Wednesday, Feb. 6, 2008 PHYS 1441-002, Spring 2008 Dr. Jaehoon Yu 1 PHYS 1441 – Section 002...

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Wednesday, Feb. 6 , 2008 PHYS 1441-002, Spring 2008 Dr. Jaehoon Yu 1 PHYS 1441 – Section 002 Lecture #7 Wednesday, Feb. 6, 2008 Dr. Jaehoon Yu Motion in Two Dimension Motion under constant acceleration Vector recap Projectile Motion Maximum ranges and heights

Transcript of Wednesday, Feb. 6, 2008 PHYS 1441-002, Spring 2008 Dr. Jaehoon Yu 1 PHYS 1441 – Section 002...

Page 1: Wednesday, Feb. 6, 2008 PHYS 1441-002, Spring 2008 Dr. Jaehoon Yu 1 PHYS 1441 – Section 002 Lecture #7 Wednesday, Feb. 6, 2008 Dr. Jaehoon Yu Motion in.

Wednesday, Feb. 6, 2008 PHYS 1441-002, Spring 2008Dr. Jaehoon Yu

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PHYS 1441 – Section 002Lecture #7

Wednesday, Feb. 6, 2008Dr. Jaehoon Yu

• Motion in Two Dimension– Motion under constant acceleration– Vector recap– Projectile Motion– Maximum ranges and heights

Page 2: Wednesday, Feb. 6, 2008 PHYS 1441-002, Spring 2008 Dr. Jaehoon Yu 1 PHYS 1441 – Section 002 Lecture #7 Wednesday, Feb. 6, 2008 Dr. Jaehoon Yu Motion in.

Wednesday, Feb. 6, 2008 PHYS 1441-002, Spring 2008Dr. Jaehoon Yu

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Announcements• 1st term exam on Wednesday, Feb. 20

– Time: 1 – 2:20pm– Place: SH103– Covers: Appendices, CH 1 – what we learn till next

Wednesday, Feb. 13– Class on Monday, Feb. 18: Jason will be here to go over

the any problems you would like to review• Colloquium

– Today at 4pm in SH101, following the refreshment at 3:30pm in SH108

– Please be sure to sign in the sign-in sheet

Page 3: Wednesday, Feb. 6, 2008 PHYS 1441-002, Spring 2008 Dr. Jaehoon Yu 1 PHYS 1441 – Section 002 Lecture #7 Wednesday, Feb. 6, 2008 Dr. Jaehoon Yu Motion in.

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Page 4: Wednesday, Feb. 6, 2008 PHYS 1441-002, Spring 2008 Dr. Jaehoon Yu 1 PHYS 1441 – Section 002 Lecture #7 Wednesday, Feb. 6, 2008 Dr. Jaehoon Yu Motion in.

Wednesday, Feb. 6, 2008 PHYS 1441-002, Spring 2008Dr. Jaehoon Yu

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Kinematic Quantities in 1D and 2DQuantities 1 Dimension 2 Dimension

Displacement

Average Velocity

Inst. Velocity

Average Acc.

Inst. Acc.

x r r

if

ifx tt

xx

t

xv

f i

f i

r r rv

t t t

r r rr

0limt

rv

t

rr

0limx t

xv

t

f i

f i

v v va

t t t

r r rr

if

xixfxx tt

vv

t

va

0limt

va

t

rr

0lim x

xt

va

t

What is the difference between 1D and 2D quantities?

f ix x f ir rr r

Page 5: Wednesday, Feb. 6, 2008 PHYS 1441-002, Spring 2008 Dr. Jaehoon Yu 1 PHYS 1441 – Section 002 Lecture #7 Wednesday, Feb. 6, 2008 Dr. Jaehoon Yu Motion in.

Wednesday, Feb. 6, 2008 PHYS 1441-002, Spring 2008Dr. Jaehoon Yu

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12 ox v v t

212ox v t at

ov v at

2 2 2ov v ax

Kinematic Equations

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Wednesday, Feb. 6, 2008 PHYS 1441-002, Spring 2008Dr. Jaehoon Yu

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This is a motion that could be viewed as two motions combined into one.

A Motion in 2 Dimension

Page 7: Wednesday, Feb. 6, 2008 PHYS 1441-002, Spring 2008 Dr. Jaehoon Yu 1 PHYS 1441 – Section 002 Lecture #7 Wednesday, Feb. 6, 2008 Dr. Jaehoon Yu Motion in.

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Motion in horizontal direction (x)

12 xo xx v v t

212xo xx v t a t

x xo xv v a t 2 2 2x xo xv v a x

Page 8: Wednesday, Feb. 6, 2008 PHYS 1441-002, Spring 2008 Dr. Jaehoon Yu 1 PHYS 1441 – Section 002 Lecture #7 Wednesday, Feb. 6, 2008 Dr. Jaehoon Yu Motion in.

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Motion in vertical direction (y)

12 yo yy v v t

212yo yy v t a t

y yo yv v a t

2 2 2y yo yv v a y

Page 9: Wednesday, Feb. 6, 2008 PHYS 1441-002, Spring 2008 Dr. Jaehoon Yu 1 PHYS 1441 – Section 002 Lecture #7 Wednesday, Feb. 6, 2008 Dr. Jaehoon Yu Motion in.

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Imagine you add the two 1 dimensional motions on the left. It would make up a one 2 dimensional motion on the right.

A Motion in 2 Dimension

Page 10: Wednesday, Feb. 6, 2008 PHYS 1441-002, Spring 2008 Dr. Jaehoon Yu 1 PHYS 1441 – Section 002 Lecture #7 Wednesday, Feb. 6, 2008 Dr. Jaehoon Yu Motion in.

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x-component

12 xo xx v v t

212xo xx v t a t

x xo xv v a t

2 2 2x xo xv v a x

12 yo yy v v t

212yo yy v t a t

y yo yv v a t

2 2 2y yo yv v a y

Kinematic Equations in 2-Dimy-component

Page 11: Wednesday, Feb. 6, 2008 PHYS 1441-002, Spring 2008 Dr. Jaehoon Yu 1 PHYS 1441 – Section 002 Lecture #7 Wednesday, Feb. 6, 2008 Dr. Jaehoon Yu Motion in.

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Coordinate Systems• They make it easy and consistent to express locations or positions• Two commonly used systems, depending on convenience, are

– Cartesian (Rectangular) Coordinate System• Coordinates are expressed in (x,y)

– Polar Coordinate System • Coordinates are expressed in distance from the origin ® and the angle measured

from the x-axis, (r)

• Vectors become a lot easier to express and compute

O (0,0)

(x1,y1)r1

1x

How are Cartesian and Polar coordinates related?

1r

y1

x1

+x

+y

1y 1tan

2 21 1x y

1y1r

1r

= (r1)

1x

1 11

1

tany

x

1cos

1sin

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Example Cartesian Coordinate of a point in the xy plane are (x,y)= (-3.50,-2.50)m. Find the equivalent polar coordinates of this point.

y

x

(-3.50,-2.50)m

r

s

r

s 180

tan s

s

2 2

3.50 2.50

18.5 4.30( )m

2 2x y

2.50 5

3.50 7

1 5tan

7

35.5o

180 s 180 35.5 216 o o o

Page 13: Wednesday, Feb. 6, 2008 PHYS 1441-002, Spring 2008 Dr. Jaehoon Yu 1 PHYS 1441 – Section 002 Lecture #7 Wednesday, Feb. 6, 2008 Dr. Jaehoon Yu Motion in.

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Properties of Vectors• Two vectors are the same if their and the are the

same, no matter where they are on a coordinate system!!

x

y

AABB

EE

DD

CC

FF

Which ones are the same vectors?

A=B=E=DA=B=E=D

Why aren’t the others?

C:C: The same magnitude but opposite direction: C=-A:C=-A:A negative vector

F:F: The same direction but different magnitude

sizes directions

Page 14: Wednesday, Feb. 6, 2008 PHYS 1441-002, Spring 2008 Dr. Jaehoon Yu 1 PHYS 1441 – Section 002 Lecture #7 Wednesday, Feb. 6, 2008 Dr. Jaehoon Yu Motion in.

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Vector Operations• Addition:

– Triangular Method: One can add vectors by connecting the head of one vector to the tail of the other (head-to-tail)

– Parallelogram method: Connect the tails of the two vectors and extend– Addition is commutative: Changing order of operation does not affect the results

A+B=B+AA+B=B+A, A+B+C+D+E=E+C+A+B+DA+B+C+D+E=E+C+A+B+D

AA

BBAA

BB=AA

BBA+BA+B

• Subtraction: – The same as adding a negative vector:A A - B = A B = A + (-BB)

AA-B-B Since subtraction is the equivalent to adding a

negative vector, subtraction is also commutative!!!

• Multiplication by a scalar is increasing the magnitude A, BA, B=2A A

AA B=2AB=2A

AB 2

A+BA+BA+BA+B

A-BA-B

OR

Page 15: Wednesday, Feb. 6, 2008 PHYS 1441-002, Spring 2008 Dr. Jaehoon Yu 1 PHYS 1441 – Section 002 Lecture #7 Wednesday, Feb. 6, 2008 Dr. Jaehoon Yu Motion in.

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Example for Vector AdditionA car travels 20.0km due north followed by 35.0km in a direction 60.0o west of north. Find the magnitude and direction of resultant displacement.

N

E

r

r

20AA

BB

60cos

60sintan 1

BA

B

Find other

ways to solve this problem…

cos2sincos 2222 ABBA

cos222 ABBA

60cos0.350.2020.350.20 22

)(2.482325 km

60cos0.350.20

60sin0.35tan 1

N W wrt to9.385.37

3.30tan 1

Bcos

Bsin 2 2

cos sinA B B