Uniform Circular Motion
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Transcript of Uniform Circular Motion
Uniform Circular Motion
Basic Principles & Formulas
Uniform Circular Motion Principles
Object moves at a constant speed (speed = scalar quantity)
Object’s velocity is constantly changing (velocity = vector quantity) due to a continuous change in direction
Velocity is tangent to circular motion While in motion, there is a force and an
acceleration being applied to the object
Uniform Circular Motion Terms & Formulas
Period (T) = time it takes to make 1 revolution (time to travel circumference).
Period may be given, obvious or determined by time/revolutions ex. 25 rev. in 10 sec. T = 10/25 .4 sec (T = 1/f)
Frequency (f) = number of revolutions made in 1 sec. (f = 1/T) units = Hz(Period & Frequency are Inversely Related)
Uniform Circular Motion Diagram
Acceleration & Force = Parallel to Radius / Velocity = Perpendicular to Radius
r
v
F
a
Uniform Circular Motion Questions
Q = While moving in a circular path, if string breaks, in what direction will the object travel?
A = In a straight line, perp. to radius (Law of Inertia; resistance to change)
Q = In what direction is the force?A = InwardQ = In what direction is the acceleration?A = Inward
Uniform Circular Motion Terms & Formulas
Velocity (v) = d or 2πr
t T
Acceleration (a) = v²
r
circumference
Time to travel around circumference once
Uniform Circular Motion Terms & Formulas
Force (F) = ma
or
mv²
r
Remember, mass must be in Kg!
UCM Example Problem
A 615 kg race car completes 1.00 lap in 14.3 sec around a circular track with a radius of 50.0 m. What is the car’s T, f, v, a, F (on tires)?
T = 14.3/1.00
= 14.3f = 1.00/14.3
= 0.0699 Hz
UCM Example Problem (cont.)
V = (2)(π)(50.0)
14.3
= 22.0 m/sa = (22.0 m/s)²
50.0
= 9.68 m/s²
UCM Example Problem (cont.)
F (on tires) = (615 kg)(22.0 m/s)²
50.0 m
= 5,950 N