The wind is blowing on a turbine 10 feet in diameter at a velocity of 12 mph. What is the power...

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The wind is blowing on a turbine 10 feet in diameter at a velocity of 12 mph. What is the power developed by the turbine? Power = 0.5 x Swept Area x Air Density x Velocity 3 2 2 2 d Swepterea 4 d 10 ft 3.048 m 3.048 Swepterea 32.96 m 4 Air density =1.23 k g/m 3 ft m m 1 m m v 12 mi 5280 .3048 19,312,3 5.36 mi ft h 3600 s s Power = 0.5 x 32.96x 1.23x 5,36 3 = 3121 W Solution;

Transcript of The wind is blowing on a turbine 10 feet in diameter at a velocity of 12 mph. What is the power...

Page 1: The wind is blowing on a turbine 10 feet in diameter at a velocity of 12 mph. What is the power developed by the turbine? Power = 0.5 x Swept Area x Air.

The wind is blowing on a turbine 10 feet in diameter at a velocity of 12 mph. What is the power developed by the turbine?

Power = 0.5 x Swept Area x Air Density x Velocity3

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22

dSwept erea

4d 10 ft 3.048m

3.048Swept erea 32.96m

4

Air density =1.23 k g/m3

ft m m 1 m mv 12mi 5280 .3048 19,312,3 5.36

mi ft h 3600 s s

Power = 0.5 x 32.96x 1.23x 5,363 = 3121 W

Solution;

Page 2: The wind is blowing on a turbine 10 feet in diameter at a velocity of 12 mph. What is the power developed by the turbine? Power = 0.5 x Swept Area x Air.

2. It is desired to obtain 25 kW of AC out of a solar array at 120 VAC, pf = 1. The inverter has an efficiency of 85% and requires 50 VDC to operate. Solar cells are available that provide a voltage output of 0.5 V at 3 A. A How many solar cells are required with a 20% safety factor?Describe the connection diagram of the solar panel array. It is not necessary to draw it.

Solution:

I = 25kW/120V = 208.33 AWith a 30E% safety factor, I = 208.33*1.2 = 250 AThis will require 250/3 = 83.33 = 84 rows (no partial rows.In series, 50/0.5 = 100 solar cells are required.

Page 3: The wind is blowing on a turbine 10 feet in diameter at a velocity of 12 mph. What is the power developed by the turbine? Power = 0.5 x Swept Area x Air.

Therefore, a total of 100 x 84 = 8400 solar cells are required.Allowing for the 85% efficiency of the inverter, 84/.85 = 98.8 = 99 rows are required and 100 in series are still required. Therefore, 100 X 99 = 9900 solar cells are required, 99 rows in parallel and 100 solar cells in seriesThe approximate cost is $625