Tambe Sirs Qn Ans

28
1 In-field electric motor efficiency measurement Rich Schiferl Rockwell Automation An Accurate Method to Determine Electric Motor Efficiency While the Motor is in Operation

Transcript of Tambe Sirs Qn Ans

Page 1: Tambe Sirs Qn Ans

1In-field electric motor efficiency measurement

Rich SchiferlRockwell Automation

An Accurate Method to Determine Electric Motor Efficiency While the

Motor is in Operation

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2In-field electric motor efficiency measurement

Outline• Background• New method for determining electric motor

efficiency• Implementation• Accuracy vs lab tests• Conclusions

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3In-field electric motor efficiency measurement

Background• Energy cost is growing at a high rate• Plants can save a substantial amount of money by

replacing existing inefficient motors with new highly efficient motors

• An accurate method to determine electric motor efficiency is needed to make these decisions– Without the need to disconnect the motor from the driven

equipment– Without the need to make connections at the motor terminal box– Include all motor losses– Provide both motor efficiency and output load information

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4In-field electric motor efficiency measurement

Electric Motor Efficiency Wizard• Portable metering

– Speed– Temperature– Resistance– Power– Voltage– Current– Frequency

• Laptop computer for data collection

• Proprietary algorithm to calculate motor efficiency

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Efficiency Wizard Kit

Measurements made at Two Motor Load Points

Motor Starter

Three phase induction motor

Current

Voltage, Frequency,Resistance

Temperature and Speed

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6In-field electric motor efficiency measurement

Test Procedure

• Disconnect motor power at the starter• Measure line to line resistances at the

starter.• Measure the motor and cable temperature

using the Infra Red meter• Record cable length (starter to motor) and

gage

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Test Procedure…...• Connect the Power Monitor and frequency

monitor leads at the starter box – current, voltage, frequency, input power

• Start data download to the Laptop PC• Record motor fan diameter and nameplate data• Start the motor and bring it to normal load

condition.• Measure motor speed and surface temperature at a

normal running load and at a second load point.• Enter data into the Laptop PC

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Motor Input Data SheetMotor Data REL S.O. Frame HP Type Hertz RPM

xxxxxxxx 75 60 1185

Volts Amps DutyAMB C/INSUL. S.F.

Nema Design

460 91 CONT B

Code Letter Enclosure E/S Rotor Test S.O. Date Test DateG TENV 2/27/02 2/27/02

Item RPMInput Power KW N. of Poles Frequency V L12 V L13

Test Point 1"High Load" 1186.7 60.51 6 60.002 466.833 466.833Test Point 2 "Low Load" 1193.2 32.976 6 59.995 469.1 469.1

Item V L23 I1 I2 I3Stator Temperature

Cable Temp

F&W watts

Test Point 1"High Load" 466.833 88.012 88.012 88.012 60 39 250Test Point 2 "Low Load" 469.1 56.299 56.299 56.299 56 39 250

Stator Resistance & Temperature** R12 total R13 total R23 total

StatorTemperature in C Cable Temp

Resistance 0.16 0.16 0.17 51 24

** Measure the resistance of the stator Motor HP

SLL % of Output

and record the temperature at the time 1 - 125of measurement. 126 - 500SLL % Factor at Rated Power 1.8 501 - 2499

Performance Curves Rated Voltage 460

Cable Gauge

Cable Length in Feet Cables /phase

Performance Curves Rated Freq. 60 1 213.5 1Design Factor 1.0325Hours Per Week 168KW hour cost in dollars 0.05

Motor Appliction#3 Boiler Fan

XEX Motor Efficiency 95

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Results Provided• Motor output torque and horsepower at the two load

points• Motor efficiency at the two load points

– Includes I2R, core, friction and windage, and stray load loss

• Motor equivalent circuit parameters• Performance curves for the motor

– Power and torque vs speed– Efficiency, power factor and current vs load

• Energy savings (in kilowatt hours and $) if this motor is replaced with an energy efficient motor– Given energy cost, hours of operation per week

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Output Data SheetMotor Data REL S.O. Frame HP Type Hertz RPM

xxxxxxxx 0 75 0 60 1185Volts Amps Duty AMB C/INSUL. S.F. Nema Design

460 91 CONT 0 0 BCode Letter Enclosure E/S Rotor Test S.O. DatTest DateG TENV 0 0 37314 37314

Item Output HPInput Current Speed

Output Torque ft.lb Power factor Efficiency

Test Point 1"Hig 72.66 88.0 1186.7 321.6 0.85 90.6Test Point 2 "Low 38.75 56.3 1193.2 170.5 0.72 88.4

Motor Parameters

Phase Resistance R1&cable

Stator Inductance

L1

Core Resistanc

e RcMagnetizing

Inductance Lm

Rotor Inductance

L2

Rotor Resistance

R20.057 0.00060 77.471 0.0189 0.00082 0.03767

Output Power HP Input Current

Power factor Efficiency Speed RPM

Output Torque ft.lb.

5.5 37.2 0.242 57.5 1199.0 24.224.8 46.1 0.595 84.8 1195.6 109.143.4 60.2 0.756 89.2 1192.3 191.060.9 76.4 0.825 90.4 1188.9 269.277.5 93.4 0.857 90.6 1185.5 343.385.4 101.9 0.866 90.6 1183.8 378.792.9 110.4 0.872 90.4 1182.1 412.9

XEX Motor Efficiency 95$ Savings Per Year 1223Annual KWH Saving 24468

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Efficiency Calculation Accuracy 10 HP Motor

84

85

86

87

88

89

90

91

92

1/4 Load 1/2 Load 3/4 Load Full Load

M otor Load

Effic

ienc

y

Measured E fficiencyEstimated Efficiency

IEEE 112B lab testEfficiency Wizard

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Efficiency Calculation Accuracy600 HP Motor

8486889092949698

100

1/4 Load 1/2 Load 3/4 Load Full LoadMotor Load

Effic

ienc

y

MeasuredEfficiency

EstimatedEfficiency

IEEE 112B lab testEfficiency Wizard

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Efficiency Calculation Accuracy

150 HP Motor

8384858687888990919293

1/4Load

1/2Load

3/4Load

FullLoad

Motor Load

Effic

ienc

y

Measured EfficiencyEstimated Efficiency

IEEE 112B lab testEfficiency Wizard

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Motor Efficiency Versus Output PowerEfficiency

0.0

10.0

20.0

30.0

40.0

50.0

60.0

70.0

80.0

90.0

100.0

0.0 10.0 20.0 30.0 40.0 50.0 60.0 70.0 80.0 90.0 100.0

Horespower

Effic

ienc

y (%

)

HP75REL xxxxxxx

Mitsubishi2/27/02#3 Boiler Fan

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Input Current Versus Output PowerInput Current

0.0

20.0

40.0

60.0

80.0

100.0

120.0

0.0 10.0 20.0 30.0 40.0 50.0 60.0 70.0 80.0 90.0 100.0

Horse Power

Inpu

t Cur

rent

(Am

ps)

75 HPREL S.O. xxxxxxxx

Mitsubishi2/27/02 #3 Boiler Fan

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Power Factor vs Output PowerPower factor

0.40

0.45

0.50

0.55

0.60

0.65

0.70

0.75

0.80

0.85

0.90

0 10 20 30 40 50 60 70 80 90 100

Horsepower

Pow

er F

acto

r

HP75REL S.O. xxxxxxxx

Mitsubishi2/27/02 #3 Boiler Fan

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Speed vs Output PowerSpeed RPM

1180

1182

1184

1186

1188

1190

1192

1194

1196

1198

1200

0 10 20 30 40 50 60 70 80 90 100

Horsepower

RPM

HP75REL S.O. xxxxxxxx

Mitsubishi2/27/02#3 Boiler Fan

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Motor Torque vs SpeedOutput Torque ft.lb.

0

50

100

150

200

250

300

350

400

450

1180 1182 1184 1186 1188 1190 1192 1194 1196 1198 1200

RPM

Torq

ue ft

.Ib

HP75REL S.O. xxxxxxxx

Mitsubishi2/27/02#3 Boiler Fan

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How Does it Work

• Input data at the two load points is used to calculate the induction motor equivalent circuit parameters– Core loss, stator I2R loss and rotor I2R loss are obtained

by solving for equivalent circuit losses

• Stray load loss is estimated from IEEE standard formula

• Friction and windage loss is determined from an electric motor database– fan diameter and speed as inputs

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Induction Motor Equivalent Circuit

aV1R 1L

mLcR

2L

1V1I 2I3I

s2R

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How Does it Work

• Performance curves are calculated using the equivalent circuit model– efficiency, power, torque, power factor

and current vs speed and/or load

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Features of the Efficiency Wizard• All electrical measurements can be made at

the motor starter– Lead length compensation is included in the

software calculations• No need to mechanically disconnect the

motor from the load– Two separate load points are required

• Definite purpose portable field kit with high accuracy metering

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Features of the Efficiency Wizard

• All motor losses are determined• Can be used on all induction motors• High accuracy test results• Motor performance curves provided• Automatic calculation of potential

energy and $ savings

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Potential Uses• Provide information for:

– Decisions to immediately replace a motor with a more efficient one

– Data base of in-service motor performance • Can be used for future motor replacement decisions• Can detect under loading or over loading• Prioritize present or future motor replacements

• Provides data for fact based decisions on motor replacement– Energy savings drop to the bottom line

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Example Results

• 250 HP motor – Existing motor efficiency = 92.4 % – Energy efficient motor efficiency = 96.2% – Annual energy cost savings with motor

replacement = $1417

• The present value of the savings over 20 years will be $15,256.

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Conclusions• An accurate field tool for determining

induction motor efficiency has been developed– Portable hardware kit– Proprietary software

• The new tool can be used on-site without the need to disconnect the motor from the driven equipment– Two load points– Electrical connections at the motor starter

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Conclusions• Accuracy is to within 1% of laboratory

test comparisons – 10 hp thru 600 hp

• Motor performance, energy and $ cost savings are calculated from in-field test data

• Energy saving opportunities can now be readily identified

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Thank You