Coordinate Algebra HomeworkUnit 1: Relationships Between Quantities

04.13.2015Instructions: Show work for every, single problem on this page in order to receive credit for this assignment. Failure to show work will result in ZERO credit for the problem in question. Circling an answer will NEVER be considered work.

1. A rectangle has length of 12 m and a width of 400 cm. What is the perimeter of the rectangle?a) 824 cm b) 1600 cm c) 2000 cm d) 3200 cm

2. The tension caused by a wave moving along a string is found using the formula

. If m is the mass of the string in grams, L is the length of the string in centimeters, and v is the velocity of the wave in centimeters per second, what is the unit of the tension of the string, T ?

a. gram-centimeters per second squaredb. centimeters per second squaredc. grams per centimeter-second squaredd. centimeters squared per second

3. The distance a car travels can be found using the formula , where d is the distance, r is the rate of speed, and t is time. How many miles does the car

travel, if it drives at a speed of 70 miles per hour for hour?a. 35 miles b. 70 miles c. 105 miles d. 140 miles

4. A certain population of bacteria has an average growth rate of 0.02 bacteria per

hour. The formula for the growth of the bacteria’s population is , where is the original population, and t is the time in hours. If you begin with 200 bacteria, about how many bacteria will there be after 100 hours?a. 7 b. 272 c. 1,478 d. 20,000

5. What is the area of a circle with a circumference of 43.98226 inches?

a.. 153.44029 in.2b. 153.93791 in.2 c.. 153.9325 in.2 d. 153.9394 in.2

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Coordinate Algebra HomeworkUnit 1: Relationships Between Quantities

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Coordinate Algebra HomeworkUnit 1: Relationships Between Quantities

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Coordinate Algebra HomeworkUnit 1: Relationships Between Quantities

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Coordinate Algebra HomeworkUnit 1: Relationships Between Quantities

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1. D: 12 meters = 1200cm. Perimeter = 1200 + 1200 + 400 + 400 = 3200cm

2. A: Gram x (cm per second)2 cm = Gram-cm. per second2

3. A: 70 MPH X 0.5 hours = 35 Miles

4. C: 200 (2.71828) .02 (100) = 1478.

5. D: 2r = 43.98266. r = 7.000057749. r2 = (7.000057749)2 = 153.940 in.2

6. C: 20 ftsec x1mile5280 ft

x 3600 sechr

=13.64MPH

7. E = Total elevation. 500 = the number of feet increased per hour. 500h = the total number of feet increased for the number of hours. 4000 is the starting point of the journey (the elevation at time zero).

8. 150 + 100 + 50+ 150 + 100 + 100 = 650. $650 / 2 = $325. The value $488 for each charity is NOT reasonable.

9. Equation: y = 10 – 2x. Y is bounded by 10 and 0. X is bounded by 0 and 5. Values for x less than 0 and greater than 5 were excluded because the domain would not make sense.

10.B: Cannot have negative beats per minute. You could have zero, decimals and numbers greater than 60.

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