WARM – UP #2 10/16/15 Fri HW: Pg. 146 #10, 16, 17, 23-39 odd.

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WARM – UP #2 1. /15 Fri HW: Pg. 146 #10, 16, 17, 23-39

Transcript of WARM – UP #2 10/16/15 Fri HW: Pg. 146 #10, 16, 17, 23-39 odd.

Page 1: WARM – UP #2 10/16/15 Fri HW: Pg. 146 #10, 16, 17, 23-39 odd.

WARM – UP #21.

10/16/15 Fri HW: Pg. 146 #10, 16, 17, 23-39 odd

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HOMEWORK LOG

Fri

10/16

Lesson 3 – 2

Learning Objective: To solve systems algebraically

Hw: Pg. 146 #10, 16, 17, 23-39 odd

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LESSON 3 – 2 SOLVING SYSTEMS

ALGEBRAICALLYAlgebra II

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LEARNING OBJECTIVE

To solve systems by substitution To solve systems by elimination

Because I know this!!!

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SOLUTIONS OF SYSTEMS 0 = 5 Never True!!

No Solution Parallel Lines

5 = 5 Always True!!Infinite Solutions Same Line

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SOLVE BY SUBSTITUTION Get a variable by itself in one equation (ISOLATE)

Plug into other equation to solve

Plug solved variable back into one eq’n to solve for other variable

Solution is where the two lines will intersect

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SOLVE BY SUBSTITUTION1. x – 7y = 11

+7y +7yx = 7y + 11

5(7y + 11) + 4y = - 23 35y + 55 + 4y = - 2339y = - 78y = -2

Now plug y = -2 into either equation to solve for x.

x – 7(-2) = 11x + 14 = 11x = -3

(-3, -2)

Modified/isolated version

substitute

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SOLVE BY SUBSTITUTION2. -2x + y = 3

+2x +2xy = 2x + 3

2x – (2x + 3) = - 62x – 2x – 3 = -6-3 = -6No Solution!

Lines are parallel & will never intersect!

Modified/isolated version

substitute

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SOLVE BY SUBSTITUTION3. 5x + y = -5

-5x -5xy = -5x - 5

6x + 2(-5x – 5) = -106x – 10x – 10 = -10-4x = 0x = 0

6(0) + 2y = -102y = -10y = - 5

(0, -5)

Modified/isolated version

substitute

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SOLVE BY ELIMINATION Pick one variable and get opposite coefficients (Ex: 5x & -5x)

Line up variables

Add straight down & solve

Plug solved variable back into one eq’n to solve for other variable

Solution is where the two lines will intersect

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SOLVE BY ELIMINATION4.

4x + 2(5) = 94x + 10 = 94x = -1

5y = 25y = 5

Since “x” already have opposite coefficients of 4 and -4, just add straight down

(, 5)

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SOLVE BY ELIMINATION5.

3x + 8(3) = 93x + 24 = 93x = -15x = -5

15y = 45y = 3

(-5, 3)

(2)( ) (2)

Eliminate x (try to get -6x and +6x)

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SOLVE BY ELIMINATION6.

6(2) – 5y = -812 – 5y = -8-5y = -20y = 4

2x = 4x = 2

(2, 4)

(-1)( ) (-1)

Eliminate y (try to get -5y and +5y)

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SOLVE BY ELIMINATION – JUST WATCH

Parallel Lines!

0 = -102

No Solution

(-3)( ) (-3)

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SOLVE BY ELIMINATION – JUST WATCH

Same Line!

0 = 0

Infinite Solutions

(-3)( ) (-3)

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SOLVE BY ELIMINATION7.

4() + 3y = 126 + 3y = 123y = 6y = 2

-34x = -51x =

(, 2)

(3)( ) (3)(-4( ) (-4)

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SOLVE BY ELIMINATION– JUST WATCH10.

2x + 7(2) = 42x + 14 = 42x = -10x = -5

-11y = -22y = 2

(-5, 2)

(2)( ) (2)(-3)( ) (-3)

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WORD PROBLEM11. An online photo store charges $0.15/photo plus $2.70 shipping.

A local store charges $0.25 with no shipping.

a) Write a cost eq’n for each store

b) When would it cost the same?

c) When do you use online vs. local?

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WORD PROBLEMa)

c) Use online store if more than 27 photos. Use local store if less than 27 photos.

b) 0.25x = 0.15x + 2.70 0.10x = 2.70x = 27 photos would cost both $6.75

Solve by substitution

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TICKET OUT THE DOOR You work for Alg Comp delivering packages. Alg Comp pays you a flat rate of $9.50 per hour. Geo Comp pays employees $2 per hour plus $3 per delivery. How many deliveries would Geo Comp’s employees have to make in four hours to earn the same pay you earn in a four-hour shift?

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ASSIGNMENT:

PG. 146 #10, 16, 17,23-39 ODD