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Transcript of ThermodynamicsM. D. Eastin Adiabatic Processes How can the first law really help me forecast...
Thermodynamics M. D. Eastin
Adiabatic Processes
How can the first law really help me forecast thunderstorms?
1000 mb1000 mb
Thermodynamics M. D. Eastin
Outline:
Review of The First Law of Thermodynamics Adiabatic Processes Poisson’s Relation
Applications Potential Temperature
Applications Dry Adiabatic Lapse Rate
Applications
Adiabatic Processes
Thermodynamics M. D. Eastin
First Law of Thermodynamics
pdα dTcdq v
Statement of Energy Balance / Conservation:
• Energy in = Energy out• Heat in = Heat out
HeatingSensible heating Latent heating
Evaporational cooling Radiational heating Radiational cooling
Change in Internal Energy
Work DoneExpansion
Compression
Thermodynamics M. D. Eastin
Forms of the First Law of Thermodynamics
For a gas of mass m For unit mass
dW dUdQ pdV dUdQ
pdV dTcdQ v
Vdp dTcdQ p
dw du dq pd du dq
pd dTcdq v
dp dTcdq p
where: p = pressure U = internal energyV = volume W = workT = temperature Q or q = heat energyα = specific volume n = number of moles
cv = specific heat at constant volume (717 J kg-1 K-1)cp = specific heat at constant pressure (1004 J kg-1 K-1)Rd = gas constant for dry air (287 J kg-1 K-1)R* = universal gas constant (8.3143 J K-1 mol-1)
nRcc *vp Rcc dvp
Thermodynamics M. D. Eastin
Types of ProcessesIsothermal Processes:
• Transformations at constant temperature (dT = 0)
Isochoric Processes:
• Transformations at constant volume (dV = 0 or dα = 0)
Isobaric Processes:
• Transformations at constant pressure (dp = 0)
Adiabatic processes:
• Transformations without the exchange of heat between the environment and the system (dQ = 0 or dq = 0)
Thermodynamics M. D. Eastin
Adiabatic ProcessesBasic Idea:
• No heat is added to or taken from the system which we assume to be an air parcel
• Changes in temperature result from either expansion or contraction
• Many atmospheric processes are “dry adiabatic”• We shall see that dry adiabatic process play a large role in deep convective processes
• Vertical motions• Thermals
Parcel0pdα dTcdq v
0dp dTcdq p
Thermodynamics M. D. Eastin
Adiabatic ProcessesP-V Diagrams:
p
V
f
i
Isotherm
Isobar
Adiabat
Isochor
Thermodynamics M. D. Eastin
Poisson’s* RelationA Relationship between Temperature and Pressure:
• Begin with:
• Substitute for “α” using the Ideal Gas Law and rearrange:
• Integrate the equation:
* NOT pronounced like “Poison”
dp dTcp
See: http://en.wikipedia.org/wiki/Simeon_Poisson
TRpα d
p
dp
c
R
T
dT
p
d
final
intital
final
initial
p
pp
d
T
T p
dp
c
R
T
dT
Adiabatic Form of the First Law
Thermodynamics M. D. Eastin
Poisson’s RelationA Relationship between Pressure and Temperature:
• After Integrating the equation:
• After some simple algebra:
• Relates the initial conditions of temperature and pressure to the final temperature and pressure
initial
final
p
d
initial
final
p
pln
c
R
T
Tln
p
dc
R
initial
final
initial
final
p
p
T
T
p
dc
R
initial
finalinitialfinal p
pT T
Thermodynamics M. D. Eastin
Applications of Poisson’s Relation
Example: Cabin Pressurization
• Most jet aircraft are pressurized to 8,000 ft (or 770 mb). If the outside air temperature at a cruising altitude of 30,000 feet (300 mb) is -40ºC, what is the temperature inside the cabin?
p
dc
R
initial
finalinitialfinal p
pT T
Thermodynamics M. D. Eastin
Applications of Poisson’s Relation
Example: Cabin Pressurization
• Most jet aircraft are pressurized to 8,000 ft (or 770 mb). If the outside air temperature at a cruising altitude of 30,000 feet (300 mb) is -40ºC, what is the temperature inside the cabin?
pinitial = 300 mb Rd = 287 J / kg Kpfinal = 770 mb cp = 1004 J / kg K
Tinitial = -40ºC = 233KTfinal = ???
p
dc
R
initial
finalinitialfinal p
pT T
Thermodynamics M. D. Eastin
Applications of Poisson’s RelationExample: Cabin Pressurization
• Most jet aircraft are pressurized to 8,000 ft (or 770 mb). If the outside air temperature at cruising altitude of 30,000 feet (300 mb) is -40ºC, what is the temperature inside the cabin?
pinitial = 300 mb Rd = 287 J / kg Kpfinal = 770 mb cp = 1004 J / kg K
Tinitial = -40ºC = 233K1004
287
final 300mb
770mbK 233 T
K 305 Tfinal
C32 Tfinal
Thermodynamics M. D. Eastin
Comparing Temperatures at different Altitudes:
Are they relatively warmer or cooler?
• Bring the two parcels to the same level• Compress 300 mb air to 600 mb
-37-37ooCC300 mb300 mb
22ooCC600 mb600 mb
Applications of Poisson’s Relation
p
dc
R
initial
finalinitialfinal p
pT T
Thermodynamics M. D. Eastin
Comparing Temperatures at different Altitudes:
Are they relatively warmer or cooler?
pinitial = 300 mbpfinal = 600 mbTinitial = -37ºC = 236 K
Tfinal = 288 K = 15ºC
Note: We could we have chosen to expand the 600 mb parcel to 300 mb for the comparison
-37-37ooCC300 mb300 mb
22ooCC600 mb600 mb
Applications of Poisson’s Relation
p
dc
R
initial
finalinitialfinal p
pT T
1515ooCC
Thermodynamics M. D. Eastin
Potential TemperatureSpecial form of Poisson’s Relation:
Compress all air parcels to 1000 mb• Provides a “standard”• Avoids using an arbitrary pressure level
• Define Tfinal = θ• θ is the potential temperature
where: p0 = 1000 mb
1000 mb1000 mb
p
dc
R
initialinitial p
1000mbT θ
p
dc
R
0
p
pT θ
Thermodynamics M. D. Eastin
Comparing Temperatures at different Altitudes:
An aircraft flies over the same location at two different altitudes and makes measurements of pressure and temperature within air parcels at each altitude:
Air parcel #1: p = 900 mbT = 21ºC
Air Parcel #2: p = 700 mbT = 0.6ºC
Which parcel is relatively colder? warmer?
Applications of Potential Temperature
p
dc
R
0
p
pT θ
Thermodynamics M. D. Eastin
Comparing Temperatures at different Altitudes:
Air Parcel #1: p = 900 mbT = 21ºC = 294 K
Air Parcel #2: p = 700 mbT = 0.6ºC = 273.6 K
The parcels have the same potential temperature!Are we measuring the same air parcel at two different levels?
Applications of Potential Temperature
286.0
900mb
1000mb294K θ
K303 θ
286.0
700mb
1000mb273.6K θ
K303 θ
Thermodynamics M. D. Eastin
Potential Temperature Conservation:
• Air parcels undergoing adiabatic transformations maintain a constant potential temperature (θ)
• During adiabatic ascent (expansion) the parcel’s temperature must decrease in order to preserve the parcel’s potential temperature • During adiabatic descent (compression) the parcel’s temperature must increase in order to preserve the parcel’s potential temperature
Applications of Potential Temperature
Constant θ
Thermodynamics M. D. Eastin
Potential Temperature as an Air Parcel Tracer:
• Therefore, under dry adiabatic conditions, potential temperature can be used as a tracer of air motions
• Track air parcels moving up and down (thermals)• Track air parcels moving horizontally (advection)
Applications of Potential Temperature
Co
ns
tan
t θ
Constant θ
Thermodynamics M. D. Eastin
How does Temperature change with Height for a Rising Thermal?
• Potential temperature is a function of pressure and temperature: θ(p,T)
• We know the relationship between pressure (p) and altitude (z):
• We can use this hydrostatic relation and the adiabatic form of the first law to obtain a relationship between temperature and height when potential temperature is conserved (dry adiabatic lapse rate)
Dry Adiabatic Lapse Rate
dz
dp g
HydrostaticRelation
dp dTcp Adiabatic Form of the First Law
TT
zzDry Adiabatic Dry Adiabatic Lapse Rate?Lapse Rate?
Thermodynamics M. D. Eastin
How does Temperature change with Height for a Rising Thermal?
• Begin with the first law:
• Substitute for “α” using the Ideal Gas Law and rearrange:
• Divide each side by “dz”:
• Substitute for “dp/dz” using the hydrostatic relation and re-arrange:
Dry Adiabatic Lapse Rate
dz
dp g
dp dTcp
p
dp
c
R
T
dT
p
d
dz
dp
p
1
c
R
dz
dT
T
1
p
d
p
d
c
g
p
TR
dz
dT
Thermodynamics M. D. Eastin
How does Temperature change with Height for a Rising Thermal?
• Substitute for “ρ” using the Ideal Gas Law and cancel terms:
• We have arrived at the Dry Adiabatic Lapse Rate (Γd):
Dry Adiabatic Lapse Rate
TRp dp
d
c
g
p
TR
dz
dT
pc
g
dz
dT
kmCd /8.9c
g
dz
dT
p
Thermodynamics M. D. Eastin
Example: Temperature Change within a Rising Thermal
• A parcel originating at the surface (z = 0 m, T = 25ºC) rises to the top of the mixed boundary layer (z = 800 m). What is the parcel’s new air temperature?
Application of the Dry Adiabatic Lapse Rate
Constant θ
Mixed Layer
kmC /8.9 dz
dT initialfinal T dz)/8.9( T kmC
258.0*8.9 Tfinal
C17.2 Tfinal
Thermodynamics M. D. Eastin
Summary:
• Review of The First Law of Thermodynamics• Adiabatic Processes• Poisson’s Relation
• Applications• Potential Temperature
• Applications• Dry Adiabatic Lapse Rate
• Applications
Adiabatic Processes
Thermodynamics M. D. Eastin
ReferencesPetty, G. W., 2008: A First Course in Atmospheric Thermodynamics, Sundog Publishing, 336 pp.
Tsonis, A. A., 2007: An Introduction to Atmospheric Thermodynamics, Cambridge Press, 197 pp. Wallace, J. M., and P. V. Hobbs, 1977: Atmospheric Science: An Introductory Survey, Academic Press, New York, 467 pp.