Introduction. Cells By Mr. Lin Image Courtesy of 208%20Images/Liver%20cells.JPG.
Water moves from a region of HIGHER WATER POTENTIAL to a region of LOWER WATER POTENTIAL...
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Transcript of Water moves from a region of HIGHER WATER POTENTIAL to a region of LOWER WATER POTENTIAL...
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Water moves from a region of HIGHER WATER POTENTIAL to a region of LOWER
WATER POTENTIALhttp://www.neosci.com/demos/10-1041_cell%20processes/Presentation%20Images/tutorials/3.01.jpg
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Pressure potential ψp
= amount of pressure on the container surrounding the solution
Water is less likely to moveinto container if ψp
is high
Increasing pressure potential Ψp
increases Ψ
Ψ = pressure potential (Ψp) + solute potential (Ψs)
http://www.phschool.com/science/biology_place/labbench/lab1/watpot.html
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Ψ = pressure potential (Ψp) + solute potential (Ψs)
PLANTSWater moving into plant cell puts pressure on cell wall.
INCREASESPRESSURE POTENTIALwhich INCREASESWATER POTENTIAL
http://www.phschool.com/science/biology_place/labbench/lab1/watpot.html
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Ψ = pressure potential (Ψp) + solute potential (Ψs)
Adding solute lowers SOLUTE POTENTIAL (ALSO CALLED OSMOTIC POTENTIAL)
Makes it more _____________ Overall WATER POTENTIAL
decreases too
Water = more likely to flow toward areas with low water potential
SOLUTE SUCKS!
NEGATIVE
animation
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In open system (like beaker)pressure potential Ψp = O
In closed system (like plant cell with rigid cell wall) pressure potential Ψp can be a positive or negative number, or zero.
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SI UNITS1 Bar = 1 Atm
1 Bar = 0.1 Megapascals (Mpa)
Ψ of pure distilled water at 1 atmosphere pressure= 0 bars
http://www.neosci.com/demos/10-1041_cell%20processes/Presentation_4.html
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Ψ = pressure potential (Ψp) + solute potential (Ψs) )
PURE WATER in an OPEN CONTAINER
Water Potential Ψ = ZERO
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http://www.cetbiology.com/biology-photographs/waterpotential.jpg
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The molar concentration of a sugar solution in an open beaker has been determined to be 0.3M. Calculate the solute potential at 27 degrees. Round your answer to the nearest hundredth.Ψs = -iCRT= -(1) (0.3 mole/L) (0.0831 liter bar/mole K) (300 K)
= -7.48 bars
Now that you know the Ψs you can calculate the water potential Ψ of this beaker of liquid.
Ψ = pressure potential (Ψp) + solute potential (Ψs)
Ψ = 0 + -7.48 bars Ψ = -7.48 bars
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What is the water potential of the distilled water?
What is the water potential of the beet core?
Which way will water move?
http://www.phschool.com/science/biology_place/labbench/lab1/quiz.html
Ψ = pressure potential (Ψp) + solute potential (Ψs)Ψ = 0 + 0 = 0 bars
Ψ = 0.2 + -0.4 = -0.2 bar
From higher Ψ to lower Ψ - move from distilled (0) in beaker into beet core (-0.2)
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http://www.phschool.com/science/biology_place/labbench/lab1/quiz.html