Y GT2 a Lec 01 Derivatives 1516
Transcript of Y GT2 a Lec 01 Derivatives 1516
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HUT – DEPARTMENT OF MATH. APPLIED--------------------------------------------------------------------------------------------------------
GIAÛI TÍCH 2 (QUOÁC TEÁ)
LECTURE 01:FUNCTIONS OF SEVERAL VARIABLES:
PARTIAL DERIVATIVES
STEWART: PAGES 855 878
PhD. NGUYEÃN QUOÁC LAÂN (August, 2015)
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LECTURE 1 CONTENTS---------------------------------------------------------------------------------------------------------------------------------
1- FUNCTION OF 2 VARIABLES: DEFINITION – GRAPH.
2- PARTIAL DERIVATIVES
4- INCREMENTAL FORMULA - DIFFERENTIAL
3- IMPLICIT DIFFERENTIATION
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FUNCTIONS OF TWO VARIABLES--------------------------------------------------------------------------------------------------------------------------------------
( ) ( )
( ) ( ){ } f R y x f y x D
D y x y x f z
of domaintheisdefined is,|,setThe
.,,,formulaaisvariablestwoof f functionA
2⊂=
∈=
( )
( ) ( ) D.domain&1,2,2,1find
,,For:Example
f f
x y y x f −=
But the graph of z = f(x, y) is a
surfacecurveaisf(x)yof graphThe =
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EXAMPLE--------------------------------------------------------------------------------------------------------------------------------------
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EXAMPLE--------------------------------------------------------------------------------------------------------------------------------------
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PARTIAL DERIVATIVES OF z = f(x, y)--------------------------------------------------------------------------------------------------------------------------------------
( )
⎪⎪⎭
⎪⎪⎬
⎫
⎢
⎢⎢⎢
⎣
⎡
==∂
∂==
==∂
∂==
=
f D f D y
f
f f
f D f D x
f f f
y x f z
y y y
x x x
2
/
1/
:,: Notation
Rule for finding partial derivatives of z = f(x, y)
( ) y x orto
respectwith
sDerivative
Partial
1/ To find f x, regard y as a constant and differentiate z = f(x, y)with respect to x
2/ To find f y, regard x as a constant and differentiate z = f(x, y)
with respect to y
⎢⎣
⎡
=
=⇒−+=
?
?2:1Example 2323
y
x
f
f y y x x f ⎢
⎣
⎡
=
=⇒=
?
?:2Exam.
y
x y
f
f x f
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HIGHER – ORDER PARTIAL DERIVATIVES--------------------------------------------------------------------------------------------------------------------------------------
( )( ) ( )
( ) ( )
K
,43defineweSimilarly,.of sderivative partialorder-Second
:,
,,of Functions,
thrd
f
z z z z
z z z z y x
z
z y x f z
yy y y yx x y
xy y x xx x x
y
x
⎢⎢⎣
⎡
==
==⇒
⎭⎬⎫
⎢⎣
⎡⇒=
K2
32
2
2
partial,second mixed :,:Symbol y x
f f
y x
f f
x
f f xyy xy xx
∂∂
∂=
∂∂
∂=
∂
∂=
2323 2of sderivative partialsecond theFind :Example y y x x f −+=
therefore43,23haveWe:Answer 2232 y y x f xy x f y x −=+=
46 ,6 ,6,26 22
2
2
2
2
2
32
2
−=∂
∂=∂∂
∂=∂∂
∂+=∂
∂ xy
y z xy
x y z xy
y x z y x
x z
...: partialsmixed ithEquality w2
3
2
33
x y
f
y x
f
x y x
f f f yx xy
∂∂
∂=
∂∂
∂=
∂∂∂
∂⇒=
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IMPLICIT PARTIAL DIFFERENTIATION--------------------------------------------------------------------------------------------------------------------------------------
( ) ( ) ?,0,, byimplicitlydefined is,Function =⇒== y x z z z y xF y x z z
( ) 16 bydefined is,if ,Find :Example 333 =+++= xyz z y x y x z z z z y x
:constantaasgconsiderin,to
respectwithimplicitlyequationthe
atedifferentiwe,find To:Answer
y x
z x
( )106633 22 =+++ x x xyz yz z z x
xy z
yz x z z x x
2
2:for(1)Solving
2
2
+
+−=
xy z
xz y z z y
z
y y
y
2
2forsolveand to
respectateDifferenti:forSimilarly
2
2
+
+−=⇒
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APPROXIMATION: INCREMENTAL FORMULA--------------------------------------------------------------------------------------------------------------------------------------
At some factory, the daily output is
units, where K – capital measured in units of $1000 and L –
labor force measured in worked – hours. The current capital is
$900.000 and 1000 worker – hours of labor are used each day.
Estimate the change in output that will result if capital isincreased by $1000 and labor is increased by 2 worker – hour
)Douglas!(Cobb60 31
2
1
LK Q =
( ) ( ) ( ) ( ) ( ) yba f xba f ba f yb xa f z y x f z y x Δ⋅+Δ⋅≈−Δ+Δ+=Δ= ,,,,:,zinchangeThe
4 4 4 4 34 4 4 4 21
units222030:Ans.32213121
=Δ+Δ=Δ∂
∂
+Δ∂
∂
≈Δ
−−
L LK K LK L L
Q
K K
Q
Q
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DIFFERENTIAL---------------------------------------------------------------------------------------------------------------------------
Given z = f(x, y), x & y: independent variables Differential
)number!realas,(Consider dydxdy
y
f dx
x
f dy f dx f dz y x
∂
∂+
∂
∂=+=⇒
( )2,1 b/ a/ find let2 22 dzdz y x z +=Given:Example
( ) dydxdz y
x
y x
ydy xdxdy zdx zdz
y x
y z
y x
x z
y x
y x
3
4
3
12,1
2
1 b/
2
2a/
2
2 ,
2
22
2222
+=⇒⎩⎨⎧
=
=
+
+=+=
⇒
+
=
+
= sderivativePartial:Answer
Second order differential d2z
222 2 dy zdxdy zdx z zd yy xy xx ++=( )1,2find
2Given:Example
2
2323
zd
y y x x f −+=
222
82414:Answer dydxdydx zd ++=