Tinh Toan U-Trench Cover
Transcript of Tinh Toan U-Trench Cover
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Follow 22 TCN 272-05 for bridge and Culvert designing standard
Open Culvert Concrete grade f'c=
b= 1000 mm ==> =
L= 500 mm
h= 100 mm
50 mm
q= 6.8 0.68
=> p= 278.8N/mm
L= 500 mm
=> M= ### N.mm
Preliminarily determine the number of reforcement rebar:
240 Mpa ==>= 0.19
===> 860.901
rebar diameter: d= 16 mm ==> n= 4.28
Choose : n= 5.00 1005.31
reverification
The position of nuetral line will be determined base on the balance equation of
C = 11.322mma= 9.462 mm50mm
Destructive moment:
==> 10,922,278.62 (N.mm ) OK
Verification of the maximum steel content:
Condition:
Where: C= 11.322
50
0.23 < 0.42 OK
Verification of the minimum steel content:
Rk=
ts= E
c=
kg/cm2 = N/mm2
fy=
As= mm2
==>As= mm2
ds=
Mph
=
dc=
C/dc=
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Condition:
Where : 0.010 > 0.004
Result: OK
Final conclusion: OK
Pmin
=As/b.h=
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Follow The standart for bridge
30 Mpa 25
0.836 440
3.45 Mpa
930,977.31 Mpa
(or Mpa) 500
QT79
0.15
A= 0.13 ==> =
0.36
Where: 30.00
compressive and tensile stress: 240
b= 1000
50
==> 848.78
Choose rebar:
d= 16==> Choose n = 5
Verification:
==> = 0.16
###
Result: OK
c= T/m3
Ru=
Rt=
ho=
Ft=
==>Mph
=
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and Culvert designing dated in 1979 (Former Standard)
1000
410
==>
0.14
Mpa
Mpa
mm
mm
mm ==>n= 4.22nos ###
==> A= 0.15 and x= 8.04 mm
N.mm
mm2
==>Ft= mm2
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Follow 22 TCN 272-05 for bridge and Culvert designing standard
Open Culvert Concrete grade f'c
b= 4000 mm ==> =
L= 1900 mm
h= 200 mm
50 mm
===> Effective height of cross section:
150 mm
q= 6.8 0.68
=> p= 278.8N/mm
L= 1900 mm
=> M= ###N.mm
Moments of the compressive and tensile stress at the cen
we have these equation as follow:
Define:
and
The structure of reinforcement concrete shall meet the cr
and A=
Rebars arrangement:
-Compressive rebar:
Sellect: d'= 16 mm
280 Mpa
Preliminarily determine the number of compressive rebars:
Compressive rebar area:
-22,697.17 ==> n'=
Sellect: n'= 18nos ==>
-Tensile rebar:
Sellect: d= 16 mm
280 Mpa
The number of tensile rebar will be determined as follow:
Tensile rebar area:
33,672.69 ==> n=
Rk=
at= E
c=
ds=
kg/cm2 = N/mm2
=C/ds
1=
d's=
f'y=
A's= mm2
A's=
ds=
fy=
As= mm2
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Sellect: n= 22nos ==> As=
Re-Verification the force bearing capactity of reinforcement concrete:
0.01 ==> OK
and A= 0.01
The distance from outer side of compressive concrete area to the nuetral line
C= 2.64 mm
The height of compressive stress block will be:
a= 2.21 mm
The Ultimate destructive moment will be determined as follow:
###N.mm > MConclusion: PASS
Verification of the maximum steel content:
Condition:
Where: C= 2.64 mm
150
0.02 < 0.42 OK
Verification of the minimum steel content:
Condition:
Where : 0.006 > 0.003
Result: OK
Final conclusion:
Coefficient 1=
Mph
=
dc=
C/dc=
Pmin
=As/b.h=
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Follow The standart for bridge
30 Mpa 25
0.836 440
3.45 Mpa
930,977.31 Mpa
1900
(or Mpa)
QT79
ter line of tensile rebar or compressive concrete area
iteria of the ultimate steel contents where :
0.55
0.40
40.00 mm
-113 nos
3619
150.00 mm
167.47 nos
c= T/m3
mm2
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4,423.36
as follow:
mm2
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and Culvert designing dated in 1979 (Former Standard)
4000
410
==>
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Follow 22 TCN 272-05 for bridge and Culvert designing standard
Open Culvert Concrete grade f'c
b= 4000 mm ==> =
L= 1900 mm
h= 200 mm
50 mm
===> Effective height of cross section:
150 mm
q= 6.8 0.68
=> p= 278.8N/mm
L= 1900 mm
=> M= ###N.mm
Moments of the compressive and tensile stress at the cen
we have these equation as follow:
Define:
and
The structure of reinforcement concrete shall meet the cr
and A=
Rebars arrangement:
-Compressive rebar:
Sellect: d'= 16 mm
280 Mpa
Preliminarily determine the number of compressive rebars:
Compressive rebar area:
-22,697.17 ==> n'=
Sellect: n'= -112 nos ==>
-Tensile rebar:
Sellect: d= 16 mm
280 Mpa
The number of tensile rebar will be determined as follow:
Tensile rebar area:
7,534.64 ==> n=
Rk=
at= E
c=
ds=
kg/cm2 = N/mm2
=C/ds
1=
d's=
f'y=
A's= mm2
A's=
ds=
fy=
As= mm2
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Sellect: n= 38.00 nos ==> As=
Re-Verification the force bearing capactity of reinforcement concrete:
0.55 ==> Fail
and A= 0.40
The distance from outer side of compressive concrete area to the nuetral line
C= 99.07 mm
The height of compressive stress block will be:
a= 82.79 mm
The Ultimate destructive moment will be determined as follow:
###N.mm > MConclusion: PASS
Verification of the maximum steel content:
Condition:
Where: C= 99.07 mm
150
0.66 > 0.42 Fail
Verification of the minimum steel content:
Condition:
Where : 0.010 > 0.003
Result: OK
Final conclusion:
Coefficient 1=
Mph
=
dc=
C/dc=
Pmin
=As/b.h=
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Follow The standart for bridge
30 Mpa 25
0.836 440
3.45 Mpa
930,977.31 Mpa
1900
(or Mpa)
QT79
ter line of tensile rebar or compressive concrete area
iteria of the ultimate steel contents where :
0.55
0.40
40.00 mm
-113 nos
-22519
150.00 mm
37.47 nos
c= T/m3
mm2
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7,640.35
as follow:
mm2
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and Culvert designing dated in 1979 (Former Standard)
4000
410
==>
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Follow 22 TCN 272-05 for bridge and Culvert designing standard
Open Culvert Concrete grade f'c
b= 4000 mm ==> =
L= 1900 mm
h= 200 mm
50 mm
q= 6.8 0.68
=> p= 278.8N/mm
L= 1900 mm
=> M= ### N.mm
Preliminarily determine the number of reforcement rebar:
240 Mpa ==>= 0.12
===> 6,314.34
rebar diameter: d= 16 mm ==> n= 31.40
Choose : n= 32.00 6,434
reverification
The position of nuetral line will be determined base on the balance equation
C = 18.11 mma= 15.14 mm150 mm
Destructive moment:
==> 219,935,026.58 (N.mm ) OK
Verification of the maximum steel content:
Condition:
Where: C= 18.11
150
0.12 < 0.42 OK
Verification of the minimum steel content:
Rk=
ts= E
c=
kg/cm2 = N/mm2
fy=
As= mm2
==>As= mm2
ds=
Mph
=
dc=
C/dc=
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Condition:
Where : 0.008 > 0.004
Result: OK
Final conclusion: OK
Pmin
=As/b.h=
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Follow The standart for bridge
30 Mpa 25
0.836 440
3.45 Mpa
930,977.31 Mpa
(or Mpa) 1900
QT79
0.09
A= 0.08 ==> =
0.36
Where: 30.00
f compressive and tensile stress: 240
b= 4000
150
==> 6263.14
Choose rebar:
d= 16==> Choose n = 32
Verification:
==> = 0.09
###
Result: OK
c= T/m3
Ru=
Rt=
ho=
Ft=
==>Mph
=
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and Culvert designing dated in 1979 (Former Standard)
4000
410
==>
0.08
Mpa
Mpa
mm
mm
mm ==>n= 31.15nos 6433.98
==> A= 0.08 and x= 12.87 mm
N.mm
mm2
==>Ft= mm2
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