TNPSC GROUP-I A CONSERVATOR OF FORESTS …...5. Sourav purchased 30 kg of rice at the rate of ì 10...

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1 | Page PH: 24339436, 42867555, 9840226187 TNPSC GROUP-I A CONSERVATOR OF FORESTS TEST vi – aptitude & mental ability 1. A shopkeeper marks his goods 30% above the cost price and allows 10% discount on the marked price. His profit per cent is: a) 10% b) 12% c) 17% d) 20% xU filf;fhuh; jd;Dila nghUl;fis mtw;wpd; mlf;f tpiyiatpl 30 tpOf;fhL mjpfkhf tpw;gid nra;a KbT nra;J> me;j eph;za tpiyapy; ,Ue;J 10 tpOf;fhL js; Sgb mspf;fpwhh;. mtUila ,yhgk; vj;jid tpOf;fhL? a) 10% b) 12% c) 17% d) 20% Solution Marked price = 130% of cost price Sale price = 130% - 10% of 130 = 117% of cost price Profit Per cent = 17% Alternative method: Profit per cent 30 10 30 10 17% 100 2. A man bought an old typewriter for ì 1200 and spent ì 200 on its repair. He sold it for ì 1680. His profit per cent is: a) 20% b) 10% c) 8% d) 16% xU egh; xU gioa jl;lr; Rg; nghwpia ì 1200 f;F thq;fp mijg; gOJ eP f;fk; nra;tjw;F ì 200 nryT nra;J> mij ì 1680f;F tpw;gid nra;jhh;. mtUila ,yhg tpOf;fhL: a) 20% b) 10% c) 8% d) 16% Solution Total cost of typerwriter = Rs.(1200+200) = Rs.1400 S.P = Rs.1680 Profit = Rs.(1680-1400) = Rs.280 Hence Profit % 2800 100 20% 1400

Transcript of TNPSC GROUP-I A CONSERVATOR OF FORESTS …...5. Sourav purchased 30 kg of rice at the rate of ì 10...

Page 1: TNPSC GROUP-I A CONSERVATOR OF FORESTS …...5. Sourav purchased 30 kg of rice at the rate of ì 10 per kg and 35 kg at the rate of ì 11 per kg. He mixed the two. At what price per

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TNPSC GROUP-I A CONSERVATOR OF FORESTS

TEST vi – aptitude & mental ability

1. A shopkeeper marks his goods 30% above the cost price and allows 10% discount on the marked price. His profit per cent is: a) 10% b) 12% c) 17% d) 20% xU filf;fhuh; jd;Dila nghUl;fis mtw;wpd; mlf;f tpiyiatpl 30 tpOf;fhL mjpfkhf tpw;gid nra;a KbT nra;J> me;j eph;za tpiyapy; ,Ue;J 10 tpOf;fhL js;Sgb mspf;fpwhh;. mtUila ,yhgk; vj;jid tpOf;fhL? a) 10% b) 12% c) 17% d) 20% Solution Marked price = 130% of cost price Sale price = 130% - 10% of 130 = 117% of cost price Profit Per cent = 17% Alternative method:

Profit per cent 30 10

30 10 17%100

2. A man bought an old typewriter for ì 1200 and spent ì 200 on its repair. He

sold it for ì 1680. His profit per cent is: a) 20% b) 10% c) 8% d) 16% xU egh; xU gioa jl;lr;Rg; nghwpia ì 1200 f;F thq;fp mijg; gOJ ePf;fk; nra;tjw;F ì 200 nryT nra;J> mij ì 1680f;F tpw;gid nra;jhh;. mtUila ,yhg tpOf;fhL: a) 20% b) 10% c) 8% d) 16% Solution Total cost of typerwriter = Rs.(1200+200) = Rs.1400 S.P = Rs.1680 Profit = Rs.(1680-1400) = Rs.280

Hence Profit % 2800

100 20%1400

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3. If 3 toys are sold at the cost price of 4 toys of the same kind, the profit will be:

a) 25% b) 33 1

3% c) 62

2

3% d) 50%

4 nghk;ikfspd; mlf;f tpiyf;F mNj tifapyhd 3 nghk;ikfis tpw;gid nra;jhy;> ,yhgk; vj;jid tpOf;fhlhf ,Uf;Fk;?

a) 25% b) 33 1

3% c) 62

2

3% d) 50%

Solution Cost price of 4 toys = Selling price of 3 toys Cost price : Selling price = 3 : 4

Profit% 1 1

100 33 %3 3

4. If selling price of an article is 8

5times its cost price, the profit per cent on it is:

a) 120% b) 160% c) 40% d) 60%

xU nghUspd; tpw;gid tpiy> mjDila mlf;f tpiyiag; Nghy 8

5 klq;F

vdpy;> me;jg; tpw;gid kPjhd ,yhg tpOf;fhL vt;tsT? a) 120% b) 160% c) 40% d) 60% Solution

Profit 8 3

15 5

3

100% 60%5

5. Sourav purchased 30 kg of rice at the rate of ì 10 per kg and 35 kg at the rate of ì

11 per kg. He mixed the two. At what price per kg (in ì ) should he sell the mixture to make a 30% profit in the transaction? a) 12.5 b) 13 c) 13.7 d) 14.25 nrsut; xU fpNyh `10 vd;w tpiyapy; 30 fpNyh mhprpiaAk;> xU fpNyh `11 vd;w tpiyapy; 35 fpNyh mhprpiaAk; thq;fpdhh;. mth; mt;tpuz;ilAk; xd;whff; fye;jhh;. mth;> me;jf; fyitia xU fpNyh vd;d tpiyf;F tpw;why; me;jg; ghpkhw;wj;jpd; thapyhf mtUf;F 30 tpOf;fhL ,yhgk; fpilf;Fk;. a) 12.5 b) 13 c) 13.7 d) 14.25 Solution

Total cost price (of 65kg) = 30 10 + 35 11 = 300 + 385 = 685 Total selling price = 685 + 30% of 685 = 890.50

Selling price per kg = 890.50 890.50

13.7065

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6. Given that 10% of A’s income = 15% of B’s income = 20% of C’s income. If sum

of their income is ` 7800, then B’s income is

a. ` 3600 b. ` 3000 c. ` 2400 d. ` 1800 A d; tUkhdj;jpy; 10 rjtPjKk;> B apd; tUkhdj;jpy; 15 rjtPjKk;> C apd; tUkhdj;jpy; 20 rjtPjKk; rkk;. ,k;%thpd; nkhj;j tUkhdk; &.7800 vdpy; B apd; tUkhdk; vt;tsT? a. ` 3600 b. ` 3000 c. ` 2400 d. ` 1800 Solution 10% of A = 15% of B = 20% of C 2A = 3B = 4C

Dividing the ratio by LCM of 2, 3 and 4 i.e., by 12, we get : 6 4 3

A B C

A:B:C = 6:4:3

B ‘s income 4

7800 240013

7. A number, on subtracting 15 from it, reduces to its 80%. What is 40% of the

number?

a. 75 b. 60 c. 30 d. 90 xU vz;zpypUe;J 15 I fopf;Fk; nghOJ me;j vz;zpd; kjpg;G Fiwe;J 80 rjtPjkhfpwJ> vdpy; me;j vz;zpy; 40 rjtPj kjpg;G ahJ? a. 75 b. 60 c. 30 d. 90 Solution Number is reduced by 15 or 20% of original number

40 % of number = 2 20% of number =2 15 = 30 8. If 60% of A’s income is equal to 75% of B’s income, then B’s income is equal to

x% of A’s income. The value of x is:

a. 70 b. 60 c. 80 d. 90 A d; tUkhdj;jpy; 60 rjtPjKk;> B apd; tUkhdj;jpy; 75 rjtPjKk; rkk; vdpy; B apd; tUkhdkhdJ A apd; tUkhdj;jpy; ‘x’ rjtPjkhFk;. vdpy; ‘x’ d; kjpg;G ahJ? a. 70 b. 60 c. 80 d. 90 Solution 60% of A’s income = 75% of B’s income A’s income : B’s income = 75 : 60 = 5 : 4

Required percentage 4

100 805

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9. If the numerator of a fraction is increased by 20% and its denominator by 25%,

then the fraction so obtained is 3

5what is the original fraction?

a. 3

5 b.

2

8 c.

5

8 d. 1

xU gpd;dj;jpy; njhFjpapd; kjpg;G 20 rjtPjk; mjpfhpf;fpwJ> gFjpapd; kjpg;G 25

rjtPjk; FiwfpwJ> gpd;G mg;gpd;dk; 3

5khWfpwJ> vdpy; mg;gpd;dj;jpidf; fhz;f.

a. 3

5 b.

2

8 c.

5

8 d. 1

Solution Let the numerator be x and denominator be y.

Now, fraction x

y

Then, from question 120 3

125 5

x

y

3 125

5 120

3 25 5

5 24 8

x

y

x

y

Original fraction = 5

8

10. In a group of students, 70% can speak English and 65% can speak Hindi. If 27%

of the students can speak none of the two languages, then what per cent of

group can speak both the languages? xU khzth;fs; FOtpy;> 70 rjtPjk; Ngh; Mq;fpyk; NgRgth;fs;> 65 rjtPjk; Ngh; ,e;jp NgRgth;fs;. 27 rjtPjk; khzth;fs; Nkw;fz;l ,uz;L nkhopfisAk; Ngrhjth;fs; vdpy;> ,uz;L nkhopfisAk; NgRk; khzth;fs; vj;jid rjtPjk;? A. 38% B. 62% C. 28% D. 23% Solution Let total students = 100 Students who know none of the two lanugages = 27 Remaining students = 100 – 27 = 73 Students who know both langugages = 70 + 65 – 73 = 62% 11. If the price of gold increased by 20% on Monday and decreased by 20% on

Tuesday then by what percentage is Tuesday's price higher or lower than the initial price of that week?

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jq;fj;jpd; tpiy jpq;fl;fpoik 20% mjpfhpf;fpwJ nrt;tha;fpoikapy; 20% FiwfpwJ vdpy; nrt;thad;W jq;fj;jpd; tpiy thuj;jpd; njhlf;ftpiyiatpl Fiwthd rjtPjk; my;yJ mjpfkhd rjtPjk; vt;tsT? a. 4% lower b. 12.5% higher c. 10% lower d. No change Solution

Formula= I×D

I-D-100

= 20 20

20 20 4%100

12. The price of a loaf of bread was increased by 25%. How many loaves can be purchased for the amount that used to buy 300 loaves?

nuhl;bj; Jz;bd; tpiy 25% Mf cah;e;jhy;> 300 nuhl;bj; Jz;Lfs; thq;fpa njhifapy; vj;jid nuhl;bj; Jz;Lfs; thq;f KbAk;?

A. 240 B. 250 C. 260 D. 275

Solution 1 bread cost = Rs.1 300 loaves = 300 Rs. 1 bread 25% increased Price = 1.25 300 nuhl;bj; Jz;Lfs; thq;fpa njhifapy; No of loaves in purchased for the amount buy 300 loaves

300 300

100 2401.25 125

13. If x% of y is 100 and y% of z is 200, then the relation between x and z.

yd; x rjtPjk; 100 kw;Wk; zd; y rjtPjk; 200 vdpy; xf;Fk; zf;Fk; cs;s njhlh;G.

a. 2

xz b. 2z x c.

4

xz d. 4z x

Solution

Given 100100

xy ------ (1) 100

100

yz ------ (2)

eqn (1) (2) 1

2

x

z

z = 2x

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14. If A exceeds B by 40%, B is less than C by 20%, then A : C is :

a. 28 : 25 b. 26 : 25 c. 3 : 2 d. 3 : 1 A d; kjpg;G B ia tpl 40% mjpfk;> B apd; kjpg;G C I tpl 20% FiwT vdpy; A : C tpfpjk; ahJ?

a. 28 : 25 b. 26 : 25 c. 3 : 2 d. 3 : 1 Solution A : B = 140 : 100 B : C = 80 : 100

140 80 28

100 100 25

A A B

C B C

15. Price of cloth having been raised by 75%, by how much per cent a householder

must reduce his consumption of cloth so as not to increase his expenditure?

a. 6

42 %7

b. 1

57 %7

c. 75% d. 50%

Jzpapd; tpiy 75% mjpfhpf;fpwJ> ,Ug;gpDk;> mth;fsJ FLk;g tuT nrytpy; ve;jtpj khw;wKk; ,y;iy vdpy;> Jzp cgNahfpf;Fk; msit vt;tsT rjtPjk; Fiwf;f Ntz;Lk;? Solution:

Formula: 100 100 75 6

42 %100 175 7

R

R

16. The population of town 2 years ago was 62,500. Due to migration to big cities, it

decreases every year at the rate of 4%. The present population of the town is: A. 56,700 B. 57,600 C. 58,800 D. 60,000 xU efuj;jpd; kf;fs;njhif ,uz;L Mz;LfSf;F Kd;G 62>500 nghpa efuq;fSf;F ,lk;ngah;tjhy; me;efufj;jpd; kf;fs;njhif Mz;Lf;F 4% FiwfpwJ. me;efuj;jpd; jw;Nghija kf;fs;njhif vt;tsT? A. 56,700 B. 57,600 C. 58,800 D. 60,000 Solution

Present population 2

4 24 2462500 1 62500 57600

100 25 25

17. Find the rate percent at which a sum of money becomes 7

6times in 3 years.

xU mryhdJ 3 tUlj;jpy; 7

6klq;fhf MFnkdpy; mjd; tl;b tpfpjk;

vt;tsT?

a. 12% b. 55

9% c. 6

5

9% d. 24%

Solution

Page 7: TNPSC GROUP-I A CONSERVATOR OF FORESTS …...5. Sourav purchased 30 kg of rice at the rate of ì 10 per kg and 35 kg at the rate of ì 11 per kg. He mixed the two. At what price per

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Principal = P

Amount 7

6

P

7P P

SI= -P=6 6

SI×100 P×100 50

R= =P×T 6×P×3 9

R = 55

9%

18. A lent ì 450 to B for 2 years, and ì 500 to c for 3 years, at a certain rate of simple

interest. If he received altogether from both ì 120 as interest, find the rate interest.

(a) 3% (b) 4% (c) 5% (d) 6% A vd;gth; B f;F 2 Mz;LfSf;F &.450 I fldhf nfhLj;jhh;> A vd;gth; C f;F 3 Mz;LfSf;F &.500 I fldhf nfhLj;jhh;> ,t;tpUtUk; &.120 jdptl;bahf nfhLj;jdh;> vdpy; Mz;L tl;b tPjk; vt;tsT? (a) 3% (b) 4% (c) 5% (d) 6% Solution

450 2 500 3

120100 100

x x

9x + 15x = 120 x = 5% 19. The Simple Interest on Rs.3,500 at 8% from 4th February, 1996 to 24th April,

1996 is... a. Rs.61.37 b. Rs.22.40 c. Rs.224 d. Rs.70.20 &.3500 I 8% jdptl;bapy; gpg;uthp 4> 1996 ypUe;J Vg;uy; 24> 1996 tiu

fpilf;Fk; jdptl;b vt;tsT? a. Rs.61.37 b. Rs.22.40 c. Rs.224 d. Rs.70.20 Solution P = Rs.3500 R = 8% N = (Feb 25 + Mar 31 + April 24) = 16/73

3500 16 8

61.37100 73

SI

20. A sum of money 5 times of itself in 22 years. In how many years would it

become 4 times of itself? a. 16 years and 3 months b. 16 years and 2 months c. 16 years and 9 months d. 16 years and 6 months xU Fwpg;gpl;l mry; njhif 22 Mz;Lfspy; 5 klq;fhfpwJ vdpy;> mNj mry;

njhif vj;jid Mz;Lfspy; 4 klq;F njhifahFk;?

Page 8: TNPSC GROUP-I A CONSERVATOR OF FORESTS …...5. Sourav purchased 30 kg of rice at the rate of ì 10 per kg and 35 kg at the rate of ì 11 per kg. He mixed the two. At what price per

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a. 16 Mz;Lfs; kw;Wk; 3 khjk; b. 16 Mz;Lfs; kw;Wk; 2 khjk; c. 16 Mz;Lfs; kw;Wk; 9 khjk; d. 16 Mz;Lfs; kw;Wk; 6 khjk; Solution

R400=100×22×

100

400R= %

22

100×N×400×1 66300= =

22×100 4

1N=16 years

2

21. A man borrowed Rs.12,000 from two persons. He paid 5% interest to one and

8% per annum to the other. In one year he paid total interest Rs.840. How much did he borrow at 5% rate? a. Rs.7500 b. Rs.4500 c. Rs.8000 d. Rs.4000 xUth; &.12000 I ,uz;L egh;fsplk; ,Ue;J fldhf ngw;whh;. ,jpy; Kjy; egh;

5% tl;bAk; kw;Wk; ,uz;lhk; egh; 8% tl;bAk; ngw;wdh;. ,t;tpUtUf;Fk; Nrh;j;J xU Mz;L Kbtpy; &.840 tl;bahf nfhLj;jhh; vdpy;> 5% tl;bapy; ngw;w fld; njhif ahJ?

a. Rs.7500 b. Rs.4500 c. Rs.8000 d. Rs.4000 Solution

12000 1 8x 1 5.840

100 100

5 96000 8 .84000

3 .12000

xRs

x x Rs

x Rs

x = 4000

22. A sum of money amounts to Rs.7,250 after 2 years and Rs.8,500 after 4 years at the same rate of simple interest. What is the rate percent? a. 14.02% b. 8.42% c. 10.42% d. 11.42%

xU Fwpg;gpl;l njhif 2 tUlq;fspy; &. 7250 MfTk; NkYk; 4 tUlq;fspy; &. 8500 MfTk; Kjph;T milfpwJ. vdpy; tl;b tPjk;? a. 14.02% b. 8.42% c. 10.42% d. 11.42% Solution

4 8500 (2)

2 7250 (1)

2 1250

P SI

P SI

SI

SI = 625 P + 2 (625) = 7250

Page 9: TNPSC GROUP-I A CONSERVATOR OF FORESTS …...5. Sourav purchased 30 kg of rice at the rate of ì 10 per kg and 35 kg at the rate of ì 11 per kg. He mixed the two. At what price per

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P = 6000

1250 100

R 10.42%6000 2

23. Find out compound interest on 16,000 at 15% per annum, compounded yearly

for 3 years. a. Rs.7200 b. Rs.9000 c. Rs.8343 d. Rs.8334 &.16000 I 15% $l;Ltl;bapy; 3 Mz;LfSf;F fpilf;fg;ngUk; tl;bj;njhif

vt;tsT? a. Rs.7200 b. Rs.9000 c. Rs.8343 d. Rs.8334 Solution

n

RCI=P 1+ -P

100

315

16000 1+ -16000100

23 23 23=16000 16000

20 20 20

24334 16000

8334

24. The compound interest on Rs.15,625 at 8% per annum is Rs.4058. The period (in

years) is .... a. 3 years b. 2 ½ years c. 2 years d. 4 years

&.15,625I 8 rjtPj $l;Ltl;bapy; vj;jid Mz;Lfspy; tl;bj;njhif &.4058 fpilf;Fk;? Solution

1 1100

nR

CI P

3

84058 15625 1 1

100

4058 271

15625 25

19683 27

15625 25

n

n

N = 3 years

25. The C.I. on Rs.24,000 at 10% per annum for 1 ½ years where interest being compounded half-yearly is _____

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6 khjj;jpw;F xU Kiw tl;b fzf;fplg;gl;lhy; &.24>000f;F 1 ½ Mz;L fhyj;jpw;F 10% tl;b tPjj;jpy; fpilf;Fk; $l;L tl;b vd;d? A. Rs. 3783 B. Rs.3873 C. Rs.3378 D. Rs.3837 Solution

105 105 105

C.I 24000 24000 27783 24000 3783100 100 100

26. A sum on compound interest becomes three times in 4 years. How many years

will it take to become 27 times the original if the interest is calculated at the

same rate? xU njhifahdJ $l;L tl;b %yk; ehd;F tUlq;fspy; 3 klq;fhfpwJ. ,Nj tl;b tPjk; %yk; me;j njhifahdJ vj;jid tUlq;fSf;Fg; gpwF 27 klq;fhFk;?

a. 8 years b. 12 years c. 24 years d. 36 years

Solution

3T 4years

9T 8 years

27T 12years

27. A man invested Rs. 25,000 at 4% per annum in compound interest and received the amount Rs. 27,040 after n years, then value of n is

xUth;> mry; &. 25>000 &ghia Mz;Lf;F $l;L tl;b 4% tPjk; KjyPL nra;J n Mz;Lfs; fopj;J & 27,040 I njhifahfg; ngWfpwhh; vdpy; n-d; kjpg;G ahJ?

a. 2 yrs b. 3 yrs c. 2½ yrs d. 3½ yrs Solution

2

104 26 2704 2625000 27040

100 25 2500 25

n n

n = 2 years

28. The least number of complete years in which a sum of money put out at 20% compound interest will be more than doubled is

20% $l;L tl;b tpfpjj;jpy; itf;fg;gl;l xU njhif ,Uklq;Ff;F Nky; Mtjw;F kPr;rpW KO Mz;Lfs; vd;d? A. 3 B. 4 C. 5 D. 6 Solution

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1 2100

201 2

100

n

n

RP P

62

5

6 6 6 62

5 5 5 5

n

4 years. 29. The difference between the simple interest and the compound interest at the

rate of 12% per annum on Rs. 5,000 for 2 year will be & 5>000f;F 2 Mz;Lfspy; 12% tl;b tpfpjj;jpy; jdptl;b kw;Wk; $l;L tl;bf;fhd tpj;jpahrk; a. Rs. 17.50 b. Rs. 36 c. Rs. 45 d. Rs. 72 Solution

2100

P=DifferenceR

5000×12×12Difference= =72

100×100

30. If 20 men can build a wall 112 meters long in 6 days, what length a similar wall

can be built by 25 men in 3 day? 20 Ml;fs; 6 ehl;fspy; 112 kP ePsKs;s Rtiu fl;b Kbj;jhy;> 25 Ml;fs; 3 ehl;fspy; vt;tsT ePsr; Rtiu fl;b Kbg;gh;? A. 56 meters B. 70 meters C. 45 meters D. 60 meters Solution

1 1 2 2

1 2

M D M D=

W W

112×25×3x= =70m

20×6

31. In a fort, food is reserved for 16 days for 125 persons. After 12 days, 75 persons

leave the fort. For how many more days the provisions would last? xU Nfhl;ilapy;> 125 egh;fSf;F 16 ehl;fSf;fhd czT Nrkpj;J itf;fg;;gl;bUf;fpwJ. 12 ehl;fs; fle;j gpd;dh;> 75 Ngh; me;jf; Nfhl;ilia tpl;L ntspNawp tpl;ldh;. me;j czTg; nghUl;fs; ,d;Dk; vj;jid ehl;fSf;F tUk;? a. 7 days b. 14 days c. 5 days d. 10 days Solution

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After 12 days ; Men Day 125 4

50 x 125 410

50x days

32. If 13 men and 24 boys can do a piece of work in 4 days and 12 men and 160

boys can do it in 5 days, how long will 8 men and 9 boys take to do it? 13 Mz;fs; kw;Wk; 24 rpWth;fs; xU Fwpg;gpl;l Ntiyia 4 ehl;fspy; nra;J Kbg;ghh;fs;> kw;Wk; 12 Mz;fs; kw;Wk; 160 rpWth;fs; me;j Ntiyia 5 ehl;fspy; nra;J Kbg;ghh;fs; vdpy;> 8 Mz;fs; kw;Wk; 9 rpWth;fs; me;j Ntiyiar; nra;tjw;F vj;jid ehl;fis vLj;Jf; nfhs;thh;fs;?

a. 15 days b. 14 days c. 10 days d. 8 days Solution

13M + 24B 4 days ------ (1)

12M + 160B 5 days -----(2)

8M + 9B ? 1 1 2 2M D =M D

(13M + 24B) 4 = (12M + 160B) 5 52M + 96B = 60M + 80B 8M = 16B M = 2B M = 2B in eqn (1) Sub. 13(2B) + 24B = 50B

50B 4days ----- (4) 8(2B) + 9B = 25B

25B ?

50×4

x= =8days25

33. Ramesh can do a piece of work in 20 days and Mohan in 25 days. They work

together for 5 days and Mohan goes away. In how many days will Ramesh finish the work? xU Fwpg;gpl;l Ntiyia uNk~hy; 20 ehl;fspYk;> Nkhfdhy; 25 ehl;fspYk; nra;a KbAk;. mth;fs; ,UtUk; Nrh;e;J 5 ehl;fs; Ntiy nra;fpwhh;fs;. gpd;dh; Nkhfd; mq;fpUe;J ntspNawp tpLfpwhh;. me;j Ntiyiar; nra;J Kbf;f uNk~; vj;jid ehl;fis vLj;Jf; nfhs;thh;?

a. 7 days b. 11 days c. 13 days d. 10 days Solution

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R = 1

12 M =

1

20

R+M work 5 days = 1 1 9

520 25 20

Remaining work 9 11

120 20

R finish the work 20 days = 11

= ×20=11days20

34. Two men undertake to do a piece of work for Rs.1000. One alone could do it in

6 days, the other in 8 days. With the assistance of a boy they finish it in 3 days. How should the money be divided? ,uz;L Mz;fs; Nrh;e;J xU Fwpg;gpl;l Ntiyia &.1000-f;F nra;J Kbg;gjhf Vw;Wf; nfhs;fpd;wh;. ,e;j Ntiyia Kjyhk; eguhy; 6 ehl;fspYk;> ,uz;lhk; eguhy; 8 ehl;fspYk; nra;a KbAk;. xU rpWtdpd; cjtpiaf; nfhz;L mth;fs; ,e;j Ntiyia 3 ehl;fspy; nra;J Kbf;fpd;wdh;. me;jj; njhif vt;thW gphpf;fg;gl Ntz;Lk;? A. Rs. 500, Rs. 300, Rs. 200 B. Rs. 400, Rs. 150, Rs. 550 C. Rs. 500, Rs. 375, Rs. 125 D. Rs. 600, Rs. 250, Rs. 150 Solution

1 1 1 1 8 4 3 1

Boy 3 6 8 24 24

1 1 1: : Multiply by 24 4 : 3 : 1

6 8 24

10001unit share= 125

8

Rs.500, Rs.375, Rs.125

35. 20 women can finish a piece of work in 16 days and 16men can finish it in

15days. What is the ratio of the working capacities of a man and a woman? xU Ntisia 20 ngz;fs; 16 ehl;fspYk; 16 Mz;fs; 15 ehl;fspYk; Kbf;fpwhh;fs;. Mz; kw;Wk; ngz;zpd; Ntiyj;jpwd; tpfpjkhdJ. A. 3:4 B. 4:3 C. 5:3 D. 2:1 Solution

16M 15D 20W 16D

1 Men 16 15 days 1 Women 20 16

Days ratio 3 : 4 Efficiency ratio 4 : 3

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36. A works twice as fast as B. If B can complete a work in 12 days independently, the number of days in which A and B can together finish the work is

A> B –I tpl 2 klq;F Ntfkhf Ntiy nra;fpwhh;. B xU Ntiyia jdpahf Kbf;f 12 ehl;fs; Mdhy;. A kw;Wk; B ,UtUk; Nrh;e;J me;j Ntiyia Kbf;f Njitg;gLk; ehl;fs; A. 4 days B. 6 days C. 8 days D. 18 days Solution

37. A can do a piece of work in 80 days. He works at it for 10 days and then B alone

finishes the remaining work in 42 days. In how much time will A and B working together finish the work?

xU Ntiyia A vd;gth; 80 ehl;fspy; nra;J Kbg;ghh;. mth; 10 ehl;fs; Ntiy nra;jgpd; kPjp Ntiyia B vd;gth; kl;Lk; 42 ehl;fspy; nra;J Kbj;jhh;. AAk; BAk; Nrh;e;J Ntiy nra;jhy; mt;Ntiyia mth;fs; vt;tsT fhyj;jpy; nra;J Kbg;ghh;. a. 28 days b. 30 days c. 29 days d. 31 days Solution

1

A1day work=80

A’s 10 days work 1 1

= 10=80 8

Remaining work 1 7

=1-8 8

B’s 7

8 work

842 48days

7

80×48A+B = =30days

128

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38. A, B together do a job in 6 days B, C together do the same job in 10 days, C, A,

todether do the same job in 1

72

days. If all three work together in how many

days will they complete the job? A, B ,UtUk; xU Ntiyia 6 ehl;fspy; nra;J Kbg;gh;. B> C ,UtUk;

mNj Ntiyia 10 ehl;fspy; nra;J Kbg;gh;. C> A ,UtUk; 1

72 ehl;fspy;

nra;J Kbg;gh;. %tUk; Nrh;e;J mt;Ntiyia vj;jid ehl;fspy; nra;J Kbg;gh;? A. 5 days B. 4 ½ days C. 4 days D. 3 days Solution

1 1 2

A+B= B+C= C+A=6 10 15

1 1 22(A+B+C)1day work= + +

6 10 15

5+3+4 12 2= = =

30 30 5

1A+B+C=

5

All three works together complete the job in 5 days.

39. ‘A’ pipe can fill a tank in 30 mins, ‘B’ pipe can fill the same in 28 mins. ¾ filed by B, then both opened. Find time to fill completely?

A. 21 min B. 20 min C. 24.6 min D. 25.6 min

A Foha; 30 epkplj;jpYk; B Foha; 28 epkplj;jpYk; xU njhl;bia epug;Gfpd;wd. Kjypy; ¾ gq;if B Foha; epug;GfpwJ gpwF ,uz;L Foha;fSk; jpwf;fg;gLfpd;wd vdpy;> mj;njhl;b KOtJkhf epuk;g vLj;Jf;nfhs;Sk; Neuk; vt;tsT?

A. 21 epkplq;fs; B. 20 epkplq;fs; C. 24.6 epkplq;fs; D. 25.6 epkplq;fs;

Solution

∴ In 1 minute Pipe B Can Fill tank = (1/28) 3/4 of the tank is filled in time = (3/4) ÷ (1/28) = 21 minutes After 21 minutes The tank remaining empty = 1 - (3/4) = (1/4)

Remaining part Filled by both = 1 30 28

3.6Minutes4 58

Total Time = 21 + 3.6 = 24.6 Minutes

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40. One pipe can fill a tank three times as fast as another pipe. If together the two pipes can fill the tank in 36 minutes, then the slower pipe alone will be able to fill the tank in: A. 81 min. B. 108 min C. 144 min D. 192 min. xU FohahdJ kw;nwhU Fohiag; Nghy 3 klq;F Ntfkhf epug;Gk;> ,t;tpuz;L Foha;fSk; Nrh;e;J 36 epkplj;jpy; xU njhl;bia epug;GfpwJ vdpy;> ,uz;lhtJ Foha; jdpahf mj;njhl;bia epug;g vLj;Jf;nfhs;Sk; Neuk; vt;tsT? A. 81 epkplq;fs; B. 108 epkplq;fs;

C.144 epkplq;fs; D. 192 epkplq;fs;

Solution

Let the slower pipe alone fill the tank in x minutes

Then, faster pipe will fill it in x/3 minutes

1 3 1

x 36

4 1

36

x

x

x = 144min

41. Two pipes can fill a cistern in 3 hours and 4 hours respectively and a waste pipe can empty it in 2 hours. If all the three pipes are kept open, then the cistern will be filled in: a) 5 hours b) 8 hours c) 10 hours d) 12 hours

xU njhl;bia ,U Foha;fs; jdpj;jdpNa KiwNa 3> kw;Wk; 4 kzpNeuj;jpy; epug;Gfpd;wJ. kw;nwhU Foha; ePh; epuk;gpa njhl;bia 2 kzpNeuj;jpy; fhyp nra;Ak;. njhl;b fhypahf ,Ue;J ,k;%d;W Foha;fSk; xNu rkaj;jpy; jpwe;J tplg;gl;lhy;> mj;njhl;b vj;jid kzpNeuj;jpy; epuk;Gk;?

a) 5 hours b) 8 hours c) 10 hours d) 12 hours Solution

Part of the cistern filled in 1 hour 1 1 1

3 4 2

4 3 2 1

12 12

Hence, the cistern will be filled in 12 hours

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42. If you write down all the numbers from 1 to 100, then how many times do you write 3? (a) 11 (b) 18 (c) 20 (d) 21 1 Kjy; 100 tiuapyhd vy;yh vz;fisAk; ePq;fs; vOjpdhy;> 3 vd;w vz;iz vj;jid jlit vOJtPh;fs;? (a) 11 (b) 18 (c) 20 (d) 21 Solution

3, 13, 23, 33, 43, 53, 63, 73, 83, 93 and ten numbers with 3 as the ten’s digit 30, 31, 32, 33, 34, 35, 36, 37, 38, 39 Total numbers = 20

43. A worker may claim Rs.15 for each km which he travels by taxi and Rs. 5 for

each km which he drives his own car. If in one week he claimed Rs 500 for traveling 80 km how many kms did he travel by taxi

A. 10 B. 20 C. 30 D. 40 xU cj;jpNahf];jh; / gzpahsh; jhk; gazk; nra;tjw;F 1 fpNyh kPl;lUf;F &.15 tPjk; gazg;gb thliff; fhhpy; nrd;why; ngwyhk;. jd; fhhpy; gazj;jhy; fpNyh kPl;lUf;F &.5 gazg;gb ngwyhk;. xU thuj;jpy; mth; &.500 gazg;gbia 80 fpNyh kPl;lh; gazj;jpw;F ngw;why; mth; thlif fhhpy; gazpj;j J}uk; vj;jid fpNyh kPl;lh;? A. 10 B. 20 C. 30 D. 40 Solution let x be the distance traveled by the worker by taxi. therefore distance traveled by the worker if he drived his own car=80-x. 15x+5*(80-x)=500 15x+400-5x=500 10x=100 x=10km 44. What is the angle between the minute hand and hour when he time is 2 – 15? A. 30° B. 22½° C. 27½° D. None of these kzp 2-15 ,Uf;Fk;NghJ epkpl Ks;Sf;Fk; kzp Ks;Sf;Fk; ,ilNa cs;s Nfhzk; vd;d? A. 30° B. 22½° C. 27½° D. ,it vJTkpy;iy Solution

1 hour angle = 30 In 15 Min = 7.5

Required angle = 30 - 7.5=22.5

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45. If A is older than B, C is older than B but younger than A. D is younger than E and B. B is older than E. Then identify who is youngest?

B ia tpl A %j;jth;> C vd;gth; B ia tpl %j;jtuhfTk; A it tpl ,isatuhfTk;. D vd;gth; E kw;Wk; B ia tpl ,isatuhfTk;> B vd;gth; E-ia tpl %j;jtuhfTk; cs;sdh;. vdpy; ,jpy; kpfTk; ,isath; ahh;? A. A B. B C. C D. D Solution A>C>B>E>D 46. Manoj and Sachin are ranked seventh and eleventh respectively from the top in

a class of 31 students. What will be their respective ranks from the bottom in the class?

A. 20th and 24th B. 24th and 20th C. 26th and 22nd D. 25th and 21st 31 khzth;fis nfhz;l xU tFg;gpy; kNdh[; kw;Wk; rr;rpdpd; juthpirahdJ NkypUe;J KiwNa VohtJ kw;Wk; gjpNdhwhtjhf ,Ue;jdh;. mt;tpUthpd; juthpirahdJ filrpapypUe;J vd;dthf ,Uf;Fk;? A. 20th, 24th B. 24th, 20th C. 26th, 22nd D. 25th, 21st Solution: Number of students behind Manoj in rank = (31 - 7) = 24. So, Manoj is 25th from the bottom. Number of students behind Sachin in rank = (31 - 11) = 20. So, Sachin is 21st from the bottom.

47. 2 2 2

3 2 2

16 2 3 2 3 11 4?

8 2 9 4 2 4

a a a a a

a a a a a

A. 1

3a B.

1

3 4a C.

2

3 4a D.

5

3 4a Solution

2 2

3 3 2

2 1 2 3 4 44

2 2 1 4 2 4

a a a aa

a a a a a

2

2

4 24 4 2 1 2 1

2 1 4 3 4 4 3 42 2 4

a aa a a a

a a a a aa a a

48. 2

2

( 8) ( 5 50)?

( 10) ( 13 40)

x x x

x x x

A. 2x B. 8

10

x

x

C. 2 D. 1

Solution

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8 10 51

10 5 8

x x x

x x x

49. x2 + y2 + z2 – 2xy + 2yz – 2zx –d; th;f;f%yk;

a. |x + y – z| b. |x – y + z| c. |x + y + z| d. |x – y – z|

The square root of x2 + y2 + z2 – 2xy + 2yz – 2zx a. |x + y – z| b. |x – y + z| c. |x + y + z| d. |x – y – z| Solution

22 2 2 2 2 2x y z xy yz zx x y z

= |x – y – z|

50. If 32 32x , then x is equal to:

a. 5 b. 3 c. 3

5 d.

5

3

32 32x vdpy; x d; kjpg;G fhz;f

a. 5 b. 3 c. 3

5 d.

5

3 Solution

1

3

53

2 32

2 2

53

x

x

x

51. The value of 8.94 8.94 8.94 3.56 3.56 3.56

8.94 8.94 8.94 3.56 3.56 3.56

is:

a. 0.538 b. 5.38 c. 0.0538 d. 53.8

8.94 8.94 8.94 3.56 3.56 3.56

8.94 8.94 8.94 3.56 3.56 3.56

d; kjpg;G fhz;f

a. 0.538 b. 5.38 c. 0.0538 d. 53.8 Solution

2 23 3

2 2 2 2

2a

2 2

a b a ab bba b

a ab b a ab b

a = 8.94 b = 3.56 a-b = 8.94 – 3.56 = 5. 38

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52. If 5 3

5 3x

and

5 3

5 3y

, then (x+y) equals

(a) 8 (b) 16 (c) 2 15 (d) 2 5 3

5 3

5 3x

kw;Wk;

5 3

5 3y

vdpy; (x+y) kjpg;G fhz;f

(a) 8 (b) 16 (c) 2 15 (d) 2 5 3

Solution

5 3 5 3 5 3 2 154 2 15

5 35 3 5 3

5 3 5 3 5 3 2 154 2 15

5 35 3 5 3

x

y

4 2 15 4 2 15 8x y

53. There are five colleges in city A and number of students enrolled is given in

diagram below. The percentage of Science students in college IV is what percentage of science students in city A? A. 10% B. 20% C. 30% D. 40%

A vd;w efuj;jpypYs;s 5 fy;Y}hpfspy; gapYk; khzth;fspd; tptuq;fs; fPo; cs;s tiuglj;jpy; nfhLf;fg;gl;Ls;sd. efuk; A tpy; gapYk; mwptpay; khzth;fspy;> fy;Y}hp 4y; gapYk; mwptpay; khzth;fspd; rjtPjk; _______? A. 10% B. 20% C. 30% D. 40% Solution

10

100 10%100

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54. Data on Coffee – Tea habits number of persons: Male Female Coffee 40 5 Tea 20 35 The percentage of tea drinkers among females is _______ A. 5% B. 35% C. 40% D. 87.5% fh/gp kw;Wk; NjePh; gof;fk; cs;sth;fspd; vz;zpf;if Mz;fs; ngz;fs; fh/gp 40 5 NjePh; 20 35 ngz;fspy; NjePh; Fbg;gth;fspd; rjtPjk; ahJ? A. 5% B. 35% C. 40% D. 87.5% Solution:

The percentage of tea drinkers among females = 20

100 87.5%35

55. From the graph given below, find out during how many years the growth rate

was below the average growth rate over the given years.

(A)3 (B)4 (C)5 (D)2 fPo;fhZk; tiuglj;jpy; nfhLf;fg;gl;Ls;s tUlq;fspy; ,Ue;J> vj;jid tUlq;fspy; tsh;r;rp tpfpjk; nkhj;j ruhrhp tsh;r;rp tpfpjj;ij tpl Fiwthf cs;sJ?

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(A)3 (B)4 (C)5 (D)2 Solution

Average = 70

8.758

Below the average growth rate 2010, 2011, 2012, 2013 4 years.

Directions (Q.No.56 ): Study the following bar-graph and answer the questions given below. mwpTiufs; (tpdhf;fs; 56): gpd;tUk; gl;b tiuglj;ijf; ftdkhf Ma;T nra;Jtpl;L> mjd; fPNo nfhLf;fg;gl;l tpdhf;fSf;F tpilaspf;fTk;.

56. What was the percentage increase in production of fertilizers in 2002 compared

to that in 1995? a. 320% b. 300% c. 220% d. 200%

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1995 Mz;Lld; xg;gpLk;NghJ 2002 Mz;bd; cw;gj;jp mjpfhpg;G tpOf;fhL vj;jidahf ,Ue;jJ? a. 320% b. 300% c. 220% d. 200% Solution:

Percentage increase = 80 25 55

100 100 220%25 25

57. Which one will replace the question mark? gpd;tUk; glj;jpypUe;J tpLgl;l vz;izf; fhz;f.

A. 36 B. 48 C. 38 D. 30

Solution: (0 + 2 + 6 + 4) - 2 = 10 and (6 + 2 + 10 + 8) - 2 = 24 Therefore, (4 + 14 + 12 + 10) - 2 = 38.

58. Which one will replace the question mark? gpd;tUk; glj;jpypUe;J tpLgl;l vz;izf; fhz;f.

A. 45 B. 41 C. 32 D. 40 Solution:

(15 x 2 - 3) = 27, (31 x 2 - 6) = 56 and (45 x 2 - 9) = 81

Directions (Q.No.59): On the basis of the information given below, answer questions. A. P, Q, R, S and T are sitting in a circle facing the centre B. R is immediate left of T C. P is between S and T 59 tpdhf;fhd mwpTiufs;: fPo;f;fz;l tptuq;fspd; mbg;gilapy>; tpdhf;fSf;F tpilaspf;fTk;.

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A. P, Q, R, S kw;Wk; T MfpNahh; ikaj;ij Nehf;fp xU tl;l tbtkhf mkh;e;Js;sdh;.

B. R Mdth;> Tf;F cldb ,lJ gf;fj;jpy; mkh;e;jpUf;fpwhh;.

C. S kw;Wk; T f;F ,ilapy; P mkh;e;Js;shh;.

59. Who is to the immediate left of R?

A. P B. Q C. S D. Cannot be determined Rf;F cldb ,lg;gf;fk; mkh;e;jpUg;gth; ahh;? A. P B. Q C. S D. eph;zapf;f ,ayhJ Solution

60. A and B travel the same distance at the speeds of 10 kmph and 15 kmph

respectively. If A takes 30 minutes longer than B then distance travelled is a. 15 km b. 20 km c. 90 km d. 30 km

A> B vd;Dk; ,Uth;> xNu J}uj;ij KiwNa 10 fp.kP/kzp> 15 fp.kP/kzp Ntfj;jpy; fle;J nry;fpwhh;. B-I tpl 30 epkplq;fs; mjpfk; A vLj;Jf; nfhs;fpwhh;. vdpy; mth;fs; fle;J nrd;w J}uk; vd;d? a. 15 fp.kP b. 20 fp.kP c. 90 fp.kP d. 30 fp.kP Solution A, B distance at the speeds

30

10 15 60

1

30 2

x x

x

x= 15km