Download - Solutions and Gases Calculations (2)

Lone Star Chemistry Solutions

A Dozen or More A Dozen or More CalculationsCalculations

GasesGasesMason, Koeck, and KulhanekMason, Koeck, and Kulhanek


BCCEBCCEAugust 1-5August 1-5

University of University of North TexasNorth Texas

Denton, TexasDenton, Texas


TEKS Development TEKS Development and Correlation to and Correlation to

CCRSCCRS Lone Star Lone Star Chemistry Chemistry SolutionsSolutions

https://callevents.unt.edu/ei/getdemo.ei?https://callevents.unt.edu/ei/getdemo.ei?id=3&s=_3000VYEX3id=3&s=_3000VYEX3


EngagementEngagement

GasesGases

Dynamic Diana’s Daring Dynamic Diana’s Daring DemoDemo


ExplorationExploration

Boyle’s LawBoyle’s Law

The pressure of a gas at The pressure of a gas at constant temperature is constant temperature is directly proportional to its directly proportional to its volume.volume.

PV= kPV= k




A gas that is at a constant A gas that is at a constant temperature has a volume of temperature has a volume of 5.0 L at a pressure of 2 atm. 5.0 L at a pressure of 2 atm. What is the volume of the same What is the volume of the same gas if the pressure is increased gas if the pressure is increased to 3 atm.?to 3 atm.?




A gas that is at a constant A gas that is at a constant temperature has a volume of temperature has a volume of 9.0 L at a pressure of 2 atm. 9.0 L at a pressure of 2 atm. What is the pressure of the What is the pressure of the same gas if the volume is same gas if the volume is decreased to 3.0 L?decreased to 3.0 L?


ExplanationExplanation

Conceptual Conceptual UnderstandingUnderstandingBoyle’s LawBoyle’s Law

5.0 L X 2 atm = 3.3 L 3 atm

P 1V1 = P2 V2

V2 = P1 V1

P2

= 5.0 L X 2 atm = 3.3 L 3 atm


ExplanationExplanation

Conceptual Conceptual UnderstandingUnderstandingBoyle’s Law #2Boyle’s Law #2

2 atm X 9.0 L = 6 atm 3.0 L

P 1V1 = P2 V2

P2 = P1 V1

V2

= 2 atm X 9.0 L = 6 atm 3.0 L


ElaborationElaboration

Derivation of Derivation of Graham’s Law of Graham’s Law of DiffusionDiffusion

Materials:

Glass Tubes 50-80 cm in length6 M HCl6 M NH4OHMeter StickCotton Balls


EvaluationEvaluation

What is the What is the Concentration?Concentration?Using the expression for kinetic energy,Using the expression for kinetic energy,

KE = ½ m vKE = ½ m v22

Derive Graham’s Law of Diffusion.Derive Graham’s Law of Diffusion.


A Dozen or More A Dozen or More CalculationsCalculations

Additional ConceptsAdditional ConceptsCharles’ Law, Dalton’s Law, Ideal Gas Law, Charles’ Law, Dalton’s Law, Ideal Gas Law,

Gas StoichiometryGas Stoichiometry