Terminal Arm Length and Special Case Triangles

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Terminal Arm Length and Special Case Triangles DAY 2

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Terminal Arm Length and Special Case Triangles. DAY 2. Using Coordinates to Determine Length of the Terminal Arm. There are two methods which can be used: Pythagorean Theorem Distance Formula Tip: “Always Sketch First!” . Using the Theorem of Pythagoras . - PowerPoint PPT Presentation

Transcript of Terminal Arm Length and Special Case Triangles

Page 1: Terminal Arm Length and Special Case Triangles

Terminal Arm Length and Special Case Triangles

DAY 2

Page 2: Terminal Arm Length and Special Case Triangles

Using Coordinates to Determine Length of the Terminal Arm

• There are two methods which can be used: – Pythagorean Theorem – Distance Formula

• Tip: “Always Sketch First!”

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Using the Theorem of Pythagoras

• Given the point (3, 4), draw the terminal arm. 1. Complete the right triangle by joining the

terminal point to the x-axis.

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Solution

2. Determine the sides of the triangle. Use the Theorem of Pythagoras.

• c2 = a2 + b2 • c2 = 32 + 42 • c2 = 25 • c = 5

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Solution continued

3. Since we are using angles rotated from the origin, we label the sides as being x, y and r for the radius of the circle that the terminal arm would make.

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Example: Draw the following angle in standard position given any point (x, y) and determine the value of r.

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Using the Distance Formula

The distance formula: d = √[(x2 – x1)2 + (y2 – y1)2]

• Example: Given point P (-2, -6), determine the length of the terminal arm.

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Review of SOH CAH TOA

• Example: Solve for x. • Example: Solve for x.

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Example: Determine the ratios for the following:

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Special Case Triangles – Exact Trigonometric Ratios

• We can use squares or equilateral triangles to calculate exact trigonometric ratios for 30°, 45° and 60°.

• Solution

• Draw a square with a diagonal. • A square with a diagonal will have angles of 45°. • All sides are equal. • Let the sides equal 1

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45°

• By the Pythagorean Theorem, r = 2

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30° and 60°

• All angles are equal in an equilateral triangle (60°)

• After drawing the perpendicular line, we know the small angle is 30°

• Let each side equal 2 • By the Theorem of

Pythagoras, y = 3

Draw an equilateral triangle with a perpendicular line from the top straight down

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Finding Exact Values

• Sketch the special case triangles and label • Sketch the given angle • Find the reference angle

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Example: cos 45°

1cos452

1 22 2

22

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Example: sin 60°

3sin602

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Example: Tan 30°

• Example: Tan 30° • Example: Cos 30°

1 3tan3033

3cos302

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Solving Equations using Exact Values, Quadrant I ONLY

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ASSIGNMENT:

• Text pg 83 #8; 84 #10, 11, 12, 13