯+2) (π‘₯βˆ’ 4 )(3 π‘₯βˆ’1)3 π‘₯βˆ’1=0

3 π‘₯=1π‘₯=

13

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Example 6: Write a polynomial function of least degree with real coefficients in standard form that has the given zeros.

y = (x + 2)(x – 4)[x – (3 – i)][x – (3 + i)]

y = (x + 2)(x – 4)[(x – 3) + i][(x – 3) – i]

y = (xΒ² – 4x + 2x – 8)[(x – 3)Β² – i(x – 3) + i(x – 3) – iΒ²]

y = (xΒ² – 2x – 8)[(x – 3)Β² + 1]

y = (xΒ² – 2x – 8)(xΒ² – 6x + 9 + 1)

y = (xΒ² – 2x – 8)(xΒ² – 6x + 10)

y = x4 – 6x3 + 10xΒ² – 2x3 + 12xΒ² – 20x – 8xΒ² + 48x – 80

y = x4 – 8x3 + 14xΒ² + 28x – 80

(x – c)3 + i

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Example 7: Write function as (a) the product of linear and irreducible quadratic factors and (b) the product of linear factors. Then (c) list all zeros.π‘˜ (π‘₯ )=π‘₯5 βˆ’18 π‘₯3+30π‘₯2 βˆ’19π‘₯+30

(a) the product of linear and irreducible quadratic factors

π‘˜(π‘₯)=(π‘₯+5) (π‘₯βˆ’2 )(π‘₯βˆ’ 3)(π‘₯2+1)

π‘₯2+1

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Example 7: Write function as (a) the product of linear and irreducible quadratic factors and (b) the product of linear factors. Then (c) list all zeros.π‘˜ (π‘₯ )=π‘₯5 βˆ’18 π‘₯3+30π‘₯2 βˆ’19π‘₯+30

(b) the product of linear factors

π‘˜(π‘₯)=(π‘₯+5) (π‘₯βˆ’2 )(π‘₯βˆ’ 3)(π‘₯2+1)

π‘₯2+1=0π‘₯2=βˆ’1π‘₯=Β±βˆšβˆ’1π‘₯=Β± 𝑖

π‘˜(π‘₯)=(π‘₯+5) (π‘₯βˆ’2 )(π‘₯βˆ’ 3)(π‘₯+ 𝑖)(π‘₯βˆ’π‘–)(c) List all zerosThere are 5 zeros: .

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Example 8: Use given zeros to find all complex zeros. Then write the linear factorization of the function.𝑝 (π‘₯ )=π‘₯4 βˆ’ 6π‘₯3+20 π‘₯2βˆ’ 22π‘₯βˆ’ 13 given 2 βˆ’3 𝑖as a zero of 𝑝 .

20

24 + 3i

– 4 – 3i

1 – 6 – 22

↓

– 13

2 – 3i – 17 + 6i

3 + 6i1 2 + 3i

13

0

2 – 3i

3 + 6i

– 2 – 3i

– 2

1 – 4 – 3i 2 + 3i

↓ 2 + 3i – 4 – 6i

– 11 0

2 + 3i

𝑝 (π‘₯ )= [π‘₯βˆ’ (2 βˆ’3 𝑖 ) ] [π‘₯βˆ’ (2+3 𝑖 ) ] (π‘₯2 βˆ’2 π‘₯βˆ’1)

π‘₯2βˆ’2 π‘₯βˆ’1

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Example 8: Use given zeros to find all complex zeros. Then write the linear factorization of the function.𝑝 (π‘₯ )=π‘₯4 βˆ’ 6π‘₯3+20 π‘₯2βˆ’ 22π‘₯βˆ’ 13 given 2 βˆ’3 𝑖as a zero of 𝑝 .

𝑝 (π‘₯ )= [π‘₯βˆ’ (2 βˆ’3 𝑖 ) ] [π‘₯βˆ’ (2+3 𝑖 )] (π‘₯2 βˆ’2 π‘₯βˆ’1)

π‘₯=βˆ’π‘Β±βˆšπ‘2 βˆ’ 4π‘Žπ‘2π‘Ž

π‘₯=2 ±√4 βˆ’ 4 (1)(βˆ’1)

2π‘₯=2 ±√8

2

π‘₯=2 Β±2√22

π‘₯=1 ±√2

𝑝 (π‘₯ )= [π‘₯βˆ’ (2 βˆ’3 𝑖 ) ] [π‘₯βˆ’ (2+3 𝑖 ) ] [π‘₯βˆ’ ( 1+√2 ) ] [π‘₯βˆ’ ( 1βˆ’βˆš2 ) ]

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βˆšβˆ’1math!

2-4 Assignment: TX p127, 4-16 EOE & 32-52 EOE

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