Two questions:
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Transcript of Two questions:
Two questions:(1) How to find the force, F on the electric charge, Q excreted by the field E and/or B?
(2) How fields E and/or B can be created?
BvqEqF
0/cos QAEE
2r
QkE
Gauss’s law for electric fieldElectric charges create electric field:
For one not moving (v<<c) charge:
Gauss’s law for magnetic field Magnetic charges do not exist:
0cos ABB
Amperes lawElectric current creates magnetic field:
IlB 0cos (As we will see later,this law should be extended)
Faraday’s law
Maxwell’s equations
tB
A changing magnetic flux induces an EMF
A changing magnetic field induces an electric field ! 1
8. Electromagnetic induction(Faraday’s law)
1) Flux (review)
cos
cos
AB
AB
B
B
2) EMF (review)
cos
cos
lE
q
lF
q
W
3) Faraday’s law
t
B
t
BA
cos t
BAlE
cos
cos
A changing magnetic flux induces an electric field !This electric field is not a potential field. The field lines form a closed loops.
A changing magnetic fluxinduces an EMF
Units: (weber) [ΦB] = 1 Wb = 1 T·m2
1 :loops For NN N
B
- EMF in the closed loop
- flux through a closed loop
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4) Lenz’s law
The direction of any magnetic induction effect is such as to oppose the cause of the effect
For instance: a current produced by an induced emf moves in a direction so that its magnetic field opposes the original change in flux
N
S
v
B
N
S
v
B
S
N
v
B
S
N
v
B
I I I I
Example: If a North pole moves toward the loop in the plane of the page, in what direction is the induced current?
Since the magnet is moving parallel to the loop, there is no magnetic flux through the loop. Thus the induced current is zero.
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1) drop the magnet2) move the magnet upwards3) move the magnet sideways4) all of the above5) only (1) and (2)
Example: In order to change the magnetic flux through the loop, what would you have to do?
Moving the magnet in any direction would change the
magnetic field through the loop and thus the magnetic flux.
1) tilt the loop2) change the loop area3) use thicker wires4) all of the above5) only (1) and (2)
Since, changing the area or tilting the loop (which varies the projected area) would change the magnetic flux through the loop.
cosBAB
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Example 1: A wire loop is being pulled away from a current-carrying wire. What is the direction of the induced current in the loop?
I
1) Clockwise2) Counterclockwise 3) No induced current
On the right side of the wire the magnetic flux is into the page and decreasing due to the fact that the loop is being pulled away. By Lenz’s Law, the induced B field will oppose this decrease. Thus, the new B field points into the page, which requires an induced clockwise current to produce such a B field.
Example 2: What is the induced current if the wire loop moves down?
I
The magnetic flux through the loop is not changing as it moves parallel to the wire. Therefore, there is no induced current.
1) Clockwise2) Counterclockwise 3) No induced current
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Example1: A wire loop is being pulled through a uniform magnetic field. What is the direction of the induced current? 1) Clockwise; 2) Counterclockwise; 3) No induced current x x x x x x x x x
x x x x x x x x x
x x x x x x x x x
x x x x x x x x x
x x x x x x x x x
Since the magnetic field is uniform, the magnetic flux through the loop is not changing. Thus no current is induced.
Example 3: A wire loop is being pulled through a uniform magnetic field that suddenly ends.What is the direction of the induced current? 1) Clockwise 2) Counterclockwise 3) No induced current
x x x x x
x x x x x
x x x x x
x x x x x
x x x x x
The B field into the page is disappearing in the loop, so it must be compensated by an induced flux also into the page. This can be accomplished by an induced current in the clockwise direction in the wire loop.
Example2: What is the direction of the induced current if the B field suddenly increases while the loop is in the region? 1) Clockwise 2) Counterclockwise 3) No induced current
The increasing B field into the page must be countered by an induced flux out of the page. This can be accomplished by induced current in the counterclockwise direction in the wire loop.
Example: If a coil is shrinking in a magnetic field pointing into the page, in what direction is the induced current? 1) Clockwise 2) Counterclockwise 3) No induced current
The magnetic flux through the loop is decreasing, so the induced B field must try to reinforce it and therefore points in the same direction — into the page. According to the right-hand rule, an induced clockwise current will generate a magnetic field into the page.
Example: If a coil is rotated as shown, in a magnetic field pointing to the left, in what direction is the induced current? 1) Clockwise 2) Counterclockwise 3) No induced current
As the coil is rotated into the B field, the magnetic flux through it increases.
According to Lenz’s Law, the induced B field has to oppose this increase,
thus the new B field points to the right. An induced counterclockwise
current produces just such a B field.7
Example: Wire #1 (length L) forms a one-turn loop, & a bar magnet is dropped through. Wire #2 (length 2L) forms a two-turn loop, and the same magnet is dropped through. Compare the magnitude of the induced currents in these two cases.
NNSS
NNSS
1) I1 > I2 2) I1 < I2 3) I1 = I2 04) I1 = I2 = 0
Induced emf is twice as large in the wire with 2 loops. The current is given by Ohm’s law: I = V/R. Since wire #2 is twice as long as wire #1, it has twice the resistance, so the current in both wires is the same.
tN
t
1BB
Example: A bar magnet is held above the floor and dropped. In 1, there is nothing between the magnet and the floor. In 2, the magnet falls through a copper loop. How will the magnet in case 2 fall in comparison to case 1?
NS
NS
When the magnet is falling from above the loop in 2, the induced current will produce a North pole on top of the loop, which repels the magnet. When the magnet is below the loop, the induced current will produce a North pole on the bottom of the loop, which attracts the South pole of the magnet.
1) it will fall slower; 2) it will fall faster; 3) it will fall the same
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Example 1: A coil of 600 turns with area 100 cm2 is placed in a uniform magnetic field. The angle between the direction of the field and the perpendicular to the loop is 60°. The field changes at the rate of 0.010 T/s. What is the magnitude of induced emf in the coil?
?
/010.0
100
60
600
2
sTt
B
cmA
N
VmsT
At
BN
tB
03.060cos10100/010.0600
cos
24
cos
coscos
At
BN
t
NBAAB
B
B
Example 2:
?
010.0
/100
60
600
2
TB
scmt
A
N
cos
coscos
t
ANB
t
NBAAB
B
B
VsmT
t
ANB
tB
03.060cos/10100010.0600
cos
24
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Example 3: A 12.0-cm-diameter wire coil is initially oriented perpendicular to a 1.5 T magnetic field. The loop is rotated so that its plane is parallel to the field direction in 0.20 s. What is the average induced emf in the loop?
?
20.0
5.1
0.122
90
0
1
2
st
TB
rA
cmr
N
in
f
V
s
mT
t
BA
t
BABA
BA
B
inB
fBB
B
22
105.820.0
2/12.05.1
90cos0cos
cos
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1) Rotating loop:
t
tBA
t
cosB
I
I
B
Tf 22
t 8a. Applications of Faraday’s law
tBABAB coscos
tBA sin
Example:
?
100
100
03.0
200
max
1
2
s
cmA
TB
N
VsmT 61001010003.0200 124max
max
NBAmax
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Example: A generator rotates at 60 Hz in a magnetic field of 0.03 T. It has 1000 turns and produces voltage that is 120 V at a pick. What is the area of each turn of the coil?
?
120
1000
03.0
60
max
A
V
N
TB
Hzf
2210
03.01000602
120m
THz
VA
NBAmax
f 2 fNBA
2max
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8b. EMF induced in a moving conductor
B
v
tvx
l
tlvxlA
A t
AB
tB
Another method:
B
v
FB
FE
qvBFB
qEFE
BlvElqvBqE
1) What is polarity of EMF?2) What would be the direction of the induced
current, if rod slides on a conducting track?
Blv
The B field points out of the page. The flux is increasing since the area is increasing. The induced B field opposes this change and therefore points into the page. Thus, the induced current runs clockwise according to the right-hand rule.
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Example: A uniform magnetic field B is perpendicular to the area bounded by the U-shaped conductor and a movable metal rod of length l. The rod is moving along the conductor at a speed v. The total resistance of the loop is R. What is the induced emf, the current in the loop, the magnetic force on the moving rod, and power needed to move the rod?
R
vlBR
R
BlvRIP
R
vlBFvP
R
vlBlB
R
BlvIlBF
R
Blv
RI
Blv
dis
ext
22222
222
22
PFI
Find
RvlB
Given
,,,
:
,,,
:
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8c. Transformers
tNV Bss
1
tNV Bpp
1
p
s
p
s
N
N
V
V
sss VIP ppp VIP
s
p
p
s
N
N
I
I
sp PP
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120 V
Example: What is the voltage across the lightbulb?
The first transformer has a 2:1 ratio of turns, so the voltage doubles. But the second transformer has a 1:2 ratio, so the voltage is halved again. Therefore, the end result is the same as the original voltage.
240 V 120 V
Example: Given that the intermediate current is 1 A, what is the current through the lightbulb?
1 A
Power in = Power out240 V 1 A = 120 V ???
1 2
Example: A 6 V battery is connected to one side of a transformer. Compared to the voltage drop across coil 1, the voltage across coil 2 is:
Batteries provide DC current.
Only a changing magnetic flux induces an EMF.
Therefore, the voltage across coil 2 is zero.
The unknown current is 2 A.
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