Systems with Three Variables Objective: I can solve systems with three or more variables.
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Transcript of Systems with Three Variables Objective: I can solve systems with three or more variables.
Systems with Three Variables
Objective:
I can solve systems with three or more variables.
How much does each box weigh?Explain your reasoning.
{ π π βπ+π=ππ+π πβ π=πππ π+πβ π=ππ
Solve the system.
π πβπ+π=ππ+π πβ π=ππ
π πβπ+π=ππ π+π βπ=ππ
π π+ππ=ππ π π=πππ=π
π (π )+π π=πππ+π π=πππ π=ππ=π
π π+ππ=ππ
π πβπ+π=ππ(π)β(π)+ π=π
π+π=ππ=π(π ,π ,π)
{ π+π+π π=πππ+π+π π=πβπβπ π+π=ππ
Solve the system.
π+π+π π=π π π+π+π π=πβπ βπ π+π=ππβπ+ππ=ππ
βπ π+π π=ππ
βπ π=βππ
βπ+π(π)=ππβπ+π=ππ
π+π+π π=ππ+(βπ)+π(π)=π
πβπ=ππ=π
π π+π+π π=πβπ βπ π+π=ππ
βπ+ππ=ππβπ π+π π=ππ
π=π
(π ,βπ ,π)
βπ πβπ π+π π=ππ
π π βπ π=βππβπ π+π π=ππ
βπ=ππ=βπ
π» +π· +πΉ=ππππππ» +ππ π·+πππΉ=πππππΉ=ππ·
π» +π· +(ππ· )=ππππππ» +ππ π·+ππ(ππ· )=ππππ
π» +ππ·=ππππππ» +πππ·=ππππ
βπππ» βπππ·=βπππππππ» +πππ·=ππππ
πππ·=πππππ·=ππ
πΉ=π(ππ)ΒΏππππ» +(ππ)+(πππ)=πππ
π»=ππ Pg. 171 #9-11, 30
You manage a clothing store and budget $6000 to restock 200 shirts.You can buy T-shirts for $12 each, polo shirts $24 each and rugby shirts for $36 each. You want to have twice as many rugby shirts as polo shirts. How many of each type shirt should you buy?
Systems with Three Variables
Objective:
I can use matrices to solve systems.
Use the rules below to change figure 1 into figure 2?
Matrix:β’ A rectangular array of numbers.β’ Dimensions: rows Γ columns
Matrix Name
[ π΄ ]=[2 5 113 β2 5 ]
Systems to matrices
matrix [1 4 52 5 4]
[1 4 50 β3 β6 ] [1 4 5
0 1 2] [1 0 β30 1 2 ]
{ π₯+4 π¦=52π₯+5 π¦=4
-2 Γ Row 1 + Row 2Put in Row 2
Divide Row 2 by -3Put in Row 2
-4 Γ Row 2 + Row 1Put in Row 1
(βπ ,π)
Reduced Row Echelon form (rref)
222
111
CyBxA
CyBxA
1A
b
a
10
011B
2A 2B1C
2Cmatrix
Systems to matrices
222
111
CyBxA
CyBxA
1A
b
a
10
011B
2A 2B1C
2Cmatrix
Reduced Row-Echelon Form
[2nd], [x-1], [βΊ], [alpha], [apps]
or
[2nd], [x-1], [βΊ], [βΌ] to rref( , [enter]
[2nd], [ x-1], [enter], [enter]
[2nd],[x-1],[βΊ] ,[βΊ], [enter]
enter rows [enter]
enter columns [enter]
enter matrix;
[2nd], [mode]
rrefmatrix
rref
[2 1 55 3 13 ]{ 2π₯+π¦=5
5 π₯+3 π¦=13(π ,π)
[1 0 20 1 1]
Solve each system using matrices
183
1152
yx
yx
183
1152
110
301
Solution:( , )3 1
12416
224
0
cba
cba
cba
121416
2124
0111Solution:
( , , )1 1
0100
1010
1001
0
Solve each system using matrices
53
724
yx
yx
513
724
5.010
5.101
Solution:( -1.5, -0.5)
12
82
23
zy
zx
zyx
1120
8201
2131Solution:
( -2 , 3, 5)
5100
3010
2001Pg. 179#15-20,24-27,
32,33,36,37
53
724
yx
yx