Ultimate Check of Shear
1
t/m' 4 WU (t/m') = m 0.6 COLUMN width C (m)= ton 15 Qumax (ton)= m 0.45 depth of beam d (m)= m 0.25 breadth of beam b (m)= (kg/cm?) 250 FCU (kg/cm?)= (kg/cm?) 3600 Fy (kg/cm?) = (kg/cm?) 2400 fystr (kg/cm?) = m / 8 Ф 5 ASSUMED STIRRUPS= 4.19 qstr= 12.90 Q CRITICAL= (kg/cm?) 11.47 qcr=Qcr/b.d = Actual stress (kg/cm?) 9.68 qc MIN= conc. Stress (kg/cm?) 28.40 qu max= Max Max stress 6.625437484 qsteel= 2.431489658 qbent= 1.23625561 Asbent mm 12 Ф 2 Bent Bars= Qumax-WU(C+d)/2= CHECK OF SHEAR ON BEAMS Qumax Qcr + + - + - d b
description
Ultimate check of shear
Transcript of Ultimate Check of Shear
-
t/m'4WU (t/m') =m0.6COLUMN width C (m)=ton15Qumax (ton)=m0.45depth of beam d (m)=m0.25breadth of beam b (m)=(kg/cm?)250FCU (kg/cm?)=(kg/cm?)3600Fy (kg/cm?) =(kg/cm?)2400fystr (kg/cm?) =
m/85ASSUMED STIRRUPS=4.19qstr=
12.90Q CRITICAL=(kg/cm?)11.47qcr=Qcr/b.d =Actual stress(kg/cm?)9.68qc MIN=conc. Stress(kg/cm?)28.40qu max=Max Max stress
6.625437484qsteel=2.431489658qbent=1.23625561Asbent
mm122Bent Bars=
Qumax-WU(C+d)/2=
CHECK OF SHEAR ON BEAMS
QumaxQcr
+ +
-+
-d
b