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![Page 1: Trigonometric Functions of Any Angle 4.4. Definitions of Trigonometric Functions of Any Angle Let is be any angle in standard position, and let P =](https://reader036.fdocuments.us/reader036/viewer/2022082417/56649d1b5503460f949f0b93/html5/thumbnails/1.jpg)
Trigonometric Functions of Any
Angle
4.4
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Definitions of Trigonometric Functions of Any Angle
• Let is be any angle in standard position, and let P = (x, y) be a point on the terminal side of . If r = x2 + y2 is the distance from (0, 0) to (x, y), the six trigonometric functions of are defined by the following ratios.
sin y
r, cos x
r, tan y
x, x 0
csc r
y,y 0 sec
r
x, x 0 cot
x
y,y 0
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Let P = (-3, -4) be a point on the terminal side of . Find each of the six trigonometric functions of .
Solution The situation is shown below. We need values for x, y, and r to evaluate all six trigonometric functions. We are given the values of x and y. Because P = (-3, -4) is a point on the terminal side of , x = -3 and y = -4. Furthermore,
r
x = -3 y = -4
P = (-3, -4)
x
y
-5
5
-5
5
Example
222 ryx
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The bottom row shows the reciprocals of the row above.The bottom row shows the
reciprocals of the row above.
sin yr
45
45
, cos xr
35
35
, tan yx
4 3
43
csc r
y
5
4
5
4, sec
r
x
5
3
5
3, cot
x
y
3
4
3
4
Example Cont.
SolutionNow that we know x, y, and r, we can find the
six trigonometric functions of .
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ExampleLet tan θ = -2/3 and cos θ > 0. Find each of the six trigonometric functions of .
x
y
3
2tan
222 ryx 222 )3()2( r
r13
13
133
13
3cos
We have to be in Quadrant IV
2
3cot
3
13sec
13
132
13
2sin
2
13csc
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x
y
Quadrant IISine and cosecant positive
Quadrant IAll functions
positive
Quadrant IIItangent and cotangent positive
Quadrant IVcosine and
secant positive
The Signs of the Trigonometric Functions
All Students Take Calculus
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Definition of a Reference Angle
• Let be a nonacute angle in standard position that lies in a quadrant. Its reference angle is the positive acute angle ´ prime formed by the terminal side or and the x-axis.
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Example
a
b
a
b
P(a, b)
Find the reference angle , for the following angle: =315º
Solution:
=360º - 315º = 45º
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Example
Find the reference angles for:345
135
6
5
4
11
15345360
45180225360135
66
5
6
6
6
5
44
3
4
32
4
11
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Using Reference Angles to Evaluate Trigonometric Functions
• The values of a trigonometric functions of a given angle, , are the same as the values for the trigonometric functions of the reference angle, ´, except possibly for the sign. A function value of the acute angle, ´, is always positive. However, the same functions value for may be positive or negative.
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A Procedure for Using Reference Angles to Evaluate Trigonometric Functions
• The value of a trigonometric function of any angle is found as follows:
• Find the associated reference angle, ´, and the function value for ´.
• Use the quadrant in which lies to prefix the appropriate sign to the function value in step 1.
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Use reference angles to find the exact value of the following trigonometric functions.
Solution
a. We use our two-step procedure to find sin 135°.Step 1 Find the reference angle, ´, and sin ´.
135º terminates in quadrant II with a reference angle ´ = 180º – 135º = 45º.
x
y
135°45°
a. sin 135°
Example
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Solution
The function value for the reference angle is sin 45º = 2 / 2.
Step 2 Use the quadrant in which è lies to prefix the appropriate sign to the function value in step 1. The angle 135º lies in quadrant II. Because the sine is positive in quadrant II, we put a + sign before the function value of the reference angle. Thus, sin135= +sin45=2 / 2
Example cont.
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Example
• Evaluate:
3
4cos
3cot
2
1
3cos
3
4cos
3
3
3
1
3tan
1
3cot
3cot