ECON 103 Principles of Macroeconomics Instructor: Bernard Malamud Office: BEH 502
WHERE DO YOU LOOK IF YOU’VE LOST YOUR MIND? -Bernard Malamud-
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WHERE DO YOU LOOK IF YOU’VE LOST YOUR MIND?
-Bernard Malamud-
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REVIEW
WHAT INFORMATION DOES THE FOLLOWING FORMULA TELL YOU?
2 (NH4)3PO4
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WHAT INFORMATION DOES THE FOLLOWING FORMULA TELL YOU?
2 (NH4)3PO4
1)You have 2 formula units of ammonium phosphate, or2)You have 2 moles of ammonium phosphate3)In those 2 formula units, you have 6 atoms of nitrogen, 24 atoms of hydrogen, 2 atoms of phosphorus, 8 atoms of oxygen, or4)In those 2 moles, you have 6 moles of nitrogen, 24 moles of hydrogen, 2 moles of phosphorus, and 8 moles of oxygen
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CALCULATE THE MOLAR MASS OF ZnSO4.
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CALCULATE THE MOLAR MASS OF ZnSO4.
1 Zn = 1 x 65 = 651 S = 1 x 32 = 324 O = 4 x 16 = 64Molar Mass = 161 g/mole
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HOW MANY MOLES OF K2SO4 ARE IN 20 GRAMS?
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HOW MANY MOLES OF K2SO4 ARE IN 20 GRAMS?
First, calculate the molar mass:K = 2 x 39 = 78S = 1 x 32 = 32O = 4 x 16 = 64•Molar mass = 174 g/mole
# moles = 20 g / 174 g/mole = 0.115 mole
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HOW MANY MOLECULES OF C2H5OH ARE IN 2.5 MOLES?
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HOW MANY MOLECULES OF C2H5OH ARE IN 2.5 MOLES?
1 mole = 6.023 x 1023 molecules
# molecules = 2.5 moles x 6.023 x 1023 molecules/mole
= 1.51 x 1024 molecules
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HOW MANY GRAMS OF PbI2 ARE IN 8.4 X 1022 MOLECULES?
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HOW MANY GRAMS OF PbI2 ARE IN 8.4 X 1022 MOLECULES?
# moles = 8.4 x 1022 / 6.023 x 1023
= 1.39 x 10-1 = 0.139 moles
Molar mass of PbI2 = 207 + 2(127) = 461 g/mole
# grams = 461 g/mole x 0.139 moles= 64 g
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BALANCE THE FOLLOWING EQUATIONS, AND TELL WHAT KIND OF REACTION THE EQUATION REPRESENTS:
a.C4H10 + O2 → CO2 + H2O
b.Fe + Cl2 FeCl3
c.Cu + AgNO3 Cu(NO3)2 + Ag
d.Pb(NO3)2 + AlCl3 Al(NO3)3 + PbCl2
e.KClO3 KCl + O2
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BALANCE THE FOLLOWING EQUATIONS, AND TELL WHAT KIND OF REACTION THE EQUATION REPRESENTS:
a.2 C4H10 + 13 O2 → 8 CO2 + 10 H2O
b.2 Fe + 3 Cl2 2 FeCl3
c.Cu + 2 AgNO3 Cu(NO3)2 + 2 Ag
d.3 Pb(NO3)2 + 2 AlCl3 2 Al(NO3)3 + 3 PbCl2
e.2 KClO3 2 KCl + 3 O2
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WHAT ARE THE SUBSTANCES ON THE LEFT SIDE OF A CHEMICAL REACTION CALLED?
WHAT ARE THE SUBSTANCES ON THE RIGHT SIDE OF CHEMICAL REACTION CALLED?
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WHAT ARE THE SUBSTANCES ON THE LEFT SIDE OF A CHEMICAL REACTION CALLED?
REACTANTS
WHAT ARE THE SUBSTANCES ON THE RIGHT SIDE OF CHEMICAL REACTION CALLED?
PRODUCTS
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WHAT IS THE LAW OF CONSERVATION OF MASS?
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WHAT IS THE LAW OF CONSERVATION OF MASS?
IN A CHEMICAL REACTION, MATTER IS NEITHER CREATED OR DESTROYED, ONLY REARRANGED.
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HOW DOES THE LAW OF CONSERVATION OF MASS APPLY TO A CHEMICAL EQUATION?
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HOW DOES THE LAW OF CONSERVATION OF MASS APPLY TO A CHEMICAL EQUATION?
YOU HAVE THE SAME NUMBER OF EACH TYPE OF ATOMS ON BOTH SIDES OF THE EQUATION – THE EQUATION IS BALANCED.
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2 NH3 + H2SO4 (NH4)2SO4
How many grams of ammonia (NH3) would be required to make 1 kilogram of ammonium sulfate?
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How many grams of ammonia (NH3) would be required to make 1 kilogram of ammonium sulfate?
X 1000 g2 NH3 + H2SO4 (NH4)2SO4
34 128
X / 34 = 1000 / 128
X = (1000 x 34) / 128 = 265.6 g
Note: molar mass of ammonium sulfate = 128 g/mole
molar mass of ammonia = 17 g/mole
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How many moles of iron, Fe, would be required to make 40 grams of hydrogen, H2?
2 Fe + 6 HCl 2 FeCl3 + 3 H2
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How many moles of iron, Fe, would be required to make 40 grams of hydrogen, H2?
2 Fe + 6 HCl 2 FeCl3 + 3 H2
Molar mass of H2 = 2 g/mole
# moles H2 = 40 g/2 g/mole = 20 moles
X 202 Fe + 6 HCl 2 FeCl3 + 3 H2
2 3
X/2 = 20/3 so X = 20/3 x 2 = 13.3 moles
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A COMPOUND CONTAINS THE ELEMENTS COPPER AND CHLORINE IN A RATIO OF 1 COPPER : 2 CHLORINE.
WHAT IS THE EMPIRICAL FORMULA FOR THIS COMPOUND?
WHAT IS THE % COMPOSITIONOF COPPER?
WHAT IS THE % COMPOSITION OF CHLORINE?
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EMPIRICAL FORMULA: CuCl2
Molar mass = 63.5 + 2(35.5) = 134.5 g/mole
% Cu = (63.5 / 134.5) x 100 = 47.2 %
% Cl = (71 / 134.5) x 100 = 52.8 %