Volumes of Pyramids & Cones Objectives: 1) Find the volume of a right Pyramid. 2) Find the volume of...
-
Upload
robyn-fowler -
Category
Documents
-
view
214 -
download
0
Transcript of Volumes of Pyramids & Cones Objectives: 1) Find the volume of a right Pyramid. 2) Find the volume of...
Volumes of Pyramids & Volumes of Pyramids & ConesCones
Objectives:Objectives:
1) Find the volume of a 1) Find the volume of a right right Pyramid.Pyramid.
2) Find the volume of 2) Find the volume of right right Cone.Cone.
I. Volume of a PyramidI. Volume of a Pyramid
PyramidPyramid – Is a polyhedron in which one – Is a polyhedron in which one face can be any polygon & the other faces face can be any polygon & the other faces are triangles.are triangles.
hVVpp = = ⅓Bh⅓Bh
Area of the Base
A = l•w
A = ½bh
Height of the pyramid, not to be confused with the slant height (l)
Ex.1: Volume of a right PyramidEx.1: Volume of a right Pyramid
Find the volume of a square pyramid with Find the volume of a square pyramid with base edges of 15cm & a height of 22cm.base edges of 15cm & a height of 22cm.
22cm
15cm
15cm
V = (⅓)Bh
= (⅓)l•w•h
= (⅓)15•15•22
= (⅓)4950
= 1650cm3
Square
II. Volume of a ConeII. Volume of a Cone
ConeCone – Is “pointed” like a pyramid, but its – Is “pointed” like a pyramid, but its base is a circle.base is a circle.
h
r
VVcc = = ⅓Bh⅓Bh
Area of the Base
A = r2Height of the cone, not to be confused with the slant height (l)
Ex.3: Find the volume of the following Ex.3: Find the volume of the following right cone w/ a diameter of 6in.right cone w/ a diameter of 6in.
11in V = ⅓Bh
= (⅓)r2h
= (⅓)(3)2(11)
= (⅓)99
= 33 = 103.7in3
Circle
3in
Ex.5: Solve for the missing variable.Ex.5: Solve for the missing variable.The following cone has a volume of 110The following cone has a volume of 110. .
What is its radius. What is its radius.
10cm
r
V = ⅓Bh
V = ⅓(r2)h
110 = (⅓)r2(10)
110 = (⅓)r2(10)
11 = (⅓)r2
33 = r2
r = √(33) = 5.7cm
Ex.4: Volume of a Composite FigureEx.4: Volume of a Composite Figure
8cm8cm
10cm10cm
4cm4cm
Volume of Cone first!
Vc = ⅓Bh
= (⅓)r2h
= (⅓)(8)2(10)
= (⅓)(640)
= 213.3 = 670.2cm3
Volume of Cylinder NEXT!
Vc = Bh
= r2h
= (8)2(4)
= 256 = 804.2cm3
VT = Vc + Vc
VT = 670cm3 + 804.2cm3
VT = 1474.4cm3