test _2015-2016
description
Transcript of test _2015-2016
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11111
XII
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1.VISUAL WILL BE SHOWN FOR 10 SECONDS.1.VISUAL WILL BE SHOWN FOR 10 SECONDS.
2.THERE ARE QUESTIONS IN EACH VISUAL. 2.THERE ARE QUESTIONS IN EACH VISUAL.
4.ANSWERS ARE TO BE GIVEN ONLY WHILE 4.ANSWERS ARE TO BE GIVEN ONLY WHILE THE VISUAL IS BEING SHOWN TO YOU.THE VISUAL IS BEING SHOWN TO YOU.
3.EACH ANSWER CARRIES ONE MARK.3.EACH ANSWER CARRIES ONE MARK.
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00:1000:0900:0800:0700:0600:0500:0400:0300:0200:0100:00Que 1
HBr AND HI REDUCE SULPHURIC ACID HCl CAN REDUCE KMnO4 AND HF CAN REDUCEa)H2SO4 b) KMnO4c) K2Cr2O7 d) NONE OF THESE
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00:1000:0900:0800:0700:0600:0500:0400:0300:0200:0100:00Que 2
THE BONDS PRSENT IN N2O5 AREA)ONLY IONIC B)COVALENT AND COORDINATEC) ONLY COVALENTD) COVALENT AND IONIC
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00:1000:0900:0800:0700:0600:0500:0400:0300:0200:0100:00Que 3
AMONGST THE TRIHALIDES OF NITROGEN WHICH ONE
IS LEAST BASIC?A)NF3 B) NCl3
C) NBr3 d) Nl3
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00:1000:0900:0800:0700:0600:0500:0400:0300:0200:0100:00Que.4THERE IS NO S-S BOND IN
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00:1000:0900:0800:0700:0600:0500:0400:0300:0200:0100:00Que 5THE FOLLOWING ACIDS HAVE BEEN ARRANGED IN THE ORDER OF DECREASING ACID STRENGTH. IDENTIFY THE CORRECT ORDER.ClOH(I), BrOH(II),IOH(III)
A)I>II>III B) II>I>IIIC) III>II>I D) I>III>II
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00:1000:0900:0800:0700:0600:0500:0400:0300:0200:0100:00Que 6
ONE MOLE OF CALCIUM PHOSPIDE ON REACTION WITH EXCESS WATER GIVESA)ONE MOLE OF PHOSPHINEB) TWO MOLES OF PHOSPHORIC ACIDC) TWO MOLES OF PHOSPHINED) ONE MOLE OF PHOSPHORUS PENTAOXIDE
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00:1000:0900:0800:0700:0600:0500:0400:0300:0200:0100:00Que 7AMONGST H2O H2S H2 Se AND H2 Te, THE ONE WITH HIGHEST BOILING POINT ISA)H2O BECAUSE OF HYDROGEN BONDING
B)H2Te BECAUSE OF HIGHER MOLECULAR WEIGHTC)H2S BECAUSE OF HYDROGEN BONDING
D)H2 Se BECAUSE OF LOWER MOLECULAR WEIGHT
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00:1000:0900:0800:0700:0600:0500:0400:0300:0200:0100:00Que 08
FOR H3PO3 AND H3 PO4 THE CORRECT CHOICE ISA)H3PO3 IS DIBASIC AND REDUCING
B)H3PO3 IS DIBASIC AND NON-REDUCING
C)H3PO4 IS TRIBASIC AND REDUCING
D)H3PO3 IS TRIBASIC AND NON REDUCING
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Que.09
WHEN I IS OXIDISED BY KMnO4 IN
ALKALINE MEDIUM, I CONVERTS INTO
A)IO-3 B) I2
C) IO4 D) IO-
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00:1000:0900:0800:0700:0600:0500:0400:0300:0200:0100:00Que 10
A PALE BLUE LIQUID WHICH OBTAINED BY EQUIMOLAR MIXTURE OF TWO GASES AT -300C IS-A)N2O B) N2O3C) N2O4 D) N2O5
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00:1000:0900:0800:0700:0600:0500:0400:0300:0200:0100:00Que 11THE PERCENTAGE OF P-CHARACTER IN THE ORBITALS FORMING P-P BONDS IN P4 ISA)25 B) 33C) 50 D) 75
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QUES 12
EXTRA PURE N2 CAN BE OBTAINED BY HEATINGA)NH3 WITH CuO B) NH4 NO3C) (NH4)2Cr2O7D) Ba(N3)2
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QUES 13THE REACTION OF WHITE PHOSPHORUS NaOH GIVES PHOSPHINE ALONG WITH ANOTHER PHOSPORUS CONTAINING COMPOUND. THE REACTION TYPE; THE OXIDATION STATES OF PHOSPHORUS IN PHOSPHINE AND THE OTHER PRODUCT ARE RESPECTIVELY:-A)REDOX REACTION-3 AND -5B) REDOX REACTION; 3 AND +5C) DISPROPORTIONATION REACTION;-3 AND +1D)DISPROPORTIONATION REACTION;-3 AND +3
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QUES-14
CONCENTRATED NITRIC ACID, UPON LONG STANDING, TURNS YELLOW BROWN DUE TO THE FORMATION OF ;-A)NOB)NO2C)N2OD)N2O4
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QUES 15
WHICH OF THE FOLLOWING PROPERTIES IS
NOT SHOWN BY NO?
A)IT IS DIAMAGNETIC IN GASEOUS STATE
B) IT IS A NEUTRAL OXIDE
C)IT IS BROWN IN COLOUR
D)IT DIMERISES AT ROOM TEMPERATURE
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CONCENTRATED NITRIC ACID OXIDIZES IODINE TO A)HI B)HIO3C)HIO4 D) I2O7
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QUES-17
WHICH OF THE FOLLOWING EQUATIONS IS NOT CORRECTLY FORMULATED?A- 2Na+2NH3 2NaNH2+H2
B- 8NH3+ 3Cl2 N2+ 6NH4 Cl excessC- NH3+3Cl2 NCl3+3HCl excessD- 4NH3+2NaOCl 2NH4Cl+2NaNH2+O2
heat
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Ques-18
PHOSPHORUS ACID HAS A)ONE HYDROGEN ATOM ATTACHED TO PHOSPHORUSB) TWO HYDROGEN ATOMS ATTACHED TO PHOSPHORUSC) THREE HYDROGEN ATOMS ATTACHED TO PHOSPHORUSD) NO HYDROGEN ATOM ATTACHED TO PHOSPHORUS
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QUES-19WHICH OF THE FOLLOWING STATEMENTS REGARDING PHOSPHORUS PENTOXIDE IS NOT CORRECT?A)IT IS AN ANHYDRIDE OF METAPHOSPHORIC ACIDB) IT IS A STRONG DEHDRATING AGENTC)IN PHOSPHORUS PENTOXIDE, EACH PHOSPHORUS IS ATTACHED TO THREE OXYGEN ATOMS AND ALSO WITH ANOTHER OXYGEN ATOM THROUGH COORDINATE BONDD)THE DEHYDRATED PRODUCT OF HNO3 OBTAINED BY TREATING WITH PHOSPHORUS PENTOXIDE IS NITROGEN PENTOXIDE
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QUES-20
HYPOPHOSPHORUS ACID IS
A)MONOBASIC
B) DIBASIC
C) TRIBASIC
D) NEUTRAL
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QUES-21
PYROPHOSPHOROUS ACID HAS THE
MOLECULAR FORMULA
A)H3PO3 B) H3PO4
C) H4P2O5 D) H4P2O7
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QUES-22
AMONG THE HYDROHALIC ACIDS, THE
STRONGEST ONE IN WATER IS
A)HF
B) HCl
C) HBr
D) HI
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QUES-23
HYPOCHLOROUS ACID IS
A)HClO B) HClO2
C) HClO3 D) HClO4
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QUES-24
THE ANHYDRIDE OF PERCHLORIC ACID IS
A)ClO2 B) ClO2
C) Cl2O3 D) Cl2O7
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QUES-25
WHICH OF THE FOLLOWING
HYDROGEN HALIDES HAS MAXIMUM
BOILING POINT?
A)HF b) HCl
C) HBr D) Hl
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Ques-26
WHEN IODINE REACTS WITH A HOT
AND CONCENTRATED SOLUTION OF
SODIUM HYDROXIDE THE PRODUCTS
OBTAINED ARE
A)I +IO B) I +IO3
C) I + IO 4 D) I + I2O 9
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QUES-27
SELECT THE INCORRECT REACTIONA) H3PO3 H+ +H2PO3
-
B) H2PO2- H+HPO2
2-
C) H3PO4 H+ +H2PO4D) H2PO3
- HPO32- + H+
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QUES-28
THE SOLID PCl5 EXISTS AS
A) PCl5 MOLECULES
B) P2 Cl10
C) [PCl4]+[PCl6]-
D) [PCl3]-[-Cl-P+Cl6-]
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Ques-29
WHICH SET DESCRIBES SHAPES OF XeF2, XeF4, XeF6, RESPECTIVELY?A) V-SHAPED, TETRAHEDRAL, OCTAHEDRALB)LINEAR, TETRAHEDRAL, DISTORTED OCTAHEDRALC) V-SHAPED, SQUARE PLANAR, OCTAHEDRALD) LINEAR, SQUARE PLANAR, DISTORTED, OCTAHEDRAL
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QUES-30
THE MIXTURE OF CONCENTRATED HCl and HNO3 MADE IN 3:1 RATIO CONTAINSA) ClO2 B). NOCl
C) NCl3 D). N2O4
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QUES-31
WHICH IS THERMODYNAMICALLY
MORE STABLE COMPLEX?
A) Ni2+ B) Pt2+
C) Co+2 D) BOTH (1) & (2)
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WHICH OF THE FOLLOWING IS MOST BASIC?A) CrO3 B). CrO
C) Cr2O3 D). Mn2O7
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Ques-33
WHICH OF THE FOLLOWING ION
IS DIAMAGNETIC?
A) Cu+2 B) Hg2+2
C). Fe3+ D). Mn+5
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Ques-34
TWO METAL ION Cu+2 AND V+4 OF TRANSITION METAL POSSESS SAME COLOUR BECAUSEA)BOTH HAVE SAME SIZEB)BOTH BELONG WITH SAME 3d SERIESC)BOTH ION HAVE SAME NO.OF UNPAIRED e-D) BOTH ION CAN VARY ITS OXIDATION STATE
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QUES-35
THE PURPLE COLOUR OF KMnO4 IS DUE TO A) INCOMPLETE d-SUBSHELLB) IONIC NATURE OF KMnO4
C) CHARGE TRANSFERD) RESONANCE IN MnO4
-ION
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QUES 36
IN WHICH CASE THERE IS CHANGE IN OXIDATION NUMBER?A) Aq.SOLUTION OF CrO42- IS ACIDIFIEDB) SO2 GAS IS PASSED INTO Cr2O7
2-/H+
C) Cr2O72- SOLUTION IS MADE ALKALINE
D) CrO2 Cl2 IS DISSOLVED IN NaOH
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QUES-37
A B
C D
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QUES-38Cr2O7 2- Ph=x CrO4 2- Ph=Y Cr2 O7 2-
pH VALUES X AND Y CAN BEA) 4 AND 5B) 4 AND 8C) 8 AND 4D) 8 AND 9
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QUES-39
WHEN EXCESS OF KCN IS ADDED TO A SOLUTION OF CuSO4, THE FINAL PRODUCT OBTAINED ISA) K2[Cu(CN)4] B). K3[Cu(CN)4]C)- CuCN D). K[Cu(CN)2]
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QUES-40
AMONGST Ni(CO)4, [Ni(CN)4]2- AND [NiCl4]2-
A) Ni(CO)4 AND (NICl4)2- ARE DIAMAGNETIC AND [Ni(CN)4]2- IS PARAMAGNETICB) [NiCl4]2- AND [NI(CN)4]2- DIAMAGNETIC AND Ni(CO)4 IS PARAMAGNETICC) Ni(CO)4 AND [Ni(CN)4]2- ARE DIAMAGNETIC AND [NiCl4]2- IS PARAMAGNETICD) Ni(CO)4 IS DIAMAGNETIC [NlCl4]2- AND [Ni(CN)4]2- ARE PARAMAGNETIC
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IN THE COMPLEX [Pt(Py)4][PtCl4], THE OXIDATION NUMBER OF Pt ATOM IN FORMER AND LATER PART OF THE COMPOUND ARE RESPECTIVELY.A) 0 AND 0 B). +4 AND +2C). +2 AND +2 D). 0 AND +4
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QUES-42WHICH ONE OF THE FOLLOWING COMPLEX ENTITIES WILL HAVE DIPOLE MOMENT=0?i.[Ni(CN)4]2-
ii.CIS-[Pt(NH3)2 Cl2]
iii.TRANS-Pt(NH3)2 Cl2]A) (iii) B). (i), (iii)C). (i) D). (ii), (iii)
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Ques-43IN WHICH OF THE FOLLOWING PAIRS OF SPECIES THE NUMBER OF UNPAIRED ELECTRONS ARE SAME
A
B
C
D
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Ques-44
A METAL ION HAS d6 CONFIGURATION. IN
OCTAHEDRAL COMPLEX ENTITY OF LOW
SPIN, THE NUMBER OF ELECTRONS PRESENT
IN eg SET OF ORBITALS IS
A)6 B) 4
C) 0 D) 2
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Ques-45
GIVE THE CORRECT INCREASING ORDER OF ELECTRICAL CONDUCTIVITY OF AQUEOUS SOLUTION OF FOLLOWING COMPLEX ENTITIES
(I)[Pt(NH3)6]Cl4 (ii) [Cr(NH3)6]Cl3
(iii) [Co(NH3)4Cl2]Cl (iv) K2[PtCl4]A) (iii)<(iv)<(ii)<(i) (B) (iv)<(ii)<(iii)<(i)(C) (ii)<(i)<(iv)<(iii) (D) (i)<(ii)<(iv)<(iii)
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QUES-46WHAT HAPPENS WHEN EXCESS Kl IS ADDED TO (i)CuSO4 (ii) HgCl2 (iii) Pb(NO3)2?
A) A WHITE PPT OF CUL IN (i) AN ORANGE PPT OF Hgl2 in (ii) AND A YELLOW PPT OF Pl2 in (iii)B) A WHITE PPT OF Cul in (i) AN ORANGE PPT. DISSOLVING TO HGL2-
4 IN (ii) AND A YELLOW PPT OF PBl2 in (iii)C) A WHITE PPT. OF Cul Hgl2 AND PBl2 IN EACH CASE D) NONE OF THESE
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QUES-47
IN NESSLER’S REAGENT, THE ACTIVE ION ISA) Hg+
B) Hg2+
C) [Hgl]2-
D) [Hgl4]2-
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Ques-48WHICH OF THE PROPERTY OF PH3 SHOWS THAT IT IS BASIC NATURE?A) IT REACTS WITH ACIDS LIKE Hl TO FORM PH4l.B)DUE TO PRESENCE OF LONE PAIR ELECTRONC)BOTH (A) AND (B)D) NONE OF THE ABOVE
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QUES-49
IN PCl5
A)ALL FIVE BONDS ARE EQUIVALENTB)THREE EQUATORIAL P-Cl BONDS ARE EQUIVALENTC) TWO AXIAL BONDS ARE LONGER THAN EQUATORIAL BONDSD) BOTH (B) AND (C)
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QUES-50
IN A REACTION OF Cl2 WITH HOT AND CONCENTRATED NaOHA)OXIDATION STATE OF CHLORINE CHANGES TO -1B) OXIDATION STATE OF CHLORINE CHANGES TO +5C)IT IS DISPROPORTIONATION REACTIOND)ALL OF THE ABOVE
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00:1000:0900:0800:0700:0600:0500:0400:0300:0200:0100:00QUES-51
FOR BrF3 SHAPE, THE INCORRECT STATEMENT IS A)THERE ARE THREE BOND PAIRS AND TWO LONE PAIRB) LONE PAIRS OCCUPY EQUATORIAL POSITION C)AXIAL FLURINES ARE LINEARLY ARRANGED D)IT HAS BENT T-SHAPE
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QUES-52
HYDROLYSIS OF XeF6
A)IS A REDOX REACTION
B) IS NOT A REDOX REACTION
C)GIVES OXYFLUORIDE
D)BOTH (B) AND (C)
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QUES-53
COVALENCY OF NITROGEN IN N2O5 IS
A)3
B)4
C)5
D)2
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QUES-54
BOND ANGLE IN PH+4 IS HIGHER THAN THAT
IN PH3 BECAUSE
A)PH+4 IS SP3D HYBRIDISED , PH3 IS SP3d
HYBRIDISED B)THRE IS NO BOND PAIR-BOND PAIR REPULSION IN PH+
4
C) THERE IS NO BOND PAIR-LONE PAIR
REPULSION IN PH+4
D) THERE IS NO BOND PAIR LONE REPULSION IN PH3
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QUES-55
TRANSITION ELEMENTS EXHIBITS HIGHER ENTHALPIES OF ATOMIZATION BECAUSEA)OF LARGE NUMBER OF UNPAIRED ELECTRONSB) OF HAVING STRONGER INTERATOMIC INTERACTIONC)OF STRONG BONDING BETWEEN ATOMSD)ALL OF THE ABOVE
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QUES-56
Cu+ ION IS NOT STABLE IN AQUEOUS SOLUTION BECAUSE A)IT UNDERGOES DISPROPORTION TO GIVE CU(S) AND CU2+ IONB) IT CAN NOT UNDERGO DISPROPORTION IN AQUEOUS SOLUTION AS E0 IS NOT FAVOURABLEC) CU+ IS VERY MUCH STABLE IN AQUEOUS SOLUTIOND)(B) AND (C) ARE CORRECT
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00:1000:0900:0800:0700:0600:0500:0400:0300:0200:0100:00QUES-57
INCORRECT REACTION ISA)FeCr2O4 +8Na2CO3 + 7O2
Na2Cr2O7+Fe2O3+CO2
B) Na2CrO4+H+ Na2Cr2O7+Na+H2O
C) Na2Cr2O7+2KCl K2Cr2O7+2NaCl
d) MnO2+KOH+O2 K2MnO4+H2O
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QUES-58
WHICH SPECIES IS NOT
CORRECT?
A)Ni(DMG)2 B) [Co(SCN)4]2-
C) [Fe(H2O)5 (SCN)]2+
D) [Al(OH)4]-
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QUES-59
THE DICHROMATE ION IS AN EQUILIBRIUM WITH CHROMATE ION IN AQUEOUS SOLUTION ASCr2 O2-
7 (aq) H2O 2CrO2-4 (aq) 2H+(aq)
THE OXOANION HAS A)SAME OXIDIZING PROPERTY IN ACIDIC AND ALKALINE SOLUTIONSB) BETTER OXIDIZING PROPERTY IN ACIDIC SOLUTIONC) BETTER OXIDIZING PROPERTY IN ALKALINE SOLUTIOND) NO OXIDIZING PROPERTY IN ACIDIC OR ALKALINE SOLUTION
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QUES-60
WHICH OF THE FOLLOWING REACTIONS WILL NOT PRODUCE CHLORINE GAS?A)K2Cr2O7+HCl
B)MnO2+HCl
C)KMnO4+ HCl
D)K2Cr2O7+ H2SO4 (conc)+NaCl
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Ques-61ZnCl2 REACTS WITH EXCESS OF NH3 SOLUTION TO PRODUCEA)A PERCIPITATE OF Zn (OH)2B) A COMPLEX ION [Zn(NH3)4]2+ WITH TETRAHEDRAL GEOMETRYC)A COMPLEX ION [Zn(NH3)2]2+ WITH LINEAR GEOMETRYD) A COMPLEX ION [Zn(NH3)4]2+ WITH SQUARE PLANAR GEOMETORY
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QUES-62
FOR WHICH OF THE FOLLOWING SPECIES d-d TRANSITION DOES NOT ACCOUNT FOR ITS COLOUR?A)Cr2 O2-
7 B)CrO2-4
C) CrO2Cl2 D)ALL
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QUES-63
WHICH OF THE FOLLOWING REACTIONS WILL OCCUR ON HEATING AgNO3 AT RED HEAT?A)2AgNO3 2AgNO2+O2
B)2AgNO3 2Ag+NO2+O2
C)AgNO3 Ag+NO+O2
D)2AgNO3 2AG+N2+3O2
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QUES-64
BROWN COLOUR IN HNO3 CAN BE REMOVED BY A)ADDING Mg POWDERB) BOILING THE ACIDC) PASSING NH3 THROUGH ACIDD) PASSING AIR THROUGH WARM ACID
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Ques-65
THE CRYSTALS OF ANHYDROUS FERROUS SULPHATE ON HEATING GIVEA)FeO+SO2+H2O
B)FeO+SO3+H2SO4+H2O
C) FeO3+SO2+SO3
D)Fe2O3+H2SO4+H2O
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QUES-66
THE COMOUND OF SULPHUR THAT CAN BE USED AS REFRIGERANT ISA)SO2 B) SO3
C) S2Cl2 D) H2SO4
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QUES-67
WHICH NOBLE GAS DOES NOT FORM CLATHRATES?A)Xe b) Krc) He d) Ar
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Ques-68WHICH ONE OF THE FOLLOWING STATEMENT REGARDING HELIUM IS INCORRECTA)IT IS USED TO PRODUCE AND SUSTAIN POWERFUL SUPERCONDUCTING MAGNETSB) IT IS USED AS A CRYOGENIC AGENT FOR CARRYING OUT EXPERIMENTS AT LOW TEMPERATURESC) IT IS NOT USED TO FILL GAS BALLOONS INSTEAD BY HYDROGEN BECAUSE IT IS HEAVIER AND INFLAMMABLED)IT IS USED IN GAS COOLED NUCLEAR REACTORS
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QUES-69
THE SHAPE OF XeO3 ISA)TETRAHEDRALB)PYRAMIDALC)TRIGONAL PLANARD)SQUARE PLANAR
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QUES-70
XeO3 IS A COLOURLESS EXPLOSIVE
SOLID AND IS PREPARED
A)THE HYDROLYSIS OF XeF2
B)THE HYDROLYSIS OF XeF4
C)THE HYDROLYSIS OF XeF6
D) BOTH (B) AND (C )
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00:1000:0900:0800:0700:0600:0500:0400:0300:0200:0100:00QUES-71
XeF4 EXISTS WHEREAS XECl4 IS NOT STABLE BECAUSE A)ELECTRON AFFINITY OF Cl IS GREATER THAN FB) OXIDATOIN POTENTIAL OF F GREATER THAN Cl C) THE SIZE OF F IS SMALLER THAN ClD) NONE OF THESE
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QUES-72
KMno4 ACTS AS AN OXIDISING AGENT IN ACIDIC MEDIUM. THE NUMBER OF MOLE OF KMnO4 THAT WILL BE NEEDED TO REACT WITH ONE MOLE OF SULPHIDE IONS IN ACIDIC Soin ISA)2/5 B) 3/5C) 4/5 D) 1/5
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QUES-73
WHICH OF THE LISTED OXIDATION STATE IS COMMON FOR ALL 1ANTH ANOIDS?A)+2B)+3C)+4D)+5
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QUES-74
WHICH OF THE FOLLOWING IS NOT THE CHARACTERISTIC PROPERTY OF INTERSTITIAL COMPOUND A)THEY HAVE HIGH MELTING POINT IN COMPARISON TO PURE METALSB)THEY ARE VERY HARDC)THEY RETAIN METALLIC CONDUCTIVITY D)THEY ARE CHEMICALLY VERY REACTIVE
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00:1000:0900:0800:0700:0600:0500:0400:0300:0200:0100:00QUES-75
HIGHEST OXIDATION STATE OF MANGANESE IN FLUORIDE IS +4 (MnF4) BUT HIGHEST OXIDATION STATE IN OXIDES IS +7 (Mn2O7) BECAUSE A)FLUORINE IS MORE ELECTRONEGATIVE THAN OXYGENB) FLUORINE DOES NOT POSSESS d-ORBITALSC)FLUORINE STABILISES LOWER OXIDATION STATED) OXYGEN CAN FORM MULTIPLE BOND
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QUES-76WHY IS HCl NOT USED TO MAKE THE MEDIUM ACIDIC IN OXIDATION REACTION OF KMnO4 IN ACIDIC MEDIUMA)BOTH HCl AND KMnO4 ACT AS OXIDISING AGENTB) KMnO4 OXIDISES HCl INTO Cl2 WHICH IS AN OXIDISING AGENTC)KMnO4 ACT AS A REDUCING AGENT THEN HClD)KMnO4 ACT AS A REDUCING AGENT IN THE PRESENCE OF HCl
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Ques-77
WHICH OF THE FOLLOWING LANTHANOIDS SHOW +2 OXIDATION STATE BESIDES +3 OF LANTHANOIDSA) Ce B)Eu C) Yb d)Ho
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Ques-78
WHICH OF THE FOLLOWING WILL NOT ACT A OXIDISING AGENTA)CrO3 B) MOO3
C)WO3 D) CrO42-
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QUES-79
WHICH OF THE FOLLOWING ION HAS THE MAXIMUM MAGNETIC MOMENTA)Mn+2 B) Fe2+
c) T12+ D)Cr2+
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00:1000:0900:0800:0700:0600:0500:0400:0300:0200:0100:00Ques- 80CERIUM (Z-58) IS AN IMPORTANT MEMBER OF THE 1ANTHANOIDE(WHICH OF THE FOLLOWING STATEMENT ABOUT CERIUM IS INCORRECT A)THE +4 OXIDATION STATE OF CERIUM IS NOT KNOW IN SOLUTION B) THE +3 OXIDATION STATE OF CERIUM IS MORE STABLE THAN +4 OXIDATION STATEC)THE COMMON OXIDATION STATE OF CERIUM ARE +3 AND +4D)CERIUM (IV) ACT AS AN OXIDISING AGENT
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00:1000:0900:0800:0700:0600:0500:0400:0300:0200:0100:00QUES-81BECAUSE OF LANTHANOID CONTRACTION A)SEPARATION OF THE ELEMENT IS POSSIBLE B) THERE IS A VERY SMALL DIFFERENCE IN THE ATOMIC SIZE OF THE TRANSITION METAL OF 5TH AND 6TH PERIOD AND PRESENT IN THE SAME GROUPC) THERE IS A GRADUAL DECREASES IN THE BASIC STRENGTH OF THE HYDROXIDE OF LANTHANOIDSD)ALL ARE CORRECT
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QUES-82
TRANSITION METAL SHOW VARIABLE OXIDATION STATE BECAUSE OFA)PARTICIPATION OF nd ELECTRON ALONG THE np ELECTRONB) PARTICIPATION OF (n-1) d AND ns ELECTRONC)PARTICIPATION OF (n-1) d AND np ELECTROND)NONE OF THESE IS CORRECT
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QUES-83
THE ACTINOIDS EXHIBIT MORE NUMBER OF OXIDATION STATE IN GENERAL THAN LANTHANOIDS. THIS IS BECAUSEA)THE 5f ORBITALS EXTEND FURTHER FROM THE NUCLEAR THAN THE 4f ORBITALSB) THE 5f ORBITALS ARE MORE BURIED THAN THE 4f ORBITALSC) THERE IS A SIMILARITY BETWEEN 4f & 5f ORBITALS IN THEIR ANGULAR PART OF THE WAVEFUNCTIOND) ACTIONOIDS ARE MORE REACTIVE THAN THE LANTHANOIDS
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QUES-84MARK THE CORRECT STATEMENT1.MANGANESE EXHIBITS +7 OXIDATION STATE2.ZINC FORMS COLORED IONS3.[CoCl6]3- IS DIAMEGNETIC4. SC FORMS +4 OXIDATION STATE 5. Zn EXHIBITS ONLY +2 OXIDATION STATEA)1 &2 B)1 AND 5 C)2 & 4 D) 3 AND 4 E) 2 AND 5
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QUES-85
1. SECONDARY VALENCY OF METAL ATOM/ION INSIDE CO-ORDINATION SPHERE
A)IS SAISFIED BY NEGATIVE IONS ONLY B) CANNOT GET IONISEC) IT IS A FIXED NUMBER FOR EVERY
METAL D) B AND C BOTH
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00:1000:0900:0800:0700:0600:0500:0400:0300:0200:0100:00QUES-86
OXIDATION NO OF Fe IN K4[Fe(CN)6]A)+2B)+3C)0D)NONE
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QUES-87
WHICH OF THE FOLLOWING WILL NOT
SHOW LINKAGE ISOMERS
A) [Pd((C6H5)2(SCN)2]
B)[Pd((C6H5)2Cl2]
C) [Pd(C6H5)2clNO2]
D) [Pd(C6H5)2(CN)2]
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QUES-88
THE CORRECT IUPAC NAME OF [Pt(NH3)2Cl2] ISA)Diamminedichloridoplatinium(ii)B) Diamminechloridoplatinium(iv)C) Diamminechloridoplatinium(O) D)Diamminechloridoplatinium(iv)
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QUES-89
IDENTIFY THE NON OPTICALLY ACTIVE COMPOUNDS FROM FOLLOWINGA)[CO(en)3]3r
B) TRANS-[CO(en)2Cl2]+
C) AS [CO(en)2Cl2]+
D) [Cr(NH3)5]Cl
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Ques-90
WHICH OF THE FOLLOWING COMPOUNDS WOULD HAVE THE HIGHER MOLAR CONDUCTIVITYA) Diamminedichloridoplatinium(ii)B) Tetraamminedichloridocobolt(iii)c) Potassiumhexacynoferrate(ii)d) Hexaaquachromium(iii)chloride
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QUES-91
A COMPLEX IN WHICH dsp2
HYBRIDISATION TAKES PLACE
A)SQUARE PLANAR
B)TETRAHEDRAL
C) TRIGONAL PLANAR
D)PYARMIDAL
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QUES-92
WHICH OF THE FOLLOWING HAS THE HIGHEST REDUCING POWERA)HCl B)HBrC) HI D) HF
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QUES-93
WHICH PRODUCT ARE EXPECTED FROM THE DISPROPORTIONATION REACTION OF HYPOCHLOROUS ACIDA)HClO3 AND Cl2O B) HCl AND Cl2O
C) HClO2 AND HClO4 D)HCl AND HClO3
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Ques-94WHICH OF THE FOLLOWING ORDER ARE CORRECT AS PER THE PROPERTIES MENTIONED AGAINST EACH:-A)Sio2<ASrO3<P2O3<SO2 ACIDIC STRENGTH
B)AsH3<PH3<NH3 ENTHALPY OF VAPORISATIONC) S<O<Cl<F MORE NEGATIVE ELECTRON GAIN ENTHALPYD) H2O>H2S>H2Te THERMAL STABILITY
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QUES-95
THE GASES PRODUCED IN THE REACTION
Pb(NO3)2 AND NH4 NO3 ARE
RESPECTIVELY
A)N2O , NO B) NO, NO2
C) N2O, NO2 D) NO2, N2O
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QUES-96
WITH EXCESS OF Cl2 , AMMONIA
FORMS
A)NITROGEN
B) AMMONIUM CHLORIDE
C) NITROSYL CHLORIDE
D) NITROGEN TRICHLORIDE
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QUES-97
THE REDDISH BROWN COLOURED GAS FORMED WHEN NITRIC OXIDE IS OXIDISED BY AIR ISA)N2O5 B) N2O4
C) NO2 D) N2O3
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QUES-98
THE STABILITY OF INTERHALOGEN COMPOUNDS FOLLOWS THE ORDERA)IF3>BrF3>ClF3
B)BrF3>IF3>ClF3
C)ClF3>BrF3>IF3
D)ClF3>IF3>BrF3
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QUES-99
THE STRUCTURE OF IF7 ISA)THE TRIGNONAL BIPYRAMIDALB)OCTAHEDRAL C) PENTAGONAL BIPYRAMIDALD) SQUARE PYRAMIDAL
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QUES-100
IN WHICH OF THE FOLLOWING PAIR THE TWO SPECIES ARE ISOSTRUCTURAL,A)BrO-
3 AND XeO3B) SF4 AND XeF4C) SO3
2- AND NO3-
D) BF3 AND NF3
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QUES-101
THE SHAPE OF XeO2F2 MOLECULE ISA)TRIGONAL BIPYRAMIDALB) SQUARE PLANARC)TETRAHEDRALD) SEE-SAW
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QUES-102
THE INCORRECT STATEMENT ABOUT O3 IS (ARE) A)O-0 BOND LENGTH ARE EQUALB) THERMAL DECOMPOSITION OF O3 IS ENDOTHERMIC C)O3 IS DIAMAGNETIC IN NATURE
D) O3 HAS A BENT STRUCTURE
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QUES-103
THE BROWN RING TEST FOR NITRATES DEPENDS UPONA)THE REDUCTION OF NITRATE TO NITRIC OXIDEB)OXIDATION OF NITRIC OXIDE TO NITROGEN DIOXIDEC)C) REDUCTION OF FERROUS SULPHATE TO IROND) OXIDISING ACTION OF SULPHURIC ACID
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QUES-104
THE FOLLOWING TWO REACTIONS OF HNO3 WITH Zn AND Cu ARE GIVEN ASZn+ dil HNO3 Zn(NO3)2
+ X+H2O Cu+ dil HNO3 Cu(NO3)2
+ Y+H2O X AND Y ARE A)NO2 AND NOB) NO AND NO2C) N2O AND NOD) NO2 AND NO2
N2O & NO
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QUES-105
WHICH AMONG THE FOLLOWING FACTORS IS MOST IMPORTANT IN MAKING FLUORINE THE STRONGEST OXIDISING AGENTA)ELECTRON AFFINITYB)HYDRATION ENERGYC) BOND DISSOCIATION ENERGYD)ALL OF THEM
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QUES-106
WHICH IS THE STRONGEST ACID IN THE FOLLOWINGA) HClO4 B) H2SO3
C) H2SO4 D) HClO3
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QUES-107
THE INSTABILITY OR DISSOCIATION CONSTANT FOR FOUR LIGANDS IS 1.) 2.1X1013 2). 3.6X10-2 3). 6.7X108
4) 8.4X1010
THE LIGANDS WOULD BE
A)1) H2O 2).CO 3.) CN- 4) NH3 B) 1) CN- 2) CO 3) H2O 4) NH3C) 1) NH3 2) CN- 3) CO 4) H2OD) 1) NH3 2) CO 3) CN- 4) H2O
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QUES-108 WHICH OF THE FOLLOWING IS NOT A
CORRECT SEQUENCE :
a) NH3>PH3>A3H3>SbH3 DECREASING BASIC STRENGTH
b) SO2<SeO2<TeO2 INCREASING BASIC CHARACTERc) ClO4>ClO3>ClO2>ClO INCREASING STABILITY OF
CONJUGATE BASEd) H2O<H2S<H2SE<H2Te – INCREASING REDUCING
STRENGTH
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QUES-109
THE CORRECT FORMULA OF IRON III HEXACYAN FERRATE (II) IS :
a) Fe3[Fe(CN)6]4b) Fe4[Fe(CN)6]c) Fe[Fe(CN)6]4 d) Fe4[Fe(CN)6]3
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QUES-110THE ORIDATION STATE OF CENTRAL METAL
ATOM IS: Na[Rh(CO)4]
a) +1b) -1c) 0d) NONE OF THESE
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QUES-111
THE HIGHER BOND ANGLE OF HYDRIDE OF FIRST ELEMENT IN EACH GROUP IS DUE TO ITS :
a) SMALL SIZEb) HIGHER ELECTRONEGATIVITYc) ABSENCE OF ‘’d’’ ORBITALd) ALL ABOVE
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QUES-112
OXIDE OF BISMITH IS MOST BASIC IN IT GP DUE TO ITS :
a) LOW IONISATION ENTHALPYb) LARGE SIZEc) BOTH a & bd) NONE
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QUES-113
85. Cu IS LESS REACTIVE THAN OTHER ELEMENTS OF 3d SERIES, YET IT EASILY REACTS WITH :
a) Conc. HNO3b) Dil. HNO3c) Conc. H2SO4d) ALL ABOVE
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QUES-114
86.MAXIMUM DIFFERENCE OF ATOMIC RADIE WILL BE OBSERVED BETWEEN :
a) N - Pb) P - Asc) As - Sbd) Sb - Bi
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QUES-115
87. IE1 OF 15 GP ELEMENT FALLEN WHICH PATTERN :
a) >14 & <16b) <14 & >16 c) <14 & <16 d) >14 & >16
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QUES-116WHICH OF THE FOLLOWING OXIDATION
STATES OF NITROGEN DO NOT TEND TO DISPROPORTIONATE :
a) +4b) +1c) -3d) +3
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QUES-117
89.WHAT IS CORRECT ABOUT THE MOLECULE P(CH3)3 P=0 :
a) P IS SP3 HAVING d -P BONDINGb) P IS SP2 HAVING d -P BONDINGc) P IS SP3 HAVING P -P BONDINGd) P IS SP2 HAVING P -P BONDING
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QUES-118
90.WHICH OF THE FOLLOWING IS CHEMICALLY SOLUBLE IN WATER :
a) NH3b) PH3c) AsH3d) BiH3
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QUES-119
91.WHICH OF THE FOLLOWING IS PREDOMINANTLY IONIC:
a) NF3b) PF3c) AsF3d) BiF3
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QUES-120
TWO COLOURLESS OXIDES OF NITROGEN REACT TOGETHER TO GIVE ANOTHER OXIDE OF NITROGEN WHICH IS A BLUE SOLID. THE OXIDES ARE:
a) NO & NO2b) NO & N2O4c) N2O & NOd) NO2 & N2O
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QUES-120
THE OXIDE OF NITROGEN WHICH IS RECYCLED IN PREPARATION OF HNO3 IS :
a) NOb) NO2c) N2O4d) BOTH a & b
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QUES-120
CARBON CAN BE OXIDESED TO CO2 BYWHICH OF THE FOLLOWING
a) Conc. HNO3b) Conc. H2SO4c) Dilt. H2SO4d) BOTH a & b
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QUES-121
THE MAIN PRODUCT OF HYDROLYSIS OF CALCIUM PHOSPHIDE IS :
a) PHOSPHORIC ACIDb) PHOSPHOROUS ACIDc) PHOSPHENEd) HYPOPHOSPHOROUS ACID
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QUES-122
WHICH OF THE FOLLOWING WILL GIVE METALIC SILVER ON TREATMENT WITH SILVER NITRATE :
a) PHOSPHORIC ACIDb) PHOSPHOROUS ACIDc) HYPOPHOSPHORIC ACIDd) HYPOPHOSPHOROUS ACID
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QUES-123
THE CORRECT INCREASING ORDER OF Heg:
a) O<S<F<Clb) S<O<Cl<Fc) Cl<F<S<Od) F<Cl<O<S
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QUES-124
THE CORRECT DIFFERENCE IN THE B.P. OF SULPHER AND OXYGEN IS DUE TO:
a) ATOMIC RADIEb) ATOMICITYc) BOTH a & b d) NONE OF ABOVE
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QUES-125
SeO2 IS LIQUID TeO2 IS SOLID BECAUSE OF :
a) SeO2 IS REDUCING, TeO2 IS OXIDISINGb) SeO2 COVALENTS, TeO2 IS IONICc) HIGH MOLECULAR MASS OF TeO2d) ALL ABOVE
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QUES-126
ALTHOUGH THE REACTION OF O2 WITH METALS ARE EXOTHERMIC YET THEY REQUITRE EXTRENAL ENERGY TO INITIATE BECAUSE :
a) LOW B.E. OF O=0b) HIGH B.E. OF O=0c) HIGH IE OF METALd) ALL ABOVE
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QUES-127 SO2 GAS WHEN PASSED IN KMnO4
SOLUTION IT REACTS AND :
a) CHANGES THE COLOUR TO GREENb) BECOME COLOURLESSc) DON’T CHANGE THE COLOURd) DOES NOT REACTS
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QUES-128
THE TWO ALLTROPS OF S ARE STABLE AT TEMP. :
a) 369 Kb) 375 Kc) 369 oCd) 375 oC
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QUES-129
105. 2X2+2H2O 4H+aq+ 4X-
aq+O2 gIN THIS REACTION X IS :
a) Cl2b) Br2c) F2d) ALL OF THEM
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QUES-130
THE HALOGEN WHICH FORMS LEAST STABLE OXIDE IS :
a) CHLORENEb) FLUORINEc) BROMINEd) IODENE
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QUES-131
STRONGEST OXIDISING AGENT IS :
a) HClO3b) HCO3c) HBrO3d) HBr
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QUES-132
THE COMPOUND USED IN ESTIMATION OF CARBON MONOXIDE IS :
a) Cl2O5b) I2O5c) Br2O5d) Cl2O4
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QUES-133
XENON TRIOXIDE CAN BE PREPARED BY WHICH OF THE FOLLOWING Xe COMPOUNDS:
a) XeF2b) XeF4c) XeF6d) b & c BOTH
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QUES-134
WHICH OF THE FOLLOWING COMPOUND ON HYDROLYSIS PRODUCE O2:
a) XeF2b) XeF4c) XeF6d) a & b BOTH
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QUES-135SF4 MOLECULE GEOMETRY IS :
a) TETRAHEDRALb) SQUAREPLANARc) SEE-SAWd) PYRAMIDAL
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QUES-136
SO2 GAS WHEN PASSED IN LIME WATER :
a) TURNS MILKYb) NO EFFECTc) SO2 BUBBLES OUTd) CURDY WHITE PPT FORMED
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QUES-137
CHLORINE GAS WAS DISCOVERED BY :
a) DAVYb) SCHEELEc) OSWALDd) NONE OF THE ABOVE
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QUES-138
NAME THE PRODUCTS FORMED WHEN A MIXTURE OF SO2 & Cl2 GASES IS DISSOLVED IN WATER AT HIGH PRESSURE :
a) SULPHER & HCLb) SO3 & HCLc) H2SO4 & HCLd) H2SO3 & HCL
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QUES-139
NAME THE PRODUCTS FORMED WHEN Cl2 GASE IS PASSED IN AQUOUS IODINE :
a) HYDROCLORIC ACIDb) HYDROIODIC ACIDc) BOTH a & bd) NONE OF THE ABOVE
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QUES-140
WHICH OF THE FOLLOWING TRANSITION METAL DOES NOT SHOW VARIABLE OXIDATION STATES :
a) Feb) Mic) Scd) Mn
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QUES-141
WHAT DOES THE GRAPH NOT EXPLAIN :
a) M.P. OF T.M. DEPENDS ON NO. OF UNPAIRED d ELECTRON.
b) M-M BONDING IN 5d>4d>3dc) STABALE CONFIGURATION LEADS TO LOW
M.P.d) M.P. INCREASES WITH INCREASING
ATOMIC NUMBER.
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QUES-142
119. EoZn+2 / Zn AND EoNi+2/Ni ARE MORE NEGATIVE THAN REMAINING ELEMENT OF 3d SEREIS. BECAUSE :
a) HIGH H HYDRATION & LOW H IONISATION
b) LOW H INONISATION & HIGH H HYDRATION
c) HIGH H HYDRATION FOR BOTHd) LOW H IONISATION FOR BOTH
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QUES-143
Zr AND Hf HAVE USUALLY SIMILAR CHEMICAL AND PHYSICAL PROPERTIES BECAUSE :
a) THEY BELONG TO SAME GROUPb) THEY BELONG TO SAME d-SERIESc) THEY HAVE SAME ATOMIC & IONE RADIEd) ALL AVOBE
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QUES-144
WHICH OF THE FOLLOWING WILL HAVE LOWER MAGNETIC MOMENT :
a) Feb) Nic) Cod) Zn
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QUES-145
MOST OF THE METAL CARBONYLS ARE FORMED IN ZERO OXIDATION STATE BECAUSE :
a) ELECTRONS OF d ORBITAL ARE AVAILABLE FOR SYNEGRIC BAND.
b) CO IS ATTRACTED BY METAL.c) CO- DOES NOT REACT WITH M+ IONd) ALL ABOVE
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QUES-146
THE SPIN MAGNETIC MOMENT OF Co IN Hg[Co(SCN)4] IS :
a) 3b) 8c) 15d) 24
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QUES-147
APART FROM +3 OXIDATION STATE Eu AND Ce ALSO FORM COMPOUND IN +2 & +4 OXIDATION STATE BECAUSE OF :
a) HALF FILLED & EMPTY f ORBITALb) EMPTY & HALF FILLED f ORBITALc) FULLFILLED f ORBITAL IN BOTHd) HALF FILLED f ORBITAL IN BOTH
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QUES-148
AMONG THE LANTHANIDES THE HIGHEST PARAMAGNETISM IS OBSERVED IN :
a) CERIUMb) LUTETIUMc) NEODYMUIMd) PROMETHIVAM
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QUES-149
WHICH OF THE FOLLOWING IS NOT A CONSITUENT OF HISCHMETAL :
a) IRONb) LANTHANOIDSc) ACTONOIDSd) CALCIUM + ALUMINIUM
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QUES-150
SECONDRY VALANCY OF METAL ION ACCORDING TO WERNER IS :
a) ALL LIGANDS DIRECTLY BOUND TO METAL ION
b) ALL NEUTRAL LIGANDSc) ANIONIC LIGANDSd) LIGANDS WHICH CAN DONATE
ELECTRONS
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QUES-151
THE VALUE OF X IN COMPOUND OF CO(NH3)X Cl3 IN INCREASING OEDER OF MOLAR CONDUCTIVITY WILL BE:
a) 6,5,4b) 4,5,6c) 6,6,6d) 5,6,6
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QUES-152
K2SO4.Al(SO4)3.24H2O IS A:
a) DOUBLE SALTb) COMPLEXc) ALUMd) BOTH a & c
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QUES-153
WHICH OF THE FOLLOWING IS A CHELATE LIGAND:
a) CN-
b) NH2CH2CH2NH2c) NO2d) ALL
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QUES-154
WHICH OF THE FOLLOWING IS NOT A HOMOLEPTIC COMPLEX :
a) [CO(NH3)4.(H2O)Cl]Cl2b) [Ni(CO)4]c) K3[Fe(C2O4)]d) Li[AlH4]
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QUES-155
WHICH OF THE FOLLOWING WILL SHOW GEOMETRICAL IOMERISM :
a) [Ni(CN)4]-2
b) [Ni(CO)4]c) [Ni(Gly)2]2-
d) [Ni(NH3)3Cl]
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QUES-156
WHICH OF THE FOLLOWING WOULD HAVE FAC AND (MER) IXMERS :
a) [CO(NH)3 (H2O)2(OX)]+
b) [CO(H2O)3 Cl3]c) [Cr(NH3)4 en]3+
d) [Cu(NH3)4]2+
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QUES-157
THE SQUARE PLANAR COMPLESEX HAVE METAL IONS WITH CONFIGURATION :
a) d6
b) d0
c) d8
d) d10
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QUES-158
A LOW SPIN COMPLEX IS:
a) [CO(H2O)6]Cl3 b) [Cr(NH3)6]Cl3c) [CO(NH3)6]Cl3 d) [CO.Cl3(H2O)3]
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QUES-159
WHICH OF THE FOLLOWING COMPLEXES MAY HAVE STRUCTURAL ISOMERS:
a) [Fe(NH3)4NO2(SO4)] b) [Fe(NH3)6)] Cl3c) K[Fe(CN)4 (H2O)2]d) NONE OF THE ABOVE
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QUES-160
THE INCREASING ORDER OF CFSE FIELD STABILIZATION ENERGY(CFCE) FOR LIGAND (1) NH3 (2) OH- (3)ETDA (4) ETHYLENE DIAMINE :
a) 1<2<3<4b) 4<1<3<2c) 2<3<1<4d) 2<1<3<1
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QUES-161
FOR THE COMPLEX [NiCl4]2- THE VALUE OF eg ORBITAL AND t2g ORBITAL.:
a) eg > t2gb) t2g > egc) eg < t2gd) NO SPLITTING OF d ORBITAL OCCURES
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QUES-162
THE COLOUR OF COMPLEX COMPOUND DEPENDS ON:
a) STRENGTH OF LIGANDb) NATURE OF METAL IONc) NO. OF UNPAIRED ELECTRONd) ALL ABOVE
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QUES-163
SYNERGIC BOND IS NET FORMED IN [Cr(NH3)6]CL3 BECAUSE:
a) CHROMIUM DOES NOT HAVE FILLED d ORBITAL
b) NH3 DOES NOT HAVE VACANT P ORBITALc) SYNERGIC BAND IS NOT REQUIREDd) ALL OF THE ABOVE