Download - Chapter 10

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Page 1: Chapter 10

Chapter 10

Energy, Work, & Simple Machines

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Energy•The ability to produce change

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Energy•The ability to do work

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Types of Energy

•Kinetic

•Potential

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Kinetic Energy (K)

•The energy of motion

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Potential Energy (U)

•Stored energy

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Kinetic Energy

•vf2 = vi

2 + 2ad

•vf2 - vi

2 = 2ad

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Kinetic Energy•a = F/m

•vf2- vi

2 = 2Fd/m

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Kinetic Energy

½ mvf2- ½ mvi

2

= Fd

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Kinetic Energy

K = ½ mv2

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Potential Energy

U = mgh

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Work (W)•The process of

changing the energy of a system

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Work•The product of

force times displacement

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Work

•W = Fd

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Work-EnergyTheorem

•W = K

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Calculate the work required to lift a 50.0 kg box to a height of 2.0 m:

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Calculate the work done when a 250 N force is applied to move a cart 40.0

km:

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Calculate the work required to push a

500.0 kg box 250 m at a constant velocity. = 0.20 between the

box & the floor.

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Constant force at an Angle

Direction of applied forceDirection of movement

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Constant force at an Angle

W = F(cos )d

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Calculate the work done when mowing the lawn when a boy applied a 50.0 N force at a 37o

from horizontal for 2.0 km.

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Calculate the work done when a girl pulls a 4.0 kg box with a rope at a 37o from horizontal for

2.0 m. = 2.5

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Power•The rate of doing work

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Power•P = W/t

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A 25 Mg elevator rises 125 m in 5.0

minutes. Calculate: F, W, & P

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A 10.0 Gg crate is accelerated by a cable

up a 37o incline for 50.0 m in 2.5 hrs. = 0.20Calculate: FT, W, & P

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A 50.0 g box is accelerated up a 53o

incline for 50.0 m at 250 cm/s2. = 0.20

Calculate: FA, vf,W, P, K, & U at the top of the ramp

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Machines• Devices used to ease force

one has to apply to move an object by changing the magnitude and direction of the force.

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Machines• Machines do not reduce the

work required, but do reduce the force required.

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Machines•The force applied is called the effort force (Fe).

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Machines•The force exerted by the machine is called the resistant force (Fr).

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Mechanical Advantage

•The ratio of resistant force to effort force

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Mechanical Advantage

Fr

Fe

MA =

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In an Ideal Situation•100 % of the work input into a system would be transferred to output work, thus:

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Wo = Wi or

Frdr = Fede or

Fr/Fe= de/dr

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Ideal Mechanical Advantage

de

dr

IMA =

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Efficiency•The ratio of output work to input work times 100 %

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Efficiency =

Wo

Wi

X 100 %

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Efficiency =

MAIMA

X 100 %

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Simple MachinesLever Inclined plane

Wedge Wheel & Axle

Screw Pulley

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Lever

Fe

Fr

dedr

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Fe

Fr

dedr

IMA = de/dr = length de/length dr

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Inclined Plane

Fe

Fr

dr

de

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Fe

Fr

dr

de

IMA = de/dr = length hyp/hyp sin

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Wedge

Fe

½ Fr

½ Fr

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Fe

½ Fr

½ Fr

IMA = de/dr = cot ½

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Screw

Fr

Fe

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Pulley

Fe

Fr

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Fe

Fr

IMA = the number of lines pulling up

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Wheel & Axle

FeFr

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FeFr

IMA = ratioof effort wheelradius/resistantwheel radius

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A 100.0 Mg trolley is pulled at 750 cm/s up a 53o

inclined railway for 5.0 km. = 0.20

Calculate: FA,W, P, K, & U at the top of the ramp

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An alien exerts 250 N on one end of a 18 m

lever with the fulcrum 3 m from a 1200 N load.

Calculate: IMA, MA, & efficiency

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A 350 N force is applied to push a 50.0

kg box up a 20.0 m ramp at 37o from

horizontal. Calculate: IMA, MA, & efficiency

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A pulley with an efficiency of 80.0 %

with 5 interconnecting ropes lifts a 100.0 kg

load. Calculate:IMA, MA, & FA

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A 1.0 m handle is connected to 5.0 cm wheel. The

efficiency of this system is 90.0 %. Calculate IMA, MA, & the force required to pull a

500 kg object connected to the wheel.

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A 100.0 cm handle is connected to 5.0 cm wheel with teeth

connecting it to another 50.0 cm wheel connected to a 2.5 cm axle. A cable is connected to the axle. The efficiency of this system is 90.0 %. Calculate IMA & MA

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A sledge hammer is used to apply 25 kN drive a 2.0 cm x 10.0 cm wedge into

a board. Calculate the force on the board if the

efficiency is 75 %.

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Design a system of simple machines that

can lift at least 100,000 times the force applied by a human. Assume 90

% efficiency.

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The front sprockets on a 21 speed bike are 24 cm, 18 cm,

& 15 cm in diameter. The back sprockets range from 12 cm to 4.0 cm. Determine the

ratio of highest to lowest gears.

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On the same bike, the wheels are 80.0 cm in diameter.

Calculate the speed in the lowest & highest gears if a

person can pedal at 1.0 revolution per second.

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A 100.0 kg block ( = .20) slides from rest down a 50.0 m ramp at 37o from horizontal. At the bottom

of the ramp, it collides with a 25 kg box ( = .25) &

stops. Calculate:

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Answer the questions on page 175 & work

Problem Section A on pages 175 & 176.

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r = 5.0 cm

10.0 m

2.0 m

1.0 Mg

The 1.0 m crank is turned lifting the box to a height of 50.0 cm in 5.0 minutes with an efficiency of 90 %. Calculate: IMA, MA, di, FA, Wo, Wi, & P.

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A 50.0 Mg elevator is raised 200.0 m in

3.0 minutes at a constant speed.

Calculate: FAupward, W, & P

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A 200.0 kg sled ( = 0.10) slides from rest

down a 500.0 m incline at 37o from horizontal.

Calculate: F,F//, Ff, Fnet, a, t, vf, Wo, P, & Kmax