TRIGONOMETRY math inverses CH 02 SEC 02 SOLUTIONS hands · CH 02 SEC 02 SOLUTIONS math hands...
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TRIGONOMETRY CH 02 SEC 02 SOLUTIONS math hands inverses intro 1. 2. To find the angle in question: adj, 4 hyp, 12 70.53 ◦ The ratio adj hyp =0.3333 so we use cos −1 (0.3333) ×0.3333 3. To find the angle in question: adj, 5 hyp, 8 51.32 ◦ The ratio adj hyp =0.625 so we use cos −1 (0.625) ×0.625 4. To find the angle in question: adj, 7 hyp, 11 50.48 ◦ The ratio adj hyp =0.6364 so we use cos −1 (0.6364) ×0.6364 5. To find the angle in question: adj, 2 hyp, 15 82.34 ◦ The ratio adj hyp =0.1333 so we use cos −1 (0.1333) ×0.1333 6. To find the angle in question: adj, 1 hyp, 8 82.82 ◦ The ratio adj hyp =0.125 so we use cos −1 (0.125) ×0.125 7. To find the angle in question: opp, 2 hyp, 10 11.54 ◦ The ratio opp hyp =0.2 so we use sin −1 (0.2) ×0.2 8. To find the angle in question: opp, 4 hyp, 12 19.47 ◦ The ratio opp hyp =0.3333 so we use sin −1 (0.3333) ×0.3333 9. To find the angle in question: opp, 5 hyp, 8 38.68 ◦ The ratio opp hyp =0.625 so we use sin −1 (0.625) ×0.625 10. To find the angle in question: pg. 1 c 2007-2011 MathHands.com v.1012
Transcript of TRIGONOMETRY math inverses CH 02 SEC 02 SOLUTIONS hands · CH 02 SEC 02 SOLUTIONS math hands...
TRIGONOMETRY
CH 02 SEC 02 SOLUTIONSmathhands
inverses
intro
1.
2. To find the angle in question:
adj, 4
hyp,
12
70.53◦
The ratio adj
hyp= 0.3333 so
we use cos−1 (0.3333)
×0.3333
3. To find the angle in question:
adj, 5
hyp,
8
51.32◦
The ratio adj
hyp= 0.625 so we
use cos−1 (0.625)
×0.625
4. To find the angle in question:
adj, 7
hyp,
11
50.48◦
The ratio adj
hyp= 0.6364 so
we use cos−1 (0.6364)
×0.6364
5. To find the angle in question:
adj, 2
hyp,
15
82.34◦
The ratio adj
hyp= 0.1333 so
we use cos−1 (0.1333)
×0.1333
6. To find the angle in question:
adj, 1
hyp,
8
82.82◦
The ratio adj
hyp= 0.125 so we
use cos−1 (0.125)
×0.125
7. To find the angle in question:
opp,
2
hyp,
10
11.54◦
The ratio opp
hyp= 0.2 so we
use sin−1 (0.2)
×0.2
8. To find the angle in question:
opp,
4
hyp,
12
19.47◦
The ratio opp
hyp= 0.3333 so
we use sin−1 (0.3333)
×0.3333
9. To find the angle in question:
opp,
5
hyp,
8
38.68◦
The ratio opp
hyp= 0.625 so we
use sin−1 (0.625)
×0.625
10. To find the angle in question:
pg. 1 c©2007-2011 MathHands.com v.1012
TRIGONOMETRY
CH 02 SEC 02 SOLUTIONSmathhands
inverses
intro
opp,
7
hyp,
11
39.52◦
The ratio opp
hyp= 0.6364 so
we use sin−1 (0.6364)
×0.6364
11. To find the angle in question:opp,
2
hyp,
15
7.66◦
The ratio opp
hyp= 0.1333 so
we use sin−1 (0.1333)
×0.1333
12. To find the angle in question:
opp,
1
hyp,
8
7.18◦
The ratio opp
hyp= 0.125 so we
use sin−1 (0.125)
×0.125
13. To find the angle in question:
adj, 8
opp,
1
7.13◦
The ratio opp
adj= 0.125 so we
use tan−1 (0.125)
×0.1
25
14. To find the angle in question:
adj, 10
opp,
2
11.31◦
The ratio opp
adj= 0.2 so we
use tan−1 (0.2)
×0.2
15. To find the angle in question:
adj, 12
opp,
4
18.43◦
The ratio opp
adj= 0.3333 so
we use tan−1 (0.3333)
×0.3
333
16. To find the angle in question:
adj, 8
opp,
532.01◦
The ratio opp
adj= 0.625 so we
use tan−1 (0.625)
×0.6
25
17. To find the angle in question:
adj, 11
opp,
7
32.47◦
The ratio opp
adj= 0.6364 so
we use tan−1 (0.6364)
×0.6
364
18. To find the angle in question:
pg. 2 c©2007-2011 MathHands.com v.1012
TRIGONOMETRY
CH 02 SEC 02 SOLUTIONSmathhands
inverses
intro
adj, 15
opp,
2
7.59◦
The ratio opp
adj= 0.1333 so
we use tan−1 (0.1333)
×0.1
333
19. To find the angle in question:
adj, 8
opp,
1
7.13◦
The ratio opp
adj= 0.125 so we
use tan−1 (0.125)
×0.1
25
20. To find the angle in question:
opp, 8
adj,
1
82.87◦
The ratio opp
adj= 8 so we use
tan−1 (8)
×8
21. To find the angle in question:
opp, 10
adj,
2
78.69◦
The ratio opp
adj= 5 so we use
tan−1 (5)
×5
22. To find the angle in question:
opp, 12
adj,
4
71.57◦
The ratio opp
adj= 3 so we use
tan−1 (3)
×3
23. To find the angle in question:
opp, 8
adj,
5
57.99◦
The ratio opp
adj= 1.6 so we
use tan−1 (1.6)
×1.6
24. To find the angle in question:
opp, 11
adj,
7
57.53◦
The ratio opp
adj= 1.5714 so
we use tan−1 (1.5714)
×1.5
714
25. To find the angle in question:
opp, 15
adj,
2
82.41◦
The ratio opp
adj= 7.5 so we
use tan−1 (7.5)
×7.5
26. To find the angle in question:
pg. 3 c©2007-2011 MathHands.com v.1012
TRIGONOMETRY
CH 02 SEC 02 SOLUTIONSmathhands
inverses
intro
adj,
2
hyp,
1582.34◦
The ratio adj
hyp= 0.1333 so
we use cos−1 (0.1333)
×0.1333
27. To find the angle in question:adj,
2
hyp,
1078.46◦
The ratio adj
hyp= 0.2 so we
use cos−1 (0.2)
×0.2
28. To find the angle in question:
adj,
4
hyp,
1270.53◦
The ratio adj
hyp= 0.3333 so
we use cos−1 (0.3333)
×0.3333
29. To find the angle in question:
adj,
5
hyp,
851.32◦
The ratio adj
hyp= 0.625 so we
use cos−1 (0.625)
×0.625
30. To find the angle in question:
adj,
7
hyp,
1150.48◦
The ratio adj
hyp= 0.6364 so
we use cos−1 (0.6364)
×0.6364
31. To find the angle in question:
adj,
2
hyp,
1582.34◦
The ratio adj
hyp= 0.1333 so
we use cos−1 (0.1333)
×0.1333
32. To find the angle in question:
adj,
1
hyp,
882.82◦
The ratio adj
hyp= 0.125 so we
use cos−1 (0.125)
×0.125
33. To find the angle in question:
opp, 2
hyp,
523.58◦
The ratio opp
hyp= 0.4 so we
use sin−1 (0.4)
×0.4
34. To find the angle in question:
pg. 4 c©2007-2011 MathHands.com v.1012
TRIGONOMETRY
CH 02 SEC 02 SOLUTIONSmathhands
inverses
intro
opp, 4
hyp,
641.81◦
The ratio opp
hyp= 0.6667 so
we use sin−1 (0.6667)
×0.6667
35. To find the angle in question:
opp, 5
hyp,
933.75◦
The ratio opp
hyp= 0.5556 so
we use sin−1 (0.5556)
×0.5556
36. To find the angle in question:
opp, 7
hyp,
1139.52◦
The ratio opp
hyp= 0.6364 so
we use sin−1 (0.6364)
×0.6364
37. To find the angle in question:
opp, 1
hyp,
134.41◦
The ratio opp
hyp= 0.0769 so
we use sin−1 (0.0769)
×0.0769
38. To find the angle in question:
opp, 2.3
hyp,
5.624.25◦
The ratio opp
hyp= 0.4107 so
we use sin−1 (0.4107)
×0.4107
pg. 5 c©2007-2011 MathHands.com v.1012
