THE PROBLEMISTSUPPLEMENT

ISSUE 88MAY 2007

EDITOR & ORIGINALS EDITOR:John Rice, 9 Manor Crescent, Surbiton KT5 8LG(johnrice@freeuk.com).Send solutions and comments to C.J.Morse,102A Drayton Gardens, London SW10 9RJ.All originals printed in the Supplement take part in thenormal Problemist tourneys, so that publication here isequivalent to publication in the main magazine. For theSupplement we look for straightforward originals of alltypes. They should be pointed and well constructed, andhave entertainment value. JMR

CONTENTSBerolina pawns, by John Rice . .Original problems PS1900-1911 . .Solutions to November originals . .Efim Rukhlis and Venelin Alaikov: a tribute by John Rice . . . .Solutions to problems from page 809 .Fairy definitions . . . .Fairy solutions (November) . .Fairy originals PS1912-1917F . .

809810812814

818818819820

C Richard SteinwegFairy Chess Review 1934

wGRdwdwd0NdwdQdwwdwdrdwd)wdkdwdwwdwdwdRddwdwdpdwwdw)wdBddwdwdKHwS#5 Berolina pawns

D Hans GruberThema Danicum 1982

wdwdwdkdIw)P)PdrwdqdwdwddwdwdwdwwdwdwdwddwdwdwdwwdwdwdwddwdwdwdwSer-S#6 Berolina pawns

BEROLINA PAWNS, by John Rice

Our interrupted survey of fairy pieces continueswith a study of the Berolina pawn. Represented onthe diagram by P, this unit reverses the move/capture arrangement of the normal pawn: it movesdiagonally and captures on the file. A Berolina pawnon the second rank can make a double diagonaljump, and may be captured en passant. On reachingits promotion square, it changes into a normal piece,thereby losing its fairy properties. The piece wasinvented by E.Hebermann in 1926 and firstintroduced by Richard Steinweg in Fairy ChessReview, February 1934.

A is a simple example. 1.R3a2 threatens fourmoves by the Berolina pawn (BP) c2, to a4, b3, d3and e4, and the four available moves of the Rc5force each one in turn. Black has a further defence1…c3, which enables the white BP to play thecapture 2.BPxc3.

B has been specially composed to illustrate the enpassant capture with Berolina pawns. In position (a)the mate will be given on c4 by the BPa2, which canreach that square in a single move: 1.BPe3 Kc72.BPd4 BPc3+ 3.Kc5 BPc4. With the (normal) blackpawn on a4 in (b), however, the white BPd2 needstwo moves to mate on b4, since the black BParriving on c4 could otherwise capture en passant onc3: 1.Kb4 BPc3 2.BPbc4 BPb3+ 3.Kb5 BPb4.

C (selfmate) and D (series-selfmate) offer solversmore of a challenge. Solutions on page 818.

A Jean OudotDie Schwalbe 1966

wdwdwdwddwdwdwdwwdpdwdwddw4wdpdwwdpdwIwd$wdwdBdwwdPdwiwd$wdwdwdw#2 Berolina pawn c2

B John RiceOriginal

wdwdwdwddKdwdwdwwdwdwdwd0p0pdwdww0k0wdwddwdwdwdwPdw)wdwddwdwdwdwH#3 (b) Pb4>a4Berolina pawns (except b4)

THE PROBLEMIST SUPPLEMENT MAY 2007810

PS1900 Fedor Kapustin(Ukraine)

rdwdkdBd0w0pdwdwwdPdw)wddwdRdwdwwdwdwdwddwdwdwdwwdwdwdwddQdwdwdK#2 (b) d7=BB

PS1901 Tony Lewis(after H.D'O.Bernard)

wdBdwGwddwdpdwdww0wdwdwddQhkhw)wwdwdRdwddwIwdwHwwdwdwdwddwdwdwdw#2

PS1902 Colin Russ

wdwdwdwdGwdwdwdwwdwdwdwddwdpdwdNw0w)kdP0dwdwdwdwwdwdPdwddwdNdwdK#3

DEFINITIONS

White plays up the board in all positions.In Directmates (those problems with a ‘#n’ notation below the diagram, where the ‘n’ denotes the number

of moves) White plays first (the key) and forces mate at latest on his nth move, whatever Black plays. Set Playis what would happen if Black were to play first in the diagram position. For instance, in a #2 there is often setplay where black moves are followed by white mates and this can form part of the theme of a problem. Triesare white moves that would solve but for a single black refutation. The black defences and white matesfollowing tries can form part of the theme of a problem.

In Helpmates (those problems with a ‘H#n’ notation below the diagram, where the ‘n’ denotes the numberof moves) Black plays first and co-operates with White to enable White to mate Black on White’s nth move.These have a single solution unless otherwise indicated below the diagram. Sometimes, the number of movesasked for in helpmates includes a half-move, such as ‘H#2½’. In these helpmates the normal sequence of movesis preceded by a white move. So ‘H#2½’ indicates the following sequence – 1...W 2.B W 3.B W#.

Twins, indicated by a notation such as ‘(b) wPe2>d3’ under the diagram, are problems with more than oneposition for solving. Unless otherwise stated, each twin position is formed from the diagram position.

Duplex problems are those where White fulfils the stipulation and then Black does. So a H#2 duplex has twosolutions, the first as in a normal helpmate and the second with White playing first and being eventually matedby Black.

All the originals in this and every issue are computer-tested. If the computer has been unable toverify soundness, the symbol C– is shown. Otherwise solvers can assume that soundness hasbeen confirmed.

Send solutions and comments to C.J.Morse (address on front page) by 1st October 2007.

ORIGINAL PROBLEMS PS1900-1911Tony’s 1901 is referred to in the report on our Torquay meeting in the main magazine. Colin and Ron each

provide a challenge characteristic of his style. Newman celebrates his 80th birthday with 1907. What is thethematic link between the solutions? To solve the five parts of 1910 you need to know about the piece-shiftsrequired: (b) Rd2>b2; (c) as (b) +Sa4>c4; (d) as (c) +BK>c6; (e) as (d) +WK>f5. You may well find that onesolution of 1911 is immediately obvious, but the second one will probably keep you guessing for a time.

Do enjoy your solving – and please put pen to paper, or fingers to the keyboard, with your comments! Theseshould go with your solutions to Jeremy Morse. JMR

MAY 2007 THE PROBLEMIST SUPPLEMENT 811

PS1903 Joaquim Crusats &Steven Dowd

(Spain/USA)

wdwdwdQddKdw0wdwwdwdw0wddpipdwdwwdpdwdwddwdwdBdwwdw$wdwddwdwdwdw#3

PS1904 Ron Fenton(USA)

wdwdwdwddwdwdwHwwdN0wdwddKdkdwdww0wdpdwddPdw)wdwwdwdwdwddwdwdwdw#8

wdwdRdwGdwdwdwdwwdb0wdwddndkdNdwwdw0wdwddwdwdwdwwdqdwdwddwdwdwdKH#2 2 solutions

PS1906 Vitaly Medintsev(Russia)

kgw$wdw4dwdNdwdpwdndKdwddwdwdwdwwdwdBdwddwdwdwdwwdwdwdwddwdwdwdbH#2 2 solutions

PS1907 Newman Guttman(USA)

Bdw1wdbddwdwhwdwwdwdwdwddwdNdp0wwdwdwdpddpdKdk4pwdwdwgN0dwdw4wdwH#2 2 solutions

PS1908 Yoel Aloni &Paul Vatarescu

(Israel)

wdwdwdwddwdndw4wkdwdwdq4dpdwdwdwwdwdwdwddwdwdwdwwdwdwdw$dwdwdwdKH#3 (b) BK>d8

PS1909 Christer Jonsson(Sweden)

wdwdwGnddwdwdbhwwdpdqdwddw0BdwdwwdwgwiwddwdwdwdwKdwHwdwddwdwdrdwH#3 2 solutions

PS1910 János Mikitovics(Hungary)

wdwdwdwddwdwdwdwwdwdwdwddwdpdwdwNdwIwdwddwdPdwdwndk4wdwddwdwdwdwH#4 (b-e) see text on page 810

PS1911 Boris Shorokhov &C.J.Feather

(Russia/GB)

wdwdwdwidwdpdPdww0wdwdwddwdwdwdwwdwdndwdgpdwdwdwPdwdwdwdIndwdqdwH#5 2 solutions

PS1905 Christer Jonsson(Sweden)

THE PROBLEMIST SUPPLEMENT MAY 2007812

SOLUTIONS (November)

PS1846 (Shire) 1.Rg7 (-) 1…R~ 2.Sd6; 1…Re6 2.Qh5; 1…Rxf6 2.Se7; 1…B~2.Sd4; 1…Be5 2.Qg4; 1…Bxf6 2.Sh6; 1…d4 2.Qe4. A seemingly pointless key,which vacates g4 for the Q, which is also relieved of guard duty (J.Gill). Amagnificent problem: a waiter in classical style (E.Petite). Rather obvious key(C.C.Frankiss). Beautiful setting, lovely two-mover! (T.H.Traum). David has aknack for finding lucid settings. This problem was composed in the late 1980s foran article on diagonal-orthogonal echoed play, but never used (MM). David’s is arare gift: his problems express their idea lucidly, succinctly and artistically, withseldom an underused piece and always good solver-appeal – which makes hiswork ideal for the Supplement! (JMR).

PS1847 (Kuzmichev) 1.Rb7 (>2.cxb8S/c8Q) 1…Kxc6 2.cxd8S; 1…Kc82.cxb8Q; 1…Kxe7 2.c8S; 1…Q,Sxc6 2.cxd8Q; 1…Rxe8+ 2.fxe8Q; 1…Sxc72.Rxc7. Various mates by promotion skilfully done (CCF). A bewildering matrix.The key eyes d7 and allows an attractive pin-mate 1…Kxc6 2.cxd8S GenerallyWhite must mind his Ps and Qs (JG). Beautiful promotion play (EP). The double-threat is perhaps a slight blemish, but otherwise the idea, though very familiar,works well (JMR).

PS1848 (Paslack) 1.Ba8? (>2.Qd6) 1…R~ 2.Sd3; 1…Rc6! 1.Ba2? (>2.Qd6)1…R~ 2.Sd3; 1…Rc4! 1.Bxe6? (>2.Qd6) 1…R~ 2.Sd3; 1…Rc6 2.Rd5; 1…Se8!1.Be4! (>2.Qd6) 1…R~ 2.Sd3; 1…Sd4 2.Sd3; 1…Se8 2.Qxe6; 1…Qa6 2.Qxc5.A nice try problem (THT). In each phase a random R defence opens a wQ guardon d4, allowing 2.Sd3, which closes the existing R guard on d4. In the group ofwhite line themes this is known as Theme B. The correction moves which defeatthe tries 1.Ba8? and 1.Ba2? also illustrate Theme A, where the bishop guard ond5 is cut in anticipation of 2.Sd3 cutting the rook guard on the same square. Thecombination of Theme A and Theme B is called the Isaev theme, probably afterproblem B in this month’s Browsing in the library article in the main magazine(MM).

PS1849 (Ganapathi) 1.Rb3 (>2.Sg2+ fxg2 3.Rh3)1…Sc3 2.Sd4 (>3.Sxf3); 1…Bc3 2.Rxb1 (>2.Rh1);1…Rc3 2.Bf6 (>3.Bxg5). Three black self-interferences. (THT) A fine example of remoteinterferences. (JG) I can’t resist quoting anotherbeautiful problem by Knud Hannemann, which mayhave been a forerunner to problem A from myBrowsing in the library article in the Marchmagazine. 1 Pr Nederlandsch-Indische Schaakbond1925 – 6s1/1p3pB1/sR6/1p1k4/p2P1P1b/1PR2P2/6K1/2SB4 #3 1.Se2 (>2.Rc5+) 1…Bf6 2.Bc2;1…Sf6 2.Re3; 1…f6 2.Rc8; 1…Be1 2.Be5; 1…b42.bxa4 (MM).

PS1850 (Blum) 1.Re2 (>2.Rxe5 > 3.Bb5, Sxb2;2…Sxe5 3.Sxe5) 1…e4 2.Qg5 (>3.Bb5, Qd5, Qb5);2…Se5 3.Sxe5; 1…Sc2,Sf3 2.Qxd3+ Kxd3 3.Bb6;1…dxe2 2.Se3+ dxe3 3.Qd5. Charming problem intraditional style with precise white continuations(EP). Good key and nice variations (THT). Goodkey well-matched by post-key play (JG).

PS1851 (Vatarescu) 1.Sc4? Kd5! 1.Qg6+? Kf4!1.Qf2, Qg1? Kf5! 1.Kh3? Kd5! 1.Qg8! (-) 1…Ke32.Qc4 Kf2 3.Qc1 Kg2 4.Qg1; 3…Ke2 4.Qe1;1…Kf4 2.Qb3 Ke4 3.Qd3+ Kf4 4.Sg6; 2…Ke53.Qc4 Kf6 4.Qf7; 1…Kf5 2.Qc4. Took some timebefore I found the key. Good miniature (THT).Surprising key, but little else (CCF).

PS1846

wdwdwdNddwdwdwdww0rdw)wddNdpdkdwwdwdwdRddwgPdw)ww0wdQdwddKdwdwdw#2

PS1847

whw4NdKddw)kGPdww$RdndQgdw1pdwdwwdwdwdbddwdwdw4wwdwdwdwddwdwdwdw#2

PS1848

wdwdwdwddwdwdwhww!wdpdKddw4Bip0wwdwdwHwd1w0wdPdwwdndwdwGdwdRdwdw#2

PS1849

wdwdwdwddw4pdwdwwdr0wdwddNdpGK0ww$wdw0BidwdwHpdwwdw)w)wdgndwdwdw#3

#4

PS1851

wdwdwdwddwdwdwdwwdwdwdw0dwdwHwdpwdwdkdwIdwdwdN!wwdwdwdwddwdwdwdw#4

PS1850

wdbdwdwddwdndw0wwdBdwdwddwdw0wdwN0k0wdNddpdpdwdww0w!w$wddKdwhwdw#3

MAY 2007 THE PROBLEMIST SUPPLEMENT 813

PS1852 (Makaronez) 1.Qe3+ Kf1 2.Qe1+ Kg23.Qg1+ Kf3 4.Sc3 (>4.Qg3) 4…Se2 5.Qh1+ Kxf26.Se4; 1…Kd1 2.Sa3 (>3.Qe1) 2…Sd3 3.Qxd3 R~4.Qf1+ Kxd2 5.Qe1+ Kd3 6.Qe3. Fine Q activity(EP). The 1…Kf1 variation is very nice (THT). Thisone proved difficult (MM).

PS1853 (Milewski) 1.Qd4 Bc5 2.Se7 Bxe7; 1.g5Bd4 2.Qxe5 Bxe5. Transformation of each pin lineinto a battery line (THT). White unpinning andcapture in both solutions (CCF).

PS1854 (Vereshchagin & Lewis) (a) 1.Bd2 Be42.e1B Bf3; (b) 1.c1S Bb4 2.Sc2 Sb2. Promotions toB and S with attractive twinning (CCF). Gentlepromotions to match the mating pieces (JG). Blackfollow-my-leader theme with promotions (THT).This was an unrewarded entry in the tourney atWageningen for joints by composers from differentcountries (MM).

PS1855 (Kirchner & Mikitovics) (a) 1.Ke3 Sh12.Rf4 Sf2 3.Bf3 Sc2; (b) 1.Bd3 Sf1 2.Ke4 Sc2 3.Rf4Sd2; 1.Re3 Sa6 2.Bf3 Se2+ 3.Ke4 Sc5. Cyclic blackfollow-my-leader theme (THT). Cyclic pattern ofblack moves with double follow-my-leader. Pity thewP is only needed to shield the K in one solution(C.Tylor). Not certain that the twinning is acceptable(CCF). The idea has been shown before, e.g.C.J.Feather, Moultings 5 1991 16/K7/4k2P/b1P1rq2/7S/7R/8 h#3 (b) h3>e2 (c) further c4>g2(a) 1.Qe3 Rd2 2.Rf4 Rd5+ 3.Ke4 Sg5; (b) 1.Kf5Rg2 2.Qe5 Rg6 3.Rf4 Sg3; (c) 1.Rd4 Rh3 2.Ke4 Rf33.Qe5 Sc3, which adds echoed mates (MM).

PS1856 (Sobrecases) 1.Bf3 Kc4 2.Ke4 Sb6 3.Rf5Sd5 4.e5 d3; 1.Ke6 Ke4 2.Bh5 d4 3.Re5+ dxe54.Bf7 Sc5. Well constructed but not too difficult(CCF). Seemingly impossible in such an opensetting (JG). Nice models, good miniature (THT).

PS1857 (Anderson) 1.c1Q Bf6 2.Be5 Bh4 3.Kd4d3 4.Qh1 Kc2 5.Qd5 Bf2. Fine intro to this cleverpiece: mixed coloured Bristol manoeuvre andunexpected promotion to Q (THT). An aestheticpiece of engineering (JG). Clever midboard mate.An enjoyable problem (CCF). Lovely little positionwith equal forces. W1-B2 magnet play, andunexpected double use of h-file (CT). A beautifulminiature (R.Lazowski). PS1841F (Sept): composer corrects: Gf3>f1.

K K K K K

Just room for a couple of selfmates for casualsolving. These two are taken from the book whichprovided inspiration for the article on page 4 of theJanuary Problemist, and are also quoted in FriedrichChlubna’s Versunkene Schätze. See if you can crackthem! Solutions on page 819.

PS1852

wdwdwdrddwdw0w0wwdwdwdKddN0wdwdwwdwdwdpddwdwdw!wwdw)kGwddwhwdwdw#6

PS1853

wdwdwdwdGw$wdw0wwdndwdwgdwdw)wdww)kdw1RddbHpdwdwwdwdwdwddwdwdwdKH#2 2 solutions

PS1854

wdKdwdwddwdwdwdwwdwdwdwddwdwdwdwwdwdwdwdGwdBhw0wwdpdpdwddwdkgwdwH#2 (b) d3=WS

PS1855

wdwdwdwddwdwdwdwwdwdwdwddwdw)wdwwHwdbiwddwdwdrHwwdwdwdwddwdwIwdwH#3(b) WK>e6: 2 solutions

PS1856

wdwdwdwddwdw0wdwwdwdwdwddrdwdkdwNdwIwdwddwdwdwdwwdw)bdwddwdwdwdwH#4 2 solutions

PS1857

wdwdwdwddwdwdwdwwdwdwdwddwdwdwdwwdwdwdwddKGkdwdwwgp)wdwddwdwdwdwH#5

1 Joseph WainwrightLes Mille et un matsinverses 1907

wdb$wdwddpGphwdwpIwdQdwd)wdwdwdwRdpip0wddwdNgpdww)P0wdwddwdndwdwS#2

2 Alain C.WhiteLes Mille et un matsinverses 1907

wdwdwiwd!w$wdwdwwdwdwHRddwdwdwdwwdwdwdw)dwdwdwdwpGp)w0w0hbIwdBdwS#3

THE PROBLEMIST SUPPLEMENT MAY 2007814

A Efim Rukhlis3 Pr CSTV 1946wdwdwdw!dwdpdwHww$w)PdwddN0kdndwRhwdwdwddPdwdwdBwdwIwdwdGwdwdwdb#2

B Efim Rukhlis1 Pr Uzbekskogo KFC1955wdbhwdKddwdwdpgww!wdwdwHdwdpdwdwwdwhwdw$dwdPip0wwdwdwdw1HwdRGBdw#2

C Efim RukhlisShakhmaty v SSSR 1948

w4wdwdwGdwdw$wHwndw0wdPd!RHwdPdwwdwiw4wdIw0bdwdqBdPdwdnddwdwdwdw#2

D Efim Rukhlis2 Pr Skakhmaty v SSSR1946bdNGRdwddwdPdwdBqdwdwhpddwdwhkdwp$wdwdwddwdwdwdPwdNdP4rddK!wdwdw#2

E Efim Rukhlis2 Pr Polski ZP 1947

w1wdwdrdgwdwdRHwwdwdnGwddwdwdwdwQdpHpiw)dwdwdPdwwdw)wdw)dwdBdRIn#2

F Efim Rukhlis1 Pr Schach 1959

qdwdwdnd0wdBdwHwwdwdpdwG!wdwdwdwwdw0kdwddNdwdwdRwdwIwdwddwdwdwdw#2

C There’s a lot of fine battery-play in this richproblem. 1.Qb6 (>2.Qxd6) Se3 2.Sge6; 1…Q,Rxf52.Sxf5; 1…Qf3 2.Se8; 1…Rxb6 2.Sh5; 1…Be42.Sce6; 1…Bc4 2.Sb3; 1…Sb4,c7 2.Sb7; 1…Rd82.Sxa6.

D A study in Black Correction, with square-vacating moves by each of the two bSs leading tothree well differentiated mates. 1.Bg8 (>2.Se7) Se~2.Sd4 (exploiting the opening of e8-e4); 1…Sf3/Sc6(corrections) 2.Qf4/Sd6; 1…Sf~ 2.Se3 (exploitingthe opening of d8-g5); 1…Sg4/Sd5 (corrections)2.Qg5/e4. All the corrections are interferences. Notealso 1…Qxc8 2.Be6.

E Unpinning play combined with mates by theR+B battery. 1.Qc6 (>2.Qxe4) Sc5/Sg5 2.Se2/Sh5(the unpinned wS cannot mate on e6); 1…Sf2/Sg32.Sdxe6/Sgxe6 (now the mates must be on e6);1…Bxd4+/Rxg7+ 2.Bxd4/Bxg7; 1…Qe5/Qa8,b72.Bg5/Qd6. The key is strong, but the complexity ofthe play is adequate compensation.

F The important black moves here are 1…Qd5(with no set mate) and 1…e5 (set 2.Bf5). 1.Qc5?(>2.Qxd4) Qd5! 1.Qa4,b4? (>2.Qxd4) Qd5 2.Re3;1…e5! 1.Qg5? (>2.Sc5) Qd5/e5/d3 2.Qf4/Qg2/Re3;1…Qc8! 1.Qa1! (>2.Qxd4) Qd5/e5 2.Qe1/Qh1. Sothe thematic black moves each refute one try andthen act as defences, with new mates to follow, aftera further try and after the key. In the post-keyposition the bK has two flights, met by the threat.

EFIM RUKHLIS AND VENELIN ALAIKOV:A TRIBUTE, by John Rice

Two masters of the chess problem are remembered in this article. Efim Rukhlisis best known for his twomovers, in particular the celebrated example of thetheme named after him (quoted on page 51 of the March Problemist). VenelinAlaikov was more versatile, being at home in many genres. The anthology of hisworks, published in 1997, contains direct-mates of all kinds, selfmates, helpmatesand fairies. We concentrate here on the 2-move output of each composer.

A 1.Sh5 (>2.Qe5). The two bSs can each defend twice, by direct guard or line-closure. In mating, White must take care of the flights e4 and e6. Moves of theSb4 open the line a4-e4, so that either 2.Sc7 or 2.Sf4 will mate, but the precisemoves 1…Sd3 (guarding f4) and 1…Sc6 (cutting b6-d6) each prevent one ofthese mates. Moves of the Sf5 open h3-e6, allowing mate by 2.Sf6 or 2.Sc3. Butthe arrival of the bS on g7 or d4 has the effect of closing a line of guard to thesquare e5, making White choose his reply with care: 1…Sg7 2.Sf6 only, and1…Sd4 2.Sc3 only. This dual-avoidance pattern is called the Java theme: inmating, White must close the same guard-line as Black has closed. Here the bK-flights, one of them given by the key, constitute attractive by-play: 1…Ke4 2.Qa8,and 1…Kxe6 2.Qg8.

B If you have studied the Rukhlis theme, you will recognise this problem asan example of it. In the set play, 1…g2, interfering with the bQ, allows 2.Sc2, and1…Se6, interfering with the Bc8, is followed by 2.Sf5, both mates beingdependent on the fact that the bSd4 is pinned. The key unpins this S: 1.Qc7, withthe threat of 2.Qf4. Now the two set mates reappear after different black defences:1.Se2 2.Sc2, and 1…S4e6 2.Sf5. After the set defences there are changed mates:1…g2 2.Qc1, and 1…S8e6 2.Sg4.

MAY 2007 THE PROBLEMIST SUPPLEMENT 815

G Efim Rukhlis1 Pr Shakhmaty v SSSR1957w4wdwdwddwdBdpdqw0wHw$w4dw0kdwdwRdwdwdwddwdpdw!wKdPdwdwdgwdwdwdw#2

H Efim RukhlisCeskoslovensky Sach1958 (v)wdwdwdwd!p)wdpdww)wip4wdIPHwHwdRwdwdwdwGdpdw)wdwwdbdwdBgdw$wdwdw#2

I Efim Rukhlis1 HM The Problemist1960wdwdwdwg4w0wdQdwqdwdwdwd0wGNiw0wwdwdwdwhdpdwdw)wwIw$wHwddwdwdwdw#2

J Efim Rukhlis1 HM ČeskoslovenskyŠach 1962K!bdwdwd$ndkdwhrw0wHwdB$dwdp0pdwwdwdNdwGdwdwdwdwwdwdwdwddw4wdwdw#2

K Efim Rukhlis1 Pr Problemista 1965

KGwdwdwd0QdwdwdwwdwHRdwddw0pdwdpwdBiw0w4$wdwdwdwwdwdwdqddbdNdwdw#2

L Efim Rukhlis2 Pr= VechernyLeningrad 1967

w$wdwdwGdw0BdwdKbdwHwdnd4wdRdw0pr)wdwipddnHw0w0wwdwgQdPddwdwdwdw#2

G White’s attempts to create threats with his S mostly fail to 1…c4! The keyblocks this annoying pawn, but at the same time gives the bK two flights, whichmeans that the mates following Black’s defences have to be carefully played toensure that everything is covered. 1.Sc4 (>2.Se3), and now Black can defend byguarding the threat-square or moving his K. Playing a piece to d4 or e5 causes aself-block: 1…Bd4/Qe4 2.Bc6/Qd6. The moves by the K are interferences witheach of these blocking pieces in turn: 1…Kd4 2.Qe5 (interference with Ba1), and1…Ke4 2.Qxd3 (interference with bQ). 1…Re8 allows 2.Sxb6.

H How many significant lines can you spot? White’s two Rs and Bh4 are allambushed behind other units, white in one case and black in the other two. Thereare two bK-flights in the diagram position, both lacking a mate. The strong key1.Qb8 threatens 2.Qf8, and at the same time creates a new white battery. Black’sprincipal defences are moves to f5, which cut the line of guard from h5 to e5 butsimultaneously open a white line to guard one of the flights. The resulting matesby the newly-formed battery take care of the other: 1…Rf5 2.c8Q, and 1…Bf52.c8S. Black can defend also by 1…Rf3, which allows an opening of the whitemasked battery on the fifth rank: 2.Sc4. 1…Ke7 is followed by 2.Qd8, while thereis an unfortunate, though perhaps unimportant, dual after 1…Kxc5, when 2.c8Qas well as the threat can be played. The bPb3 has been added to eliminate a cook.

I The wS does battle with the bQ in seven convincing tries, each of whichthreatens 2.Rd5 and sometimes other mates as well: 1.Sb6? Qd3! 1.Sxc7? Qc6!1.Se7? Qb7! 1.Sf6? Qe6! 1.Sf4? Qc4! 1.Se3? Qe6! 1.Sc3? Qc4! In each case thereare defences by the bQ which White can meet, either by playing one of the extrathreats or by exploiting an unguard, the thematic wS having provided additionalwhite guards on its arrival. The key must clearly be 1.Sb4!, with only 2.Rd5 as athreat, but with 2.Sc6 and 2.Sbd3 lying in wait to be played after defences by thefocally-placed bQ. 1…Qe6 is answered by 2.Re2, another “mate-in-waiting”.

J introduces us to a cyclic pattern that has gainedconsiderably in popularity in recent years. This is theLačný theme, or cyclic shift of mates between twophases: in the set play defences a/b/c lead to matesA/B/C, and after the key the same defences arefollowed by mates B/C/A respectively. Set 1…Ke6 a2.Bxf5 A; 1…Kc6 b 2.Qxc8 B; 1…Se8 c 2.Bxe8 C.1.Sc4 (>2.Qd6) opens the masked line h6-c6, closesthe line c1-c8 and crucially removes the guards bythe Sd6 of squares in the bK’s extended field. Sonow we get 1…Ke6 a 2.Qxc8 B; 1…Kc6 b 2.Be8 C;and 1…Se8 c 2.Bxf5 A.

K The bQ stands in a 3-point focal position,from where she guards potential mating squares forthe wQ at b2, d5 and g7. The wRa3 does what it canto eliminate one of these lines of control by meansof shut-offs. 1.Rf3? (>2.Qxd5) Qxf3/Qg5 2.Qg7/Qb2; 1…Be4! 1.Rg3? (>2.Qg7) Qe4/Qe2 2.Qb2/Qxd5; 1…Rg4! So another white piece has a go:1.Sf2? (>2.Qb2) Qf3/Qg3 2.Qg7/Qxd5; 1…Rh3!Finally the Re6 takes over, giving a flight as itleaves the e-file: 1.Rg6 (>2.Qg7) Qe4/Qe2 2.Qb2/Qxd5. 1…dxc4 leads to 2.Sb5 throughout.

L Multiple Nowotnys (moves by White to theintersection square of black R- and B-lines), with theusual double threats in each phase: 1.b5? Sd4!1.Scb5? cxd6! 1.Sdb5? Bxc3! 1.Qb5? e2! 1.Rbb5?Sf8+! 1.Rdb5? Bb7! 1.Bb5! (>2.Rf5/Qf1). Thethreats are different in two of the phases, when theSc3 comes into play as a threat-piece.

THE PROBLEMIST SUPPLEMENT MAY 2007816

M Venelin Alaikov1 Pr Shakhmatna Misl 1971

wdwdw4wd0wdwdrdpwdQ)wdPdINdqdPdwwdpdkdBddwdw)wGRwdwdPdwddwdNdwgw#2

N Venelin AlaikovSchach-Echo 1976

wIwdndBh!wdwdwdww)wdwdpddp0Ndwdww0k)wdwddRdpdwdww4wdwdwdGrHw$wdw#2

O Venelin AlaikovHM Mat 1978

wdwdwdwddn0wdw)rwdBdK!w0dwdw)wdwwGwiwdwddw$wdpdwwHw)bdndHrdqdwdw#2

Q Venelin Alaikov1 Pr Israel Ring Ty 1982

wdwdwdwddwdBdwHwp0wdwdpd!bdwdw)wwdwdPiNGdwgRdwdwndwdRdwIdwdwdwdw#2

R Venelin Alaikov3 Pr Schach 1983

bdwdwdwddwdQGwdww0wdwdwddPdnHrgww0wiwdNddPdwdwdRw)w0w)wddBdRdwdK#2

P In the standard Nowotny a white unit plays onto the intersection square of the lines of two blackpieces moving in different ways, most commonly Rand B. In the Finnish Nowotny, illustrated here, theintersection square is occupied by a bP, which Whitecaptures. 1.Rexe6? Rxe6/Bxe6 2.Sd5/Se4 (boththreatened); but 1…Sxe3! So 1.Bxe6! Rxe6/Bxe62.Qc5/Qe5 (new threats); 1…Sxd3/Qxe4 2.Sd5/Sxe4 (the try-play threats recurring); 1…Qf5/Qh52.Rxf5/Rh6 (mates by the B+R battery). Oddlyenough, the problem works perfectly well withoutthe bPe6, though there is then a set check without areply: 1…Bxa2+.

Q 1.Kg2? (>2.Rf3) Bxd3 2.Bg3; but 1…Bxd7!1.Kh3? (>2.Se6) Bxd7 2.Bg3; but 1…Bxd3! It’sclear from this try-play that White is short of guardson potential bK-flights f3 and g4. The key providesnew guards, but gives a flight at the same time:1.Se5! (>2.Sxg6). Now the Dombrovskis patternemerges: 1…Bxd3 2.Se6, and 1…Bxd7 2.Rf3. Thetry-play mate 2.Bg3 recurs after 1…Kxe5, while1…Bxe5 gives the wQ a bit more work: 2.Qd2.

R The Nowotny try 1.f4? threatens 2.Rxd2 and2.Sf3, these mates being separated in the usual wayby the captures on f4. But 1…Bxe7! refutes. SoWhite plays 1.Qc6! (>2.Qc4), unpinning the bS andallowing it to pin the wQ by vacating d5 (the Daltontheme). This S has a random move plus twocorrections that reintroduce the try-play threats:1…S~ 2.Rd3; 1…Sf4 2.Sf3; 1…Se3 2.Rxd2;1…Bxc6 2.Sxc6.

M White has three thematic tries: 1.Rh5? (>2.Bf3), refuted by 1…Rxf5!;1.Bf4? (>2.Sdc3), which fails to 1…Bxe3!; and 1…Ka4? (>2.Sbc3), which doesnot cater for 1…Qxc6! The key is 1.Rh4!, threatening a battery-mate by 2.Bh3.All three of Black’s refutations are now playable as defences, and each one isanswered by the very mate prevented in the try-play: 1…Rxf5 2.Bf3; 1…Bxe32.Sdc3; and 1…Qxc6 2.Sbc3. You will surely have recognised this as the themenamed after Alfred Dombrovskis, described in some detail in the March issue.This threefold setting has the weakness that the key is very probably the firstmove that any solver would play, since the wR is clearly out of play on h3. In asituation such as this, there is the danger that the thematic try-play would gounnoticed.

N Thematic try-play is featured here too. 1.b7? (>2.Qxc5) cxd4 2.Se3;1…Kxd4 2.Rxb4; but 1…Rxc1! 1.Qd7? (>2.Se3) cxd4 2.Qc6; 1…Kxd4 2.Qg4;but 1…Sd6! So 1.Qa2! (>2.Rxb4) cxd4 2.Rc3; 1…Kxd4 2.Rxd3; 1…Rxa2 2.Se3.It’s fascinating to see how white moves recur as threats and as mates in thevariation-play across the three phases. The fact that the two moves 1…cxd4 and1…Kxd4 have different replies each time makes this an example of theZagoruiko pattern. There are hints of the Dombrovskis pattern as well: 2.Se3follows 1…cxd4 in the first phase, but is prevented by this defence in the second,and 1…Kxd4 allows 2.Rxb4 in the first phase but prevents it after the key.

O The first thing a solver will notice is that Black has various checks to thewK available, all set with replies: 1…Sc5+ 2.Bxc5; 1…Sd8+ 2.Qxd8; 1…Sf4+2.Qxf4; 1…Qb3+ 2.Sxb3; and 1…Bc4+ 2.Rxc4. Nothing very subtle about allthis, of course, since the replies are direct recaptures. But the key upsets the wholearrangement: 1.Kf5! (>2.e6). Now the checks come from different squares:1…Sd6+ 2.exd6; 1…Se3+ 2.dxe3; 1…Sh4+ 2.Qxh4; 1…Qc2+ 2.Sxc2; and1…Bd3+ 2.Rxd3.

P Venelin Alaikov2 Pr Die Schwalbe 1980

w4wdrdbG0wdwdwdqwdwHp$wddpdwdB!wwdwdRHwd)wiP)pdwPdw0wdwddKdnhwdw#2

MAY 2007 THE PROBLEMIST SUPPLEMENT 817

S Venelin Alaikov4 Pr Shakhmatna Misl1986wdwdRdwddnIwdwdwwdNdw0wddwdkdPdww)pdwdBddw4wdwdww1wgPdNddwdw4wGw#2

T Venelin Alaikov1 Pr Manev-60 JT 1987

wdwdwdwddwdpgwHwRHwdwdRGdw0wiwdwwdwdwdw4dw0w)BdbwdwdwdwddQdwIwdw#2

U Venelin Alaikov1 Pr Buletin Problemistic1990wdb4wdwddwdp)R!wwGPdwdwddwdwdpHpwdwdwiw4dwdRdP0wKHwdwdn1dBgwdwhw#2

V Venelin AlaikovRochade Europa 1994

whwdwdwddwdwdwdKwgPdwdw$dndk)Bdww)p1wdwd!wdR)bdNwdPHwdwGdwdw4wdw#2

W Venelin Alaikov1 Pr Gambit 1994

wdw4wdwddndwdwdrwdw0w0wdgw0kdNdwQdNdwhBddwGp$wdwwdwdwdwddKdw$wdb#2

X Venelin AlaikovSchach-Aktiv 1994

whwdwGwddpdwdwIwwdwdpHwddw0Biw0wpdP$wdPd4wdwdwdwwdw!wdwddbdwHRdw#2

S There are Nowotny tries on e3 threatening 2.Bf3/Sf4, with the threatenedmates separated by 1…Bxe3 and 1…Rxe3. 1.Be3? fails to 1…Rf1!, becauseWhite has deprived himself of the chance to play 2.e4 (B interferes with P). 1.e3?is refuted by 1…Qxb4!, the wP having cut the wB’s line of guard to c5. So thesolver’s attention switches away from the Nowotny. The key is 1.Re6!, an anti-critical move across the square e7 and threatening 2.Se7. The Nowotny threatsnow follow the Grimshaw on e3: 1…Re3/Be3 2.Sf4/Bf3, while 1…Rxg1 allows2.e4, and 1…Qxb4 gives 2.Sxb4.

T White has a choice between two Nowotnys on g4. Try 1.Bg4? (>2.Qf5/Bf4),but 1…c2! shuts off the wQ. The key 1.Rg4! gives the bK two flights and soeliminates the try-play threats. However, Sb6 can now mate, on d7 or c4according to Black’s captures of the key-piece: 1…Rxg4 2.Sxd7, and 1…Bxg42.Sc4. Do we see the original threats again? Yes, they reappear after bK-moves:1…Kf6 2.Qf5, and 1…Kd6 2.Bf4. This, therefore, is a form of the Rukhlis theme(see B above), with threats as thematic moves.

U The Finnish Nowotny, seen in P, is found again here. So, too, is the Rukhlispattern. 1.cxd7? threatens 2.Se6 and 2.Bc7, with separation by the captures on d7.1…Sxf3! is the refutation. 1.Rxd7! succeeds where the capture by the P fails, andnow the previous threats are not playable because the key-R has relinquished itsguard of the squares f3 and e3. The new threats make use of the opening of theline b1-f5, and the vacation of d3: 2.Rxf5 and 2.Sd3. Black’s defences are self-blocks on the squares f3 and e3, which enable the units providing single guards tomate: 1…Sxf3 2.Se6, and 1…Se3 2.Bc7 – the original threats again.

V The try 1.Qa8?, threatening 2.Be6 (the B can close the line h6-c6 becauseWhite has placed an extra guard on c6), fails to 1…Qxd3!, pinning the wB. Asecond try 1.Re6? places an additional guard on e5 and thereby threatens 2.Sf4,closing the line h2-e5. But 1…cxd3! refutes by unpinning the bQ. The key 1.Qc3!threatens 2.Qxc4. Black defends with the two movesseen as refutations of the tries, much as in theDombrovskis pattern (see M above). But the patternhere is different: 1…cxd3 opens the line c3-c6 andso allows 2.Be6, while 1…Qxd3 open c3-e5, thuspermitting 2.Sf4. This is the Hannelius pattern: try1.X? (>2.A) a!; try 1.Y? (>B) b!; key 1.Z! (>2.~) a/b2.B/A – the reverse of the Dombrovskis pattern anddiffering from it in offering no paradoxical element.It requires complex strategy, as here, to make itconvincing.

W The try 1.Re7? carries two threats: 2.Sce3 and2.Sfe3. If 1…Rxe7, 2.Sxe7, but 1…Rh3! refutes.1.Re4? threatens only 2.Sce3, because the line of thewQ must be opened to guard e4 when e1-e4 isclosed by the arrival of the S. 1…Bxe4 allows theother S-mate, 2.Sfe3 (now g4-e6 must be opened),but there is no reply to 1…Sg2! Accordingly, Whiteplays 1.Re6!, threatening only 2.Sfe3 since g4-e6must be opened. 1…Sxe6 brings in the other S-mateagain: 2.Sce3. This is the Sushkov/pseudo le Grandpattern, much worked by David Shire among others.By-play: 1…Bxc3/Rh3/Sg2 2.Sb6/Se7/Bf3.

X 1.Bd~? (>2.Bd6) Bd3/Rd3 2.Sf3/Re4, but1…cxd4! 1.Be4? cxd4 2.Qxg5, but 1…Rd3! 1.Bf3?cxd4 2.Qg2, but 1…Bd3! So 1.Bxb7! (>2.Bd6) Bd3/Rd3 2.Sf3/Re4, and 1…cxd4 2.Qa5. Tries withwhite correction, closing lines to enable the Q tomate after 1…cxd4 but failing through white self-interference.

THE PROBLEMIST SUPPLEMENT MAY 2007818

C Richard SteinwegFairy Chess Review 1934wGRdwdwd0NdwdQdwwdwdrdwd)wdkdwdwwdwdwdRddwdwdpdwwdw)wdBddwdwdKHwS#5 Berolina pawns

D Hans GruberThema Danicum 1982

wdwdwdkdIw)P)PdrwdqdwdwddwdwdwdwwdwdwdwddwdwdwdwwdwdwdwddwdwdwdwSer-S#6 Berolina pawns

Solutions to problems with Berolina pawns (page 809)

C was among the first problems with Berolina pawns to be published. White’starget of selfmate in 5 depends on allowing the BPa7 to move diagonally downthe board until it reaches f2. This means that moves off that diagonal must beprevented. Theoretically the BP could reach f2 in 4 moves. Can White cope withthis if Black’s first move is 1…BPc5? Tries such as 1.Rc3? look promising.1…BPb6 2.Sd8 BPc5 3.Rd3+ (the check prevents 3…BPb4) BPd4 4.Rc3 (a neatswitchback) BPe3 followed by a white waiting move and 5…f2#. The same playworks if White’s first and second moves are interchanged. But there is nocontinuation after 1…BPc5! So White must prevent this move, and at the sametime provide a way of preventing 3…BPb4. 1.Sc5 does the trick, and now theplay is different: 1…BPb6 2.Sb3 BPc5 3.BPb4 (the white BP is the only unit thatcan occupy b4 – 3.Rb4? BPd4! and the BK escapes to e4) 3…BPd4 4.Rc3 (nowthis move is playable) BPe3 5.Sd2 BPf2#. Notice that the BPf3 guards f2 in themate. This is an attractive problem, in which it is by no means obvious that thewhite BPd2 will provide an obstruction on b4 rather than on its home square. Thewhite BPa5 could be a normal pawn.

No prizes for guessing that the four white BPs in D will all promote, and todifferent (orthodox) pieces! But which ones, and in what order? Because Blackhas just a single move, only one of the promoting pawns can be captured. So theothers must be hemmed in somehow, which suggests a wR a8 and wB b8, withwS c7 which will eventually be pinned. That in turn implies that the bK willcapture a Q on f8. Thus the sequence emerges: 1.BPfe8S 2.BPc8R 3.Ra84.BPb8B 5.Sc7 6.BPf8Q+ Kxf8. A pleasant lightweight, which appealed to thejudges for the FIDE Album.

n n n n n

FAIRY DEFINITIONS (see originals on page 820)

Selfmate (S#n): White plays and forces Black to give mate in n moves.

Series-helpmate (Ser-H#n): Black plays a sequence of n consecutive moves (White not moving at all) untilat the end of that sequence White can mate in one. Check may be given only on Black’s last move.

Series-selfmate (Ser-S#n): White plays n moves (with Black not moving until the end of the series) to reacha position where Black is forced to mate White immediately.

Take&Make: Having captured, a unit must immediately, as part of its move, play a non-capturing move inimitation of the captured unit from the capture-square. If no such move is available, the capture is illegal.Promotion by capture occurs only when a pawn arrives on the promotion rank as the result of a take&makemove. Checks are as in normal chess: after the notional capture of the checked K, the checking unit does notmove away from the K’s square. In PS1913F, if White were to capture the bR with his S, the S wouldimmediately move to a1, b2 or c2.

Einstein chess: all units (Ks excluded) change their type when they move, according to a precise pattern.For non-capture moves: Q>R, R>B, B>S, S>P, P remains P. For capture-moves: R>Q, B>R, S>B, P>S, Qremains Q.

Maximummer: throughout the solution, except on his last move in a selfmate, Black must play hisgeometrically longest move, distances being measured from the centre of each square (so a1-b2 is longer thana1-b1).

Andernach chess: a unit (Ks excluded) making a capture changes colour on completion of the capture.

Berolina pawn (p): moves diagonally and captures on the file. A Berolina pawn on the second rank canmake a double diagonal jump, and may be captured en passant. On reaching its promotion square, it changesinto a normal piece, thereby losing its fairy properties.

MAY 2007 THE PROBLEMIST SUPPLEMENT 819

SOLUTIONS TO FAIRIES (November)

PS1858F (Harris) 1.Be4 Rc7 2.Ra3 Bb7 3.Ra7Rc5. Ingenious construction of bK shelter from bRin the mate. Attractive diagram (C.C.Lytton).Difficult logic (CCF). Mate is impossible if the bR isable to attack the bK, making RxK illegal, so ahiding place must be found for the bR. A very clearexample of Isardam (MM).

PS1859F (Wenda) 1.h1Q a8Q 2.Qh4 Qc6 3.Qe7dxe7 4.Kd7 e8Q. Neat thematic Patrol stalematewith bK sandwiched between two wQs. Noteworthyis the position of wK which forces bQ journey andalso generates lots of tries, a single move too long(CCL). Three promotions to Q, nicely done (CCF).

PS1860F (Bakcsi & Zoltán) 1.Sf2 Kxf3 2.g6 Ke23.Sxg4[Pg7] g8Q (g8R?) 4.g5 Qxg5[Pg2] 5.Sh6Qxh6. I was expecting 1-2.f1Q g6 3.Qf7 gxf7, whichis just too late. Despite the static bK, not easy(CCL). Clever sequence of moves and captures(CCF).

PS1861F (Stephenson) 1.Ld7 (>2.Bd5) 1…Ld62.Bc2; 1…Lg2 2.Ph4; 1…Vd6 2.Lh7; 1…Pd12.Pe1; 1…Pd6 2.La4. The variety includes aGrimshaw on d6 with thematic Chinese defence butorthodox errors (CCL).

PS1862F (Harris & Rice) 1.Gb8 axb8G[Gb1]2.Gxb8[Gh8] Kxb8[Gb2]; 1.Gd6 Kxd6[Gc1]2.Qxa7[Pc8Q] Qxc1[Ga2]. Both solutions difficultto find! Plenty of Supercirce motifs (CCL).Supercirce problems are always difficult to solveand this is no exception (CCF).

PS1863F (Stephenson) 1.d3 b5 2.Be3 b4 3.Bb6b3 4.d4 bxc2 5.b4 cxb1B 6.Qa4 Bxa2 7.Rd1 Bd58.Qa1 Bxg2 9.Bxg2 c5 10.Bb7 Sc6 11.d5 Rb812.Ba8 Sd4. Attractive problem (CCF). Blackbishop Frolkin, with pleasing successiveannihilations on c2, b1 and a2, allowing wQ, wRPlatzwechsel. Not easy either, both sides have sparemoves in the diagram, but White loses one and hasto hesitate with his B because of mutual unlockcycle in the NW corner (CCL). In the Frolkin theme(or Ceriani-Frolkin – is there agreement on theterminology in the retro community?) a pawn ispromoted and the promoted piece subsequentlycaptured. Brian’s idea was the Platzwechsel (wQand wR swap squares). Having found that the

PS1858F

BdwdwdwddwdRdwdwwdwdwdwddwdkdwdwwdwdwdwddwdrdwdwwdwdwdbddwdwdwdwH#3 IsardamNo WK

PS1859F

wdwdwdwd)wdwdwdwwdw)kdwddwdwdwdKwdwdwdwddwdwdwdwwdwdwdw0dwdwdwdwH=4 Patrol Chess

PS1860F

wdwdwdwddwdwdw0wwdwdwdwddwdwdwdwwdwdwdPddwdwdpIwwdwdwdwddwdndwiwH=5 Mirror Circe

PS1862F

wdwdwdwd)wIwdwdwwdwdwdwddwdw1wdwwdwdwdwddwdwdwdwqdwdwdw1iwdwdwdwH#2 2 solutionsSupercirceGrasshoppers e5, h2

PS1863F

B4b1kgn40wdp0p0pwGwdwdwddw0Pdwdww)whwdwddwdwdwdwwdwdP)w)!wdRIwHRPG 12.0

PS1861F

wdK$wgwd!wdwdwdww4wdwdwddwdwdP)wwdw)kdPddBdwdwdwwdwdPdw1dwGw4wdR#2 Pao d8, h1, b6, e1;Vao f8; Leo a7, h2

underpromotion was the easiest way to achieve this,he then wanted to hide the bB from the diagramposition to offer solvers some kind of challenge(MM).

Solutions to selfmates on page 8131 1.Sf2 (-) d6 2.Qe5+ Kxe5; 1…d5 2.Rxc4+ Kxc4; 1…Sxf2 2.c3+ Kd3; 1…Sxb2 2.c3+ Kxc3; 1…Sc3

2.bxc3+ Kxc3; 1…Se~ 2.Q(x)d5+ Kxd5; 1…Bxf2 2.Qxe4+ Kxe4.2 1.Rcg7 (-) h1Q 2.Qa8+ Qxa8 3.Ba3+ Qxa3; 1…h1R 2.Qxf2 R~/Rh3 3.QxR/Bxh3 Sb3; 1…h1B 2.Rg2

Bxg2 3.Rxg2 Sb3; 1…h1S 2.d3 Sg3 3.Rxg3 Sb3.

THE PROBLEMIST SUPPLEMENT MAY 2007820

FAIRY PROBLEMS PS1912-1917F

FAIRY ORIGINALS PS1912-1917FOne of the Originals Editor’s hardest jobs is to

judge how difficult a problem is going to prove. Idon’t have the time to solve each item as it comes in,and anyway what one solver finds a tough nut maybe a piece of cake to another. So I make nopredictions about this month’s fairy offerings,though my suspicion is that most of them will turnout to be in the piece-of-cake category. All that willbe required will be the mental adjustment necessaryto switch from one fairy genre to another. Even theAmerican/Finnish collaboration should not be toohard on the teeth.

Enjoy the selection, and don’t forget to send inyour comments!

JMR

The Problemist Supplement is one of the twomagazines produced for its members by theBritish Chess Problem Society, which exists topromote the knowledge and enjoyment of chesscompositions. Membership is by calendar yearand is open to chess enthusiasts in all countries.

Membership renewal (due 1st January) is£25 for Fellows and £18 for Members (£9 forunder-21s). New members first year £15 (£7.50if joining after 1st July or if under 21). Airmailmagazine delivery costs extra: £1 Europe, £3.50elsewhere. Payments, in £ sterling to BCPS,should be sent to S.J.G. Taylor, Greenways,Cooling St., Cliffe, Rochester ME3 7UB (emailsjgt@btinternet.com).

PS1912F John Bowden

wdwdwdngdwdwdwipwdwdwdpddwdwdB)wwdwIw)wddwdwdwdwndwdwdwddwdwdwdwSer-S#9

PS1913F Guy Sobrecases &John Rice

(France/GB)

wdwdwdwddwdwdwdwwdwIwdwdGwdwdwdwwdkdwdwd0pdwgwdwrdwhwdwddwHwdwdwH#2 Take&Make chess(b) Pb3>c5

PS1914F Lee Poissant(USA)

wdwdwdwddwdwdwdwwdpdwdwdHwdwhwdwwdwdwdPddwdwdPdwwdw0wdpddKdkdwdwH#4 Einstein chess

PS1915F Steven Dowd &Marko Ylijoki

(USA/Finland)

wdwdwdwddwdwdw0wwdwdwdkddwdwdwdwwdwdwdwddpdpdpdpPdPdPdPddwdwdBdKH#8 Berolina pawns

PS1916F John Rice

wdwdwdwddwdw0kdwwdwdwdwddwdwdwdwwdwdndwIdwdwdwdwwdwdwdw)drdbdwdwS#6 Maximummer 2 solutionsBerolina pawn h2

PS1917F Vito Rallo(Italy)

wdwdwdwddwdwdpdwwdwdw)wddwdKHkdwwdndw)wddwdwdwdwbdwdwdwddrdwdwdwSer-H#8 Andernach chess