Combustion and burners
Rudolf Žitný, Ústav procesní a zpracovatelské techniky ČVUT FS 2010
HEAT PROCESSESHP10
Combustion and burners (pulverized coal, biofuels, oil and gas burners, NOx reduction, CFD analysis of gas burner). Properties of fuels, reaction enthalpy, combustion heat. Enthalpy balances, adiabatic flame temperature. Heat transfer by radiation, emissivity and absorptivity of flue gases. Hottel’s diagram.
Combustors, burners, boilers,
can be classified according to size of fuel particles
Large lumps (Stoker fired furnaces, bio-fuels, wastes)
Medium particles (fluidised beds)
Fine particles (conveying burners)
Liquid fuels (atomizers)
Gas burners
Combustion and burnersHP10
Tomasso
Bio-fuels, wastes
Moving horizontal grate with screw feeder for wood chips combustion with maximum power 240 kW. Two pass heat exchanger for heating water.
Optimisation of primary and secondary air streams, with the aim to minimise NOx emissions.
HP10 Stoker fired furnaces
Energy, Volume 30, Issue 8, June 2005, Pages 1429-1438
See also workshop Biomass combustion modelling, Sevilla, 2000 (interesting presentations TNO Netherlands,…, TU Graz - next slide)
T [0C]
HP10 Stoker fired furnaces
CFD analysis of stoker fired furnace (temperature and composition of flue gases)
Optimisation of Low-NOx Biomass Grate Furnaces with CFD Modelling
CO [ppm]
Research groupTHERMAL BIOMASS UTILISATIONTechnical University Graz
HP10 Stoker fired furnaces
Retrofit travelling grate stoker boiler ALSTOM Power Inc.
Arrangement of the Stoker (left) and computational mesh Fluent (right)
Biomass Boiler Retrofit to Increase Capacity by 25% and Decrease Ash Carryover by 60%
Iso-surfaces of turbulence levels for the original and retrofit firing conditions
Wood particle tracks colored by residence time for the retrofit case
Concept of „cigar burner“ was devoped in Denmark for combustion of straw bales.
Bales are fed into the furnace with a hydraulic piston, and only the forehead (top) of the bale combusts in the furnace. Bales are being dried while entering the furnace, and after that devolatilisation occurs, while char combustion is done on a movable water-cooled grate. Furnace temperature should not exceed 900C, and water-cooled furnace walls or flue gas re-circulation are necessary.
HP10 Cigar burner - boiler
R. Mladenovic et al. : The boiler concept for combustion of large soya straw bales. Energy 34 (2009) 715–723
Fluidized beds suspend solid fuels on upward-blowing jets of air during the combustion process. The result is a turbulent mixing of gas and solids. The tumbling action, much like a bubbling fluid, provides more effective chemical reactions and heat transfer. FBC plants are more flexible than conventional plants in that they can be fired on coal and biomass, among other fuels. Combustion systems for solid fuels FBC reduces the amount of sulfur emitted in the form of SOx emissions. Limestone is used to precipitate out sulfate during combustion, which also allows more efficient heat transfer from the boiler to the apparatus used to capture the heat energy (usually water tubes). The heated precipitate coming in direct contact with the tubes(heating by conduction) increases the efficiency. Since this allows coal plants to burn at cooler temperatures, less NOx is also emitted. However, burning at low temperatures also causes increased polycyclic aromatic hydrocarbon emissions. FBC boilers can burn fuels other than coal, and the lower temperatures of combustion (800 °C / 1500 °F ) have other added benefits as well.
HP10 Fluidised bed combustion
HP10 Fluidised bed combustionFluidised bed types
HP10 Fluidised bed boilerExample: Babcock&Wilcox bubbled fluidised bed boiler
HP10 Rotational furnaceRotational furnace with gas burner
HP10 Pulverised fuelUpright tubular boilers CFD simulation of a 180 MW coal fired boiler
Video Youtube (Fluent)
Bark combustion
Pulverised coal boiler
HP10 Pulverised fuelExample: Babcock&Wilcox spiral wound universal pressure (SWUP™) boiler
HP10 Burner - Pulverised fuel
Control of secondary air swirling
Control of secondary air
Primary air
HP10 Liquid fuels burners
Vortex chamber nozzle Steam atomizer
air Oil Oil
Oil Oil
Steam
Ultrasound atomizer Rotating cup
A nice video: Boilers and Their Operation 1956 US Navy Instructional Film
HP10 Gaseous fuels burners
air gas
• Fuel composition and Heating value
• Statics of combustion
• Mass and enthalpy balancing
• Heat transfer - radiation
HP10 COMBUSTION - fundamentals
Benson
HP10 Fuels calorific value
1. qv high heating value HHV MJkg-1, heat released by by combustion of 1 kg
fuel, when all products are cooled down to initial temperature and water in flue gas condenses (latent heat of evaporation is utilised).
2. qn low heating value LHV MJkg-1, less by the enthalpy of evaporation
Element composition (C-carbon, atomic mass AC=12,01), (O-oxygen, AO=16), (H-
hydrogen, AH=1,008), (N-nitrogen, AN=14,01), (S-sulphur, AS=32,06) and free water
explicitly (W-water, MW=18,015 kgkmol-1, moisture is determined by drying of sample
at 1050C) and ash (A-ash, minerals).
Composition is expressed in mass fractions C (kg carbon in kg of fuel), O, … and
these values enable to estimate LHV assuming prevailing chemical reactions
OSNHCvq 84,909,1928,632,12403,34
WHvn qq 951,2
Enthalpy of evaporation OkgHkgH
OHOH
2
222
364
22
Jigisha Parikh, S.A. Channiwala, G.K. Ghosal:
A correlation for calculating HHV from proximate analysis of solid fuels. Fuel, Volume 84, Issue 5, March 2005, Pages 487-494.
HP10 Fuels air consumption-flue gas production
222,3
12 4 32 32C S OH
OV
2
"
"1 ,
0,21O
Air
VpV
p p
222,3
12 32 28 2 18C S N WH
fg air OV V V
Consumption of oxygen necessary for combustion of 1 kg of fuel with known elemental composition (expressed as volume Nm3/kg)
Volume of 1 kmol of gas at normal conditions (0,1013
MPa and 00C) in m3
12kg C requires 1 kmol of O2 (C+O2CO2)
4kg of H requires 1kmol of O2 (2H2+O22H2O)
Consumption of pure oxygen can be easily recalculated to consumption of humid air ( is relative mumidity, p” pressure of saturated steam)
<1 lean fuel combustion =1 stoichiometric combustion >1 rich fuel combustion
In the same way production of flue gases can be expressed
Example: Combustion chamber f-fuel, o-oxidiser, fg-flue gas streams
{inlet flowrate} = {outlet flowrate}
f Air fgm m m
2 2 2
2 2 2{inlet flowrate of O } = {outlet flowrate of O } + {rate of production of O inside the black box}
O ,Air O , fg Om = m m
,Air ,fg2 2 2O Air O fg Om m m
Mass balance of mixture
Mass balances of individual components (chemical compounds)
Mass flowrate [kg/s]. Streams are composed of O2,N2,CO2,CO,CH4,H2O
4 2
4 4 2
, ,( )C C Cf fg CH e CO e
CH CH CO
M M Mm m
M M M
Mass balances of elements (C,H,O,N - four equations)
HP10 Mass balancing
fuelfm
airmCombustion chamber
flue gasfgm
HP10 Enthalpy balancing, temperatures
Enthalpy balance of a combustion chamber
f f f air air air fg fg fg
f f air air air fg fg fgf
m h T m h T m h T Q
Qh T m h T m h T
m
Boiler RUN video
, fuelf fm T
,air airm T
Combustion chamber
, flue gasfg fgm T
releasedheat Q
Relative consumption of air Relative production
of flue gases
It would be heating value of fuel if the temperatures
Tf,Tair,Tfg will be the same
ffgfg
fg
mmm
m
/mass flowrate of flue gas [kg/s]
relative flowrate of flue gas [dimensionless]
HP10 Enthalpy balancing, temperatures
So that it could be possible to express enthalpies by temperatures it is necessary to modify the previous equation formally as
0 0 0 .
fg
f f air air air fg fg fg nf
Q Tc T T m c T T m c T T q
m
0 0 0
0 0 0
f f f air air air air fg fg fg fg
fg
f air air fg fgf
h T h T m h T h T m h T h T
Q Th T m h T m h T
m
This term is heating value qn for Tf=Tair=Tfg=T0
qn is the low heating value as soon as the reference temperature T0 is above
the temperature of condensation of water in flue gases
Pierre-Alexandre Glaude, René Fournet, Roda Bounaceur, Michel Molière: Adiabatic flame temperature from biofuels and fossil fuels and derived effect on NOx emissions. Fuel Processing Technology, Volume 91, Issue 2, February 2010, Pages 229-235.
Kubota, N. (2007) Thermochemistry of Combustion, in Propellants and Explosives: Thermochemical Aspects of Combustion, Second Edition, Wiley-VCH Verlag GmbH & Co. KGaA, Weinheim, Germany. doi: 10.1002/9783527610105.ch2
HP10 Enthalpy balancing, temperatures
0 0
,max 0 ,n f f air air air air
fgfg fg fg
q c T T V c T TT T
V c
Adiabatic flame temperature is the temperature of flue gases for the case that the combustor chamber is thermally insulated (Q=0). This maximal temperature follows directly from the previous enthalpy balance
0 1 ,fg fgc T c c T
2
0 0,max 0 0 0 0
1 1 1
1 4
2fg n f f air air air airfg
c cT T T q c T T V c T T
c c c V
mair=Vairair
Specific heat capacities of fuel and air (cf,cair) can calculated easily, but the specific heat capacity cfg depends upon temperature and upon unknown composition of flue gases. Fortunately the product of density and specific heat capacity depends upon composition only weakly and can be approximated by linear function of temperature c0=1300 [J.m-3.K-1] c1=0,175 [J.m-3.K-1]
Substituting this linear relationship results to a quadratic equation for adiabatic flame temperature with the following solution
HP10 Enthalpy balancing, temperatures
Actual flame temperature and actual temperature of flue gases cannot be calculated so easily. It is necessary to express the power Q in terms of mean temperature of flame TS and the temperature of wall Tw .
.44wgSg TATSQ
TS
Tw
Q Tfg
Heat transfer by radiation dominates at high temperatures. In this case the heat flux is proportional to 4th power of thermodynamic temperature and
Heat flow emitted by hot gas and absorbed
by wall
Heat flow emitted by wall and absorbed by
molecules of gas
Irradiated heat transfer surface
-emisivity A-absorptivity
4Tq Stefan Boltzman
HP10 Enthalpy balancing, temperatures
TS
Tw
Tfg
Photon absorbed by molecule of water Photon is not
absorbed by oxygen
Photon absorbed by opposite wall – no contribution to Q
Most photons emitted by gas are absorbed by wall
Photon absorbed by CO-no net
contribution to Q
Photons emmited at high temperature TS (short wavelength)
Photons emmited at low temperature Tw (long wavelength)
Wall of combustor chamber is almost “black body”, therefore all photons impacting to wall are absorbed and not bounced off. On the other hand the photon emitted by wall has only limited probability to be absorbed by a heteropolar molecule (H2O, CO2, homeopolar molecules like O2,N2 are almost transparent for photons). The probability of absorption is proportional to density of heteropolar molecules (to their partial pressure) and to the length of ray L. Probability of catching depends also upon the photon energy (wavelength), the greater is energy the lower is probability of absorption.
HP10 Enthalpy balancing, temperatures
.44wgSg TATSQ
Emissivity of gas corresponding to
temperature of gas Ts
Absorptivity of gas corresponding to wall
temperature Tw
According to Kirchhoff’s law Emissivity=Absorptivity (g = Ag ) but this equivalence holds only at the same wavelength (monochromatic radiation). Emissivity and absorptivity of photons depends upon their wavelength (frequency, energy). The first term (g) should be evaluated for high energy photons emitted by hot gas, while the second term (Ag) for photons emitted by colder wall.
Let us return back to the expression for resulting power exchanged between the hot gas and the wall of combustion chamber
HP10 Enthalpy balancing, temperatures
Hottel’s diagram for emissivity of CO2 and H2O as a function of temperature and pL (partial
pressure pCO2 is calculated from composition of flue gas, and length of ray L=3.5V/S – empirical approximation)
,14
222 108,311608
10Tp
Lpp
gOH
COOH
eT
Instead diagrams this approximation
can be used
HP10 Enthalpy balancing, temperatures
4 4,max
g gfg fg fg fg S w
f g
S Am c T T T T
m
Subtractinq equations (enthalpy balance for real and insulated combustors)
0 0 0
fg
f f air air air fg fg fg nf
Q Tc T T m c T T m c T T q
m
0 0 ,max 0
0f f air air air fg fg fg n
f
c T T m c T T m c T T qm
we arrive to the equation for two unknown temperatures Tfg and TS
The flame temperature TS must be somewhere between Tfg and Tfg,max and can be approximated by geometric average of these two temperatures, giving
2 2 4,max ,max
g gfg fg fg fg fg fg w
f g
S Am c T T T T T
m
Quadratic equation for flue gas temperature
HP10 Enthalpy balancing, temperatures
4,max
4,max
3,max
41 1 1
2
,
fg g wfg
g fg
fg fg
g fg
T Bo A TT
Bo T Bo
m cBo
S T
The solution of quadratic equation for flue gas temperature can be expressed in terms of Boltzmann criterion (ratio of overall transferred heat to the heat transferred only by radiation)
Remark: this formula is only a rough approximation. Its application will be demonstrated on the following example.
HP10 Example: steam reforming (1/2)Furnace for steam reforming (reaction proceeds inside a set of vertical tubes) makes use a row of gas burners, consuming natural gas as fuel.
, / ,MCHQ
qnkg s
40 0222
For given mass flowrate of fuel
It is possible to evaluate consumption of air and production of flue gases
4
2
3
3
3
22,3 22,3 0,75 0,251,05 13,94 / ,
0,21 12 4 0,21 12 4
0,31 / ,
22,3 22,3 22,312 2 12 2 12 4
22,3 15,34 / .4
C Hair
air CH air
C C CH H Hfg air O air
Hvz
V m kg
V M V m s
V V V V
V m kg
For temperature of methane and preheated air TCH4=291 K, Tair=573 K, and for heating value of methane qn=49,9 MJkg-1 it is possible to evaluate temperature of adiabatic flame
2
0 0,max 0 0 0 0
1 1 1
2
6
1 4
2
1 1300 1300 4273 273 49,9 10 2190 18 13,94 1,276 1006 300 375
2 0,175 0,175 0,175 15,333
fg n f f air air air airfg
c cT T T q c T T V c T T
c c c V
K
2
air
Natural gasReaction mixture
Flue gas
HP10 Example: steam reforming (2/2)The relative emisivity g(TS) is calculated for estimated flame temperature TS2000 K
The relative absorptivity Ag=g(Tw) is calculated for estimated temperature of wall Tw1200 K.
Mean path of ray L is estimated from geometry of combustion chamber (rectangular channel of height 10.8 m a width 2.5 m) as L=3,5 V/S=3,5(10,8.2,5)/(2.10,8)=4,4 m
Partial pressures are determined by composition of flue gas composed of H2O, CO2,a N2. This calculation follows from previously evaluated relative volume of air VO2=2,9 (m3 oxygen/kg methane) and stoichiometry of reaction
VH2O= VO2=2,9
VCO2=0,5 VO2=1,45
VN2= Vvz-VO2=11
Corresponding ratio of partial pressures is
2,9:1,45:11
and because sum of pressures is atmospheric pressure p=pH2O+pCO2+pN2 the partial pressures of heteropolar gases are
pH2O=0,0192 MPa, pCO2=0,0096 MPa.
Using these values in Hottel’s diagrams (or using mentioned correlation for relative emissivity follows
g(TS)=0,258 and Ag=g(Tw)=0,49, and final result (flue gas temperature)
check Vfg= VH2O+ VCO2+VN2
3 3 8 3
,max ,max
4 4,max
4,max
15,34 0,0222 1300 0,174 20000,133
2 10,8 5,67 10 0,258 2375
4 2375 0,133 4 0,49 12001 1 1 1 1
2 2 0,133 0,25
fg fg fg fg fg
g fg g fg
fg g wfg
g fg
M c V cBo
S T S T
T Bo A TT
Bo T Bo
41
8 2375 0,133
1056 .K
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