Version 001 – One dimensional Motion – ramadoss – (1234) 1 · 2019. 7. 12. · Motion 007...
Transcript of Version 001 – One dimensional Motion – ramadoss – (1234) 1 · 2019. 7. 12. · Motion 007...
Version 001 – One dimensional Motion – ramadoss – (1234) 1
This print-out should have 113 questions.Multiple-choice questions may continue onthe next column or page – find all choicesbefore answering.You will complete at least 80 percent of this
assignment depending on your learning needs.If you are confident of some these questions,you are allowed to skip. If you are not able tosolve any of these, it is your responsibility tosend me an email, see me or ask a friend.
Displacement and Distance001 (part 1 of 2) 10.0 points
A physics book is moved once around theperimeter of a table of dimensions 1 m by 3m.If the book ends up at its initial position,
what is the magnitude of its displacement?
1. 6 m
2. 4 m
3. 1 m
4. 7 m
5. 2 m
6. None of these
7. 0 m correct
8. 8 m
9. 5 m
10. 3 m
002 (part 2 of 2) 10.0 pointsWhat is the distance traveled?
1. 0 m
2. 2 m
3. 7 m
4. 4 m
5. 3 m
6. 6 m
7. 5 m
8. 1 m
9. 8 m correct
10. None of these
Mile Markers003 (part 1 of 2) 10.0 points
While John is traveling along an interstatehighway, he notices a 159 mi marker as hepasses through town. Later John passes a116 mi marker.What is the distance between town and
John’s current location?1. 42.02. 55.03. 40.04. 56.05. 37.06. 47.07. 52.08. 43.09. 38.010. 67.0
Correct answer: 43 mi.
004 (part 2 of 2) 10.0 pointsWhat is John’s current position?1. 100.02. 109.03. 113.04. 102.05. 120.06. 116.07. 118.08. 107.09. 111.010. 104.0
Correct answer: 116 mi.
Version 001 – One dimensional Motion – ramadoss – (1234) 2
More Mile Markers005 (part 1 of 2) 10.0 points
While John is traveling along a straight inter-state highway, he notices that the mile markerreads 242 km. John travels until he reachesthe 130 km marker and then retraces his pathto the 179 km marker.What is John’s resultant displacement from
the 242 km marker?1. -73.02. -85.03. -86.04. -88.05. -84.06. -71.07. -92.08. -54.09. -63.010. -74.0
Correct answer: −63 km.
006 (part 2 of 2) 10.0 pointsHow far has he traveled?1. 127.02. 120.03. 164.04. 111.05. 124.06. 161.07. 139.08. 108.09. 117.010. 137.0
Correct answer: 161 km.
Motion007 10.0 points
Which of the following are important in mea-suring motion?
1. distance, time, speed correct
2. velocity, acceleration, density
3. distance, volume, speed
4. acceleration, momentum, speed
Ant Race008 10.0 points
Two ants race across a table 57 cm long. Onetravels at 4.59 cm/s and the other at 3 cm/s.When the first one crosses the finish line,
how far behind is the second one?1. 35.78442. 27.92593. 9.598874. 19.74515. 25.47736. 31.6857. 32.47718. 39.05769. 38.25110. 21.7291
Correct answer: 19.7451 cm.
AP M 1998 MC 3009 10.0 points
The graph shows the velocity v as a functionof time t for an object moving in a straightline.
t
v
0 tQ t
RtS
tP
Which graph shows the corresponding dis-placement x as a function of time t for thesame time interval?
1. tx
0 tQ t
RtS
tP
2.
t
x
0 tQ t
RtS
tP
correct
Version 001 – One dimensional Motion – ramadoss – (1234) 3
3.
t
x
0 tQ t
RtS
tP
4. None of these graphs is correct.
5. tx
0 tQ t
RtS
tP
6.t
x
0 tQ t
RtS
tP
7.t
x
0 tQ t
RtS
tP
8.
t
x
0 tQ t
RtS
tP
9.tx
0 tQ t
RtS
tP
Bird and Runner010 (part 1 of 2) 10.0 points
A runner is jogging at a steady 3.6 km/hr.When the runner is 8.3 km from the finishline, a bird begins flying from the runner tothe finish line at 18 km/hr (5 times as fastas the runner). When the bird reaches thefinish line, it turns around and flies back tothe runner.
L
vb
vr
finishline
How far does the bird travel? Even thoughthe bird is a dodo, assume that it occupies
only one point in space (a “zero” length bird)and that it can turn without loss of speed.1. 4.642. 11.33333. 13.83334. 6.755. 4.333336. 7.27. 10.88. 3.159. 8.410. 6.33333
Correct answer: 13.8333 km.
011 (part 2 of 2) 10.0 pointsAfter this first encounter, the bird then turnsaround and flies from the runner back to thefinish line, turns around again and flies backto the runner. The bird repeats the back andforth trips until the runner reaches the finishline.How far does the bird travel from the be-
ginning (including the distance traveled to thefirst encounter)?1. 12.32. 14.03. 17.44. 16.85. 10.06. 33.07. 15.98. 41.59. 9.010. 12.0
Correct answer: 41.5 km.
Bug Laps012 (part 1 of 2) 10.0 points
A bug completes one lap along the edge of acircular planter of radius 13.7 cm in 17.79 s.How fast was it traveling?1. 7.279612. 6.065023. 16.24694. 4.838655. 9.709416. 11.6377
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7. 4.337078. 9.535429. 5.5236810. 15.9896
Correct answer: 4.83865 cm/s.
013 (part 2 of 2) 10.0 pointsHow fast in m/s?1. 0.1160662. 0.1204283. 0.1319674. 0.06122835. 0.04754846. 0.1396437. 0.04838658. 0.1125769. 0.072634610. 0.0745949
Correct answer: 0.0483865 m/s.
Bug Laps 02014 (part 1 of 2) 10.0 points
A bug walking on the circular rim of a flowerpot completes one lap around the planter in8.824 s.If the radius of the planter is 10.6 cm, how
fast was it traveling?1. 5.246572. 7.54783. 5.564644. 4.642945. 7.470336. 9.476117. 4.741168. 10.93819. 5.9069210. 6.82229
Correct answer: 7.5478 cm/s.
015 (part 2 of 2) 10.0 pointsHow fast in m/s?1. 0.0754782. 0.07700993. 0.04299664. 0.1020095. 0.0623791
6. 0.0676577. 0.04116978. 0.08208289. 0.055408210. 0.0465816
Correct answer: 0.075478 m/s.
Cars Leaving School016 (part 1 of 4) 10.0 points
Both car A and car B leave school at the sametime, traveling in the same direction. Car Atravels at a constant speed of 78 km/h, whilecar B travels at a constant speed of 89 km/h.How far is Car A from school 3 h later?1. 260.72. 197.53. 244.84. 134.35. 250.86. 138.77. 248.08. 165.09. 234.010. 170.4
Correct answer: 234 km.
017 (part 2 of 4) 10.0 pointsHow far is car B from school 3 h later?1. 160.22. 156.63. 186.04. 176.05. 154.86. 225.67. 269.78. 249.29. 300.310. 267.0
Correct answer: 267 km.
018 (part 3 of 4) 10.0 pointsHow long does it take car A to reach a gasstation a distance 211 km from the school?1. 2.169012. 3.088613. 3.18667
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4. 2.6255. 2.316466. 2.987017. 3.58. 2.457149. 2.7051310. 2.34177
Correct answer: 2.70513 h.
019 (part 4 of 4) 10.0 pointsHow long does it take car B to reach the gasstation?1. 1.677422. 1.730343. 1.806454. 1.968095. 2.559146. 1.941867. 2.613648. 2.370799. 2.0543510. 2.82759
Correct answer: 2.37079 h.
Constant Velocity 01020 10.0 points
At 1:00 p.m. a car, traveling at a constantvelocity of 78 km/h toward the west, is 16 kmto the west of our school.How far from the school will it be at 3:30
p.m.?1. 230.02. 243.03. 222.04. 211.05. 260.06. 240.57. 278.58. 214.09. 256.510. 234.0
Correct answer: 211 km.
Displacement Curve 02021 (part 1 of 2) 10.0 points
Consider a moving object whose position x
is plotted as a function of the time t. Theobject moved in different ways during thetime intervals denoted I, II and III on thefigure.
2 4 6
2
4
6
t
x
I II III
During these three intervals, when was theobject’s speed highest? Do not confuse thespeed with the velocity.
1. During interval II
2. During interval III correct
3. During interval I
4. Same speed during intervals II and III
5. Same speed during each of the three in-tervals.
022 (part 2 of 2) 10.0 pointsDuring which interval(s) did the object’s ve-locity remain constant?
1. During interval I only
2. During interval III only
3. During each of the three intervals cor-rect
4. During interval II only
5. During none of the three intervals
Displacement vs Time 04023 (part 1 of 2) 10.0 points
Consider the following graph
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0 2 4 6 8 10 12 14 16 18 20−10
−8
−6
−4
−2
0
2
4
6
8
10
displacement(m
)
time (s)
Displacement vs Time
What is the displacement at 10 s?
1. 2 m
2. Unable to determine
3. −3 m
4. None of these
5. 0 m
6. −1 m
7. −4 m correct
8. 1 m
9. 3 m
10. −2 m
024 (part 2 of 2) 10.0 pointsWhat is the velocity at 10 s?
1. −2 m/s
2. −1 m/s
3. 0 m/s correct
4. 3 m/s
5. 2 m/s
6. −3 m/s
7. None of these
8. 1 m/s
9. Unable to determine
10. 4 m/s
Distance Time Graph 01 short025 (part 1 of 3) 10.0 points
Consider the following graph of motion.
0 1 2 3 4 50
10
20
30
40
50
Time (sec)
Dis
tanc
e (m
)How far did the object travel between 2 s
and 4 s?
1. 50 m
2. 20 m correct
3. 30 m
4. 10 m
5. 40 m
026 (part 2 of 3) 10.0 pointsThe graph indicates
1. constant position.
2. constant velocity. correct
3. increasing velocity.
4. no motion.
Version 001 – One dimensional Motion – ramadoss – (1234) 7
5. decreasing velocity.
027 (part 3 of 3) 10.0 pointsWhat is the speed from 2 s to 4 s?
1. 0 m/s
2. 20 m/s
3. 5 m/s
4. 10 m/s correct
5. 15 m/s
Distance Time Graph 02028 (part 1 of 3) 10.0 points
Consider the following graph of motion.
0 1 2 3 40
10
20
30
Time (hr)
Dis
tanc
e (k
m)
What distance was covered in the first 3hours?
1. 30 km
2. 20 km
3. 5 km
4. 10 km
5. 15 km correct
6. 25 km
029 (part 2 of 3) 10.0 pointsThe graph indicates
1. constant velocity.
2. changing velocity. correct
3. constant position.
4. no motion.
5. no acceleration.
030 (part 3 of 3) 10.0 pointsConsider the following graph of motion.
0 1 2 3 4 5 6 7 8 90
50
100
150
200
250
300
350
400
Time (sec)
Dis
tanc
e (m
)
The distance is
1. increasing.
2. decreasing. correct
3. constant.
Earthquake Transverse Waves031 10.0 points
The velocity of the transverse waves producedby an earthquake is 4.64 km/s, while that ofthe longitudinal waves is 8.0736 km/s. A seis-mograph records the arrival of the transversewaves 76.8 s after that of the longitudinalwaves.How far away was the earthquake?1. 671.3992. 464.6873. 709.4654. 421.2425. 897.9476. 1103.217. 812.8898. 837.9099. 587.15610. 743.937
Correct answer: 837.909 km.
Glacier Movement032 (part 1 of 2) 10.0 points
A glacier advances at 5.9× 10−6 cm/s.
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How far will it move in 38000 s?1. 0.5762. 0.30783. 0.22424. 0.20525. 0.2526. 0.18047. 0.16348. 0.299. 0.415810. 0.4575
Correct answer: 0.2242 cm.
033 (part 2 of 2) 10.0 pointsHow far will it move in 3.8 y?1. 618.1062. 728.4823. 1097.454. 707.0375. 807.3226. 629.1437. 1251.358. 1174.099. 781.46210. 1311.27
Correct answer: 707.037 cm.
Graphical Analysis 01034 (part 1 of 7) 10.0 points
Consider the following graph of motion.
0 10 20 30 40 500
20
40
60
80
100
Time (sec)
Dis
tanc
e (m
)
Swimmer
1
Swimmer 2
How many meters can Swimmer 1 cover in30 seconds?
1. 50 m
2. 70 m
3. 30 m
4. 40 m
5. 90 m
6. 100 m
7. 20 m
8. 80 m
9. 60 m correct
10. 10 m
035 (part 2 of 7) 10.0 pointsHow far can Swimmer 2 cover in 30 seconds?
1. 40 m
2. 90 m
3. 70 m
4. 80 m
5. 30 m correct
6. 20 m
7. 50 m
8. 100 m
9. 10 m
10. 60 m
036 (part 3 of 7) 10.0 pointsPredict the distance Swimmer 1 can go in 60seconds.
1. 90 m
2. 80 m
3. 120 m correct
4. 50 m
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5. 70 m
6. 40 m
7. 130 m
8. 110 m
9. 100 m
10. 60 m
037 (part 4 of 7) 10.0 pointsPredict the distance Swimmer 2 can go in 60seconds.
1. 110 m
2. 130 m
3. 80 m
4. 40 m
5. 120 m
6. 100 m
7. 70 m
8. 50 m
9. 60 m correct
10. 90 m
038 (part 5 of 7) 10.0 pointsWhich swimmer has the greatest speed?
1. Unable to determine.
2. The speeds are the same.
3. Swimmer 1 correct
4. Swimmer 2
039 (part 6 of 7) 10.0 points
What is the speed of Swimmer 1?
1. None of these
2. 4 m/s
3. 1 m/s
4. 6 m/s
5. 8 m/s
6. 5 m/s
7. 3 m/s
8. 7 m/s
9. 2 m/s correct
040 (part 7 of 7) 10.0 pointsWhat is the speed of Swimmer 2?
1. 4 m/s
2. 8 m/s
3. 3 m/s
4. 6 m/s
5. 2 m/s
6. None of these
7. 7 m/s
8. 1 m/s correct
9. 5 m/s
Hewitt CP9 03 E01041 10.0 points
What is the impact speed when a car mov-ing at 200 km/h bumps into the rear of an-other car traveling in the same direction at87 km/h?1. 107.02. 230.0
Version 001 – One dimensional Motion – ramadoss – (1234) 10
3. 218.04. 113.05. 115.06. 40.07. 35.08. 30.09. 16.010. 18.0
Correct answer: 113 km/h.
Average Speed042 10.0 points
A car is moving at a constant speed of 15 m/swhen the driver presses down on the gas pedaland accelerates for 14 s with an accelerationof 1.8 m/s2.What is the average speed of the car during
the period?1. 18.252. 22.63. 27.64. 23.95. 21.66. 23.257. 23.08. 20.259. 19.2510. 26.9
Correct answer: 27.6 m/s.
Average Speed 04043 10.0 points
On a drive from your home to town, you wishto average 48 mph. The distance from yourhome to town is 94miles. However, at 47 miles(half way), you find you have averaged only36 mph.What average speed must you maintain in
the remaining distance in order to have anoverall average speed of 48 mph?1. 56.42. 96.03. 55.24. 49.85. 66.06. 78.07. 90.0
8. 72.09. 84.010. 50.4
Correct answer: 72 mph.
Average Speed on a Trip044 (part 1 of 2) 10.0 points
A person travels by car from one city to an-other. She drives for 29.7 min at 73.7 km/h,14.7 min at 110 km/h, 35.1 min at 31.7 km/h,and spends 17.8 min along the way eatinglunch and buying gas.Determine the distance between the cities
along this route.1. 75.77082. 77.33723. 104.1184. 81.9765. 83.3936. 79.6057. 100.2558. 94.58859. 71.486510. 92.0482
Correct answer: 81.976 km.
045 (part 2 of 2) 10.0 pointsDetermine the average speed for the trip.1. 42.39442. 60.04863. 44.31424. 51.41145. 50.55056. 53.03977. 53.74548. 55.68279. 49.148110. 47.6264
Correct answer: 50.5505 km/h.
Average Velocity on a Trip046 10.0 points
A car travels along a straight stretch of road.It proceeds for 10.4 mi at 53 mi/h, then 26 miat 47 mi/h, and finally 32.7 mi at 30.4 mi/h.What is the car’s average velocity during
Version 001 – One dimensional Motion – ramadoss – (1234) 11
the entire trip?1. 41.69442. 39.09893. 43.45084. 44.22585. 35.7776. 44.83527. 37.86148. 40.66869. 38.687710. 40.1034
Correct answer: 37.8614 mi/h.
Car and Checkpoints 01 v1047 10.0 points
Consider a car which is traveling along astraight road with constant acceleration a.There are two checkpoints A and B which area distance 101 m apart. The time it takes forthe car to travel from A to B is 5.82 s.
A B
5.83 m/s2
101 m
Find the velocity vB for the case where theacceleration is 5.83 m/s2.1. 31.20792. 31.7673. 38.34624. 34.31935. 40.52136. 35.43757. 36.8388. 24.5319. 38.888210. 39.8525
Correct answer: 34.3193 m/s.
Car and Checkpoints 02048 (part 1 of 2) 10.0 points
Consider a car which is traveling alonga straight road with constant acceleration7.5 m/s2 . There are two checkpoints A and Bwhich are a distance 95.1 m apart. The timeit takes for the car to travel from A to B is4.71 s .
A B
7.5 m/s2
95.1 m
Find the velocity difference, ∆v = vB − vAbetween the two checkpoints.1. 32.38322. 21.67123. 42.41934. 22.67375. 35.3256. 24.25927. 20.03288. 31.95719. 29.667210. 12.8934
Correct answer: 35.325 m/s.
049 (part 2 of 2) 10.0 pointsFind the velocity vB .1. 35.59512. 34.69453. 37.85364. 30.97995. 40.28916. 24.1957. 24.86288. 28.90159. 32.81810. 31.4717
Correct answer: 37.8536 m/s.
Average and Instantaneous V050 (part 1 of 2) 10.0 points
The position versus time for a certain objectmoving along the x-axis is shown. The ob-ject’s initial position is −7 m.
Version 001 – One dimensional Motion – ramadoss – (1234) 12
−10
−8
−6
−4
−2
0
2
4
6
0 1 2 3 4 5 6 7 8 9
b
b
b b
b
b
time (s)
position(m
)
Find the instantaneous velocity at 6.5 s.1. -3.52. -5.03. -2.666674. -12.05. -4.56. -7.57. -3.666678. -8.09. -4.010. -7.0
Correct answer: −3.66667 m/s.
051 (part 2 of 2) 10.0 pointsFind the average velocity over the whole timeshown.1. 0.7777782. 0.6666673. 1.111114. 1.05. 0.8888896. 1.222227. 0.1111118. 1.333339. 0.55555610. -0.111111
Correct answer: 0.888889 m/s.
Calc Practice 03052 10.0 points
Suppose the position equation for a moving
object is given by
s(t) = 3 t2 + 2 t+ 5
where s is measured in meters and t is mea-sured in seconds.Find the velocity of the object when t = 2.
1. 14 m/sec correct
2. 6 m/sec
3. 13 m/sec
4. None of these
5. 10 m/sec
Calc Practice 05053 (part 1 of 3) 10.0 points
A particle moves along the x-axis so thatits velocity at any time t ≥ 0 is given byv(t) = 3t2 − 2t− 1. The position x(t) is 5 fort = 2.Find a polynomial expression for the posi-
tion of the particle at any time t ≥ 0.
1. t3 + t2 + 6t+ 3
2. t3 − t2 − t+ 3 correct
3. t3 + t2 − 3t+ 3
4. 2t3 − t2 − t− 3
5. 3t3 − 2t2 − t+ 3
054 (part 2 of 3) 10.0 pointsFor what values of t, 0 ≤ t ≤ 3, is the par-ticle’s instantaneous velocity the same as itsaverage velocity on the closed interval [0, 3]?
1. 2.813
2. 3.798
3. 3.296
4. 2.917
5. 1.786 correct
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055 (part 3 of 3) 10.0 pointsFind the total distance traveled by the parti-cle from time t = 0 until time t = 3.
1. 17 correct
2. 18
3. 15
4. 14
5. 16
Calc Practice 07056 10.0 points
A particle moves in a straight line with veloc-ity
v(t) = 3t2 − 6t.
If it initially starts moving from 0 (wherex = 0), what is its position x(t)?
1. x(t) = t3 − 3t2 + 1
2. x(t) = 6t
3. x(t) = 6t− 6
4. x(t) = 6t− 3t2
5. x(t) = t3 − 3t2 correct
Displacement vs Time 02057 (part 1 of 5) 10.0 points
Consider the displacement curve OABC
0 1 2−2
−1
0
1
2
x(m
)
t (s)
Displacement vs Time
O
A
B
C
What is the average velocity from point Oto A?
1. vOA
= +√3 m/s
2. vOA
= +2 m/s correct
3. vOA
= −√3 m/s
4. vOA
= 0 m/s
5. vOA
= −2 m/s
058 (part 2 of 5) 10.0 pointsWhat is the average velocity for the motionfrom point O to point B?
1. vOB
= −√3 m/s
2. vOB
= −2 m/s
3. vOB
= +2 m/s
4. vOB
= 0 m/s correct
5. vOB
= +√3 m/s
059 (part 3 of 5) 10.0 pointsWhat is the average speed for the motion frompoint O to point B?
1. sOB
= −2 m/s
Version 001 – One dimensional Motion – ramadoss – (1234) 14
2. sOB
= +√3 m/s
3. sOB
= −√3 m/s
4. sOB
= +2 m/s correct
5. sOB
= 0 m/s
060 (part 4 of 5) 10.0 pointsWhat is the instantaneous velocity at pointB?
1. vB= 0 m/s
2. vB= −
√3 m/s
3. vB= +2 m/s
4. vB= +
√3 m/s
5. vB= −2 m/s correct
061 (part 5 of 5) 10.0 pointsWhat is the instantaneous speed at point B?
1. sB= −2 m/s
2. sB= +2 m/s correct
3. sB= +
√3 m/s
4. sB= 0
5. sB= −
√3 m/s
Displacement vs Time 03062 (part 1 of 5) 10.0 points
Consider the displacement curve OABC
0 1 2 3 4 5−2
−1
0
1
2
x(m
)
t (s)
Displacement vs Time
O
A
B
C
What is the average velocity from point Oto A?
1. vOA
= +1.33 m/s
2. vOA
= −1.0 m/s
3. vOA
= −2.0 m/s
4. vOA
= +1.0 m/s
5. vOA
= 0 m/s
6. vOA
= −1.33 m/s
7. vOA
= +2.0 m/s correct
063 (part 2 of 5) 10.0 pointsWhat is the average velocity for the motionfrom point O to point B?
1. vOA
= +1.0 m/s
2. vOA
= +2.0 m/s
3. vOA
= −1.0 m/s
4. vOA
= −1.33 m/s
5. vOA
= 0 m/s correct
6. vOA
= +1.33 m/s
Version 001 – One dimensional Motion – ramadoss – (1234) 15
7. vOA
= −2.0 m/s
064 (part 3 of 5) 10.0 pointsWhat is the average speed for the motion frompoint O to point B?
1. sOB
= 0 m/s
2. sOB
= +1.0 m/s
3. sOB
= +1.33 m/s correct
4. sOB
= +2.0 m/s
5. sOB
= −1.33 m/s
6. sOB
= −2.0 m/s
7. sOB
= −1.0 m/s
065 (part 4 of 5) 10.0 pointsWhat is the instantaneous velocity at pointB?
1. vB= +1.0 m/s
2. vB= +1.33 m/s
3. vB= −2.0 m/s
4. vB= 0 m/s
5. vB= −1.0 m/s correct
6. vB= −1.33 m/s
7. vB= +2.0 m/s
066 (part 5 of 5) 10.0 pointsWhat is the instantaneous speed at point B?
1. sB= −2.0 m/s
2. sB= 0 m/s
3. sB= +1.0 m/s correct
4. sB= +2.0 m/s
5. sB= −1.33 m/s
6. sB= −1.0 m/s
7. sB= +1.33 m/s
Serway CP 02 16067 (part 1 of 3) 10.0 points
A race car moves such that its position fitsthe relationship
x(t) = (5.4 m/s) t+ (0.98 m/s3) t3
where x is measured in meters and t in sec-onds.Approximate the instantaneous velocity at
2.6 s, using a centered time interval of 0.1 s.1. 26.82562. 11.65643. 37.29024. 22.58875. 38.32326. 9.907957. 10.58898. 9.151679. 25.276810. 36.8066
Correct answer: 25.2768 m/s.
068 (part 2 of 3) 10.0 pointsUse a 0.2 s interval centered at 2.6 s to ap-proximate the instantaneous velocity at 2.6 s.1. 45.05362. 10.10523. 10.63764. 10.49385. 35.29326. 18.79567. 9.96068. 27.4889. 5.899310. 25.2842
Correct answer: 25.2842 m/s.
069 (part 3 of 3) 10.0 pointsFind the average velocity during the 2.6 s.1. 7.212. 12.0248
Version 001 – One dimensional Motion – ramadoss – (1234) 16
3. 8.25284. 14.31995. 13.61786. 5.6257. 12.86858. 10.6489. 7.646410. 14.704
Correct answer: 12.0248 m/s.
Serway CP 02 15070 (part 1 of 4) 10.0 points
The position versus time for a certain objectmoving along the x-axis is shown. The ob-ject’s initial position is −4 m.
−6
−4
−2
0
2
4
6
8
0 1 2 3 4 5 6 7 8 9
b
b
b b
b
b
time (s)
position(m
)
Find the instantaneous velocity at 0.5 s.1. 5.02. 11.03. 10.04. 7.05. 6.06. 12.07. 8.08. 4.09. 6.510. 3.5
Correct answer: 10 m/s.
071 (part 2 of 4) 10.0 pointsFind the instantaneous velocity at 2.5 s.1. -1.333332. -0.6666673. -5.0
4. -2.05. -2.56. -1.666677. -1.58. -4.09. -3.010. -1.0
Correct answer: −1 m/s.
072 (part 3 of 4) 10.0 pointsFind the instantaneous velocity at 4.5 s.
Correct answer: 0 m/s.
073 (part 4 of 4) 10.0 pointsFind the instantaneous velocity at 8 s.
Correct answer: 1.5 m/s.
Accelerating Object074 10.0 points
If the acceleration of an object is zero at someinstant in time, what can be said about itsvelocity at that time?
1. It is positive.
2. It is zero.
3. Unable to determine.
4. It is negative.
5. It is not changing at that time. correct
Acceleration075 10.0 points
A car travels in a straight line for 3.1 h at aconstant speed of 59 km/h .What is its acceleration?
Correct answer: 0 m/s2.
Acceleration vs Time 01076 (part 1 of 4) 10.0 points
Consider the plot below describing the accel-eration of a particle along a straight line withan initial position of 43 m and an initial ve-
Version 001 – One dimensional Motion – ramadoss – (1234) 17
locity of 9 m/s.
−1
0
1
2
3
4
5
6
0 1 2 3 4 5 6 7 8 9
time (s)
acceleration(m
/s2)
What is the velocity at 1 s?1. 5.02. 15.03. 9.04. 28.05. 21.06. -39.07. 22.08. 2.09. 14.010. 33.0
Correct answer: 14 m/s.
077 (part 2 of 4) 10.0 pointsWhat is the position at 1 s?1. -37.52. 36.03. 9.54. 2.05. -68.06. 54.57. 6.08. -31.09. -34.010. -18.5
Correct answer: 54.5 m.
078 (part 3 of 4) 10.0 pointsWhat is the velocity at 6 s?1. -18.02. -43.03. 34.0
4. 54.05. -5.06. 3.07. -23.08. -9.09. 24.010. 19.0
Correct answer: 34 m/s.
079 (part 4 of 4) 10.0 pointsWhat is the position at 6 s?1. -35.02. -60.03. -208.54. -4.55. 72.06. 117.07. 126.08. 47.59. -49.510. 184.5
Correct answer: 184.5 m.
Acceleration Time Graph 02080 10.0 points
Consider a toy car which moves to the right(positive direction) on a horizontal surfacealong a straight line.
carv
O +
Which acceleration-time graph correspondsto the motion of the car if it moves toward theright, while slowing down at a steady rate.
1. t
a
correct
Version 001 – One dimensional Motion – ramadoss – (1234) 18
2. t
a
3. None of these graphs is correct.
4. t
a
5. t
a
6. t
a
7. t
a
8. t
a
Antilock Brakes081 10.0 points
The following acceleration vs time plots showdata gathered from an automobile fitted withan accelerometer. In each case the driver ac-celerated to cruising speed and then slammedon the brakes. In one case the car is equippedwith an antilock braking system (ABS), whilein the other the car is not. ABS tends toprevent skidding and did just that in this ex-
periment, allowing a more rapid deceleration.
0 2 4 6 8 10Time (seconds)
0
0 2 4 6 8 10Time (seconds)
0
A
A
Which data set, the upper or lower, morelikely came from the car equipped with ABS,and why?
1. Lower case, because of data between 2.5and 6.5 seconds
2. Upper case, because of data between 6.5and 9 seconds correct
3. Lower case, because of data in the first2.5 seconds
4. Upper case, because of data between 9and 10 seconds
5. Upper case, because of data between 2.5and 6.5 seconds
6. Lower case, because of data between 6.5and 9 seconds
7. Upper case, because of data in the first2.5 seconds
8. Lower case, because of data between 9and 10 seconds
Version 001 – One dimensional Motion – ramadoss – (1234) 19
Acceleration Time Graph 01082 (part 1 of 5) 10.0 points
Consider a toy car which can move to theright (positive direction) or left on a horizon-tal surface along a straight line.
car
v
O +
What is the acceleration-time graph if thecar moves toward the right (away from theorigin), speeding up at a steady rate?
1. t
a
correct
2. t
a
3. None of these graphs is correct.
4. t
a
5. t
a
6. t
a
7. t
a
8. t
a
083 (part 2 of 5) 10.0 pointsWhat is the acceleration-time graph if the carmoves toward the right, slowing down at asteady rate?
1. t
a
2. t
a
3. t
a
4. None of these graphs is correct.
Version 001 – One dimensional Motion – ramadoss – (1234) 20
5. t
a
6. t
a
correct
7. t
a
8. t
a
084 (part 3 of 5) 10.0 pointsWhat is the acceleration-time graph if the carmoves towards the left (toward the origin) ata constant velocity?
1. t
a
2. t
a
correct
3. t
a
4. t
a
5. t
a
6. t
a
7. None of these graphs is correct.
8. t
a
085 (part 4 of 5) 10.0 pointsWhat is the acceleration-time graph if the carmoves toward the left, speeding up at a steadyrate?
1. t
a
Version 001 – One dimensional Motion – ramadoss – (1234) 21
2. t
a
correct
3. t
a
4. None of these graphs is correct.
5. t
a
6. t
a
7. t
a
8. t
a
086 (part 5 of 5) 10.0 pointsWhat is the acceleration-time graph if the carmoves toward the right at a constant velocity?
1. t
a
2. t
a
3. t
a
4. t
a
5. None of these graphs is correct.
6. t
a
7. t
a
8. t
a
correct
Average Acceleration087 10.0 points
Version 001 – One dimensional Motion – ramadoss – (1234) 22
An object travels 7 m in the first second oftravel, 7 m again during the second second oftravel, and 7 m again during the third second,all in the same direction.What is the approximate average accelera-
tion of the object during this time interval?
1. 8 m/s2
2. 6 m/s2
3. 5 m/s2
4. 0 m/s2 correct
5. 7 m/s2
6. 3 m/s2
7. 9 m/s2
8. 4 m/s2
9. Unable to determine
Holt SF 02C 01088 10.0 points
A car accelerates uniformly from rest to aspeed of 23.9 km/h in 4.7 s.Find the distance it travels during this time.1. 19.71252. 15.83333. 24.9754. 15.60145. 20.32226. 14.8757. 17.34038. 22.48339. 20.533310. 21.3097
Correct answer: 15.6014 m.
Holt SF 02C 02089 10.0 points
When Maggie applies the brakes of her car,the car slows uniformly from 14.7 m/s to 0m/s in 2.36 s.How far ahead of a stop sign must she apply
her brakes in order to stop at the sign?1. 17.3462. 18.4223. 17.13854. 16.0365. 18.76156. 17.7847. 15.3018. 16.5369. 16.774510. 19.422
Correct answer: 17.346 m.
Holt SF 02C 03090 10.0 points
A jet plane lands with a speed of 120 m/s andcan decelerate uniformly at a maximum rateof 5.1 m/s2 as it comes to rest.Can this plane land at an airport where
the runway is 0.85 km long? Answer this bycalculating.1. 1.12. 1.51253. 1.475614. 1.315225. 1.06146. 1.041677. 1.263168. 1.411769. 1.756110. 1.21
Correct answer: 1.41176 km.
Holt SF 02C 04091 10.0 points
A driver in a car traveling at a speed of67 km/h sees a cat 124 m away on the road.How long will it take for the car to acceler-
ate uniformly to a stop in exactly 120 m?1. 10.49142. 11.7123. 10.75074. 9.378955. 12.3136. 10.33857. 10.96128. 12.6
Version 001 – One dimensional Motion – ramadoss – (1234) 23
9. 12.104310. 12.8955
Correct answer: 12.8955 s.
Holt SF 02C 05092 10.0 points
A car enters the freeway with a speed of 6.3m/s and accelerates uniformly for 3.2 km in2.9 min.How fast is the car moving after this time?1. 18.26192. 14.70543. 22.00744. 18.85765. 29.28526. 34.82567. 30.48168. 30.03229. 27.823810. 23.0474
Correct answer: 30.4816 m/s.
Holt SF 02D 01093 (part 1 of 2) 10.0 points
A car with an initial speed of 23.1 km/h ac-celerates at a uniform rate of 0.99 m/s2 for 3.6s.Find the final speed of the car.1. 9.223562. 10.87173. 9.401674. 10.6155. 10.16. 8.437117. 9.105118. 9.655339. 9.8166710. 9.98067
Correct answer: 9.98067 m/s.
094 (part 2 of 2) 10.0 pointsFind the displacement of the car after thattime.1. 0.02631052. 0.03837163. 0.0200911
4. 0.02983355. 0.03197786. 0.02808657. 0.02951528. 0.02421629. 0.025992510. 0.0377295
Correct answer: 0.0295152 km.
Particle Collision095 10.0 points
This time particle A starts from rest and ac-celerates to the right at 63.2 cm/s2. ParticleB starts 386 cm down the track and moves ata constant velocity of 50.8 cm/s to the left.When will they meet?1. 2.572512. 2.738853. 2.782474. 2.693815. 2.529976. 2.652587. 2.620068. 2.927379. 2.8162710. 2.87385
Correct answer: 2.78247 s.
Paths Cross096 10.0 points
Runner A is initially 4.4 mi west of a flagpoleand is running with a constant velocity of5.9 mi/h due east. Runner B is initially 3.9 mieast of the flagpole and is running with aconstant velocity of 5.7 mi/h due west.How far are the runners from the flagpole
when they meet?1. 0.02. 0.08753. 0.1784484. 0.2309095. 0.05853666. 0.03035717. 0.520878. 0.2752149. 0.12711910. 0.504348
Version 001 – One dimensional Motion – ramadoss – (1234) 24
Correct answer: 0.178448 mi.
Speedboat097 (part 1 of 2) 10.0 points
A speedboat increases in speed from 18.9 m/sto 31.4 m/s in a distance 193 m.Find the magnitude of its acceleration.1. 1.284672. 1.271153. 1.628894. 1.758075. 1.604216. 1.028717. 1.510418. 1.218099. 1.980810. 0.997009
Correct answer: 1.62889 m/s2.
098 (part 2 of 2) 10.0 pointsFind the time it takes the boat to travel thisdistance.1. 6.804122. 7.380073. 8.223944. 9.511115. 7.673966. 7.023177. 8.662428. 7.821019. 7.2138210. 7.5514
Correct answer: 7.67396 s.
Stopping car099 10.0 points
At time t = 0 a car moving along a straightline has a velocity of 16 m/s. It slows downwith a constant acceleration of −0.5 m/s2. Itstops at t =
1. 4 s
2. 32 s correct
3. 64 s
4. 16 s
5. 8 s
A Ball Hits the Ground100 (part 1 of 2) 10.0 points
A ball is dropped from the top of a tall build-ing of height h = 50 m .About how long does it take for the ball to
hit the ground? (Neglect air resistance.)
1. 5.2 s
2. 1 s
3. 3.1 s correct
4. 10 s
5. 2.4 s
101 (part 2 of 2) 10.0 pointsIf the ball has lost half the magnitude of itsimpact momentum immediately after it re-coils, to what height does the ball reach afterits first rebound?
1.h
4correct
2.h
2
3. 0
4.h
3
5. h
Acceleration 24102 10.0 points
If you drop an object, it will accelerate down-ward at a rate of g = 9.8 m/s2.If you throw it downward instead, its accel-
eration (in the absence of air resistance) willbe
1. Unable to determine.
Version 001 – One dimensional Motion – ramadoss – (1234) 25
2. greater than 9.8 m/s2.
3. less than 9.8 m/s2.
4. 9.8 m/s2 correct
Acceleration at the Top103 10.0 points
A stone is thrown straight upward and at thetop of its trajectory its velocity is momentar-ily zero.
What is its acceleration at this point?
1. Unable to determine
2. 9.8 m/s2 up
3. Zero
4. 9.8 m/s2 down correct
Air Jordan104 10.0 points
A basketball player achieves a hang time of0.562 s in dunking the ball.What vertical height will he attain? The
acceleration of gravity is 9.8 m/s2 .1. 1.29962. 0.9856463. 0.8216824. 0.3869095. 0.4986296. 1.648367. 1.171698. 1.005529. 0.4846610. 1.4025
Correct answer: 0.386909 m.
AP B 1993 MC 5105 10.0 points
An object is released from rest on a planetthat has no atmosphere. The object fallsfreely for 3 m in the first second.What is the magnitude of the acceleration
due to gravity on the planet?
1. 1.5 m/s2
2. 12.0 m/s2
3. 10.0 m/s2
4. 6.0 m/s2 correct
5. 3.0 m/s2
AP M 1993 MC 1106 10.0 points
In the absence of air friction, an objectdropped near the surface of the Earth ex-periences a constant acceleration of about 9.8m/s2.This means that the
1. speed of the object as it falls is 9.8 m/s.
2. speed of the object increases 9.8 m/s dur-ing each second. correct
3. object falls 9.8 meters during the firstsecond only.
4. derivative of the distance with respect totime for the object equals 9.8 m/s2.
5. object falls 9.8 meters during each sec-ond.
AP M 1993 MC 19107 10.0 points
An object is shot vertically upward into theair with a positive initial velocity.What correctly describes the velocity and
acceleration of the object at its maximumelevation?
Version 001 – One dimensional Motion – ramadoss – (1234) 26
Velocity Acceleration
1. positive negative
2. zero negative correct
3. zero zero
4. negative negative
5. positive positive
Average Speed of a Fall108 10.0 points
A ball is released from rest and falls a distanceh under the influence of gravity.What is its average speed during the fall?
1.1
2
√
g h
2. 2√
g h
3. 0
4.√
g h
5.√
2 g h
6.
√
1
2g h correct
Approaching Cars109 (part 1 of 3) 10.0 points
Two cars approach each other; both cars aremoving westward, one at 70 km/h, the otherat 65 km/h.What is the magnitude of the velocity of the
first car relative to (in the frame of referenceof) the second car?1. 26.02. 22.03. 18.04. 16.05. 8.06. 5.07. 19.08. 6.09. 24.010. 15.0
Correct answer: 5 km/h.
110 (part 2 of 3) 10.0 pointsWhat is the direction of the resultant veloc-ity?
1. Westward correct
2. Unable to determine.
3. Eastward
111 (part 3 of 3) 10.0 pointsAfter they pass, how will their relative veloc-ity change?
1. No change correct
2. Greater than before
3. Less than before
4. Unable to determine
Motion 03112 10.0 points
Motion is
1. the stopping of an object relative to aframe of reference.
2. a change in position relative to a frame ofreference. correct
3. a decrease in the speed of an object.
4. an increase in the speed of an object.
Motion 11113 10.0 points
The most common frame of reference is
1. the sky.
2. the object you are observing.
3. you.
Version 001 – One dimensional Motion – ramadoss – (1234) 27
4. the Earth. correct