ANTHE-2020 (Engineering) (For Class XII Studying moving to XII Passed) - (Sample Paper)_Answers
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ANSWERS
Physics Chemistry Mathematics
1. Answer (2)
2. Answer (1)
3. Answer (3)
4. Answer (2)
5. Answer (2)
6. Answer (1, 2, 4)
7. Answer (2, 3)
8. Answer (1)
9. Answer (4)
10. Answer (1)
11. A R
B S
C P
D Q
12. Answer (3)
13. Answer (1)
14. Answer (4)
15. Answer (2)
16. Answer (3)
17. Answer (1, 3, 4)
18. Answer (2, 4)
19. Answer (2)
20. Answer (3)
21. Answer (2)
22. A R
B P
C P, R, S
D Q
23. Answer (2)
24. Answer (2)
25. Answer (3)
26. Answer (1)
27. Answer (4)
28. Answer (2)
29. Answer (1, 3, 4)
30. Answer (2, 3)
31. Answer (1, 4)
32. Answer (3)
33. Answer (3)
34. Answer (1)
35. A R
B Q
C P
D S
(For Class XII Studying moving to XII Passed) - (Sample Paper)_Solutions ANTHE-2020 (Engineering)
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ANSWERS & SOLUTIONS
PHYSICS
1. Answer (2)
0 2sin60º4
IB
d
0total
3 3
4
IB
d
2
tan30ºd
a
0 0total
3 3 93
3 2
I IB
a a
2. Answer (1)
Maximum potential is at x = 6
v – 5 = 30
v = 35
3. Answer (3)
0 1t
i iT
220
0
1
Tt
H i R dtT
3
20
0
1
3
T
t
Ti RT
20
3
i RT
d
3
ANTHE-2020 (Engineering) (For Class XII Studying moving to XII Passed) - (Sample Paper)_Solutions
4. Answer (2)
At steady state current through capacitor is zero.
0 23
C
VV R
R
5. Answer (2)
tan45ºcos
v
H
B
B
tan cos
1tan (cos )
6. Answer (1, 2, 4)
01
2
VI
R
02
2
3
VI
R
1
2
3
4
I
I
7. Answer (2, 3)
Theoretical
8. Answer (1)
9. Answer (4)
Solution of Q. Nos. 8 and 9
0
4
VI
R
2
0 002
4 2
V VP V
R R
00 0
32 0
4
C
VV V V
0
4C
VV
10. Answer (1)
Sensitivity length of wire.
11. Answer A(R); B(S); C(P); D(Q)
| x |
tan L Cx
R
In LR circuit, current lags voltage.
In RC circuit, current leads voltage.
(For Class XII Studying moving to XII Passed) - (Sample Paper)_Solutions ANTHE-2020 (Engineering)
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CHEMISTRY
12. Answer (3)
50%
ln2T
k
93.75% 50%
1 100 4ln2t ln 4t
k 6.25 k
13. Answer (1)
2 2Pt | H (10 atm) | HCl(pH 4.7) || HCl(pH 1.3) | H (1 atm) | Pt
The overall reaction is
2 a c a 2 c(H ) 2(H ) 2(H ) (H )
2a 2 c
cell 2c 2 a
[H ] (pH )0.059E 0 log
2 [H ] (pH )
a c
0.0590.059[(pH) (pH) ] log10
2
= 0.2006 + 0.0295 = 0.2301 V
14. Answer (4)
According to Bent’s rule, the halogen atom being more electronegative, will extract higher p-character of sp3
hybridised P-atom in the given species. In P2H4, there is no halogen atom bonded to P-atom. So relatively
P – P bond will have higher p-character and hence higher bond length.
15. Answer (2)
Cl2O6 in the solid state exists as 2 4ClO ClO
. Oxidation states of Cl in the cationic and anionic parts are +5
and +7 respectively.
16. Answer (3)
2 4 2 4
(A)
Na SO BaCl 2NaCl BaSO
4(B)
BaSO 4C BaS 4CO
2 2
(C)
BaS 2HCl BaCl H S
17. Answer (1, 3, 4)
The lobes of xyd , 2 2x yd
and 2z
d will favour the pentagonal bipyramidal geometry.
18. Answer (2, 4)
Protective colloids must be lyophilic in nature.
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ANTHE-2020 (Engineering) (For Class XII Studying moving to XII Passed) - (Sample Paper)_Solutions
19. Answer (2)
20. Answer (3)
Solution of Q. Nos. 19 and 20
2 2Cu(s) Cl CuCl (s)
In CuCl2 (s), each Cu2+
ion is surrounded by 4 Cl– ions in its layer and 2 Cl
– ions of the adjoining layers.
22 4
Yellow
CuCl 2HCl 2H [CuCl ]
2 24 2 2 4
Yellow Blue
[CuCl ] 4H O [Cu(H O) ] 4Cl
21. Answer (2)
According to Henry’s law, the solubility of a gas in a solvent (expressed as mole fraction Xg of the gas in
solution) is directly proportional to partial pressure of gas in contact with solution
g H gP K (X )
where KH is Henry’s law constant and Pg is partial pressure of gas. As temperature increases Xg decreases.
So KH increases because Pg is kept constant.
22. Answer A(R); B(P); C(P, R, S); D(Q)
RbBr has rock salt structure. Rb+ and Br
– have co-ordination number 6 each. BeO has zinc blende type
structure. Be2+
and O2–
have co-ordination number 4 each. Mn3O4 has a spinel structure. Cs+ and Cl
– have
co-ordination number 8 each.
MATHEMATICS
23. Answer (2)
2( ) 1 3 0f x x
and ( ( )) (1 5 ) f f x f x
31 1 5 x x x
3 4 0 x x
( 2)( 2) 0 x x x
( , 2) (0, 2) x
24. Answer (2)
2
0
2 [sin cos ] 2( )
I x x dx
0 2–2
+ +––
(For Class XII Studying moving to XII Passed) - (Sample Paper)_Solutions ANTHE-2020 (Engineering)
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25. Answer (3)
( ) 2(1 sin4 )f x x
2(1 0) 24
f
26. Answer (1)
1 1 1 1( ) ( ) I P Q P Q P Q P P Q P
1 1 1( ) ( ( ) )Q Q P P P I P Q P
1 1( ) Q Q P Q P I
27. Answer (4)
1/
2 4
0
lim cot 4
x
x
x e k e
28. Answer (2)
cos3
x
29. Answer (1, 3, 4)
/22
2
0
sin
m
mI x dx
2 1 2 3 1.......
2 2 2 2 2
m m
m m
and 2 1
2 2 2 2.......2 1 2 1 3
m
m mI
m m
and 2 1
2 2 2.......2 1 3
m
mI
m
30. Answer (2, 3)
( ) 0f x at x = 1
(1) ( 1) 0 f f
( 2, 2) a
31. Answer (1, 4)
2 4 12 2 3 5 30 8 4 5 4 8 0x x x x
2 4 14 15 66 52 16 0x x x x
2 x 35 0x
0, 35x
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ANTHE-2020 (Engineering) (For Class XII Studying moving to XII Passed) - (Sample Paper)_Solutions
32. Answer (3)
33. Answer (3)
Solution of Q. Nos. 32 and 33
2
1 18 ( ) 6 1f x f
x x
1
(1)2
f
and 2 (1) (1) dy
f fdx
6 1
7 2 =
19
14
34. Answer (1)
2
2
(tan )sec
2( )
d xxdx
xd x
dx
35. Answer A(R); B(Q); C(P); D(S)
(A) 2
12
(B) ( ) | ln| ||f x x is continuous and non-differentiable at 1 x
(C) max( ) 4f x
(D) Area =
13
1 2
0
0
42 3 2 3
3 32
xx dx
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