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    HUT – DEPARTMENT OF MATH. APPLIED--------------------------------------------------------------------------------------------------------

    GIAÛI TÍCH 2 (QUOÁC TEÁ)

    LECTURE 01:FUNCTIONS OF SEVERAL VARIABLES:

    PARTIAL DERIVATIVES

    STEWART: PAGES 855 878

       PhD. NGUYEÃN QUOÁC LAÂN (August, 2015)

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    LECTURE 1 CONTENTS---------------------------------------------------------------------------------------------------------------------------------

    1- FUNCTION OF 2 VARIABLES: DEFINITION – GRAPH.

    2- PARTIAL DERIVATIVES

    4- INCREMENTAL FORMULA - DIFFERENTIAL

    3- IMPLICIT DIFFERENTIATION

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    FUNCTIONS OF TWO VARIABLES--------------------------------------------------------------------------------------------------------------------------------------

    ( ) ( )

    ( ) ( ){ }   f  R y x f  y x D

     D y x y x f  z

     of domaintheisdefined is,|,setThe

    .,,,formulaaisvariablestwoof f functionA

    2⊂=

    ∈=

    ( )

    ( ) ( ) D.domain&1,2,2,1find 

    ,,For:Example

     f  f 

     x y y x f    −=

    But the graph of z = f(x, y) is a

    surfacecurveaisf(x)yof graphThe   =

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    EXAMPLE--------------------------------------------------------------------------------------------------------------------------------------

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    EXAMPLE--------------------------------------------------------------------------------------------------------------------------------------

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    PARTIAL DERIVATIVES OF z = f(x, y)--------------------------------------------------------------------------------------------------------------------------------------

    ( )

    ⎪⎪⎭

    ⎪⎪⎬

    ⎢⎢⎢

    ==∂

    ∂==

    ==∂

    ∂==

    =

     f  D f  D y

     f 

     f  f 

     f  D f  D x

     f  f  f 

     y x f  z

     y y y

     x x x

    2

    /

    1/

     :,: Notation

    Rule for finding partial derivatives of z = f(x, y)

    ( ) y x orto

    respectwith

    sDerivative

    Partial

    1/ To find f x, regard y as a constant and differentiate z = f(x, y)with respect to x

    2/ To find f y, regard x as a constant and differentiate z = f(x, y)

    with respect to y

    ⎢⎣

    =

    =⇒−+=

    ?

    ?2:1Example 2323

     y

     x

     f 

     f  y y x x f  ⎢

    =

    =⇒=

    ?

    ?:2Exam.

     y

     x y

     f 

     f  x f 

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    HIGHER – ORDER PARTIAL DERIVATIVES--------------------------------------------------------------------------------------------------------------------------------------

    ( )( ) ( )

    ( ) ( )

    K

    ,43defineweSimilarly,.of sderivative partialorder-Second 

    :,

    ,,of Functions,

    thrd 

     f 

     z z z z

     z z z z y x

     z

     z y x f  z

     yy y y yx x y

     xy y x xx x x

     y

     x

    ⎢⎢⎣

    ==

    ==⇒

    ⎭⎬⎫

    ⎢⎣

    ⎡⇒=

    K2

    32

    2

    2

      partial,second mixed :,:Symbol y x

     f  f 

     y x

     f  f 

     x

     f  f   xyy xy xx

    ∂∂

    ∂=

    ∂∂

    ∂=

    ∂=

    2323 2of sderivative partialsecond theFind :Example   y y x x f    −+=

     therefore43,23haveWe:Answer  2232  y y x f  xy x f   y x   −=+=

    46 ,6 ,6,26 22

    2

    2

    2

    2

    2

    32

    2

    −=∂

    ∂=∂∂

    ∂=∂∂

    ∂+=∂

    ∂ xy

     y z xy

     x y z xy

     y x z y x

     x z

    ...: partialsmixed ithEquality w2

    3

    2

    33

     x y

     f 

     y x

     f 

     x y x

     f  f  f   yx xy

    ∂∂

    ∂=

    ∂∂

    ∂=

    ∂∂∂

    ∂⇒=

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    IMPLICIT PARTIAL DIFFERENTIATION--------------------------------------------------------------------------------------------------------------------------------------

    ( ) ( ) ?,0,, byimplicitlydefined is,Function =⇒==   y x   z z z y xF  y x z z

    ( ) 16 bydefined is,if ,Find :Example 333 =+++=   xyz z y x y x z z z z  y x

    :constantaasgconsiderin,to

    respectwithimplicitlyequationthe

    atedifferentiwe,find To:Answer 

     y x

     z x

    ( )106633 22 =+++   x x   xyz yz z z x

     xy z

     yz x z z  x x

    2

    2:for(1)Solving

    2

    2

    +

    +−=

     xy z

     xz y z z y

     z

     y y

     y

    2

    2forsolveand to

    respectateDifferenti:forSimilarly

    2

    2

    +

    +−=⇒

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    APPROXIMATION: INCREMENTAL FORMULA--------------------------------------------------------------------------------------------------------------------------------------

    At some factory, the daily output is

    units, where K – capital measured in units of $1000 and L –

    labor force measured in worked – hours. The current capital is

    $900.000 and 1000 worker – hours of labor are used each day.

    Estimate the change in output that will result if capital isincreased by $1000 and labor is increased by 2 worker – hour

    )Douglas!(Cobb60 31

    2

    1

     LK Q =

    ( ) ( ) ( ) ( ) ( )   yba f  xba f ba f  yb xa f  z y x f  z  y x   Δ⋅+Δ⋅≈−Δ+Δ+=Δ= ,,,,:,zinchangeThe

    4 4 4 4 34 4 4 4 21

    units222030:Ans.32213121

    =Δ+Δ=Δ∂

    +Δ∂

    ≈Δ

      −−

     L LK K  LK  L L

    Q

    K K 

    Q

    Q

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    DIFFERENTIAL---------------------------------------------------------------------------------------------------------------------------

    Given z = f(x, y), x & y: independent variables Differential

    )number!realas,(Consider dydxdy

     y

     f dx

     x

     f dy f dx f dz  y x

    ∂+

    ∂=+=⇒

    ( )2,1 b/ a/ find let2 22 dzdz y x z   +=Given:Example

    ( )   dydxdz y

     x

     y x

     ydy xdxdy zdx zdz

     y x

     y z

     y x

     x z

     y x

     y x

    3

    4

    3

    12,1

    2

    1 b/ 

    2

    2a/

    2

    2 ,

    2

    22

    2222

    +=⇒⎩⎨⎧

    =

    =

    +

    +=+=

    +

    =

    +

    = sderivativePartial:Answer

    Second order differential d2z

    222 2   dy zdxdy zdx z zd   yy xy xx   ++=( )1,2find 

    2Given:Example

    2

    2323

     zd 

     y y x x f    −+=

    222

    82414:Answer    dydxdydx zd    ++=