Z Scores
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Transcript of Z Scores
Z scoresAnd whatnot
This is a NORMAL DISTRIBUTION
Most people are near the hump
So the Mean, Median, and Mode fall in the middle too
Note the symmetry off the curve
Normal Distributions standardize information from different data sets so
the Mid-point is 0
0
Each point is just like standard counting numbers, so to speak
1 2 3-1-2-3
The segments on the left are negative
0 1 2 3-1-2-3
Its essentially a number line
You typically won’t see higher than 4
Next we’ll start getting into numbers
Here are the formulas…
Z = Z =X - μ
σX - μ
S
X = μ + (Z)(σ)
Learn them, Love them
Z =
Z =
X - μ
σ
X - μ
S
X = μ + (Z)(σ)
A problem may be given and from it you can pull out X (some score), Mu (the mean), and Sigma
(standard deviation)
Here are some numbers for example
X = 300 μ = 200 σ = 50
You pretty much just plug in the numbers from there
Remember these numbers, I’ll refer to them a lot
Z =
Z =
X - μ
σ
X - μ
S
X = μ + (Z)(σ)
X = 200 μ = 300 σ = 50
Z =X - μ
σChose a formula that has the matching
components
Z =
Z =
X - μ
σ
X - μ
S
X = μ + (Z)(σ)
X = 300 μ = 200 σ = 50
Z =X - μ
σ
Z =
Z =
X - μ
σ
X - μ
S
X = μ + (Z)(σ)
X = 300 μ = 200 σ = 50
Z =300 - 200
50
Solve
Z =
Z =
X - μ
σ
X - μ
S
X = μ + (Z)(σ)
X = 300 μ = 200 σ = 50
Z =300 - 200
501002
Z =
Z =
X - μ
σ
X - μ
S
X = μ + (Z)(σ)
X = 300 μ = 200 σ = 50 Z = 2
0 1 2 3-1-2-3
Lets bring back that normal distribution now
You put the Z score right on the graph
And that’s it
Z =
Z =
X - μ
σ
X - μ
S
X = μ + (Z)(σ)
You can practice with these numbers
X= 50
μ =30
σ =5
X= 8
μ =6
σ =2
X =80
μ =100
σ =5
X =18
μ =36
σ =6
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(click for answers)
Z =
Z =
X - μ
σ
X - μ
S
X = μ + (Z)(σ)You might be
wondering about this formula
In that case you’d be given Z and solve for X
Z =
Z =
X - μ
σ
X - μ
S
X = μ + (Z)(σ)
Z = 1 μ = 10 σ = 2
You would be given this
X = μ + (Z)(σ)
X = 10 + (1)(2)
X = 10 + 2
Z =
Z =
X - μ
σ
X - μ
S
X = μ + (Z)(σ)
X = 12
Easy enough
A few more things about the normal distribution
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There can be more than one Z score on the graph
It can be negative
And it can have decimals, in that case you just estimate where it sits
Z =
Z =
X - μ
σ
X - μ
S
X = μ + (Z)(σ)
X= 50
μ =30
σ =5
X= 8
μ =6
σ =2
X =80
μ =100
σ =5
X =18
μ =36
σ =6
4 1 -4 -3
Remember these answers from before?
4 1 -4 -3
0 1 2 3-1-2-3
Its uncommon to go beyond 3, but it is possible as is the
case here
-4 4
These numbers were from different data sets but can share the same graph
Ok, so what if you’re asked to find a percent of data under or above a
certain score?
X = 300 μ = 200 σ = 50 Z = 2
0 1 2 3-1-2-3
Lets bring back the data we worked with earlier to save some time
What if you need to know what percent is below the Z-score?
Well, at this point you go into that nifty page at the back of your Stat-psych book and look up under
column (A) the Z score “2”
You can look it up yourself if you want, its on page 529
You go to your z score, in our case its 2, then you take the number from the column of the
area you want to know.
(B) Is body
(c) Is tail
(D) Is proportion between the Mean and Z
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This is the body
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This is a tail
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We want the body
That gives us the number .9772
What does that mean!?!
Nothing when you want the percent
So you just multiply that number (.9772) by 100 and you have your percent of
area.
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.9772 x 100 = 97.72So about 98%
Ok, that’s awesome when you want all the data under or above a
Z-score, but what if you want to see… lets say, 60% of the data
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Hmmmm…
No picture for this yet
Whatever, I’ll skip it
So you bust out that stylish book of yours and go to page 528
We want 60% of the data so we’re going to look at column D, the proportion between the mean and Z-score and you’re going to
want the number closest to .3000
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Ok, now we can use the picture
So, You want to look up the closest number to 30%
or .3000
If you look up the closest to .6000 (60%) in column D it
will be looking for 60% on both sides
And that just doesn’t work
That will put 30% on each side adding up to a total 60%
0 1 2 3-1-2-3
The number happens to be .2995
Z-score of 0.84
So, lets draw that on
That’s what it looks like, but now what if you need the score to be within the
60% of the data?
X = μ + (Z)(σ)
Remember this formula?
Just plug in your numbers and you’ll have your answer
X = μ + (Z)(σ)μ = 200 σ = 50 Z = + .84Data from before
X = 200 + (.84)(50)
X = 200 + 42
X = 242
X = 200 + (-.84)(50)
X = 200 - 42
X = 158
There's the low and the high scores to be within 60% of the data
I’ll wrap this up with a quick review of the Central limit theorem as It was taught on
Tuesday and I’m not really sure whether I’m suppose to include it or not in my lesson
Its for small samples, but you generally want a sample in the 20s or so, a “n” of 3 doesn’t really work so well
And you know to use this when you see “n” which we haven’t seen at all in Z-scores
So here is the formula
Z =M - μ
σm
You’ll be given μ, M, σ, and n so it really makes things simple.
It only looks complicated but its really quite easy
Just take it one step at a time.
μ = 95
M = 100
σ = 20
N = 25
Take your numbers and plug them in Z =
M - μ
σm
M - μ 100 – 95 = 5
σm = σ
N√=
20
√25205
= = 4 4
Z = 1.25
= ZM - μ
σm
1. (Here is the formula)
2. (start with the top)
3. (next do the bottom)
4. (Put it together)
= 5
5. (that’s all)
And there you have it
Z scoresAnd whatnot