TimeDependentCurrents

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    Time dependent currents

    in RC circuits

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    A simple RC circuit:

    charging a capacitorIntroduce initial conditions:

    1. The capacitor is initially uncharged.

    2. The switch is closed at t = 0.

    Then apply Kirhhoffs

    rules to solve for I(t).

    This leads to a first order

    linear differential

    equation for q(t):

    - R dq/dt - q/C = 0 => q(t). Then I(t) = dq/dt

    t = 0

    I(t)

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    The solution is:

    q(t) = C[ 1 - exp(-t/RC) ]

    We define a time constant

    = RC (units seconds).

    This is a measure of how fast the

    circuit reaches equilibrium.

    A simple RC circuit

    I(t) = Io exp[-t/RC]

    with Io = /R

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    Example 1

    A 5 F capacitor is being charged by a battery. The circuit

    resistance is 3 .

    How long after closing the switch will it take before thecapacitor reaches 99% of its final voltage?

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    Introduce initial conditions:

    1. The capacitor is initially charged to Qo2. The switch is closed at t = 0.

    As before apply Kirhhoffs

    rules to solve for q(t).

    q(t) = Qo exp(-t/RC) and I(t) = - dq/dt = Qo/RC exp(-t/RC)

    A simple RC circuit:

    discharging a capacitort = 0

    I(t)

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    A simple RC circuit:

    discharging a capacitor

    q(t) = Qo exp(-t/RC) I(t) = Qo/RC exp(-t/RC)Io = Qo/RC

    = RC

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    Measuring DC currentand voltage

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    The heart of current, volt and ohm meters is a galvanometerthat can measure very small currents.

    The currents pass through a wire

    coil in a magnetic field.This causes a torque on the coil

    and it rotates to equilibrium opposite

    to the torque applied by

    an opposing spring.The rotation is recorded on a scale

    that is calibrated to the current.

    A galvanometer

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    Measuring currents (ammeter) and

    voltages (voltmeter)

    A galvanometer

    records small currents

    on a digital or analogue meterI

    V

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    Magnetic forces and fields

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    For the electrostatic force we developed a field formalismwhere, given the electric field E, the force on a pointparticle q is:

    Fq = q E

    We now want to develop a similar field formalism for themagnetic force.

    The magnetic force on a pointparticle q is:

    Fq = q v x B

    Introduction: the magnetic force

    SI units of E V/m

    SI units of B Tesla

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    The magnetic force

    on a point particle

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    Given the electric and magnetic fields E and B, thecompletely general equation for the force on a

    point particle q is:

    Fq = q E + q v x B

    This is referred to as the Lorentz equation.

    The force on an any charged object is obtained by summing(or integrating) over the forces on each point qi (ordifferential dq ) charge component.

    The complete EM force

    The fundamental

    force law of

    electromagnetism

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    Example 3 (velocity selection)

    How can electric and magnetic fields be used to

    velocity- select particles?

    That is given a beam of particles with charge q and a

    continuous spectrum of velocities, select those

    with velocity vo .

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    Circular motion in a

    Uniform B field

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    Since a current is moving charges, there is a magnetic forceon a current carrying wire.

    For a straight segment of wire carrying a constant current

    I, the force isF = I L x B

    where L is a vector along the wire in the direction of thecurrent

    Magnetic force on

    a current carrying wire