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Transcript of Well performance
4
Pressure losses from the reservoirto the separator
SEPARATOR
P1flow in porous media
P2vertical and inclinedmultiphase flow
Pr Pwf
Pup
Pdown Ps
multiphase flowin the pipeline
P4
flow in thewell head P3
5
rate of productionduring the well life
Time
qp (Rate ofproduction)
beginningof the
production
build up
production facilities tobe installed
plateau rate
stop ofthe production
6
Aim of this course
To foresee the different facilities of theproduction system
(wells, artificial lift systems, pipelines, etc...)for a given reservoir pressure (Pr) and a
given separator pressure (Ps),
to optimizethe rate of production, qp
7
How to determine qp ?
qp = intersection between IPR curve andVLP curve
• IPR curve = Index of Productivity Relationship– description of the flow in the reservoir
• VLP curve = Vertical Lift Performance –description of the flow from the bottom of thewell to the separator
8
SEPARATOR
Pr
Ps
q
IPR curve
IPR
qp
PPPPwfwf
== PPwfwf
For given Ps, Pr, and productionfacilities,
there is a unique possibility ofproduction rate
=intersection between IPR and VLP
VLP curve
VLP
Pup
9
To plot IPR and VLP curves, wehave to estimate pressure losses
• by using models dedicated to :– flows in porous media– vertical and inclined flows– flows in the choke
• we have to distinguish between :– single phase flows and two phase flows– vertical wells and deviated wells– gas or oil reservoirs,– isotropic or anisotropic reservoirs,– ...
10
Plan of this course• Part 1 : Flow in the porous media, IPR
curve, horizontal wells• Part 2 : Multiphase flow
– application to vertical flows in the well – VLPcurve
– application to flows in the pipelines• Part 3 : Flow through the choke• Summary of the results
11
schedule
Exam and conclusionEnd of the project17 dec
projectproject16 dec
projectProsper : how to design a gas lift system ? ex : Well 5Summary of the course + questions
15 dec
Choke and gas liftNodal analysisTutorial 9 and 11Prosper : how to match a model ? ex : Well 4
Tutorial 8VLP analysis + pressure losses in a pipelineSensitivities on Prosper
14 dec
VLP in the case of oil wells – correlationsTutorial 4 to 7Prosper tutorial 3
Multiphase flow+ VLP in the case of gas wells
13 dec
Introduction to PROSPER+ Prosper tutorial 1 to 2
IPR curve (end)+ tutorial 1 to 3
12 dec
Introduction – IPR curve11 dec
Afternoon 13h to 16hMorning 8h – 11h30date
13
Plan of this course• Part 1 : Flow in the porous media, IPR
curve• Part 2 : Multiphase flow
– application to the vertical flow in the well –VLP curve
– application to the flow in the pipelines• Part 3 : Flow through the choke• Summary of the results
15
First conditions to flow ...
flow only if difference between pressures
P1 P2
P1 P2
we open No flow
P1 = P2
P1 > P2
we open flow
16
Pressure losses during production
reservoir
wel
l
Pup
Pr
Pressure
Abscissa
PBH PrPup
EQUILIBRIUMFLOW
Pressure Drawdown = Pr – Pwf ensures the production
Pwf
Pwf < PBHPup new < Pup
Pup
17
first assumption ...
• we consider that the flow in the reservoir ispseudo-permanent :– sealed reservoir
t
Pwf
pseudo-permanentzone
transitionzone
transientzonePwf = bottom hole
flowing pressure
18
Productivity Index (PI)
• Productivity Index = ratio of the rate ofproduction per pressure drawdown
psidaybblsP
q
PP
qJPI
wfrm
//1
q = Production Rate (in bbls/day for an oil well)Prm = Static Reservoir Pressure (psi),
calculated at the middle point of the reservoirPwf = Flowing Bottom Hole Pressure (psi)
19
Inflow Performance Relationshipa relation between the production rate
and the flowing down hole pressure (Pwf)
rmwf PqJ
P
1
Pwf(psi)
qthqmax
first approximation
Prm
second approximation
q(bbls/day)
qth = pseudo qmax,in the case of no free gas
qmax = maximum rate of production,obtained when Pwf = 0
PI1
PI2
q2q10
not linear – due to2 phase flow, turbulence, etc...
20
From IPR curve to PI
PI = the productivity at a particular rate= f(q,Prm)= calculated by using the slope of theIPR curve at the considered point
We have to determine the IPR curvecorresponding to the reservoir which weare considering, in order to give PI at eachflow rate
21
How to calculate the IPR ?
- by using known quantities = thecharacteristics of the reservoir
- by using theoretical models for flows inporous media = the Darcy's law
- by using measurements = different welltests
22
characteristics of the reservoirknown quantities
Pr,Tr
rw
reh
k : absolute permeabilityko,g : effective permeability of the rock to oil / to gaso,g : effective viscosity of oil / gas, at average pressureWC : water cutGOR = gas oil ratio
23
Case of oil wellsEffective and relative permeabilities
effects of water production (1/2)
dlAdPq
ko
ooo
ko = effective permeability of the rock to oil
sw,o = water or oil saturation.For oil and water system, sw + so = 1
k = absolute permeability = single phase permeability
k
kk
k
kk w
rwo
ro ; = relative permeabilities (oil ; water)
24
Case of oil wellsEffective and relative permeabilities
effects of water production (2/2)
oil
watersw
so
1
0 0
1
swcsor
010 1
k rw
k ro
no oilflow
no waterflow
sor = residual oil saturation ; swc = connate water saturation
25
Models for flows in porous media :Darcy's law – experimental results
SAND
A = r²
L P
Water injection(rate = q)
L
PkAq
r
k = permeability of the sandµ = viscosity of the water
where :
m² Pa = N/m²
Pa.sm
26
Darcy's law applied topetroleum production
dPPf
Sr
r
hkq
r
wf
P
PP
w
e
)(
'43
ln
.00708.0
qFSS ND'S = skin factorFND q = turbulent flow term
f(P) = a function of pressurewhich depends on the state
of the flow in the porous medium
Prm = reservoir pressure atthe outer boundary
we have to distinguish betweensingle phase flow and two phase flow
- in field units
27
Hypothesis of IPR calculationconcerning the reservoir
• Homogeneous (permeability k andsaturation s constant in all horizontaldirections)
• Horizontal• Circular• The thickness h is constant• It is drained by a single fully penetrating
well located at its centre
h
28
Different cases of flowHydrocarbon phase diagram
80%40
%
20%
0%
10%
5%
Reservoir Temperature
Res
ervo
irP
ress
ure
Criticalpoint
Dew pointBubble point
Cricondenthermpoint
lines of constantphase distribution(% = liquid volume)
gas reservoircondensatereservoir
Joule-Thomsonexpansion
oilreservoir
generalization
UndersaturatedOil reservoir
saturatedOil reservoir
29
IPR calculation versus type of flow
Oil (undersaturated reservoirs)Gas
Oil and free gas (saturatedreservoirs)
Type of flow DefinitionIPR
calculation
30
Oil – no free gas
80%40
%
20%
0%
10%
5%
Temperature
oilreservoir
Pb Pwf Prm
Pb
Prm
Pwf
Pb = bubble point pressure
31
oil / no free gas
B
kPf ro
)(
B = Formation Volume Factorof the fluid
relative permeabilityof the rock to oil
= viscosity of the fluidat average pressure
Pb Pwf Prm
Specific assumptions :- the oil satures completely the formation (no free gas)- the flow rate is low no turbulence
),(
),(
stdstd
rr
TPV
TPVFVFB
PB<Pwf<Prm
32
oil / no free gas
PPB
o
Bo
oo
ro
B
kPf
)(
kro = 1
viscosity versus pressure
f(P) almost constant for P > PB
Case of oil :
B almost constant
PB<Pwf<Prm
33
oil / no free gas
'43
ln
00708.0
Sr
rB
PPhkq
w
eoo
wfrmoo
rmw
e
o
ooowf PS
r
r
hk
BqP
'
4
3ln
00708.0
Darcy's lawin this case:
P
Prm
w
er
r
most of pressure lossesnear the wellbore
PB<Pwf<Prm
34
oil / no free gas
'
43
ln
00708.0
Sr
rB
hk
PP
qJ
w
eoo
o
wfrm
o
For a given system,oo
o
B
hkconstJ
.
Non accurate, but gives a quick idea of J
PB<Pwf<Prm
Note: if q in m3/d, h in m & P in bara(instead of bpd, ft & psia) replace0.007082 by 0.053578
35
oil / no free gascase of oil and water flow
If both oil and water are flowing,we use the Darcy's law for each fluid :
ww
w
oo
o
w
e B
k
B
k
Sr
rh
J'
43
ln
00708.0
oil water
PB<Pwf<Prm
Note: if q in m3/d, h in m & P in bara(instead of bpd, ft & psia) replace0.007082 by 0.053578
36
IPR calculation versus type of flow
Oil (saturated reservoirs)Gas
Oil and free gas(undersaturated reservoirs)
Type of flow DefinitionIPR
calculation
38
Case of gas
gg
g
B
kPf
)( If there are no condensation or
liquid accumulation problems,kg = cte
sg P
TZB
Re
02827.0
Z = gas compressibility
factor, which variesT = absolute T°
where :
Specific assumptions :- the compressibility and the viscosity of the fluid can’t be
considered as constant- the flow rate is high turbulence more pressure losses- the liquid fraction is neglected
39
case of gas
• an empirical method : use of well testresults to elaborate a relation between q,Pwf and Pr.1°) gas well tests2°) back pressure equations
40
Different types of gas-well tests
• drawdown : decrease of pressure during production atconstant flow rate
• pressure buildup : increase of pressure with the wellclosed-in
Gas-well tests– stabilized production point test– multiple-rate drawdown tests : non stabilized
flow conditions– multiple-rate drawdown tests : isochronal and
p²-plot methods
41
Stabilized production point method
• initially : close the well buildup pressure determination of Pi
• four times : well flowed at a constant rateq for a sufficient time that Pwf stabilizes four couples (q, Pwf )
• main disadvantage : unrealistically longtest periods (to attain the stabilized Pwf)
42
Stabilized productionpoint method
Time
Pwf
PPrmrm
q
q1q2
q3q4
Pwf1
Pwf2
Pwf3
Pwf4
t1 t2 t3 t40
4 couples (q,Pwf)
stabilized values
43
Multiple-rate drawdown tests :isochronal procedures
• in order to avoid the long delay necessary for a stabilizedsituation (stabilized production point method), before Pwf isrecorded.
• 2 examples : Cullender test and Katz test common test conditions :
- generally 4 different flow rates q1<q2<q3<q4- same fixed delay t for the 4 sequencies of production :sufficiently short to assume transient flow conditions
- a last test period of production with Pwf stabilization
44
Cullender's test
In this test, (q5,Pwf5) arethe sole stable values
Specific test conditions : we wait until the pressures build upto the static value with the well closed-in
stabilized pressure
q
Pwf initial = Prm
t1f t2i t3i t3f Time
Pwf
t2f
t t t
PPrmrm
t4i t4f
t
q1
q2
q3q4
q5
Pwf1 Pwf2Pwf3 Pwf4 Pwf5
t1i
45
Katz's test
t1f t2i t3i t3f Time
Pwf
t2f
t t t
PPrmrm
t4i t4f
t
q
q1q2
q3q4
q5
Pwf1 Pwf2
Pwf3Pwf4
Pwf5
t1i
Pwf initial = Prm
tbu tbutbu
Specific test condition : buildup period tbu is fixed
stabilized pressure
In this test, (q5,Pwf5) arethe sole stable values
46
Conditions for using these methods
• in the case of a low permeability k :– tests don't allow stabilized conditions.
inaccurate measurements
• for a good k :– the period of stabilization is short
good accuracy of the method
case of gas – well tests
47
from these tests ...
• 2 main types of gas well behaviours :– first back pressure equation :
– second back pressure equation :
0
22
1
2
1
q
PP
C
Cq
C
F wfrmND
nwfrmg PPCq 22
48
Case of gas :first back pressure equation
dPPf
Sr
r
hkq
r
wf
P
PP
w
e
g
)(
'43
ln
.00708.0
ZT
PPf
g02827.0)( with
Assumption : we consider the averageof the different quantities.
demonstration
49
rm
wf
P
P g
w
e
gg ZT
PdP
Sr
r
hkq
'
43
ln
10*4066.1 3
case of gas :first back pressure equation
qFSr
rTZ
PPhkq
NDw
eaaga
wfrmgg
43
ln
10*703.0 223
for assumed average properties and pressuresXa = average of the quantitiy, calculated at the average pressure
term due toturbulent flow
(in Mscf/d)
demonstration
50
aag
g
TZ
hkC
6
1
10.703.0
Sr
rC
w
e
4
3ln2
02212
2 wfrmND PPCqCqF
If we consider and
we obtain
0
22
1
2
1
q
PP
C
Cq
C
F wfrmND
Case of gas -First back pressure equation
term due toturbulent flow
demonstration
51
0
22
1
2
1
q
PP
C
Cq
C
F wfrmND ybax straight line
Sr
r
kh
ZTb
krh
GZTa
q
PPy
qx
w
e
w
wfrm
4
3ln
10.422.1
10.13.0
6
342
6
22
non Darcy coefficient(turbulent flow)
coefficient of Darcy effects
where :
Case of gas -First back pressure equation
• a and b are empirically determinedby using well test regression
demonstration
52
How to use the gas well tests to determinethe equation parameters ?
example of the second Back Pressure equation
22logloglog wfrmg PPnCq 22log wfrm PP
log qg
logC
n = slope of the straight line
logC = intersection between the straight lineand the logq axis
log-log plot
Case of stabilized data
53
How to use the gas well tests to determinethe equation parameters ?
example of the second Back Pressure equation
nwfrmg PPCq 22
C = gas well performance coefficientn = exponent of the back pressure equation
0.5 < n < 1
High turbulent effect
qg inMMscf/d
Low turbulent effect
22logloglog wfrmg PPnCq
54
Use of Cullender or Katz's testsn and logC determination
22log wfrm PP
log q
logC
nn == slope
slope ofof thethe lineline
pointpoint obtainedobtainedwithwith ((PPwf5wf5,q,q55))
pointspoints obtainedobtainedduringduring drawdowndrawdown periodsperiods
((PPwfiwfi,,qqii) , i = 1..4) , i = 1..4
nwfrmg PPCq 22
Case of only 1stabilized data
55
IPR determination for a gas-wellexample of second back pressure equation
With tests, we measure q and Pwf
22log wfrm PP We calculate log q and22logwfrmPP
22logwfrmPP
We plot log q versus 22log wfrm PP
linear regression + use of stabilized (q,Pwf)
n and logC determination IPR
56
Absolute Open Flow Potential qmax
nrShutInPCq 2max
qmax represents the ideal case of production, where Pwf = 0.
nwfrmg PPCq 22
In this case, P1 is maximum, because :
wfrShutIn PPP 1
0
Then, the production is maximum(by considering only the reservoir point of view).
The back pressure equation :
can be written :
57
IPR calculation versus type of flow
Oil (undersaturated reservoirs)Gas
Oil and free gas (saturatedreservoirs)
Type of flow DefinitionIPR
calculation
58
Two phase flow – oil and free gas
80%40
%
20%
0%
10%
5%
Temperature
oilreservoir
Pwf Prm Pb
Pb
Prm
Pwf
Pb = bubble point pressure
Case of only2 phase flow
59
Two phase and single phase flow –oil and free gas
0%
5%
Temperature
oilreservoir
Pwf Pb Prm
Pb
Prm
Pwf
Pb = bubble point pressure
Case of single phase and2 phase flow
q1
q2
60
Two phase flow – oil and free gas
80%40
%
20%
0%
10%
5%
Temperature
oilreservoir
Pwf Prm Pb
Pb
Prm
Pwf
Pb = bubble point pressure
Case of only2 phase flow
61
Two phase flow
dPPf
Sr
r
hkq
rm
wf
P
PP
w
e
o
)(
'43
ln
.00708.0
first case : PB > Prm
not constant,function of pressure
The equation can't be solved without the knowledgeof the relation between kro/oBo and (Prm – Pwf) = P1
oo
ro
B
kPf
)(with
function of saturation
PB > Prm
62
Two phase flow
oo
ro
B
k
kro can be estimated in lab with experience
but
is different at each level in the reservoir, for the same rockPrm varies oil and gas saturations varie kr varies
P P
Pwf Prm
I1 I2
P
I1 I2dPB
krmP
Pwf oo
ro
qo depends on the levelof pressure.It depends on the GORtoo (the curve is not thesame).
PB > Prm
63
Two phase flowAn empirical method
rm
wf
P
P
maxq
q
measurements
measurements are usedto establish an empirical equation
=IPR equation
PB > Prm
Pressures and corresponding rates of productionmeasured for different field cases are normalized
by qmax and Prm resp.
Curves of each fieldcan be superposed.
64
Two phase flow PB > Prm
IPR equations
2
max
11
rm
wf
rm
wf
P
PV
P
PV
q
q
rm
th
wfrm P
q
PP
qJ
V = 0 : IPR = straight line
V = 0.8 VOGEL's equation
V = 1 FETKOVITCH's equation
)( 222
maxwfrm
rm
PPP
PB > Prm
q
Pwf
(qmax)F (qmax)V qth
PrmIPR curves
65
Two phase flowrelation between J* and qmax
wfrm PP
qJ
rm
wf
rm
P
P
Pq
J
1
J is defined by :
rm
wf
rm P
P
P
qJ 8.01max
rmP
qJ max8.1
*
Definition : If Pwf = Prm, we have J = J*.
Case of Vogel's equation :
rm
wf
rm P
P
P
qJ 1max
rmP
qJ max2
*
Case of Fetkovich's equation :
PB > Prm
66
Two phase flowIPR equations : How to determine qmax ?
• if we know Prm, by using one result of welltest (= one couple (q,Pwf))
or• without the knowledge of Prm, by using two
results of well tests (= 2 couples (q,Pwf))
PB > Prm
67
Two phase flow PB > Prm
exercise 1.1We consider an oil well, which produces in the
following conditions :– Prm = 2500 psi– qi = 3000 bbls/d– Pwfi = 1800 psi– Prm < Pb
Question : Give the IPR curve using Fetkovich'sapproach, and Vogel's one.
68
Oil and free gas
0%
5%
Temperature
oilreservoir
Pwf Pb Prm
Pb
Prm
Pwf
Pb = bubble point pressure
Case of single phase and2 phase flow
Pwf < PB < Prm
69
oil and free gas
B
kPfand
dPPf
Sr
r
hkq
ro
P
PP
w
e
o
rm
wf
)(
)(
'43
ln
.00708.0
when Pwf > Pb, single phase f(P) almost constant
when Pwf < Pb , two phase flow (oil + gas) f(P) is a function of saturation and pressure
Pwf < PB < Prm
70
oil and free gas
dPB
kdP
B
k
Sr
r
hkq
rm
b
b
wf
P
PP
ro
P
PP
ro
w
e
oo
'43
ln
.00708.0
B
PPdP
B
k
Sr
r
hkq brm
P
PP
r
w
e
ob
wf
'43
ln
.00708.0
part of the IPR curve given by Vogel's or Fetkovich's models
Pwf < P < Pbtwo phase flow
Pb < Psingle phase flow
Pwf < PB < Prm
71
Oil and free gasIPR curve
Part of single phase flowStraight line PI = J = cte
rate at bubblepoint pressure
Part of two phase flowcurve
q1 q2
qqmax(AOFP)
qb
qmax-qb
Pwf
Prm
Pb
qp
production rate
Physically, the transition from pure liquidflow to the presence of some free gas
in the flowing stream is a continuous one continuity and derivability
of IPR at this point
Pwf < PB < Prm
72
Oil and free gas
0%
5%
Temperature
oilreservoir
Pb
Prm
Pwf
Pb = bubble point pressure
q1
q2
Pwf < PB < Prm
qp = q1 + q2
73
Two phase flowFetkovich's approach to calculate
b
boo
ro
oo
ro
b P
P
Bk
Bk
Pf
Pf
)(
boo
ro
bB
kP
PPf
)(
• we know the conditions of Pressure, viscosity, etc...at the bubble point
• assumption : f(P) is a linear function of pressure
b
wf
P
P
dPPf )( Pwf < PB < Prm
74
Two phase flowFetkovich approach to calculate
22
2
1
'43
ln
.00708.0wfb
bboo
ro
w
e
PPPB
k
Sr
r
hkq
22
2
1
'43
ln
.00708.0wfb
b
w
eoo
o PPP
Sr
rB
hkq
where J is the PI in the case of single phase flow (q1 calculation)
22
2 wfbb
PPP
Jq we can write : or 22' wfb PPJq
where J' is referred to a pseudo productivity index
Pwf < PB < Prmb
wf
P
P
dPPf )(
75
Fetkovich approachIPR equation
q1
qqmax(AOFP)
qb
qmax-qb
Pwf
Prm
Pb
q2
qp
brm PPJq 1
single phase portion
222 2 wfb
b
PPP
Jq
two phase portion
22
2 wfbb
brm PPP
JPPJq Total rate : and
2maxb
rm
PPJq
q2
qp
Pwf < PB < Prm
76
2
max 8.02.01b
wf
b
wf
P
P
P
Pqq
The two phase part of the curve can be written likein the case of two phase flow where Prm < Pb, with the assumption thatPrmPb :
To obtain the real equation of IPR in the case of two phase flow wherePwf < PB < Prm, we have to shift this curve by introducing the bubble flow rate qb :
2
max 8.02.01b
wf
b
wfbb P
P
P
Pqqqq
Pwf < PB < Prm
Two phase flowVogel's approach
77
Two phase flow – free gasrelation between J* and qmax
Definition : If Pwf = Pb, we have J = J*=Jstraight line.
b
b
P
qqJ
)(2* max
b
b
P
qqJ
)(8.1* max
Case of Vogel's equation : Case of Fetkovich's equation :
Pwf < PB < Prm
Prm Pb
0 qb
qmax- 0 qmax - qb
ShiftShift ofof thethe 22--phasephase curvecurve
qmax0 qb
Pb
0 qmax
PrmJ* J*
78
Changes of IPR curve ...
• Case of horizontal and deviated wells• Modification due to the skin factor• Evolution of IPR
– IPR in the future, during the field life
79
Horizontal wells
- When to use them ?- How to calculate the flow rate ?- Influence of reservoir anisotropy- Case of slant wells
80
Why to use horizontal wells?
Mainly :• To increase the surface of contact
between the well and the reservoir
• To enhance the productivity
81
SIDETRACKINGSIDETRACKING
OFFSHOREOFFSHORE SHORELINESHORELINE
RELIEFRELIEF--WELLWELL
MULTIPLE ZONESMULTIPLE ZONES
Why to use horizontal wells ?
HEAVY OIL
THIN PAY-ZONES
LAYED RESERVOIR
FRACTURED RESERVOIRS
WATER / GAS CONING
GAS WELLS
Why to use horizontal wells?
83
drainage areaof a vertical well
Drainage area in the case of ahorizontal well
L
X
drainage shape = ellipsoïdal
X = large half-axis
kv
kh
84
Surface of contact betweenthe well and the reservoir
re
Vertical well Horizontal well
X
2
LX
Examples :For 1000 ft : Horizontal area = 2 * Vertical areaFor 2000 ft : Horizontal area = 3 * Vertical area
85
How to know the gainin productivity by drilling
a horizontal well ?
• By doing a comparison between :– Horizontal well PI and vertical well PI– The number of vertical wells required to
obtain the same level of productivity as asingle horizontal one
86
Quantities used in this part• L = Horizontal well length• h = Thickness of the pay-zone• rw = Wellbore radius• re = Drainage radius• q = Flow rate• k = permeability
• subscripts :h horizontal d deviatedv vertical
87
Flow rate estimation
Several methods have been developed,and, more particularly the ones given by :– Renard and Dupuy– Joshi
Assumption : reservoirs are isotropic (horizontalpermeability = vertical one)
88
Renard and Dupuy’s model
w
ooh
h
r
h
L
h
L
Xch
B
Phk
q
2ln
2
2
1
SI Units
Field Units
w
ooh
h
r
h
L
h
L
Xch
B
Phk
q
2ln
2
00708.0
1
where 2X = major axisof the drainage ellipse
L
Xch
B
Phk
q ooh
h 2
00708.0
1
If L>>h
specific tothis model
89
Joshi’s model
If L>>h
w
ooh
h
rh
Lh
L
Laa
BP
hkq
2ln
2
2²ln
2
2
where :
42
25.05.02
L
rLa eh
SI Units
field units :2 0.00708
2rw rw
2
2²ln
22
L
LaaB
Phkq
oo
hh
specific tothis model
90
A model to comparehorizontal and vertical PI
w
eh
eh
w
ev
v
h
rh
Lh
rL
rL
r
r
J
J
2ln
2
211
ln
ln
2
0 if h <<L
v
h
J
J'25h
'50'200
'400
L
Conclusion : The gain of J in a thin reservoiris higher than for a thick zone
h in feet
Hyp : kv/kh = 1
91
Case of anisotropic reservoirsAssumption : kv kh (anisotropic reservoir)
and the reservoir thickness is modified :
hk
khh
v
heff
In this case, the anisotropy can be characterized by :
v
h
k
k kh = permeability in the horizontal plane
kv = vertical permeability
92
Case of anisotropic reservoirs
Conclusions :- The gain of PI is higher for reservoirs of good vertical permeabilities,- this impact is relaxed in the case of thin reservoirs.
v
h
J
J
v
h
k
k
L
h1 < h2
h1 = cte
h2 = cte
93
Case of anisotropic reservoirsanisotropy in the horizontal plane
largerlarger horizontalhorizontal anisotropyanisotropy
smallersmaller horizontalhorizontal anisotropyanisotropy
case 1 : productivity = optimized case 2 : productivity = minimum
better = well drilled normal tothe larger horizontal anisotropy
94
Case of anisotropic reservoirs• Joshi’s model :
• Renard and Dupuy’s model :
w
h
h
r
h
L
hL
Laa
B
phk
q
2ln
2
2ln
00708.0
22
00
w
hh
R
h
L
h
L
Xarcch
B
phkq
2ln
2
100708.0
00
v
h
k
kwhere
2
1 ww rRwhere
and a defined aspreviouslyfor Joshi's model
95
How to calculatethe effective radius rw' ?
Assumption : ehev rr
hv JJ
rw' can be defined as the radius of a fictivevertical well which produces with the sameflow rate as the considered horizontal well.
same drainage radius
same productivity index
96
By using Joshi’s equation : vh JJ
'
22 ln
00708.0
2ln
2
2ln
00708.0
w
e
oo
h
w
oo
h
rr
Bhk
r
h
L
hL
Laa
Bhk
L
h
w
eh
w
r
hLaa
Lr
r
22
22
2
'
v
h
k
k=>
(general relation, which takes into account the anisotropy)
98
Cinco, Miller and Ramey modelassumption : < 75°
v
h
wd k
k
r
hh deviated thickness :
tanarctan
v
hd k
kdeviated inclination :
dsww err 'effective wellbore radius :
100ln
5641
865.106.2
dddd
hs
99
Cinco, Miller and Ramey modelSlant well / Vertical well comparison
w
e
w
e
v
d
r
r
r
r
JJ
'ln
ln
Conclusion : Jd/Jv increases with kv (as for horizontal wells)and with h (in contrast to horizontal well)
v
d
J
J
'400h'300
'200'100
hyp : kv=kh
100
Van der Vlis’s modelAssumption : 20° and kv=kh
L
h
ww h
rLr
360sin454.0
4'
cos
hL with :
Then, we can apply :
w
e
w
e
v
d
r
r
r
r
JJ
'ln
ln
to compare Jd and Jv.
101
Conclusion
It’s only in the case of thick reservoirs thatslant wells can be more interesting than
horizontal ones.
For thin pay-zones, horizontal wells arealways better.
102
Changes of IPR curve ...
• Case of horizontal and deviated wells• Modification due to the skin factor• Evolution of IPR
– IPR in the future, during the field life
103
pay zone kks
Zone of changed permeability
SKIN EFFECT, characterized by the « skin factor », noticed S
rw
rs
re
Skin factor
"S" takes into account the non homogeneity of the reservoir permeability .
105
Formation damage is any impairment ofFormation damage is any impairment ofreservoirreservoir permeabilitypermeability around thearound the wellborewellbore
It is a consequence of the drilling, completion,work-over, production, injection or stimulation
operationsProductivity orProductivity or InjectivityInjectivity
are affectedare affected
Formation damage :Formation damage :definitiondefinition
106
•Drilling•Cementing•Perforating•Completion and workover•Gravel packing•Production•Stimulation•Injection operations
Sources of Formation damage
107
Interface well-reservoir during drilling
cakecake
reservoir rock
Filtration through the wellbore
Control of fluid lossthrough the wellbore
understanding of themechanisms of filtration andformation of cakes of complexwell fluids with models
impermeable zone
108
Fluid characterization• Density control,• Suspension stability,• Rheological properties,• Filtration properties :
Static : V = a' + b' t 1/2
where b' = ( 2 k P A2/ h)1/2
Dynamic : V = a + b t
V filtration volume, k cake permeability, A area of filtration, filtrate viscosity, P differential pressure , h cake thickness
109
Drillingmud withdispersed
solids
Externalmud cake
Shale
1m
Drilling operationVirgin reservoir
Quartzgrains
110
Wellbore filtration
Definition of the zones invaded by the filtrate
Circulating drilling fluid Well
External cake
Internal cake
Invaded zone
Non invaded zone
111
Near wellbore damage under overbalanceddrilling
• Whole mud invasion(spurt period):– Internal and then
external filter cakes• Filtrate invasion
(filtrate displacing oil):– Dynamic period
(mud is circulating)– Static period
(well is left underoverbalanced pressure)
112
Drilling damages
• Drilling mud solids - solid penetration
• Water based mud filtrate - additive residues- formation sensitivity: pH,salinity- interactions with reservoir oil- fine migration
• Oil based mud filtrate - oil + surfactant invasion :wettability, emulsion...
115
Horizontal Well - 12000 BOPDProductivity Impairment due to Filtrate Invasion
Depth of invasion (inches)
Flow
Rat
e (B
OPD
)
PermeabilityReduction
116
•Drilling•Cementing
•Perforating
•Completion and workover•Gravel packing•Production•Stimulation
•Injection operations
Sources of Formation damage
118
Clearance
Charge
Casing
Cement
Rp
Formation
Lp
Crushed zones
Perforations
may create more damage than it overcomes :• fluids, debris• control : depth, geometry ...
121
To summarize :Types of formation damage
ONLY TWO TYPES !!!ONLY TWO TYPES !!!
• Although there are a number of damagemechanisms, there are only two ways inwhich near wellbore permeability can bereduced:–– Physical reduction in pore/pore throat size,Physical reduction in pore/pore throat size,–– Relative permeability reductionRelative permeability reduction.
122
Process fluid rock fluidfluid
P, T mechanical
Physical poresize reduction
finemigration,
clayswelling,
solidinvasion,
adsorption/precipitationof polymers
scaleemulsion
sludge
scalewax
asphaltene
perforationplugging
Relativepermeability
reduction
wettability fluidsaturation,
fluidblocking
(water, gas)
gas breakout,
condensatebanking,
waterconing,
Classification of damage
123
How to know the presence of skin ?
• In this case, the actual production rate isdifferent than expected from calculation
Presence of (P)skin
124
Skin factor – ex. of oil field
qFSS
P
Sr
rB
hkq
ND
w
eoo
o
'
'43
ln
00708.0
2
00708.000708.04
3ln
00708.0q
kh
BDq
kh
BSq
r
r
kh
BP
w
e
2. qeffectturbqeffectskinqPIP ideal
(given by Darcy's equation)
125
Skin effect and pressure lossesChange of pressure profile in the formation
PPR
radius
Pwf
Pskin > 0
Pskin < 0
Estimated Pwf for a given q
Actual Pwf in the case of a positive skin factor
Actual Pwf in the case of a negative skin factor
ActualwfEstimatedwfskin PPP
127
Models of skin factor calculationassumptions
Assumptions concerning the damaged area :• Fluids are considered as uncompressible• At any time, the volume of incoming fluid is
equal to the volume of outgoing fluid.
• All these conditions suppose a permanentflow in the damaged area.
128
Models of skin factor calculation"Permanent skin" method
skinoo
PqB
hkS
00708.0
S > 0 when the permeability near the wellbore is less than far from it :ks < kS = 0 when there is no change of permeabilityS < 0 in the case of ks > k (after an acidizing process for example)
S can be determined by using well tests (cf course about well testanalysis).
first relation
w
s
s
s
r
r
k
kkS ln s skin
w wellsecond relation
129
Rw
Rd
KdK
K= 500mDKd= 50mD (1/10)Rw= 8 1/2
Rd= Rw + 30cm
S = + 11.9S = + 5.9 if Rd= Rw + 10cmS = + 5.3 if Kd= 100mD
Examples of skin factor calculation
Skh
qBP
R
R
K
KS
skin
w
d
d
*2
ln1
130
Models of skin factor calculationEffective wellbore radius method (1/3)
• The principle of this method is to create afictive well which skin factor is 0 and whichproduction rate is the same as the actual one.
• The effective wellbore radius r’w is thetheoretical radius of this well.
• This method is available when the skinpermeability and its radius are not too high.
131
Models of skin factor calculationEffective wellbore radius method (2/3)
p
r
rB
khq
w
eoo
'ln
00708.0
'ln
00708.0
w
eoo r
rB
khJ
'
lnw
e
r
r
Flow rate :
Productivity Index :
'4
3ln S
r
r
w
e
replaces
132
Models of skin factor calculationEffective wellbore radius method (3/3)
rdrd
rw r’w
In this example, S<0 rw <r’w
Sww err '
r’w = effectivewellbore radius
(ks)(k) (k)(k)
actual well : kd ≠ k fictive well : kd = k
s estimation
133
Case of horizontal wells (1/2)Skin effect
Vertical wells :(P)skin is proportional
to the flow rate perunit length h of thewellbore in the pay-zone.
h
qP skin
Horizontal wells :(P)skin is proportional
to the flow rate perunit length L ofhorizontal part of thewellbore in the pay-zone.
L
qP skin
Influence of damage in productivity less detrimental for horizontal wells
134
Case of horizontal wells (2/2)Effective wellbore radius
• In this case, the effective wellbore radius is theradius of a fictive vertical well which verifies :– its PI is the same as the PI of the considered
horizontal well,– Its skin is 0.
• To calculate the effective wellbore radius :– we convert the horizontal well Productivity Index to
that of the equivalent vertical wellor
– we write that both flow rates are equal (cf. "horizontalwells").
135
Case of high permeability reservoirs
In this case, (P)skin may be very largecompared with other pressure drops.Therefore, we can write :
SB
khJand
Skh
BqP
PP
oo
oototal
skintotal
00708.000708.0
J cte
136
Changes of IPR curve ...
• Case of horizontal and deviated wells• Modification due to the skin factor• Evolution of IPR
– IPR in the future, during the field life
137
Prediction of the future IPR
• In the previous part of the course, we havemodeled the behavior of the flow in thereservoir today.
• But what will happen in 3, 4 or 10 years ?
138
Prediction of the future IPRPrm < Pb
JP*
qqPmax
J
J = measured value of PI actual value
J* = initial value of J= the value of PI when q 0i.e. Pwf Prm
Pwf
PrmP
JF*
qFmax
PrmF
P = presentF = future
?How to calculate the future IPR,
by using only J, and PrmP ?
139
Prediction of the future IPR - Prm < Pb
Fetkovich's procedure
22* wfrm PPJq
22*wfFrmF
rmP
rmFPF PP
P
PJq
rmP
rmF
P
F
P
P
J
J
*
*
Assumption : J* declines in proportion to the decline in pressure.
Fetkovich's model :
where :rmP
JJ
2*
140
Prediction of the future IPR - Prm < Pb
Standing procedure
rm
wf
P
P
JJ
8.01
8.1*
rmP
qJ max8.1
J* is in terms of J. It can be calculated from it, which is measured.
We know that :(Vogel's model)
and :
rm
wf
rm P
P
P
qJ 8.01max
(Based on Vogel's model)
Assumption : The curvature of the IPR will be the same in the future.
141
Prediction of the future IPR - Prm < Pb
Standing procedure
2
8.02.018.1
*
rm
wf
rm
wfrm
P
P
P
PPJq
Then, the Vogel's equation can be written as follows :
This equation can be applied as the IPR's one in the future, with :Prm = PrmF ; J* = JF*
2
8.02.018.1
*
rmF
wfF
rmF
wfFrmFFF P
P
P
PPJq
To be predicted
142
Prediction of the future IPR - Prm < PbStanding procedure
Poo
ro
Foo
roPF B
k
B
kJJ
**
'43
ln
00708.0*
Sr
rB
hkJ
w
eoo
o
J* can be calculated from the radial flow equation :
How to predict J*F ?
rmP
wfP
PP
P
PJ
J
8.01
8.1*
JF* can be calculated and future IPR generated if kro, µo and Bo can be predictedfrom values of pressure and saturation today and in the future
143
Prediction of the future IPRComparison of the procedures
JP*
qqPmax
J
Pwf
PrmP
JF*PrmF
future IPR Standing proc.future IPR Fetkovich's method
IPR today
(qFmax)Stand(qFmax)Fetk