Estimating Temperature Rise of Transformers Orenchak G. 2004)
Volume Flow and Temperature Rise in Pumps
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Ads by Google ► Heat Pumps ► Water Pump ► Pump Pumps ► Liquid Pump Search - "Search is the most efficient way to navigate the Engineering ToolBox!" Volume Flow and Temperature Rise in Pumps Calculate temperature rise in pumps Sponsored Links Boerger Rotary Lobe Pumps boerger.com Positive Displacement, Self-Priming Rotary Lobe Pumps No pump is perfect with 100% efficiency. The energy lost in friction and hydraulic losses are transformed to heat - heating up the fluid transported through the pump. The temperature rise can be calculated as dt = P s (1 - μ) / (c p q ρ) (1) where dt = temperature rise in the pump ( o C) q = volume flow through the pump (m 3 /s) P s = brake power (kW) c p = specific heat capacity of the fluid (kJ/kg o C) μ = pump efficiency ρ = fluid density (kg/m 3 ) Typical relation between the centrifugal pump flow, efficiency and power consumption, is indicated in the figure below: Example - Temperature rise in water pump
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TEM RISE
Transcript of Volume Flow and Temperature Rise in Pumps
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Volume Flow and Temperature Rise in PumpsCalculate temperature rise in pumps
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No pump is perfect with 100% efficiency. The energy lost in friction and hydraulic losses are transformed to heat - heating up the fluid transportedthrough the pump.
The temperature rise can be calculated as
dt = Ps (1 - μ) / (cp q ρ) (1)
where
dt = temperature rise in the pump (oC)
q = volume flow through the pump (m3/s)
Ps = brake power (kW)
cp = specific heat capacity of the fluid (kJ/kgoC)
μ = pump efficiency
ρ = fluid density (kg/m3)
Typical relation between the centrifugal pump flow, efficiency and power consumption, is indicated in the figure below:
Example - Temperature rise in water pump
The temperature rise in a water pump working at normal conditions with flow 6 m3/h (0.0017 m3/s), brake power 0.11 kW and pump efficiency of 28%(0.28), can be calculated as
dt = (0.11 kW) (1 - 0.28) / ((4.2 kJ/kgoC) (0.0017 m3/s) (1000 kg/m3))
= 0.011 oC
If the flow of the pump is reduced by throttling the discharge valve, the temperature rise through the pump will increase. If the flow is reduced to 2m3/h (0.00056 m3/s), the brake power is slightly reduced to 0.095 kW and pump efficiency reduced to 15% (0.15), the temperature rise can be calculatedas
dt = (0.095 kW) (1 - 0.15) / ((4.2 kJ/kgoC) (0.00056 m3/s) (1000 kg/m3))
= 0.035 oC
With the standard documentation provided by a manufacturer it should be possible to express the temperature rise as a function of volume flow asshown in the figure below:
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