Tuesday March 17, 2020 Activator · What is the “Box Method?” It is a way to multiply with...
Transcript of Tuesday March 17, 2020 Activator · What is the “Box Method?” It is a way to multiply with...
-
Tuesday March 17, 2020 Activator
What is the “Box Method?” It is a way to multiply with variables, an easier way to distribute.
Multiply (74)(392) = 29008
Multiply (70+4)(300+90+2) = 29008
Can you expand integers (normal numbers)? Yes
Why is the method used? to double distribute
Page #3Lesson 7.1
-
Today’s New Vocab (1 of 4)
+ 21,000 + 6,300 + 140
+ 1,200 + 360 +8
70+4
300 +90 +2Multiply using the “Box Method”
There must be a
sign in every box.Write down all of the boxes.
21,000 + 6,300 + 140 + 1,200 + 360 + 8 is 29,008
Combine like terms
Page #3Lesson 7.1
-
(2 of 4)
Combine Like Terms (CLT)
Definition
Example(s) Non-Example(s)
FactsTo write the answer
in an easier way.
• Used only with Add and Subtract
• The exponent does NOT change.
4𝑥2 + 3𝑥2 = 7𝑥2
4𝑥2 − 3𝑥2 = 𝑥24𝑥2 + 3𝑥3 ≠ 7𝑥5
Not the same exponent
-
Today’s New Vocab (3 of 4)Combine Like Terms: Does the exponent change?
Addition vs. No why? The exponent is multiplication.
(𝑥3) + (𝑥3) = 2𝑥3Subtraction
Exponent change? No
(5𝑥3) − (𝑥3) = 4𝑥3
Exponent change? No
𝑥3 + 𝑥3 = 2𝑥3 5𝑥3 − 𝑥3 = 4𝑥3
Why? We did not multiply a variable by a variable.
-
Today’s New Vocab (4 of 4)Combine Like Terms Will the answer have an equal sign? No Why? No equal sign in the question.
Line 1: (7𝑥3+ 3𝑥2) - (9x - 5𝑥2)
Line 2: 7𝑥3+ 3𝑥2 - 9x + 5𝑥2
Line 4: 7𝑥3 + 8𝑥2 - 9x
Distribute
Combine Like Terms
Line 3: 7𝑥3+ 3𝑥2 + 5𝑥2 - 9x Commute
Page #4Lesson 7.1
-
Tuesday March 17, 2020 Work Period
(2𝑥2 + 6x + 5 ) - (6𝑥2 +3x + 5)
If A=(2𝑥2 + 6x + 5 ) and B=(6𝑥2 +3x + 5), what is A-B?
2𝑥2 + 6x + 5 - 6𝑥2 - 3x - 52𝑥2- 6𝑥2 + 6x - 3x + 5 - 5
-4𝑥2 + 3x + 0
-4𝑥2 + 3x
Distribute
Commutative
Combine like Terms
Page #4Lesson 7.1
-
.
Tuesday March 17, 2020 Exit TicketWhat is the sum of 8𝑥2 - x + 4 and x - 5 ?
(8𝑥2 - x + 4) + (x – 5) 8𝑥2 - x + 4 + x - 5
8𝑥2 + 0x - 1 8𝑥2 - 1
8𝑥2 - x + x + 4 - 5
Distribute
Commutative
Combine like Terms
Page #4 Lesson 7.1
-
Today’s Objective
Students will be able to use the box method and combine like terms.
Unit 7Lesson 1
-
Wednesday April 10, 2020 Activator
Monomial
2𝑥3(5𝑥3) 2𝑥3 + 5𝑥3
Simplify the expressionsMonomial Monomial Monomial
10𝑥6
7𝑥32∙ 𝑥3(5)(𝑥3)
2∙ 5 𝑥3(𝑥3) Does the exponent change?No Why? Addition and subtraction
does not change exponents.
Page #7Lesson 7.2
-
(1 of 4)
Monomial
Definition
Example(s) Non-Example(s)
Facts
• has one sign and/or number
and/or variable
-1 -1𝑥2
3x 5 8𝑥4
x - 1 2x+4
−2𝑥2 + 3𝑥
Is one part of an expression
Page #7Lesson 7.2
-
Today’s New Vocab (2 of 4)Simplify the expression
x (x – 4)
x
x – 4
Can this be graphed? NoWhy? The variable needs distributed.
𝑥2 - 4x
A sign (±) 𝑚𝑢𝑠𝑡 𝑔𝑜 𝑖𝑛 𝑒𝑎𝑐ℎ 𝑏𝑜𝑥.
Are these like terms? ______Same variable & same exponent
No+ 𝒙𝟐
- 4x
Page #7Lesson 7.2
-
Today’s New Vocab (3 of 4)Simplify the expression
x (𝑥2 + x - 4) Write all boxes down
A sign (±) 𝑚𝑢𝑠𝑡 𝑔𝑜 𝑖𝑛 𝑒𝑎𝑐ℎ 𝑏𝑜𝑥.
Are these like terms? ______Same variable & same exponent
+𝒙𝟑 +𝒙𝟐 -4xx
𝑥2 + x - 4
𝑥3 + 𝑥2 - 4x
No Can this be graphed? NoWhy? The variable needs distributed.
-
Today’s New Vocab (4 of 4)Simplify the expression
(x + 3)(x - 4) Write all boxes down
A sign (±) 𝑚𝑢𝑠𝑡 𝑔𝑜 𝑖𝑛 𝑒𝑎𝑐ℎ 𝑏𝑜𝑥.
+𝒙𝟐 -4x
+3x -12
x + 3
x -4 𝑥2 − 4𝑥 + 3𝑥 − 12
𝑥2 − 1𝑥 − 12Can this be graphed? YesWhy? The variables are in ( ).
Page #8Lesson 7.2
-
Wednesday April 10, 2020 Work Period
.
The expression (𝑥 − 6)2 is equivalent to
+ 𝒙𝟐 - 6x
- 6x + 36
𝑥 − 6𝑥
−6
Write all boxes down
𝑥2 − 6𝑥 − 6𝑥 + 36
𝑥2 − 12𝑥 + 36
LikeTerms
Page #8Lesson 7.2
-
Wednesday April 10, 2020 Exit Ticket F(x) = (𝑥 − 6)2
x G(x)
4 4
5 1
6 0
7 1
G(x) = 𝑥2 − 12𝑥 + 36 𝑎𝑛𝑑
Does G(x) and F(x) have an infinite (ALL) number of solutions?
Yes, because it is the same line.
-
Today’s Objective
Students will be able to multiply polynomials.
Unit 7Lesson 2
-
Friday April 12, 2020 Activator Simplify the following expressions. Are they equivalent? YES
x(x) -2𝑥2 + 3𝑥2
𝑥2 𝑥2Does the exponent change? Does the exponent change?
Yes. Why? Multiplying variables
No Why? Combining variables
Page #11Lesson 7.3
-
Today’s New Vocab (1 of 4)Axis of Symmetry –
x = lines that splits the graph in half.
Root, Zero, or Solutions –
Where the graph crosses the x-axis.
Vertex – The maximum or Minimum point on the graph.
Page #11Lesson 7.3
-
.
When x = -1 and x = 3, write the factors
(x + 1) ( x - 3) = 0 (x + 1) = 0 ( x - 3) = 0
x = -1 x = 3 +1 +1 -3 -3
Solution
Factor x - 3 = 0 x + 1 = 0
Factor
Solution
Today’s New Vocab (2 of 4)
To write the factors, you need to sign switch from the solutions.
Page #11Lesson 7.3
-
Today’s New Vocab (3 of 4)
+ 𝒙𝟐 - 3x
+ 1x -3
Determine the product of the following expression.
𝑥 − 3𝑥
+1
Write all boxes down
𝑥2 + 1𝑥 − 3𝑥 − 3
𝑥2 − 2𝑥 − 3
LikeTerms
(x + 1)(x - 3)
Page #11Lesson 7.3
-
Today’s New Vocab (4 of 4)Graph the polynomial f(x) = (x + 1)(x − 3)
x f(x)
-1 0
0 -3
1 -4
2 -3
3 0
BOX the Roots’s
X = _____X = _____
-13
(-1,0) (3,0)Page #12
Lesson 7.3
-
+ 2𝒙𝟐 - 4x
+ 4x - 8
Determine the product of the following expression.
2𝑥 − 4𝑥
+2
Write all boxes down
2𝑥2 − 4𝑥 + 4𝑥 − 8
2𝑥2 − 8
LikeTerms
(x + 2)(2x - 4)
Friday April 12, 2020 Work Period
Page #12Lesson 7.3
-
Friday April 12, 2020 Exit Ticket F(x) = (x + 2)(2x - 4) G(x) = 2𝑥2− 8 𝑎𝑛𝑑
Is (-2,0) a solution to the system?
Yes, because it is on both lines and both tables.
x F(x)
-2 0
-1 -6
0 -8
1 -6
2 0
-
Today’s Objective
Students will be able to multiply binomials.
Unit 7Lesson 3
-
Graph the polynomial f(x) = (x + 1)(x +4)
Write the Vertex (1, -4)
Is the Vertex a Minimum or Maximum?
Why? Vertex is at the bottom of the graph.
Minimum
Friday April 12, 2020 Activator
Page #15Lesson 7.4
-
Today’s New Vocab (1 of 4)Factor the polynomial f(x) = 𝑥2+ 5x + 4
x f(x)
-4 0
-3 -2
-2 -2
-1 0
BOX the Solutions
Can you get the factors from the graph? Yes How?Change the signs on the Solutions.
f(x) = (x + 1) ( x + 4) Page #15
Lesson 7.4
-
.
Solve for x when 𝑥2 + 5x + 4 = 0 ?
(x + 1) ( x + 4) = 0
(x + 1) = 0 ( x + 4) = 0
x = -1 x = -4 -1 -1 -4 -4
This graph will cross the x-axis at (-4,0) and (-1,0).
Set both parentheses equal to zero.
Solution
Factor x + 4 = 0 x + 1 = 0
Factor
Solution
Today’s New Vocab (2 of 4)
Page #15Lesson 7.4
-
Today’s New Vocab (3 of 4)Graph the polynomial f(x) = −2(𝑥 − 1)2
x f(x)
-1 -8
0 -2
1 0
2 -2
3 -8
BOX the Zero’s
X = ___1(1,0)
Can the vertex also be a zero?
YESPage #15
Lesson 7.4
-
Today’s New Vocab (4 of 4)Graph the polynomial f(x) = 2𝑥3 − 12𝑥2 + 10𝑥
x f(x)
0 0
1 0
5 0
BOX the Zero’s
X = ___
X = ___
Write the solutions.
X = ___0
15 Page #16
Lesson 7.4
-
Wednesday April 24, 2020 Work PeriodCompare the graph of f(x) = 𝑥2 to the graph
of g(x) = (𝑥 − 2)2 + 3. Which two directions did the g(x) shift(move)? 2 right and 3 up
x f(x)
-2 4
0 0
2 4
x g(x)
0 7
2 0
4 7
f(x) g(x)
-
Wednesday April 24, 2020 Exit TicketWhat is f(6) – g(6)? 36 – 19 = 17
f(x) = 𝑥2 g(x) = (𝑥 − 2)2 + 3
f(6) = 36
g(6) = (6 − 2)2 + 3f(6) = (6)2
g(6) = (4)2 + 3
g(6) = 16 + 3
g(6) = 19
Show your work. Page #16
Lesson 7.4
-
Today’s Objective
Students will be able to graph quadratics.
Unit 7Lesson 4
-
Monday April 16, 2020 Activator
1
2
How do you graph radical equations?
Page #19Lesson 7.5
x
2 steps
-
(1 of 4)
Radical/Root
Definition
Example(s) Non-Example(s)
Facts
Page #19Lesson 7.5
• Opposite of an exponent• Fractional • exponent
𝑥
9 = 3 16 = 4
𝑥12 𝑥2
x𝑥3
A radical(root) is an operation to remove (undo) an exponent.
-
Today’s New Vocab (2 of 4)Perfect Squares
9 = 3
16 = 4
Calculate the (square) roots.
25 = 5
36 = 6
49 = 7
100 = 10
144 = 12
-
Today’s New Vocab (3 of 4)
x f(x)
0 0
1 1
4 2
9 3
Graph the function f(x) = 𝑥How is this calculated?
f(x) = 𝑥
f(9) = 9
f(9) = 3 Page #19Lesson 7.5
-
Today’s New Vocab (4 of 4)
x f(x)
-5 3
-4 4
-1 5
4 6
Graph the function f(x) = 𝑥 + 5 + 3
How did the graph shift?
5 units left3 units up Page #20
Lesson 7.5
-
Monday April 16, 2020 Work Period
.
Graph f(x) = 𝑥 + 2 over the domain −2 ≤ x ≤ 7.
x f(x)
-2 0
-1 1
2 2
7 3
Intervals have no ARROWS.
starts. ends.Is there shading on the graph?
No, it is an equation.
Page #20Lesson 7.5
-
Monday April 16, 2020 Exit Ticket
.
Evaluate f(-2) and f(7) when f(x) = 𝑥 + 2.
f(x) = 𝑥 + 2
f(-2) = (−2) + 2
f(-2) = 0
f(-2) = 0(-2,0) is a point
on the line.
f(x) = 𝑥 + 2
f(7) = (7) + 2
f(7) = 9
f(7) = 3(7,3) is a point
on the line.
-
Today’s Objective
Students will be able to graph quadratic (radical) equations.
Unit 7Lesson 5
-
Monday April 16, 2020 Activator
Page #23Lesson 7.6
Can you take the (square root) of a negative number? NoWhy? Two of the same numberscannot multiply to be negative
Calculate −9
Error: non-real (irrational)
(3) (3) = +9(-3)(-3)= +9
-
Today’s New Vocab (1 of 4)
Page #23Lesson 7.6
How do you solve radical equations?
You can (square) root both sides.
Solve. 𝑥2 = 36
x = 6
Check your
Work.
𝑥2 = 36
(6)2= 36
36 = 36
Yes, x = 6 is a solution.
-
Today’s New Vocab (2 of 4)
Page #23Lesson 7.6
However, is x = 6 the only solution? No
𝑥2 = 36
(−6)2= 36
36 = 36
x = -6 is also a solution.
Check on the calculator.
Make a table for f(x) = 𝑥2 - 36
x f(x)
-6 0
6 0
-
Today’s New Vocab (3 of 4)
Page #23Lesson 7.6
Solve the quadratic (number exp.) equation.
𝑥2 − 5 = 44
𝑥2 = 9
𝑥2 + 7 = 16
𝑥2 = 49
x = 3
x = −3
-7 -7
x = 7
x = −7
+5 +5x y
7 0
-7 0x y
3 0
-3 0
-
Today’s New Vocab (4 of 4)
Page #24Lesson 7.6
Solve the quadratic (number exp.) equation.𝑥2
3= 27
4𝑥2 − 3 = 97
x y
9 0
-9 0x y
5 0
-5 0
4𝑥2 = 100
X = ±5
𝑥2 = 25
+3 +3
÷ 4 ÷ 4 𝑥2 = 81
X = ±9
(3) (3)
-
Monday April 16, 2020 Work Period
.
A landscaper is creating a square flower bed such that the length is L, feet. The area of the flower bed is 81 square feet. Write and solve an equation to determine length.
Let L = Length 𝐿2 = 81
𝐿 = 9The length of the
flower bed is 9 feet.
How many 1-foot stones are needed for the perimeter? 9+9+9+9 = 36 stones Page #24
Lesson 7.6
-
Monday April 16, 2020 Exit Ticket
.
Determine the cost of the garden with tax.
Page #24Lesson 7.6
Stones (36) at $1.95 each
Flowers (25) at $3.95 eachMulch (6) at $3.33 each
Weed Barrier (2) rolls at $15.99 each
$220.91 (1.08) = $238.58Tax Final Cost
-
Today’s Objective
Students will be able to solving equations with
exponents using radicals.
Unit 7Lesson 6
-
Monday April 16, 2020 Activator
Page #27Lesson 7.7
Solve for x. How do you remove the root? ( )2
4 = X
( )2 ( )23 = 𝑥 + 5
9 = x + 5-5 -5
Check your work.
3 = (4) + 5
3 = 93 = 3 Yes
-
Today’s New Vocab (1 of 4)
Page #27Lesson 7.7
Graph g(x) = 3 − 𝑥 + 5. x g(x)-5 3
-4 2
-1 1
4 0
Is (4,0) a root?
Yes, it is on the table next
to a zero.
-
Today’s New Vocab (2 of 4)
Page #27Lesson 7.7
Evaluate g(4) when g(x) = 3 − 𝑥 + 5.
g(4) = 3 − (4) + 5
g(4) = 3 − 9
g(4) = 3 − 3
g(4) = 0
x g(x)
-2 1.26
4 0
Is g(4) rational or irrational? Rational b/c
9 𝑖𝑠 𝑝𝑒𝑟𝑓𝑒𝑐𝑡.
Is g(-2) rational? NoIt has a decimals on the table.
-
Today’s New Vocab (3 of 4)
Page #27Lesson 7.7
Graph f(x) = 1
3𝑥 + 4.
x f(x)
-4 0
5 1
Is (-4,0) a root?
Yes, it is on the table next
to a zero.
-
Today’s New Vocab (4 of 4)
Page #28Lesson 7.7
Evaluate f(-4) when f(x) = 1
3𝑥 + 4.
f(-4) = 1
30
f(-4) = 0
x g(x)
-4 0
-2 0.47
Is f(-4) rational or irrational? Rational b/c
0 𝑖𝑠 𝑝𝑒𝑟𝑓𝑒𝑐𝑡.
Is f(-2) rational? No,It has a decimals on the table.
f(-4) = 1
3(−4) + 4
-
Monday April 16, 2020 Work Period
.
The number of people, p involved in recycling in a community is
modeled by the function p = 90 3𝑥 + 400, where x is the number of months the recycling plant has been open. How people were involved starting out? After 3 months? After 12 months?
x P(x)
0 400
3 670
12 940
Does this graph indicate growth or decay of this
recycling program? GrowthWhy? The people helping
are increasing.
-
Monday April 16, 2020 Exit Ticket
.
Page #28Lesson 7.7
The number of people, p involved in recycling in a
community is modeled by the function p = 90 3𝑥 + 400. How many people will be helping after 4 years(48 months)?
p(x) = 90 3𝑥 + 400
p(48) = 90 3(48) + 400
p(48) = 90 144 + 400
p(48) = 90(12) + 400
p(48) = 880
x p(x)
48 880
The more helping hands the better.
-
Today’s Objective
Students will be able to graph complex radical equations.
Unit 7Lesson 7
-
Thursday May 2, 2020 Activator
#5: Evaluate the function when x = 8.
Page #29Unit 7 Review
-
Today’s New Vocab (1 of 4)#10: What is the product of (3x-3) and (x+1)?
Product means multiply
Page #31Unit 7 Review
-
Today’s (2 of 4)#11: Make a table, graph.
12. Write the Solutions
x = -1 and x = 1
Page #31Unit 7 Review
-
Page #32Unit 7 Review
Today’s New Vocab (3 of 4)#17. Solve the quadratic equation for x.(𝑥 + 3)2 = 49
(x + 3) = 7x + 3 = 7
x = 4-3 -3
(𝑥 + 3)2 = 49
(x + 3) = -7x + 3 = -7
x = -10-3 -3
-
Today’s New Vocab (4 of 4)#14: Simplify the expression. Page #31
Unit 7 Review
-
#9: What is equivalent to 2𝑥2(4x + 5)?
𝐼𝑠 2𝑥2
𝑎 𝑓𝑎𝑐𝑡𝑜𝑟? YesPage #30
Unit 7 Review
Thursday May 2, 2020 Exit Ticket
-
Monday May 6, 2019 Activator • Please take out your Homework • Please take out your Classwork• Unit #7 Test: 10% Question #19• No work needed on #2• You must receive at least a 65%, or you
must stay after school to complete it.
• Tutoring: Mon 2:45-4:15, Wed 2:45-4:15
-
Today’s Objective
Students will be able to review objectives from Unit 7.
Unit 7Review