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Page 1: MATH1014 Calculus II Tutorial 2

MATH1014 Calculus II

Tutorial 2 (1) Method of Slicing

(a) Cross-sectional Area A(x) perpendicular to the x-axis, The Volume 𝑽 = ∫ 𝑨(𝒙)𝒅𝒙𝒃

𝒂

(b) Cross-sectional Area A(y) perpendicular to the y-axis, The Volume 𝑽 = ∫ 𝑨(π’š)π’…π’šπ’…

𝒄

(2) Disk / Washer Method

(a) Revolved about the x-axis,

The Volume = ∫ π…π’šπŸπ’…π’™π’ƒ

𝒂= ∫ 𝝅(𝒇(𝒙))πŸπ’…π’™

𝒃

𝒂 .

(b) Revolved about the y-axis,

The Volume = ∫ π…π’™πŸπ’…π’šπ’…

𝒄= ∫ 𝝅(π’ˆ(π’š))πŸπ’…π’š

𝒅

𝒄 .

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(3) Cylindrical Shell Method

(a) Revolved about the y-axis,

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The Volume = ∫ πŸπ… π’™βŸπ’“π’‚π’…π’Šπ’–π’”

(𝒇(𝒙) βˆ’ π’ˆ(𝒙))⏟ π’‰π’†π’Šπ’ˆπ’‰π’•

𝒅𝒙𝒃

𝒂 .

(b) Revolved about the x-axis,

The Volume = ∫ πŸπ… π’šβŸπ’“π’‚π’…π’Šπ’–π’”

[π’Ž(π’š) βˆ’ 𝒏(π’š)⏟ π’‰π’†π’Šπ’ˆπ’‰π’•

]π’…π’šπ’ƒ

𝒂 .

Example

Solution:

(4) Volume of Revolution about an axis other than the x-axis and y-axis

(a) Revolving about the line π’š = 𝒉 .

Let π’š = 𝒇(𝒙) be a function continuous on [a, b] and let S be the region bounded by

the curve π’š = 𝒇(𝒙) and the line 𝒙 = 𝒂 , 𝒙 = 𝒃 and π’š = 𝒉 . Then the volume of the

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solid generated by revolving the region S one complete revolution about the line

π’š = 𝒉 is given by : 𝑽 = ∫ 𝝅(π’š βˆ’ 𝒉)πŸπ’…π’™ = ∫ 𝝅(𝒇(𝒙) βˆ’ 𝒉)πŸπ’…π’™π’ƒ

𝒂

𝒃

𝒂 .

(b) Revolving about the line 𝒙 = π’Œ .

Let 𝒙 = 𝝋(π’š) be a function continuous on [c, d] and let S be the region bounded by

the curve 𝒙 = 𝝋(π’š) and the line π’š = 𝒄 , π’š = 𝒅 and 𝒙 = π’Œ . Then the volume of the

solid generated by revolving the region S one complete revolution about the line

𝒙 = π’Œ is given by : 𝑽 = ∫ 𝝅(𝒙 βˆ’ π’Œ)πŸπ’…π’š = ∫ 𝝅(𝝋(π’š) βˆ’ π’Œ)πŸπ’…π’šπ’ƒ

𝒂

𝒅

𝒄 .

Exercises

Washers vs. shells method

1) Let R be the region bounded by the following curves. Let S be the solid generated

when R is revolved about the given axis. If possible, find the volume of S by both the

disk / washer and shell methods. Check that your results agree and state which

method is easiest to apply. For question 1(a) and 1(b)

(a) 2)2( 3 xy , 250 yandx ; revolved about the y -axis.

(1(a) Ans. = 500Ο€)

(b) 4xxy ,π’š = 𝟎 ; revolved about the y -axis.

(1(b) Ans. =Ο€/3)

2) (METHOD OF SLICING) The solid

with a circular base of radius 5 whose cross

sections perpendicular to the base and

parallel to the x -axis are equilateral

triangles. (2. Ans=πŸ“πŸŽπŸŽβˆšπŸ‘

πŸ‘)

3) The solid whose base is the region bounded

by2xy , and the line 1y and whose

cross sections perpendicular to the base and parallel to the x -axis are squares.

(ANS.=2)

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4) (Stewart p.438)

A wedge is cut out of a circular cylinder of radius 4

by two planes. One plane is perpendicular to the

axis of the cylinder. The other intersects the first at

an angle of πŸ‘πŸŽπŸŽ along a diameter of the cylinder.

Find the volume of the wedge.

5) (Stewart Ex.6.2#55)

The base 𝑺 of is an elliptical region with boundary curve

πŸ—π’™πŸ + πŸ’π’šπŸ = πŸ‘πŸ”. Cross-sections perpendicular to the x–axis are isosceles right

triangles with hypotenuse in the base.

6) (Stewart Ex.6.2#49) Find the volume of a cap of sphere with

radius 𝒓 and height 𝒉.

7) (Stewart Ex.6.2#12)

Find the volume of the solid obtained by rotating the region

bounded by the curves π’š = π’†βˆ’π’™ , π’š = 𝟏 , 𝒙 = 𝟐 ; about the

line π’š = 𝟐 . Sketch the region, the solid, and a typical disk or washer.

8) (Stewart Ex.6.2#33(b))

Set up an integral for the volume of the solid obtained by rotating the region bounded

by the curves π’™πŸ + πŸ’π’šπŸ = πŸ’ about the line 𝒙 = 𝟐 . Then use your calculator to

evaluate the integral correct to five decimal places.

9) (Stewart Ex.6.3#12)

Use the method of cylindrical shells to find the volume of the solid obtained by

rotating the region bounded by the curves

𝒙 = πŸ’π’šπŸ βˆ’ π’šπŸ‘ , 𝒙 = 𝟎 ; about the x-axis.

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10) (Stewart Ex.6.3#17)

Use the method of cylindrical shells to find the volume generated by rotating the

region bounded by the curves π’š = πŸ’π’™ βˆ’ π’™πŸ , π’š = πŸ‘ ; about the axis 𝒙 = 𝟏 .

11) (Stewart Ex.6.3#19)

Use the method of cylindrical shells to find the volume generated by rotating the

region bounded by the curves π’š = π’™πŸ‘ , π’š = 𝟎 , 𝒙 = 𝟏 ; about the axis π’š = 𝟏 .

12) (Stewart Ex.6.3#24)

(a) Set up an integral for the volume of the solid obtained by rotating the region

bounded by the curves 𝒙 = π’š , π’š =πŸπ’™

𝟏+π’™πŸ‘ ; about the axis 𝒙 = βˆ’πŸ .

(b) Use your calculator to evaluate the integral correct to five decimal places.

13) (Stewart Ex.6.3#26)

(a) Set up an integral for the volume of the solid obtained by rotating the region

bounded by the curves π’™πŸ βˆ’ π’šπŸ = πŸ• , 𝒙 = πŸ’ ; about the axis π’š = πŸ“ .

(b) Use your calculator to evaluate the integral correct to five decimal places.

14) (Stewart Ex.6.3#39)

The region bounded by the curves π’šπŸβˆ’π’™πŸ = 𝟏 , π’š = 𝟐 is rotated about the x-axis.

Find the volume of the resulting solid by any method.

Graph

15) (Stewart Ex.6.2#45)

(a) If the region shown in the figure is rotated

about the x-axis to form a solid, use the

Midpoint Rule with 𝒏 = πŸ’ to estimate the

volume of the solid.

(b) Estimate the volume if the region is rotated about the y-axis. Again use the

Midpoint Rule with 𝒏 = πŸ’ .

16) (Stewart Ex.6.3#28)

If the region shown in the figure is rotated about

the y-axis to form a solid, use the Midpoint Rule

with 𝒏 = πŸ“ to estimate the volume of the solid.