Volts per division = 2 V

Peak Voltage = 1.5 x 2 = 3 V

Volts per division = 5 mV

Volts per division = 20 V

Peak voltage = 3 x 5 = 15 mV ( 0.015 V)

Peak voltage = 1.5 x 20 = 30 V

12 V3

1.5

1.5

3

5

1. What is this meter measuring?2. What is the current going through the bulb?3. If both resistors are identical, what current is going through each?4. How would you measure the voltage across a bulb?5. What would be the voltage across each resistor?

7

1 Energy = 2kJ Time = 5 s Power = ?

2 Current = 2 A Voltage = 2V Resistance = ?

3 Current = 15 A Time = 120 s Charge = ?

4 Voltage = 12 V Current = 0.5 A Resistance

5 Charge = 13 C Time = 2 minutes Current = ?

6 Current = 25 mA Power = 1000W Voltage = ?

7 Power = 1000 W Time = 150 s Energy = ?

10

8. Find the resistance (a)10 10

10

(b)

(c) X

4 Y

12

Y

10 Ω

20 Ω20 Ω

(d)

1. P = E÷ t = 2000 ÷ 5 = 40 W 2. R = V ÷ I = 2 ÷ 2 = 1 Ω

3. Q = It = 15 x 120 = 1800 C 4. R = V ÷ I = 12 ÷ 0.5 = 24

5. I = Q ÷ t = 13 ÷ 120 = 0.11 A

6. V = P ÷ I = 1000 ÷ 0.025 = 40 000 V

7. E = Pt = 1000 x 150 = 150 000J

8. (a) Rt = R1 + R2 = 10 + 10 = 20

(b) 10 ÷ 2 = 5

(c) 1/RT = 1/R1 +1/R2 = ¼ + 1/12 = 0.25 + 0.08333= 0.333

RT = 1/0.333 = 3

(d) 1/RT = 1/R1 +1/R2 = 1/20 + 1/10 = 0.05 + 0.1= 0.15

RT = 1/0.15 = 6.7 add to series part 6.7 + 20 = 26.7 Ω