Support Vector Machine & Its Applications

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Support Vector Machine & Its Applications Abhishek Sharma Dept. of EEE BIT Mesra Aug 16, 2010 A portion (1/3) of the slides are taken from Prof. Andrew Moore’s SVM tutorial at http://www.cs.cmu.edu/~awm/tutorials onsiderable part (1.8/3) is taken from SVM presentation of Mingyue Tan The University of British Columbia

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Support Vector Machine & Its Applications. Abhishek Sharma Dept. of EEE BIT Mesra Aug 16, 2010. A portion (1/3) of the slides are taken from Prof. Andrew Moore’s SVM tutorial at http://www.cs.cmu.edu/~awm/tutorials A considerable part (1.8/3) is taken from SVM presentation of - PowerPoint PPT Presentation

Transcript of Support Vector Machine & Its Applications

Support Vector Machine & Its Applications

Abhishek SharmaDept. of EEE

BIT MesraAug 16, 2010

A portion (1/3) of the slides are taken from Prof. Andrew Moore’s

SVM tutorial at http://www.cs.cmu.edu/~awm/tutorials

A considerable part (1.8/3) is taken fromSVM presentation of

Mingyue Tan The University of British Columbia

Overview

Artificial Neural Networks vs. SVM Intro. to Support Vector Machines (SVM) Properties of SVM Applications

Text Categorization

References

ANN vs SVM

The development of ANNs followed a heuristic path, with applications and extensive experimentation preceding theory.

In contrast, the development of SVMs involved sound theory first, then implementation and experiments.

A significant advantage of SVMs is that whilst ANNs can suffer from multiple local minima, the solution to an SVM is global and unique.

Two more advantages of SVMs are that that have a simple geometric interpretation and give a sparse solution.

Unlike ANNs, the computational complexity of SVMs does not depend on the dimensionality of the input space.

The reason that SVMs often outperform ANNs in practice is that they deal with the biggest problem with ANNs, SVMs are less prone to overfitting.

Researchers’ Opinions "They differ radically from comparable approaches such

as neural networks: SVM training always finds a global minimum, and their simple geometric interpretation provides fertile ground for further investigation."Burgess (1998)

"Unlike conventional statistical and neural network methods, the SVM approach does not attempt to control model complexity by keeping the number of features small.

"In contrast to neural networks SVMs automatically select their model size (by selecting the Support vectors)."Rychetsky (2001)

Support Vector Machine (SVM) A classifier derived from statistical learning theory

by Vapnik, et al. in 1992 SVM became famous when, using images as

input, it gave accuracy comparable to neural-network with hand-designed features in a handwriting recognition task

Currently, SVM is widely used in object detection & recognition, content-based image retrieval, text recognition, biometrics, speech recognition, etc.

V. Vapnik

Linear Classifiers

f x

yest

denotes +1

denotes -1

f(x,w,b) = sign(w x + b)

How would you classify this data?

w x +

b=0

w x + b<0

w x + b>0

Linear Classifiers

f x

yest

denotes +1

denotes -1

f(x,w,b) = sign(w x + b)

How would you classify this data?

Linear Classifiers

f x

yest

denotes +1

denotes -1

f(x,w,b) = sign(w x + b)

How would you classify this data?

Linear Classifiers

f x

yest

denotes +1

denotes -1

f(x,w,b) = sign(w x + b)

Any of these would be fine..

..but which is best?

Linear Classifiers

f x

yest

denotes +1

denotes -1

f(x,w,b) = sign(w x + b)

How would you classify this data?

Misclassified to +1 class

Classifier Margin

f x

yest

denotes +1

denotes -1

f(x,w,b) = sign(w x + b)

Define the margin of a linear classifier as the width that the boundary could be increased by before hitting a datapoint.

Classifier Margin

f x

yest

denotes +1

denotes -1

f(x,w,b) = sign(w x + b)

Define the margin of a linear classifier as the width that the boundary could be increased by before hitting a datapoint.

Maximum Margin

f x

yest

denotes +1

denotes -1

f(x,w,b) = sign(w x + b)

The maximum margin linear classifier is the linear classifier with the, um, maximum margin.

This is the simplest kind of SVM (Called an LSVM)Linear SVM

Support Vectors are those datapoints that the margin pushes up against

1. Maximizing the margin is good according to intuition and PAC theory

2. Implies that only support vectors are important; other training examples are ignorable.

3. Empirically it works very very well.

Let me digress to…what is PAC Theory? Two important aspects of complexity in machine learning.

First, sample complexity: in many learning problems, training

data is expensive and we should hope not to need too much of it.

Secondly, computational complexity: A neural network, for example, which takes an hour to train may be of no practical use in complex financial prediction problems.

Important that both the amount of training data required for a prescribed level of performance and the running time of the learning algorithm in learning from this data do not increase too dramatically as the `difficulty' of the learning problem increases.

Such issues have been formalised and investigated over the past decade within the field of `computational learning theory'.

One popular framework for discussing such problems is the probabilistic framework which has become known as the `probably approximately correct', or PAC, model of learning.

Let me digress to…what is PAC Theory?

Linear SVM Mathematically

What we know: w . x+ + b = +1 w . x- + b = -1 w . (x+-x-) = 2

“Predict Class

= +1”

zone

“Predict Class

= -1”

zonewx+b=1

wx+b=0

wx+b=-1

X-

x+

ww

wxxM

2)(

M=Margin Width

Linear SVM Mathematically Goal: 1) Correctly classify all training data

if yi = +1

if yi = -1

for all i

2) Maximize the Margin

same as minimize

We can formulate a Quadratic Optimization Problem and solve for w and b

Minimize

subject to

wM

2

www t

2

1)(

1bwxi

1bwxi

1)( bwxy ii

1)( bwxy ii

i

wwt

2

1

Solving the Optimization Problem

Need to optimize a quadratic function subject to linear constraints.

Quadratic optimization problems are a well-known class of mathematical programming problems, and many (rather

intricate) algorithms exist for solving them. The solution involves constructing a dual problem where a

Lagrange multiplier αi is associated with every constraint in the primary problem:

Find w and b such thatΦ(w) =½ wTw is minimized;

and for all {(xi ,yi)}: yi (wTxi + b) ≥ 1

Find α1…αN such that

Q(α) =Σαi - ½ΣΣαiαjyiyjxiTxj is maximized and

(1) Σαiyi = 0(2) αi ≥ 0 for all αi

A digression… Lagrange Multipliers In mathematical optimization, the method of Lagrange

multipliers provides a strategy for finding the maxima and minima of a function subject to constraints.

For instance, consider the optimization problem maximize 

subject to 

We introduce a new variable (λ) called a Lagrange multiplier, and study the Lagrange function defined by

(the λ term may be either added or subtracted.) If (x,y) is a maximum for the original constrained problem, then there

exists a λ such that (x,y,λ) is a stationary point for the Lagrange function (stationary points are those points where the partial derivatives of Λ are

zero).

The Optimization Problem Solution The solution has the form:

Each non-zero αi indicates that corresponding xi is a support vector.

Then the classifying function will have the form:

Notice that it relies on an inner product between the test point x and the support vectors xi – we will return to this later.

Also keep in mind that solving the optimization problem involved computing the inner products xi

Txj between all pairs of training points.

w =Σαiyixi b= yk- wTxk for any xk such that αk 0

f(x) = ΣαiyixiTx + b

Dataset with noise

Hard Margin: So far we require all data points be classified correctly

- No training error

What if the training set is noisy?

- Solution 1: use very powerful kernels

denotes +1

denotes -1

OVERFITTING!

Slack variables ξi can be added to allow misclassification of difficult or noisy examples.

wx+b=1

wx+b=0

wx+b=-

1

7

11 2

Soft Margin Classification

What should our quadratic optimization criterion be?

Minimize

R

kkεC

1

.2

1ww

Hard Margin v.s. Soft Margin The old formulation:

The new formulation incorporating slack variables:

Parameter C can be viewed as a way to control overfitting.

Find w and b such that

Φ(w) =½ wTw is minimized and for all {(xi ,yi)}yi (wTxi + b) ≥ 1

Find w and b such that

Φ(w) =½ wTw + CΣξi is minimized and for all {(xi ,yi)}yi (wTxi + b) ≥ 1- ξi and ξi ≥ 0 for all i

Linear SVMs: Overview The classifier is a separating hyperplane. Most “important” training points are support vectors; they

define the hyperplane. Quadratic optimization algorithms can identify which training

points xi are support vectors with non-zero Lagrangian multipliers αi.

Both in the dual formulation of the problem and in the solution

training points appear only inside dot products: Find α1…αN such thatQ(α) =Σαi - ½ΣΣαiαjyiyjxi

Txj is maximized and (1) Σαiyi = 0(2) 0 ≤ αi ≤ C for all αi

f(x) = ΣαiyixiTx + b

Non-linear SVMs Datasets that are linearly separable with some noise

work out great:

But what are we going to do if the dataset is just too hard?

How about… mapping data to a higher-dimensional space:

0 x

0 x

0 x

x2

Non-linear SVMs: Feature spaces General idea: the original input space can always be

mapped to some higher-dimensional feature space where the training set is separable:

Φ: x → φ(x)

The “Kernel Trick” The linear classifier relies on dot product between vectors K(xi,xj)=xi

Txj

If every data point is mapped into high-dimensional space via some transformation Φ: x → φ(x), the dot product becomes:

K(xi,xj)= φ(xi) Tφ(xj)

A kernel function is some function that corresponds to an inner product in some expanded feature space.

Example:

2-dimensional vectors x=[x1 x2]; let K(xi,xj)=(1 + xiTxj)2

,

Need to show that K(xi,xj)= φ(xi) Tφ(xj):

K(xi,xj)=(1 + xiTxj)2

,

= 1+ xi12xj1

2 + 2 xi1xj1 xi2xj2+ xi2

2xj22 + 2xi1xj1 + 2xi2xj2

= [1 xi12 √2 xi1xi2 xi2

2 √2xi1 √2xi2]T [1 xj12 √2 xj1xj2 xj2

2 √2xj1 √2xj2]

= φ(xi) Tφ(xj), where φ(x) = [1 x1

2 √2 x1x2 x22 √2x1 √2x2]

What Functions are Kernels? For some functions K(xi,xj) checking that

K(xi,xj)= φ(xi) Tφ(xj) can be cumbersome.

Mercer’s theorem:

Every semi-positive definite symmetric function is a kernel

Examples of Kernel Functions Linear: K(xi,xj)= xi

Txj

Polynomial of power p: K(xi,xj)= (1+ xi Txj)p

Gaussian (radial-basis function network):

Sigmoid: K(xi,xj)= tanh(β0xi Txj + β1)

)2

exp(),(2

2

ji

ji

xxxx

K

Non-linear SVMs Mathematically Dual problem formulation:

The solution is:

Optimization techniques for finding αi’s remain the same!

Find α1…αN such thatQ(α) =Σαi - ½ΣΣαiαjyiyjK(xi, xj) is maximized and (1) Σαiyi = 0(2) αi ≥ 0 for all αi

f(x) = ΣαiyiK(xi, xj)+ b

SVM locates a separating hyperplane in the feature space and classify points in that space

It does not need to represent the space explicitly, simply by defining a kernel function

The kernel function plays the role of the dot product in the feature space.

Nonlinear SVM - Overview

Properties of SVM Flexibility in choosing a similarity function Sparseness of solution when dealing with large data

sets - only support vectors are used to specify the separating

hyperplane Ability to handle large feature spaces - complexity does not depend on the dimensionality of the

feature space Overfitting can be controlled by soft margin

approach Nice math property: a simple convex optimization problem

which is guaranteed to converge to a single global solution Feature Selection

SVM Applications

SVM has been used successfully in many real-world problems

- text (and hypertext) categorization

- image classification – different types of sub-problems

- bioinformatics (Protein classification,

Cancer classification)

- hand-written character recognition

Weakness of SVM It is sensitive to noise - A relatively small number of mislabeled examples can

dramatically decrease the performance

It only considers two classes - how to do multi-class classification with SVM? - Answer: 1) with output arity m, learn m SVM’s

SVM 1 learns “Output==1” vs “Output != 1” SVM 2 learns “Output==2” vs “Output != 2” : SVM m learns “Output==m” vs “Output != m”

2)To predict the output for a new input, just predict with each SVM and find out which one puts the prediction the furthest into the positive region.

Application: Text Categorization Task: The classification of natural text (or

hypertext) documents into a fixed number of predefined categories based on their content.

- email filtering, web searching, sorting documents by topic, etc..

A document can be assigned to more than one category, so this can be viewed as a series of binary classification problems, one for each category

Application : Face Expression Recognition Construct feature space, by use of

eigenvectors or other means Multiple class problem, several expressions Use multi-class SVM

Some Issues Choice of kernel - Gaussian or polynomial kernel is default - if ineffective, more elaborate kernels are needed

Choice of kernel parameters - e.g. σ in Gaussian kernel - σ is the distance between closest points with different

classifications - In the absence of reliable criteria, applications rely on the use

of a validation set or cross-validation to set such parameters.

Optimization criterion – Hard margin v.s. Soft margin - a lengthy series of experiments in which various parameters

are tested

Additional Resources LibSVM

An excellent tutorial on VC-dimension and Support Vector Machines:

C.J.C. Burges. A tutorial on support vector machines for pattern recognition. Data Mining and Knowledge Discovery, 2(2):955-974, 1998.

The VC/SRM/SVM Bible: Statistical Learning Theory by Vladimir Vapnik, Wiley-Interscience; 1998

http://www.kernel-machines.org/

Reference

Support Vector Machine Classification of Microarray Gene Expression Data, Michael P. S. Brown William Noble Grundy, David Lin, Nello Cristianini, Charles Sugnet, Manuel Ares, Jr., David Haussler

www.cs.utexas.edu/users/mooney/cs391L/svm.ppt Text categorization with Support Vector

Machines:learning with many relevant features

T. Joachims, ECML - 98