Solving Systems by Graphing
Unit 6 Lesson 1
SOLVING SYSTEMS BY GRAPHING
Students will be able to:
Recognize the different types of linear systems of equations and find its solution by graphing.
Key Vocabulary:
Solve Linear Systems by Graphing
Linear Equations in two variables
Point of Intersection between Linear Functions
Independent System
Dependent System
Inconsistent System
LINEAR SYSTEM OF EQUATIONS
is a set of equations with thesame variables. When we aresolving systems graphically, wehave to find the intersectionbetween the two lines.
SOLVING SYSTEMS BY GRAPHING
-3
-2
-1
0
1
2
3
4
5
-3 -2 -1 0 1 2 3 4
Point of intersection
CLASSIFICATION OF LINEAR SYSTEMS
1. Independent System (One solution).
2. Dependent System (Infinite solutions).
3. Inconsistent System (No solution).
SOLVING SYSTEMS BY GRAPHING
INDEPENDENT SYSTEM is asystem where two distinct non-parallel lines intersect at onespecific point (x,y).
SOLVING SYSTEMS BY GRAPHING
-6
-4
-2
0
2
4
6
8
10
12
14
16
-2 -1 0 1 2 3 4 5 6 7 8
Solution (5,2)
DEPENDENT SYSTEM is a systemwhere appears to show only oneline. Actually, there are two lines,one upon the other, then it hasinfinite solutions.
SOLVING SYSTEMS BY GRAPHING
0
0.5
1
1.5
2
2.5
3
3.5
4
4.5
-2.5 -2 -1.5 -1 -0.5 0 0.5 1 1.5 2 2.5
INCONSISTENT SYSTEM is asystem where two distinct linesare parallel. Since parallel linesnever intersect, then there canbe no solution.
SOLVING SYSTEMS BY GRAPHING
-2
-1
0
1
2
3
4
5
6
7
-2.5 -2 -1.5 -1 -0.5 0 0.5 1 1.5 2 2.5
There is no intersection between the lines, so there is no solution!
LINEAR FUNCTION to graph a linear function it is necessary to find its pointof intersection with the axes.
X axis, where y=0Y axis, where x=0
EQUATION OF A LINEAR FUNCTION it is represented by the followingequation:
π¦ βπ¦1 = π(π₯ β π₯1)
Where m is the slope of the line and (x1, y1) is a point that belongs to thelinear function. The slope can be calculated by selecting two points fromthe graph and substituting them in the following equation:
π =π¦2βπ¦1
π₯2βπ₯1
SOLVING SYSTEMS BY GRAPHING
Sample Problem 1: From the given graph, identify the equations of the linear function that compose the system
SOLVING SYSTEMS BY GRAPHING
-2
-1
0
1
2
3
4
5
6
7
8
9
-2.5 -2 -1.5 -1 -0.5 0 0.5 1 1.5 2 2.5
Sample Problem 1: From the given graph, identify the equations of the linear function that compose the systemSelect two points for each linear function to calculate its equation, onepoint would be the intersection point and the other a point that belong toeach of the corresponding linear function.β’ For the blue line: (-1,2) and (0,1)
πβ ππ =ππ β ππ
ππ β ππ(π β ππ)
π β π =π β π
βπ β π(π β π)
π = βπ + π β π + π = π
SOLVING SYSTEMS BY GRAPHING
Sample Problem 1: From the given graph, identify the equations of the linear function that compose the system
β’ For the pink line: (-1,2) and (0,4)
πβ π =π βπ
βπβ π(π βπ)
π = π πβπ + π
π = ππ+ π β βππ+ π = π
SOLVING SYSTEMS BY GRAPHING
Sample Problem 1: From the given graph, identify the equations of the linear function that compose the system
SOLVING SYSTEMS BY GRAPHING
β’ For the pink line: (-1,2) and (0,4)
πβ π =π βπ
βπβ π(π βπ)
π = π πβπ + π
π = ππ+ π β βππ+ π = π
Finally:
x + y= 1
-2x + y= 4
Sample Problem 2: Find the solution of the following system by graphing:
3X βY = 3
X +Y = -3
SOLVING SYSTEMS BY GRAPHING
Sample Problem 2: Find the solution of the following system bygraphing:
One easy way to graph each linear function is to find its interceptswith the axes.
SOLVING SYSTEMS BY GRAPHING
β’ ππβπ = ππ₯ = 0 β π¦ = β3 β (0,β3)
π¦ = 0 β π₯ = 1 β (1,0)
β’ π+ π = βππ₯ = 0 β π¦ = β3 β (0,β3)
π¦ = 0 β π₯ = β3 β (β3,0)
Sample Problem 2: Find the solution of the following system bygraphing:
SOLVING SYSTEMS BY GRAPHING
-10
-8
-6
-4
-2
0
2
4
-2.5 -2 -1.5 -1 -0.5 0 0.5 1 1.5 2 2.5
Solution (0,-3)
Sample Problem 3: Identify the solution of the system anddetermine what type of system is
SOLVING SYSTEMS BY GRAPHING
-8
-6
-4
-2
0
2
4
6
8
0 0.5 1 1.5 2 2.5 3 3.5 4 4.5
Sample Problem 3: Identify the solution of the system anddetermine what type of system is
SOLVING SYSTEMS BY GRAPHING
-8
-6
-4
-2
0
2
4
6
8
0 0.5 1 1.5 2 2.5 3 3.5 4 4.5
Solution (2,0)
The solution of the system isgiven by the point ofintersection between thelines, in this case is the point(2,0) and it represents anindependent system.
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