Download - 2.4 Reasoning with Properties from Algebra

Transcript
Page 1: 2.4 Reasoning with Properties from Algebra

2.4 Reasoning with 2.4 Reasoning with Properties from Properties from

AlgebraAlgebraUse properties of AlgebraUse properties of Algebra

Page 2: 2.4 Reasoning with Properties from Algebra

Properties of Algebra

Addition Property

If a = b, then a + c = b + c

If x – 4 = 20, then x – 4 + 4 = 20 + 4

Page 3: 2.4 Reasoning with Properties from Algebra

Properties of Algebra

Multiplication Property

If a = b, then a * c = b * c where c ≠ 0

If ⅛ x = 4, then 8 * ⅛ x = 4 * 8

Page 4: 2.4 Reasoning with Properties from Algebra

Other properties in Algebra

Reflexive Property x = x

Symmetric Property

If a = b, then b = a

Transitive Property

If a = b and b = c, then a = c

Page 5: 2.4 Reasoning with Properties from Algebra

More properties in Algebra

Substitution Property

If x = 4, then 3x + 2 = 3(4) + 2

Distributive Property

2(x + 4) = 2x + 2(4)

Page 6: 2.4 Reasoning with Properties from Algebra

Using the property of Algebra to solve an equation

3x + 12 = 8x – 18 Given

Page 7: 2.4 Reasoning with Properties from Algebra

Using the property of Algebra to solve an equation

3x + 12 = 8x – 18 Given

- 3x = - 3x Reflexive Property

Page 8: 2.4 Reasoning with Properties from Algebra

Using the property of Algebra to solve an equation

3x + 12 = 8x – 18 Given

- 3x = - 3x Reflexive Property

3x – 3x + 12 = 8x – 3x – 18Add. Property

Page 9: 2.4 Reasoning with Properties from Algebra

Using the property of Algebra to solve an equation

3x + 12 = 8x – 18 Given

- 3x = - 3x Reflexive Property

3x – 3x + 12 = 8x – 3x – 18Add. Property

12 = 5x -18 Simplified

Page 10: 2.4 Reasoning with Properties from Algebra

Using the property of Algebra to solve an equation

3x + 12 = 8x – 18 Given

- 3x = - 3x Reflexive Property

3x – 3x + 12 = 8x – 3x – 18Add. Property

12 = 5x -18 Simplified

18 = 18 Reflexive Property

Page 11: 2.4 Reasoning with Properties from Algebra

Using the property of Algebra to solve an equation

3x + 12 = 8x – 18 Given

- 3x = - 3x Reflexive Property

3x – 3x + 12 = 8x – 3x – 18 Add. Property

12 = 5x -18 Simplified

18 = 18 Reflexive Property

12 + 18 = 5x – 18 + 18 Add. Property

Page 12: 2.4 Reasoning with Properties from Algebra

Using the property of Algebra to solve an equation

3x + 12 = 8x – 18 Given - 3x = - 3x Reflexive Property

3x – 3x + 12 = 8x – 3x – 18Add. Property12 = 5x -18 Simplified18 = 18 Reflexive Property

12 + 18 = 5x – 18 + 18 Add. Property30 = 5x Simplified

Page 13: 2.4 Reasoning with Properties from Algebra

Using the property of Algebra to solve an equation

3x + 12 = 8x – 18 Given - 3x = - 3x Reflexive Property

3x – 3x + 12 = 8x – 3x – 18 Add. Property12 = 5x -18 Simplified18 = 18 Reflexive Property

12 + 18 = 5x – 18 + 18 Add. Property30 = 5x Simplified

1/5 = 1/5 Reflexive Property

Page 14: 2.4 Reasoning with Properties from Algebra

Using the property of Algebra to solve an equation

3x + 12 = 8x – 18 Given - 3x = - 3x Reflexive Property

3x – 3x + 12 = 8x – 3x – 18 Add. Property12 = 5x -18 Simplified18 = 18 Reflexive Property

12 + 18 = 5x – 18 + 18 Add. Property30 = 5x Simplified

1/5 = 1/5 Reflexive Property30 * 1/5 = 5x * 1/5 Mult. Property

Page 15: 2.4 Reasoning with Properties from Algebra

Using the property of Algebra to solve an equation

3x + 12 = 8x – 18 Given - 3x = - 3x Reflexive Property

3x – 3x + 12 = 8x – 3x – 18 Add. Property12 = 5x -18 Simplified18 = 18 Reflexive Property

12 + 18 = 5x – 18 + 18 Add. Property30 = 5x Simplified

1/5 = 1/5 Reflexive Property30 * 1/5 = 5x * 1/5 Mult. Property

6 = x Simplified

Page 16: 2.4 Reasoning with Properties from Algebra

Using the property of Algebra to solve an equation

3x + 12 = 8x – 18 Given - 3x = - 3x Reflexive Property

3x – 3x + 12 = 8x – 3x – 18 Add. Property12 = 5x -18 Simplified18 = 18 Reflexive Property

12 + 18 = 5x – 18 + 18 Add. Property30 = 5x Simplified

1/5 = 1/5 Reflexive Property30 * 1/5 = 5x * 1/5 Mult. Property

6 = x Simplifiedx = 6 Symmetric Property

Page 17: 2.4 Reasoning with Properties from Algebra

Since this is Geometry, we will show Geometry facts with Algebra

Given A B C D ;

AC = BD Verify that AB = CD

AC = BD Given

Page 18: 2.4 Reasoning with Properties from Algebra

Since this is Geometry, we will show Geometry facts with Algebra

Given A B C D ;

AC = BD Verify that AB = CD

AC = BD Given

AC = AB + BC

Page 19: 2.4 Reasoning with Properties from Algebra

Since this is Geometry, we will show Geometry facts with Algebra

Given A B C D ;

AC = BD Verify that AB = CD

AC = BD Given

AC = AB + BC Segment Addition

Page 20: 2.4 Reasoning with Properties from Algebra

Since this is Geometry, we will show Geometry facts with Algebra

Given A B C D ;

AC = BD Verify that AB = CD

AC = BD Given

AC = AB + BC Segment Addition

BD = BC + CD Segment Addition

Page 21: 2.4 Reasoning with Properties from Algebra

Since this is Geometry, we will show Geometry facts with Algebra

Given A B C D ;

AC = BD Verify that AB = CD

AC = BD Given

AC = AB + BC Segment Addition

BD = BC + CD Segment Addition

AB + BC = BC + CD

Page 22: 2.4 Reasoning with Properties from Algebra

Since this is Geometry, we will show Geometry facts with Algebra

Given A B C D ;

AC = BD Verify that AB = CD

AC = BD Given

AC = AB + BC Segment Addition

BD = BC + CD Segment Addition

AB + BC = BC + CD Substitution Prop.

Page 23: 2.4 Reasoning with Properties from Algebra

Since this is Geometry, we will show Geometry facts with Algebra

Given A B C D ; AC = BD Verify that AB = CD

AC = BD GivenAC = AB + BC Segment AdditionBD = BC + CD Segment AdditionAB + BC = BC + CD Substitution Prop.BC = BC Reflexive Prop.

Page 24: 2.4 Reasoning with Properties from Algebra

Since this is Geometry, we will show Geometry facts with Algebra

Given A B C D ; AC = BD Verify that AB = CD

AC = BD GivenAC = AB + BC Segment AdditionBD = BC + CD Segment AdditionAB + BC = BC + CD Substitution Prop.BC = BC Reflexive Prop.AB = CD Addition/ Subtraction

Prop.

Page 25: 2.4 Reasoning with Properties from Algebra

Given Find

#1. #1. Given

18043

9321

180321

mm

mm

mmm

4m

18043

180321

mm

mmm

Page 26: 2.4 Reasoning with Properties from Algebra

Given Find

#1. #1. Given

#2. #2. Subst. Prop

18043

9321

180321

mm

mm

mmm

4m

18043

180321

mm

mmm

43321 mmmmm

Page 27: 2.4 Reasoning with Properties from Algebra

Given Find

#1. #1. Given

#2. #2. Subst. Prop

#3. #3. Reflex Prop.

18043

9321

180321

mm

mm

mmm

4m

18043

180321

mm

mmm

43321 mmmmm

33 mm

Page 28: 2.4 Reasoning with Properties from Algebra

Given Find

#1. #1. Given

#2. #2. Subst. Prop

#3. #3. Reflex Prop.

#4. #4. Add./Subt Prop.

18043

9321

180321

mm

mm

mmm

4m

18043

180321

mm

mmm

43321 mmmmm

33 mm

421 mmm

Page 29: 2.4 Reasoning with Properties from Algebra

Given Find

#1. #1. Given

#2. #2. Subst. Prop

#3. #3. Reflex Prop.

#4. #4. Add./Subt. Prop.

#5. #5. Given

18043

9321

180321

mm

mm

mmm

4m

18043

180321

mm

mmm

43321 mmmmm

33 mm

421 mmm

9321 mm

Page 30: 2.4 Reasoning with Properties from Algebra

Given Find

#1. #1. Given

#2. #2. Subst. Prop

#3. #3. Reflex Prop.

#4. #4. Add./Subt. Prop.

#5. #5. Given

#6. #6. Substitution

18043

9321

180321

mm

mm

mmm

4m

18043

180321

mm

mmm

43321 mmmmm

33 mm

421 mmm

9321 mm

493 m

Page 31: 2.4 Reasoning with Properties from Algebra

HomeworkHomework

Page 99 – 101 Page 99 – 101

# 10 - 25, 27, 32# 10 - 25, 27, 32