Typepad · Math 2 Test Review Fall 2011 Evaluate. 2 1-7, f(x) -2 3x — 4, 2. 5. 8. 11. Name Date...

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Transcript of Typepad · Math 2 Test Review Fall 2011 Evaluate. 2 1-7, f(x) -2 3x — 4, 2. 5. 8. 11. Name Date...

Page 1: Typepad · Math 2 Test Review Fall 2011 Evaluate. 2 1-7, f(x) -2 3x — 4, 2. 5. 8. 11. Name Date h(x) = f(x) = period 110 3. 6 9. 1. 4. 7. 3x+1, x > 5 —10
Page 2: Typepad · Math 2 Test Review Fall 2011 Evaluate. 2 1-7, f(x) -2 3x — 4, 2. 5. 8. 11. Name Date h(x) = f(x) = period 110 3. 6 9. 1. 4. 7. 3x+1, x > 5 —10
Page 3: Typepad · Math 2 Test Review Fall 2011 Evaluate. 2 1-7, f(x) -2 3x — 4, 2. 5. 8. 11. Name Date h(x) = f(x) = period 110 3. 6 9. 1. 4. 7. 3x+1, x > 5 —10

Part II. Linear Algebra - UHetgen/Lin-Alg.pdf−3x+ 6y − z = 9 13. x +3y −4z = −2 −3x−9y + 12z = 4 14. x− 2y + z = 3 3x+y −2z = 2 15. x+2y − z = 3 2x+5y − 4z = 5

Part II. Linear Algebra - UHetgen/Lin-Alg.pdf−3x+ 6y − z = 9 13. x +3y −4z = −2 −3x−9y + 12z = 4 14. x− 2y + z = 3 3x+y −2z = 2 15. x+2y − z = 3 2x+5y − 4z = 5

PREPARATORY EXAMINATION 2018 - Crystal Math · 2019-01-04 · 10611/18 3 2 2 3 3 6 3 x x d 6 2 3 d 9x 2 6x 9x2 3x d 0 3x2 3x d 0 3x(x 1)t 0 x t 0 or xd 1 simplify standard form correct

PREPARATORY EXAMINATION 2018 - Crystal Math · 2019-01-04 · 10611/18 3 2 2 3 3 6 3 x x d 6 2 3 d 9x 2 6x 9x2 3x d 0 3x2 3x d 0 3x(x 1)t 0 x t 0 or xd 1 simplify standard form correct

Quadratic Formula. Solve x 2 + 3x – 4 = 0 This quadratic happens to factor: x 2 + 3x – 4 = (x + 4)(x – 1) = 0 This quadratic happens to factor: x 2.

Quadratic Formula. Solve x 2 + 3x – 4 = 0 This quadratic happens to factor: x 2 + 3x – 4 = (x + 4)(x – 1) = 0 This quadratic happens to factor: x 2.

Linear programming maximize x 1 + x 2 x 1 + 3x 2 3 3x 1 + x 2 5 x 1 0 x 2 0.

Linear programming maximize x 1 + x 2 x 1 + 3x 2 3 3x 1 + x 2 5 x 1 0 x 2 0.

M3U3D4 Warm Up Divide using Synthetic division: (2x ³ - 5x² + 3x + 7) /(x - 2) 2x² - x + 1 + 9/(x-2)

M3U3D4 Warm Up Divide using Synthetic division: (2x ³ - 5x² + 3x + 7) /(x - 2) 2x² - x + 1 + 9/(x-2)

Differentiation. f(x) = x 3 + 2x 2 – 3x + 5 f’(x) = 3x 2 + 4x - 3 f’(1) = 3 x 1 2 + 4 x 1 – 3 = 3 + 4 – 3 = 4 If f(x) = x 3 + 2x 2 –

Differentiation. f(x) = x 3 + 2x 2 – 3x + 5 f’(x) = 3x 2 + 4x - 3 f’(1) = 3 x 1 2 + 4 x 1 – 3 = 3 + 4 – 3 = 4 If f(x) = x 3 + 2x 2 –

8.2 P.O.D. Simplify the following expressions. 1.2(y 2 ) 5 2. 3x 3 + 2x 3 3. (2x)(4x 2 )(-10x 3 ) 4. 3(x 3 ) 5 5. -3x 2 + x 4.

8.2 P.O.D. Simplify the following expressions. 1.2(y 2 ) 5 2. 3x 3 + 2x 3 3. (2x)(4x 2 )(-10x 3 ) 4. 3(x 3 ) 5 5. -3x 2 + x 4.

(iii) x 2 x 1 x 1 x 3 (vi) x 3x 1 x 2 › prod › content-files... · 2018-10-05 · 2 2 22 (vi) x 3x 1 x 2 x 3x 1 x 4 4x 7x 3 0 It is not of the form . Hence, the given equation

(iii) x 2 x 1 x 1 x 3 (vi) x 3x 1 x 2 › prod › content-files... · 2018-10-05 · 2 2 22 (vi) x 3x 1 x 2 x 3x 1 x 4 4x 7x 3 0 It is not of the form . Hence, the given equation

Name:__________ warm-up 6-2 Using f(x) = 3x + 2 and g(x) = 2x 2 – 1, find (f – g)(x), if it exists. Using f(x) = 3x + 2 and g(x) = 2x 2 – 1, find (f ●

Name:__________ warm-up 6-2 Using f(x) = 3x + 2 and g(x) = 2x 2 – 1, find (f – g)(x), if it exists. Using f(x) = 3x + 2 and g(x) = 2x 2 – 1, find (f ●

Factoring Trinomials. Multiply. (x+3)(x+2) x x + x 2 + 3 x + 3 2 Multiplying Binomials (FOIL) FOIL = x 2 + 2x + 3x + 6 = x 2 + 5x + 6 Distribute.

Factoring Trinomials. Multiply. (x+3)(x+2) x x + x 2 + 3 x + 3 2 Multiplying Binomials (FOIL) FOIL = x 2 + 2x + 3x + 6 = x 2 + 5x + 6 Distribute.

10-4 Multiplying and Dividing Rational Expressions Warm Up Multiply. 1. 2x 2 (x + 3)2. (x – 5)(3x + 7) 3. 3x(x 2 + 2x + 2)4. Simplify. Divide. Simplify.

10-4 Multiplying and Dividing Rational Expressions Warm Up Multiply. 1. 2x 2 (x + 3)2. (x – 5)(3x + 7) 3. 3x(x 2 + 2x + 2)4. Simplify. Divide. Simplify.

1. 3x + 2 = ½ x – 5 2. |3x + 2| > 12 3. 4x – 5 < -3x + 2 4. |x + 2| < 15 Algebra II 1.

1. 3x + 2 = ½ x – 5 2. |3x + 2| > 12 3. 4x – 5 < -3x + 2 4. |x + 2| < 15 Algebra II 1.

MULTIPLYING BINOMIALS. Solve the following problems using the distributive property. x ( 3 + 7 ) = ( 2x + 3 ) x = 3x + 7x 10x 3x + 7x 10x 2x 2 + 3x.

MULTIPLYING BINOMIALS. Solve the following problems using the distributive property. x ( 3 + 7 ) = ( 2x + 3 ) x = 3x + 7x 10x 3x + 7x 10x 2x 2 + 3x.

ABSOLUTE VALUE INEQUALITIES. Just like absolute value equations, inequalities will have two solutions: |3x - 2| ≤ 7 3x – 2 ≤ 7 +2 +2 3x ≤ 9 x ≤ 3 -5/3.

ABSOLUTE VALUE INEQUALITIES. Just like absolute value equations, inequalities will have two solutions: |3x - 2| ≤ 7 3x – 2 ≤ 7 +2 +2 3x ≤ 9 x ≤ 3 -5/3.

x + 2y = 11 −3x + y = 2

x + 2y = 11 −3x + y = 2

Algebraic long division Divide 2x³ + 3x² - x + 1 by x + 2 x + 2 is the divisor The quotient will be here. 2x³ + 3x² - x + 1 is the dividend.

Algebraic long division Divide 2x³ + 3x² - x + 1 by x + 2 x + 2 is the divisor The quotient will be here. 2x³ + 3x² - x + 1 is the dividend.

Chapter 19 Technology … · Chapter 19 Technology. ... Perfect-Substitution Technologies 9 3 18 6 24 8 x 1 x 2 x 1 + 3x 2 = 18 x 1 + 3x 2 = 36 x 1 + 3x 2 = 48 All are linear and

Chapter 19 Technology … · Chapter 19 Technology. ... Perfect-Substitution Technologies 9 3 18 6 24 8 x 1 x 2 x 1 + 3x 2 = 18 x 1 + 3x 2 = 36 x 1 + 3x 2 = 48 All are linear and

WU #19 1.Simplify: 4x 2 – 2x + 4 + 3x 2 + 4x – 1 2.Multiply: (x + 7)(x – 2) 3.Multiply: (3x + 9)(7x – 1) 4.Multiply: (x + 1)(x – 1) 5.Multiply: (2x -

WU #19 1.Simplify: 4x 2 – 2x + 4 + 3x 2 + 4x – 1 2.Multiply: (x + 7)(x – 2) 3.Multiply: (3x + 9)(7x – 1) 4.Multiply: (x + 1)(x – 1) 5.Multiply: (2x -

Bellwork Solve for x 5x-4=3x+10 x 2 -3x-10=0 4x-3+5x-7+8x-12=360 Clickers.

Bellwork Solve for x 5x-4=3x+10 x 2 -3x-10=0 4x-3+5x-7+8x-12=360 Clickers.

2. 7(x + 3)= 105 7x + 21 = 105 -21 -21 7x = 84 7 7 x = 12 Solve. 1. 5x + 18 = -3x – 14 +3x +3x 8x + 18 = -14 - 18 -18 8x = -32 8 8 x = -4.

2. 7(x + 3)= 105 7x + 21 = 105 -21 -21 7x = 84 7 7 x = 12 Solve. 1. 5x + 18 = -3x – 14 +3x +3x 8x + 18 = -14 - 18 -18 8x = -32 8 8 x = -4.