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    THE PROBLEMIST

    SUPPLEMENTISSUE 116

    JANUARY 2012

    EDITOR: Geoff Foster20 Allchin Circuit, Kambah ACT 2902, Australia([email protected])

    ORIGINALS EDITOR: John Rice9 Manor Crescent, Surbiton KT5 8LG([email protected])

    Send solutionsand commentsto C.J.Morse102A Drayton Gardens, London SW10 9RJ(or by email to the Editor)

    All originals printed in the Supplement take part in thenormal Problemist tourneys, so that publication here isequivalent to publication in the main magazine.

    CONTENTSBritish Helpmate Composers: Three Directmate

    Specialists, by Chris Feather . . 181Original problems PS2537-48 . . . 182Solutions to July originals . . . 184Miniatures solving contest, July 2011: solutions . 185Variations on a Theme of Yuri Sushkov,

    by David Shire . . . . 188P is for Promotion, by David Shire . . 189Fairy solutions (July) . . . . 191Fairy originals PS2549-54F . . . 192

    BRITISH HELPMATE COMPOSERS,by Chris FeatherIII: Three directmate specialists

    The three first-rate composers featured this time all contributed prominently to the famous 1966 book TheTwo-move Chess Problem: Tradition and Development, which recorded a remarkable period in Britishdirectmate composition. Their helpmates are not numerous but they deserve attention, not least because theytend to be overshadowed by their composers other achievements.

    John Driver (1928-1980) lived all his life in Northamptonshire, where I got to know him in the 1970s. Hewas a semi-invalid for more than 30 years but was able to make short outings, for example to visit us inStamford; he also very much enjoyed the day trips put on by a local coach firm. His creative talent wasexpressed not only in chess composition but also in painting. In addition to the orthodox mate in two he mademany fine unorthodox problems; indeed he invented the edgehog, a fairy piece which deserves to be used moreoften. John enjoyed solving helpmates and faithfully supported the Problemistcolumn, finally taking over as itseditor, sadly for only three years at the end of the 1970s. Like Bill Trumpers, most of Johns own helpmates

    (there are about 50 of them) have dated rather badly. His earliest come from the beginning of the 1960s; thereare quite a few single-liners among them. He became very interested in cyclic play in helpmates and gave aBCPS lecture on it in 1968, having made some pioneering examples of what was still quite a new idea at thattime. Unfortunately the development of technique has since made these works unsatisfactory in their

    directmate-like use of white material, so I am not quoting any here. HoweverJohn was quick to learn and the development of the Problemist column underTrumper provided him with good models. One of his most interesting helpmatesis A, which shows doubly anticipatory interferences, never an easy theme. Blackmust start by closing a potentially damaging line before his own king and thewhite mating piece open it. The reader will note some unevennesses in the way inwhich the idea is made to work, using varied tactics to force the move order, andincorporating a pin mate in one part only. Those features would be seen as defects

    by the exact correspondence school of helpmate composition. However I thinkthat John enjoyed mixed tactics for their own sake, provided that the main themeis crystal clear, as it is here. Quoted at the end of this article for solving is anotherhelpmate in two with similar qualities (defects if you like), composed jointly withour next subject.

    (continued on page 190)

    A John DriverProblem Observer1976

    wdwdwdwddwdwdwdww0wIN)wddwdwdw)w

    pdwdkdB1dwdnhRdwwdw4pdw4dwdwdwdbH#2 (b) Kd6>a3

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    THE PROBLEMIST SUPPLEMENT JANUARY 2012182

    PS2537 Rainer Paslack(Germany)

    wdBdwdwdgw!w0wdwwdp)Ndwd$whriw)wwdwdwdPddwdw)Kdw

    wdw)wdwddwdwdwdw#2

    PS2538 Michael Lipton

    wdwdQ$wddKdRdqdwwdwdwgwddwdwdkdBw)wdp)wddwdw)wdw

    wdwdwdwddwdwdwdw#2

    PS2539 K.Seetharaman(India)

    wdwdwdwddwdpdwdwwdw0wdw0dpdwiP0NwGpdwdP)dwIpdwdw

    wdwdw)wddBdwdwdQ#2

    ORIGINAL PROBLEMS PS2537-48Only one home-grown item this month, from a composer who enjoys searching for novelty in well-known

    themes. Has Michael found something new in PS2538? Some good try-play in PS2539may keep you guessingfor a while. The two parts of PS2541offer rather different play.

    Among the helpmates the emphasis is on attractiveness rather than difficulty. Solvers will readily appreciate

    why PS2547 and PS2548 have been published together. One suspects that each of these problems can beimproved: who would like to have a go? Enjoy your solving and the reconstruction too, if you have any goodideas!

    JMR

    DEFINITIONSWhite plays up the board in all positions.

    In Directmates(those problems with a #n notation below the diagram, where the n denotes the numberof moves) White plays first (the key) and forces mate at latest on his nth move, whatever Black plays. Set Playis what would happen if Black were to play first in the diagram position. For instance, in a #2 there is often setplay where black moves are followed by white mates and this can form part of the theme of a problem. Tries

    are white moves that would solve but for a single black refutation. The black defences and white matesfollowing tries can form part of the theme of a problem.

    In Helpmates(those problems with a H#n notation below the diagram, where the n denotes the numberof moves) Black plays first and co-operates with White to enable White to mate Black on Whites nth move.These have a single solution unless otherwise indicated below the diagram. Sometimes, the number of movesasked for in helpmates includes a half-move, such as H#2. In these helpmates the normal sequence of movesis preceded by a white move. So H#2 indicates the following sequence: 1...W 2.B W 3.B W#. An asteriskfollowing the stipulation indicates the presence of set play, so H#2* means 1W 2.B W# plus 1.B W 2.B W#.

    Twins, indicated by a notation such as (b) wPe2>d3 under the diagram, are problems with more than oneposition for solving. Unless otherwise stated, each twin position is formed from the diagram position.

    Duplexproblems are those where White fulfils the stipulation and then Black does. So a H#2 duplex has twosolutions, the first as in a normal helpmate and the second with White playing first and being mated by Black.

    All the originals published in every issue of the Supplement are computer-tested. If the computer has been

    unable to verify soundness, the symbol C? is shown. Otherwise solvers can assume that soundness has been

    confirmed.

    Send solutions and comments to C.J.Morse (address on front page) by 1st June 2012. Solutions and

    comments may also be sent by email to the Editor.

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    JANUARY 2012 THE PROBLEMIST SUPPLEMENT 183

    PS2540 Petrain Petrainovi(Serbia)

    wdwdwdwddwdwdwdw

    wdwdpdwddQ0wGwdwwdwdkdwddwdNdwdwwdwdw)wddwdKdwdN#3

    PS2541 Leonid Makaronez(Israel)

    wdwdwdwddwdwGpdw

    wdwdwdwddwdw0wdwwdwdwiPddwdwdwdwwdKdwdQddwdwdwdw#4 (b) Pe5>h4

    PS2542 Petros Lambrinakos(Greece)

    wdwdwdwddwdpdwdw

    wdw0wdwddwdwiNGwwdwHwdwddwdwdPdwKdwdwdwddwdwdwdw#5

    PS2543 Slobodan aleti(Serbia)

    rdwdkdw40wdndwdpKdwdwdwddwdBdwdwwdwdw1wddwdwdwdwwdRdwdwddwdwdwGwH#2 2 solutions

    PS2544 Menachem Witztum(Israel)

    wdw4wdwddbIwdw$wwdwdw0wddwdwHRdwwGwdw1P0dwdPdwdpwdw)wipddwdrdwdwH#2 2 solutions

    PS2545 Andy Kalotay(USA)

    wdRdwdwddw0wdwdwwdwdwdwddwdRdwdwpgwdndwddwdwdwdwwdkdwdwddwGwhKdwH#2 (b) d5=wB

    PS2546 Roland Lecomte &Jean Morice

    (France)

    wdwdwdwddwdwdwdwKdwdwdwddwdwdwdkwdw)wdwddwdNdP4w

    wdwdNgpddwdwdbdwH#3 2 solutions

    PS2547 Jos C.Vinagre(Portugal)

    wdqdwdwddwgwdwdwwdbdwdwddw4wdwdwwdwdkdwddwdw0wdw

    wdPdwdwdIwdwdwdwH#5

    PS2548S.K.Balasubramanyam

    (India)

    wdwdwgwddwdwdqdwwdwdw4wddwdwdndwwdwdw4wddwIwdpdw

    w0wdw)wdiwdwdwdwH#6

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    THE PROBLEMIST SUPPLEMENT JANUARY 2012184

    SOLUTIONS (July)PS2459 (Lyons) 1.Qe2? (>2.Qd1) Sf4! 1.Qg1? (>2.Qd1) Rf2! 1.Qh1?

    (>2.Qd1) 1Rf2, Rf1 2.Qxe4; 1e2! 1.Qg4!(>2.Qxe4) 1Rf4 2.Qd1; 1Sf42.Qg7; 1Sg5 2.Qd7; 1Sc5 2.Bc3. Interesting tries to threaten 2.Qd1. Themost important of these tries is 1.Qh1?, since this gives a pseudo le Grandrelationship with the key phase. A first contribution of considerable promise!

    (D.J.Shire). A fine problem (B.Conway). The pseudo le Grand theme (1.Try?(>2.A) 1x 2.B; 1.Key! (>2.B) 1y 2.A) differs from the le Grand theme in thatthe thematic defence is not the same in each phase (MMcD).

    PS2460 (Lewis, after Heathcote) 1.Qg3? (>2.Bg6) 1Rg5 2.Qh3; 1Kh62.Qg6; 1Bxh8! 1.f8Q? (>2.Q8f7,h6) 1Rc6 2.Q8f5; 1Rg5! 1.f8S!(>2.Bg6)1Re5+ 2.Be4; 1c3+ 2.Bd3; 1Rb2+ 2.Bc2. A neat cross-checker with anunderpromotion key (J.Gill). Checks by Black interfere with the B at a1(C.C.Frankiss). A delight to solve! (BC). The best setting of Heathcotes originalto date with promotion try and key validating the set checks. Is there a version tobe discovered with an acceptable and genuinely thematic key? (DJS). The originalsetting was G.Heathcote, 1 Pr Revue dEchecs 1904 b4b2/3r4/3pr3/8/1K5S/

    2PR4/Q3p3/5kBR #2 1.Qa6.PS2461 (McDowell, after Chepizhny) 1.Qd2? (>2.Qd5) 1Kg5 2.Ke4;

    1Ke6 2.Qd7; 1c6! 1.Qe2! (>2.Qg4) 1Kg5 2.Qh5; 1Ke6 2.Kf4. The Qambushes itself behind the K and orchestrates two good changes following theflights (DJS). The idea (inspired by the Myllyniemi zeroposition in my January2011 Browsing article) was to show two sets of three precisely matchingvariations. Viktor Chepizhnys miniature (Sp.Pr. Shakhmaty v SSSR1991 4R3/8/4Sp2/4k3/8/3K1B2/8/3Q4 #2 1.Ba8? (-) 1Kf5 2.Qh5; 1Kd6 2.Ke4; 1f5!;1.Qc2? (>2.Qc5) 1Kf5 2.Kd4; 1Kd6 2.Qc7; 1f5!; 1.Qa4! (>2.Qf4) 1Kf52.Qe4; 1Kd6, f5 2.Qd4) shows a 3x2 Zagoruiko, but both threats are unrealised,and 1.Bb7? has the same effect as 1.Ba8? (MMcD).

    PS2462 (Guida) 1.Sc~? (>2.Qxc5/Rc4/Rd3) Sxe4! 1.Sxe3? (>2.Qxc5/Rd3)1Sxe4 2.Se6; 1Sxf3! 1.Sxe5! (>2.Qxc5) 1Sxf3 2.Rc4; 1Sxe4 2.Rd3;1Se6+ 2.Sxe6; 1Kxe5 2.Qf6. Good threat reduction with a beautifullyeconomical separation of 2.Rc4/2.Rd3 in the actual play. Initially I missed the try

    PS2459

    wdwdwdwddwdwdwdwwHwdndwddwdwdwdwwGNipdwd

    dwdw0rdwwIBdwdQddwdwdwdw#2

    PS2460

    wdwdwdw$dwdwdPdBwdwdwdwddb4wdwdkw4pdw!wd

    dwdwdwdwwdwdKdwdgwdwdwdw#2

    PS2461

    wdwdwdwddw0wdpdwwdwdwHw$dwdwdkdwwdNdwdwd

    dwdwIw0wQdwdwdwddwdwdwdw#2

    PS2462

    w w w wdwdwdnIww!wdwdpddw4w0whRbdNiBdwddw$w0Pdww)wdwdwddwdwdwdw#2

    PS2464

    wdwdwdwddwdw0wdKwdwdw0wddwdwdkHwwdwdrdwddwdwdw4wwdwgwdwGdwdwdwdwH#2 2 solutions

    PS2465

    wdwdwdwddwhpdwdwpdwdpdwddw0wdwdwwdkgwdQd)whpdwdwwIwdR0wddwdwdqdBH#2 4 solutions

    PS2463

    w w w wdwdwdwdwwdNdpdwddwdkHPdwwdpdw0w)dwdwdwdwwdwdwdwddQdwdwdw#3

    play, as wRh5 totally telegraphs the key (DJS). Thesacrificial key yields four pleasing mates (JG). Nicemates after captures by bSg5 (CCF). There must bea reason for the wR on h5 (M.Merkert).

    PS2463 (Lambrinakos) 1.Qf1 (>2.Qxc4+ Kd63.Qd4/Sf7) 1Ke4 2.Ke7 Kxf5 3.Qb1; 2Kd53.Qxc4; 2Ke3 3.Qe1; 2exf5 3.Qf3; 2f33.Qxf3; 2c3 3.Qd3; 1Kc5 2.Kc7 ~ 3.Qxc4. Thewaiting 2.Ke7 is the Petros trademark with quiteunexpected and extensive play (DJS). I solved thisby looking for a variation where the hP is needed(MM).

    PS2464 (Piet) 1.e6 Sf7 2.Rg5 Sh6; 1.Rgg4 Se62.Bg5 Sg7. The wS does the multi-taskingefficiently (JG). A Grimshaw shut-off in each line(CCF). Neat Grimshaw play. I think I would havechosen twin form to avoid any redundancy 7K/5p2/2S2kS1/5br1/24/4r3 (b) c6 > d4 (DJS).

    PS2465 (Vinagre) 1.Qg1 Rc2 2.d2 Qe2; 1.Sd5+Qxd4+ 2.Kxd4 Re4; 1.e5 Re4 2.Kd5 Rxd4; 1.Kb5Re5 2.Be3 Qb4. Attractive pin-mates though at thecost of much spare material (JG). The white Q and Rget through a lot of work but I am not sure what thetheme may be (DJS).

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    JANUARY 2012 THE PROBLEMIST SUPPLEMENT 185

    PS2466 (Simadhinata) 1.Ke5 Bd3 2.Rd5 Sc4;1.Ke6 Sf5 2.Rd5 Bc8. The bK moves along the pinlines, allowing one of the Rs to move (CCF). Nicelyvaried reciprocation (JG). Very fine analogy(R.Lazowski). The matching strategy is put togethermost efficiently with a nice role swap between wBa6and wSe3. I am fearful of anticipation(DJS).

    PS2467 (Jones) 1.Sb3 dxe4 2.Kd3 Rxc4 3.Kxc4Ba6; 1.Ke3 dxc4 2.Rcd3 Bxe4 3.Kxe4 Re7. Nicecorrespondence (MM). More solver friendly than theaverage Jones (JG). Chris is no longer holding meup for so long! All the familiar elements are here,woven together with customary skill (DJS). Zilahicaptures with matched play in this composers style(CCF).

    PS2468 (Milewski) (a) 1.Rg2 Kxf3 2.Rh2+ Kf43.Bd5 cxd5; (b) 1.Bg2 Kxg3 2.Bh1+ Kf4 3.Qg5+hxg5. Switchbacks by both sides to allow the

    opening of lines (CCF). The SE cluster is a clearclue but a lot goes on in this problem. A goodexample of how solving can be straightforward butsatisfying (DJS). Simple but effective (JG).

    PS2469(Ramaswamy) (a) 1.Qd4+ Kh5 2.e5 Be6

    PS2467

    wdwdwdwddB$wdwdwwdw0wdwddwdwdwdnw)p4pdKd

    )w4PdwdwwdwhkdwddwdwdwdwH#3 2 solutions

    PS2469

    wdbdwdw1dwdn0pdwwdwdwdwddwdrdw0wwdwdwdKd

    dwhriwdBwdwdwdwddwdwgwdwH#4 (b) h3=wS

    PS2470

    wdwdwdwddwdpdwdwwdwdwdwddpdwdwdww0w0wdwd

    dPdpdwdww)w)wdwddwdKdkdwH#10

    PS2477

    w w k wdbIRdwdwwdwdwdwddwdwdwdwwdwdpdwddwdwdwdwwdwdwdwddQdwdwdw

    PS2479

    wdKdwdwddwdwdwdwwdwdwdwddwdpdwdwwdwGwiwddwHwdwdwwdwdwdwddwdwdw!w#3

    3.Ke4 Kg4 4.Re3 Bf5; (b) 1.f5+ Kxg5 2.Kd4 Kf4 3.Ba6 Sg5 4.Bc4 Se6. Noteasily fathomed. Satisfying to solve (JG). I much appreciated the role of the bBc8,selfblocking in (b) and determining an avoidance of 2Bxd7 in (a) (DJS). Nicetwinning (CCF).

    PS2470 (Kupper) 1.Kg2 Ke1 2.Kh3 Kf2 3.Kh4 Kf3 4.Kg5 Ke4 5.Kf6 Kd56.Ke7 Kc5 7.d5 Kxb4 8.Kd6 Ka3 9.Kc5 b4+ 10.Kc4 b3. An efficient marshalling

    of the Ks with a timely d7-d5 (DJS). Remarkable that the play is exact (CCF).Commentating on PS2416 David Shire opened up an interesting debate. For myown part I find these long forced one-liners quite fascinating, though quitedifferent from the complex intricacies of modern 2-movers. Perhaps differentparts of the brain are involved. But I doubt David would deny the intellectual/aesthetic pleasure in uncovering the secret of this particular 10-mover (JG).

    Comments edited by Michael McDowell.

    #2

    PS2466

    wdwdwdwddwdwdpdwB$w4wiwddwdwdwdpwdw4wdwd

    dwdwHwIwwGwdwdwddwdwdwdwH#2 2 solutions

    PS2468

    wdwdwdwddw0RdwdwwdPdk0wddwdwdwdPwdPdwIw)

    dwdpdp0pwdw)w0w4dwdwgr1bH#3 (b) bKe6bPf6

    MINIATURES SOLVING CONTEST, JULY 2011:

    SolutionsPS2477 (Lincoln) 1.Qb4? (>2.Qe7) Rh7! 1.Qb2? (>2.Qxh8) 0-0/Rf8

    2.Qg7/Qe5; 1R~! 1.Qb3! (>2.Qf7) Rf8/Rh7/Bd5 2.Qe6/Qg8/Qb8. Good that1.Qb3! succeeds in preference to the stronger-looking 1.Qb4? (PB).

    PS2478

    w w w wdwdPdwIwwdw$wdwddwdQdwdww$wdwdwddwdwGwdwwdwdwdwddwdwdwdw#2 How many keys?

    PS2478(Morse) By my reckoning every move ofevery piece is a key (BC) unless there is sometrick that I havent spotted (CF). I started countingand counting some more. Finally I realised! (SP).So its 64 keys altogether, with no trick (JMR).Possibly a record in miniature (Composer).Imaginative task very well achieved (PB).

    PS2479(Howard) 1.Kd8 (-) Kf3 2.Be5 d4 3.Qg3;1Kf5 2.Qg3 Ke6 3.Qg6. Key-move difficult (BC).Key-move only has use after 1Kf5 (CF). A verynice problem (RC). Took me a while to see it (SP).

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    PS2480(Fenton) 1.Be5 (>2.d8Q) Ke7 2.Bc7 Ke63.d8R ~ 4.Re8. The composer has set a trap: 3.d8Q?is stalemate. I have only attempted a few problems,but this I enjoyed most (BC). Good key: not obviousthe bK can be caught after 1Kxe5 (PB).

    PS2481 (Makaronez) (a) 1.Bf2 Kf3 2.Qh4 Kg2

    3.Qg3+; (b) 1.Ka5 Kc3 2.Ka4 Kd4 3.Ka3. Mate bysuffocation. Neat white play in (b) (CF, sim.PB).Solution to (b) is very difficult (RC).

    PS2482 (Grinchenko) 1.Kxh4 Bd1 2.Bh3 Bf6;1.Kxh5 Sf3 2.Bg4 Bg6. Enjoyable for solving (RC).I had a hunch the Ss could be sacrificed one at atime and still have enough strength left for a matingnet. This puzzle presents a valuable solvingexperience (SP). Surprise captures of wSs (CF).

    PS2483(Carf) 1.Bf5 Se6 2.Ke4 Qe2; 1.Bd7 Se82.Ke6 Qf6; 1.Rd7 Sa6 2.Kd6 Qc5. Selfblocks by bR

    and bB; a nice composition (RC). Variety of matingpatterns (PB). The first two solutions came fairlyquickly, but for the third I was stumped, until Ithought about symmetries I love the sparsenesshere a beauty (SP).

    PS2484 (Bantush) 1.Kd5 Kf5 2.c6 Be5 3.Rc5Se3; 1.Rd3 Se3 2.Kd4 Kf4 3.c5 Be5. Ideal mates(AN). All units move a perfectly crafted endeavour(SP).

    PS2485 (Prcic) 1Rxa2 2.Kb5 Rb2 3.Ka4 Rb14.Ka3 Ra1; 1c3 2.Kb5 Kd2 3.Ka4 Kc2 4.Qb5

    Rxa2. Chameleon echo (AN). Chameleon mateswith nice rundlauf in the first line (CF). SP found aH#3 and then realised that triangulation would addthe extra half-move. His comment continued: ThenI looked some more and found another H#3 wow! Greater puzzle than I thought before.Pleasing echoed mates and very nice minimalrundlauf (PB).

    PS2486 (Diaz) (a) 1.Bd4 Kd6 2.Bg1 Ke5 3.Rh1Kf4 4.Kh2 Kxg4; (b) 1.Be5+ Kd7 2.Bg3 Ke7 3.Kh4Kf6 4.Rh3 Kg6. Chameleon mates but ratherobvious play (CF). Echoed mates and matching play

    (PB).

    PS2487 (Sobrecases) 1.Qc5 Rh1 2.Kc1 Ke2+3.Qg1 Kd3 4.Kd1 Rxg1; 1.Kc2+ Ke2 2.Kb1 Kd33.Qf1+ Kc3 4.Kc1 Rxf1. Difficult to find the firstmove 1.Qc5 (RC). A beauty. I found the 1.Kc2+solution through symmetry; it had to start somethinglike this to give the wK some breathing room (SP).Very nice play, particularly by bK (CF). Surprising and matching active sacrifices of bQ (PB).

    PS2488(Solja) 1.Qc1+ Kg2 2.Bf4 Sb4 3.Bd2 Sc64.Kd3 Kf3 5.Qc2 Se5. I like the way the bB chases

    the bQ. The S has to be pulled out of the corner withhaste rewarding (SP).

    PS2489(Carf) 1.Bd6 Kd2 2.Qd5+ Ke3 3.Kf5 Sb34.Ke5 Sc5 5.Bf5 Sd7. Straightforward selfblockingproblem (CF).

    PS2480

    wdwdwdwddwdPdwdwwdBdkGKddwdwdwdwwdwdwdwd

    dwdwdwdwwdwdwdwddwdwdwdw#4

    PS2482

    wdwdwdwddwdbdKGwwdwdwdwddwdwdwdNwdwdwdkH

    dwdwdwdwwdBdwdwddwdwdwdwH#2 2 solutions

    PS2484

    wGwdwdwddw0wdwdwwdwdwdwddwdwiwdwwdwdwdKd

    dw4wdwdwwdNdwdwddwdwdwdwH#3 2 solutions

    PS2486

    w w w wdwIwdwgwwdwdwdwddwdwdwdwwdwdwdpddwdwdwdkwdwdwdp4dwdwdwdwH#4 (b) Bb8>d8

    PS2488

    wdwdwdwddwdwdwdwwdwdwdwddwdwdwdwwdw0k1wddw0wdwdwNdwdwdwgdwdwdwdKH#5

    PS2489

    wdwdwdwddwdwdwdwwdwdpdwddwdwdwdwwgwdwdkddqdwdwdbwdwdwdwdHwIwdwdwH#5

    PS2487

    w w w wdwdwdwdwwdwdwdwddwdwdwdwwdwdwdwddwdwdw0wwdwdwdPddw1kdK$wH#4 2 solutions

    PS2481

    wdwdwdwddwdwdwdwwdwdwdwddwdwdw!wwdwdkdwd

    dwdpGwdwwdwIwdwddwdwdwdw#4 (b) rotate 90 clockwise

    PS2483

    wdwdwdwddwHwdwdwwdwdbdwddwdriwdwwdwdwdwd

    dwdwdwdwwdwdw!wddwdwdwdKH#2 3 solutions

    PS2485

    wdwdwdwddwdwdwdwwdkdwdwddwdwdwdww1wdwdwd

    dwdwdwdwpdPdpdwd$wIwdwdwH#3 2 solutions

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    JANUARY 2012 THE PROBLEMIST SUPPLEMENT 187

    PS2490(Mintz) 1.e1Q f4 2.Qe8 f5 3.Qg6+ fxg6 4.a1Q g7 5.Qe5 g8Q 6.Qb5 Qa2. Enjoyable problem to findthe first 3 moves of Black (RC). A puzzlers delight: lots of misdirection. I learned plenty about the physics ofthe chessboard from this one (SP). 3 promotions to Q in a miniature setting; fine composition (CF). Goodproblem with excelsior and phoenix. Nice that the black sacrifice facilitating promotion takes place on theremote g-file (PB). Excelsior: a pawn moves from its initial square to the promotion square; phoenix: a capturedunit is replaced by means of promotion (JMR).

    PS2491F (Rice) 1.Qf7 (-) BPg6/BPf5/BPg4/Kg4/Kh6 2.Qf4/Qg7/Rh5/Qxh5/Rxh5. Neat waiter with goodplay (CF). 5 mates economically shown (PB). Entertaining. Fairy chess sure is a different world, like an

    PS2490

    wdwdwdwddwdwdwdwwdwdw0wddwdwdwdwk0wdwdwddwdwdwdwpdwdp)Kd

    dwdwdwdwH#6

    PS2491F

    wdwdwdwddwdwdwdpwdwdQdwddwdwdwipwdwdwdwddwdwIwdRwdwdwdwd

    dwdwdwdw#2 Berolina pawns

    PS2492F

    wdwdwdwddwdwdwdwwdwIwdqddwdwdwdwwdwdwdkddwdwdwdwwdwdwdwddwdQdwdwH#2* 2 solutionsIsardam

    PS2493F

    wdwHwIwGdw0PdwdwwdwdwdwddwdwdbiwwdwdwdwddwdwdwdwwdwdwdwddwdwdwdwH#2 2 solutionsTake&Make

    PS2497F

    w w w wdQdwdwdwwdwdwdwddwdwdwdwndqdwdwddwdwdwdwwhwdwdwdiwIwdwdwH#5 (b) a4=bBGrasshoppers

    PS2498F

    w w w wdwdwdwdwwdwdw!wddwdwdwdwwdwiqdwddwdwdwdwwdwdw!Kddwdw1wdwH#5 (b) bK>f5Grasshoppers

    PS2494F

    wdwdwdwddwdwdwdwwdwdwdwdIwdwdwdwwdwdwdwddwipdwdwwdB1wdwddrdwdNdwH#3 2 solutionsCirce

    PS2495F

    wdB$KdwddwdQdwdwwdwgpdwddwdwdwdwwdwdkdwddwdwdwdwwdwdwdwddwdwdwdwH#3 (b) rotate 90 clockwiseEquileaper d7

    PS2496F

    w w w wdKgwiBdwwdwdwdwddwdwdwdwwdwdwdwddwdpdwdwwdwdwdwddwdwdwdwH#4 Circe

    alternate universe or something, pushing yourimagination. This puzzle is a lovely thing it haspurity of thought, an elemental simplicity, and hencea captivating quality (SP). Thanks for this comment but Im not sure this simple problem deserves it!(JMR).

    PS2492F (Sobrecases) Set 1Ke5 2.Qh5+ Kf4.1.Kf5 Qd5 2.Qg5 Ke6; 1.Kf4 Qd4+ 2.Qg4 Ke5.Ideal mates, chameleon echo (AN). Isardam play isalways rather tricky (CF).

    PS2493F (Tritten) 1.Bh7 Bf6+ 2.Kxf6-h8 Sf7;1.Kg6 Sf7 2.Kxf7-d8 Bf6. Nice point in solutionwith 2Kxf7-d8 that 3.Kxd7? would mean the onlymake was back to d8 (PB). Reciprocation of whitemoves is an attractive feature (JMR).

    PS2494F (Tar) 1.Rb3 Bxd3[Pd7] 2.d5 Se3 3.d4Sd1; 1.Rb2 Sg3 2.dxc2[Bf1] Bc4 3.Qd4 Se4. CleverCirce mates with the bQ unable to capture the wS inboth lines (CF). Very clever problem (PB, whomakes the same point about the illegal captures).

    PS2495F(Feather) (a) 1.Be5 Ef3 2.Bf4 Rd3 3.e5Bf5; (b) 1.f3 Ee1 2.Bd3 Be3+ 3.Ke4 Re5. Mostingenious (CF). CJF always produces problems ofvery high quality (PB). Nobody remarked on Tarand Feather side by side! (JMR).

    PS2496F (Ibran) 1.Kf6 Kxc7[Bf8] 2.Kxf7[Bf1]Be2 3.dxe2[Bf1] Bxe2[Pe7] 4.Ke8 Bh5. Good use ofthe Circe condition, particularly black capture on e2to get bP on right file (CF). Surprising tempo loss bybK and even more surprising play by wB.Remarkable problem (PB).

    PS2497F (Dietrich) (a) 1.Sc3 Gb1 2.Sd5 Gb33.Ga2 Ge6 4.Sb6 Ga6+ 5.Sa4 Ga3; (b) 1.Bb3 Kd22.Ga2 Kc1 3.Bd5 Ge4 4.Bb7 Ga8+ 5.Sa4 Ga3. Asexpected, Black guides wG onto a-file; well done,though (CF). I would have preferred to omit (b), asthere are two repeatedblack moves and thestrategy seems toosimilar to (a) (PB).

    PS2498F(Rallo) (a)1.Kd3 Gf1 2.Gc2+Gb2 3.Ke2 Gh3 4.Gf2

    Kh1 5.Kf1 Gg2; (b)1.Ge5 Gf4+ 2.Kg5Kh2 3.Gg4 Gh4 4.Gh5Ge1 5.Kh4 Gg3.

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    Similar final positions which must be on an edge;not easy to find (CF). Bewildering G-play (PB).Ideal mates (AN).

    PS2499F (Bakcsi) 1.Ke1 Ke6 2.Kf2 Kf73.Kxg3[Sg1] Kg8 4.Kh2 Sxf3+ 5.Kxh1[Bf1] Bxh3.Very ingenious play all black moves made by K

    (CF). One of the best problems of the set (PB).PS2500F (Morse) 1.g4 4.g7 8.Kf8 9.g8Q 10.Qf712.Kf6 13.Qe6 15.Kd6 17.Kxb6 19.Qb7 21.Ka822.Qc8+ Kxc8. Good accurate play with wQproviding necessary guards (CF). Good problemwith 5 anticipatory interferences (PB).

    PS2500F

    w w w wdwdw4wdww0wdwIwddwdpdwdwwdw)wdwddwdwdwdwwdwdwdPddwdwdwdwSer-S=22

    PS2499F

    w w w wdwdwdwdwwdwdwdwddwdKdwdwwdwdwdwddwdwdnHnwdwdwdwddwdkdwdBH=5 Circe

    Many thanks to all who sent solutions, and particularly to those solvers who also commented: Paul Bissicks(PB), R.Chandramouli (RC), Bryan Conway (BC), Charles Frankiss (CF), Alexander Nikolichev (AN) andSpiros Pantos (SP). Last year Charles narrowly missed the prize, but this year he has been luckier, sending acomplete set of correct solutions and brief comments on everything. Congratulations to him, and also a pat onthe back to Paul Bissicks, whose comments are quoted extensively above. I enjoyed Spiros Pantoss comments

    too: they revealed a refreshing enthusiasm! I hope there will be enough miniatures in the file for a further setnext July (JMR).

    Variations on a Theme of Yuri Sushkov,by David ShireIn Mansfields classic tome,Adventures in Composition, the author describes how the novice composer can

    adapt the matrix of a completed problem to create the basis of a new work. For example, he suggests a changeof axis as one possibility of potential. However, there is validity in using the samematrix to differentends.

    Threat correction and threat avoidance are close allies; these were the interests of Yuri Sushkov when Awaspublished. 1.Rf1? (>2.Sf2) 1fxe2 2.Qd5; 1f2! 1.Rxf3!? (>2.Qd5) 1Bxf3 2.Sf2; 1Kxf3 2.Qg4; 1Sb4!

    1.Bb4? (>2.Sc5) 1d3! 1.Ba7? (>2.Sc5) 1d3 2.Rxe3; 1Rb5! 1.Bxd4!(>2.Qg4) 1Sxd4 2.Sc5; 1Kxd4 2.Qd5; 1fxe2 2.Qd5; 1Sxe5 2.Qxe5. Thisis both heavy and complex. In particular, there are parallels to be drawn in therelationship between the threat correction phases, 1.Rxf3!? and 1.Bxd4!. Thethreat of one phase is transferred to the bK flight in the other, with the primary wSthreat recurring after a self-blocking capture. Sadly wSa6 serves only to mate onc5 whereas wSd1 mates andessentially guards both f2 and c3. There is a sense ofimbalance here and moreover the wPh3 is a little naughty, since the solver mayfeel that such a unit should ideally be employed in the post-key play.

    In B the bQ exerts focal control over e6 and f3. We further notice that bRe8and bBh1 would also guard the relevant squares were it not for the fact that theyare currently ambushed behind bSs 1.Rd5? (>2.Qe6) 1Se~ 2.Qf5; 1Sxd5

    2.Qg6; 1Qxd5 2.Sc3; 1Qb2 2.Qf3. It is unfortunate that the threat recurs afterthe flight but 1Qh3! is a fine refutation. 1.Be3! (>2.Qf3) 1Sg~ 2.Qxf4;

    B Yuri SushkovThe Problemist1977

    wdwgrdwddwdKhwdwwdN0wdwddp0wdw$wwdwdk0QddqdwdwdwwdwGPdnddNdwdwdb#2

    A Yuri SushkovProbleemblad1976

    wdwdwdwddwdw0wdwNdndQdpddwGw)w0wwdP0kdwddrdwgp)PwdPdR$wIdwdNdwdb#2

    C Yuri SushkovPedagogusok Lapja1981

    wdwdwdwddpIndpdww4pdw0wddpdwdBdww!Piwdw4dwdwdwHwwdw)Rdwddwdwhwdw#2

    1Sxe3 2.Sd2; 1Qxe3 2.Qe6. Again the flightcapture fails to defeat the threat. The theme of A iswhite correction. Yuri achieves the object of blackcorrection with the matrix in Bbut still the restlesssearching continued.

    C 1.Bd3? (>2.Qd6) 1Sxd3 2.Sf5; 1Kxd32.Qc3; 1c5,Sc5 2.Qc3; 1Rh5! 1.Re5!(>2.Qc3)1Sxe5,fxe5 2.Se2; 1Kxe5 2.Qd6. A bareminimum of white force is used and we witness the

    matching play normally associated with a twosolution h#2. In this the role of wSg3 is crucial foracross the twin phases it both guards and mates onthe squares e2 and f5. I just love this and the FIDEAlbum judges were similarly impressed!

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    D1.Bd4? (>2.Qg4) 1Sxd4 2.Sf2; 1Kxd4 2.Qd5; 1Bf5 2.Qd5 1Rf1!1.Rf3!(>2.Qd5) 1Sxf3 2.Sc3; 1Kxf3 2.Qg4; 1Bg8 2.Qf5. Up to this pointD seems to repeat C with the difference that a telling wPh3 has re-emerged.(Fortunately in this instance the offender cannot be classified as camouflage!)What did the author have in mind? The extra try, 1.Kf6?, places guards on bothe5and f5 so that 2.Qg4 and2.Qd5 are threatened. The pinning 1Ra6! defeats this

    Barnes try. A further layer has been added but is more necessarily better?This quartet of #2s is presented in chronological order of publication but this

    may not necessarily imply a similar sequence of composition. Nonetheless aconnecting thread of thought is apparent. You can guess that my favourite is C.Before casting your vote you must decide which features you value most!

    D Yuri Sushkov1 Pr Vecherny Leningrad1983

    wdwdwdwddpdwdwIbwdwdQdwd

    dpdw)w0wwHwdkdwddn$wdw)PwdwhwGpd4wdN4wdw#2

    P is for Promotion,by David Shire

    In the orthodox twomover we normally take into account promotion to Q and Sonly. Let us analyse A. There are set mates (with dual avoidance) for the self-blocking promotions; 1e1Q/e1S 2.Rd4/Be3. However, there is no provision for1Ke1 and this suggests an opening move by wSd1. 1.Se3? (-) e1Q/e1S/Ba32.Qc2/Sf1/Sce4 but 1Bb2! a refutation making subtle use of the distant wK.1.Sf2!(-) gives a second flight! 1e1Q/e1S/B~/Ke1/Ke3 2.Qd3/Sfe4/Sfe4/Qxc1/Qd3. Here we have 3x2 mate change; a Zagoruiko rendering of the theme usingonly 9 units. A sensational work of art!

    Since the queen combines the powers of R and B, it is fascinating to encounterthose problems where all four promotions (Allumwandlung) are pertinent. TheBK has two flight squares, b6 and d5, in B and 1.d8Q? takes both of them;stalemate! 1.d8R? (>2.Be3) Kb6! and 1.d8B? (>2.Rh5) Kd5! force the pace with

    threats. The gentle 1.d8S!(-) solves. The key arranges guards for b7 and e6 in theextended bK field so that a paradox emerges; 1Kb6/Kd5 2.Be3/Rh5. The blackdefences that refute certain threats in the try play allow these very moves tofunction as post-key mates. This may not be a true Dombrovskis in the sense thatthe virtual threats can never be realised. Nevertheless, this twomover is amazinglyrich given its miniature form.

    Jacques Savournin is one of the relatively unsung composers of his generation.He achieves something very novel in C. Set 1c5 2.Se3 1.Bg8? threatens anypromotion of wPf7. However, a guard of e4 is released so that 1cxb6!/cxd6!/c6!and c5! all defeat the intention by opening a line for the bRa7. 1.f8R? (>2.Bg8) c52.Se3 1cxb6!/cxd6!/c6! 1.f8B? (>2.Bg8) cxb6 2.Sxb6 1cxd6!/c6! 1.f8Q?

    (>2.Bg8,Qg8,Qff7) cxd6 2.Qxd6 1c6! Key 1.f8S! (>2.Bg8) cxb6/cxd6/c62.Qb5/Qb5/Qe6. Allumwandlung is here combined with refutation reduction; amost original conception. See also the very recent C10946 in the November 2011issue of the main magazine.

    A Ottavio Stocchi2 Pr LItalia Scacchistica1958 (v)

    wdwdwdwIdwdwdwdwwdwdwdwddwdwdwdwwdRdwdwddwHwdwdwwdwipdwddQgNdwGw#2

    B Michel Caillaud2 Pr Probleemblad1985

    wdwdNdw$dwdPdwdwwdwdwdwddwiwdwdwQdwdwdwddwdwdwdwwdwdwdwd

    dwGwdwdK#2

    C Jacques Savournin5 Pr Thmes-641966

    wdNIQdwg4w0wdPdBw)w)wdwddwdk0wdwwdwdRdNhdwdwdwdwwhwdwdwddwdw$wGw#2

    Black Allumwandlung is demonstrated in thecombinative separation scheme of D. Black hasthree set defences; 1cxd5/Sb3/Sxd3 answered by2.Bxd5/cxb3/cxd3. If the innocent BPe2 wereremoved, no mate would be apparent to follow1Se2. In the absence of a waiting move we try1.Sf3! with three threats; 2.Rxd4(A)/2.Se5(B)

    /2.Sd2(C). 1e1Q/Sb3/Sxd3 2.A/B/C. 1e1B

    2.A/B, 1cxd5 2.B/C, 1e1R 2.C/A. 1e1S2.A/B/C. Black has just seven defences to yieldevery possible permutation of the three threats. Toachieve this in block-threat form is truly remarkable.

    D Jan Strydom1 Pr The Problemist1996

    wdwdwdwddw0wdwdwwdpdwdpddw)Ndw$wK)k0wdPddwdRdwdwp0Pdpdw0grhwHwdB#2

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    Fairy definitions (see originals on page 192)Helpselfmate (HS#n): with White starting, Black plays helpful moves until his final (mating) move, which

    must be forced.Series-helpmate(Ser-H#n): Black plays a series of n consecutive moves (White not moving at all) until at

    the end of it White can mate in one. Check may be given only on Blacks last move.

    British Helpmate Composers(continued from page 181)Barry Barnes is well known to almost all readers. His range in composition is largely limited to his

    outstanding directmate twomovers, but in his work for the BCPS he ranged very widely, notablygeographically, attending many international meetings as an affable advertisement for Britishness! It would befutile for me to attempt to supplement here what he has written about himself in Barnes about Chess Problems,a unique book which I very much recommend. Barry has composed (so far? regrettably, I fear, he may now

    B Barry BarnesThe Problemist1974

    w w w wGwdwdw$wwdw0KdwddpdwdwdpwdwdwdN0dwgw)wdpRdw)q0w)dbdwdwirH#2 (b) Pe3Sg4

    C John Rice1 Pr Zajic TT 2000-1

    wdndwdwddwhpdwdww0wgk1wddw0w4wdwpdKdw0wHdwdw4pdw

    w$wdpdwddwdwdwdwH#3 2 solutions

    novel enhancing and unifying effect (and not as easyas he makes it look). In contrast to the previous twocomposers, it is impossible to detect from Johnshelpmates that they are the work of someone who isnot primarily a helpmate specialist. He is stillcomposing in the rare intervals allowed by editing,so let us hope for more!

    Solutions: A (a) 1.Rg2 Kc6 2.Ke5 Rxe3; (b)

    1.Sf4 Kb4 2.Kd3 Bf5. B(a) 1.f1R d3 2.Qxe3+ Se5;(b) 1.f1B dxc3 2.Qxg4+ Sf5. C1.Rf5 Sxf3 2.Ree5Sxe5 3.Kxe5 Rxe2; 1.Be7 Sf5 2.Sd6+ Sxd6 3.Kxd6Rxb6.

    Dand Eare for solving (solutions on page 192).

    For PS2459 (see page 184), one solver incorrectly described the defences on f4 as showing dual avoidance.This would only be the case if a dummy piece arriving on f4 allowed the mates on d1 and g7, with the moves ofR and S each introducing an element which eliminates the other mate (MMcD).

    D Barry Barnes & JohnDriverThe Problemist1974

    wdwdwdwdGwdwdwdwwdwdwdwgdwdwdwdp

    RdwdKdw)dwdwhpibwdndwdwddw4wdwdwH#2 (b) wBh3

    E John Rice3 Pr Magyar Sakklet1971

    wdwdwdwddwdwdwdwwdwdwdwddwiwdwdw

    wdwdqdw$dwdwdwGRwdwdw)wddbdwdwIBH#2 2 solutions

    have abandoned composition altogether) about 30 helpmates, often technicallygood ones, but very much influenced by directmate ideas. The crosschecks in Bwould surely have appealed to Mansfield! Many a helpmate composer would bepleased to have composed this problem, and the various motifs incorporated areall interesting, but the idea clearly evolved backwards, with the first moves beingadded to supplement the spectacular ending, rather than the whole thing havingbeen conceived as a characteristic helpmate theme. That may sound a little harsh,but such a meticulous composer as Barry would, I feel sure, not take it amiss.Undoubtedly a perfectionist, he would worry ideas as a dog does a bone, but Ithink that he found the cook-prevention work in helpmate composition extremelyirksome, which is perhaps why he did not persevere with a genre which he couldsurely have mastered as thoroughly as the directmate twomover.

    Finally we come to John Rice. Appropriately for this article, it was John Driverwho introduced him to helpmates, about 50 years ago. JMR is of coursesuccessful in all genres, including helpmates, although he has composed scarcelymore examples than Barry. He is also an accomplished helpmate judge, and fromhis wide knowledge he knows the difficulty of finding original ideas. Perhaps themost notable talent which emerges from Johns many writings is the ability toanalyse compositions and understand their workings, so that he very quicklygrasps the mechanisms and techniques and sees further possibilities. That may bewhy he likes composing to set themes, as in the case of C. Zajics paradoxicalidea was that Blacks penultimate move should block the square to which his kingfinally needs to move, thus requiring a clearance sacrifice by White andpotentially creating a Zilahi when paralleled in a second line, as here. In writingabout this theme, I had opined that it was unsuitable for a three-move settingbecause the first moves would be superfluous, but John was no doubt delighted toprove me wrong by making Blacks first moves vacate the thematic square, a

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    PS2471F

    wgwdwdwddwhwdwdww$w4wdwdGwiNdwdR

    wdwhwdwddwIwdwdwwdQdrdwddwdwdwdwSer-S#8

    PS2472F

    wdwdwdwddw$wdwdwwdwdw$wddwdkdwdw

    wdbdndwddwdwdwdwwdwdwdKddwdwdwdwH#2 2 solutionsTake&Make

    PS2473F

    wdwdwGwgdwdwdw0wwdwhwdwd

    4wdNdwdwwdwdkdwddPdndw$wwdwdwdwddKdwdwdw

    H#2 2 solutionsTake&Make

    PS2474F

    wdwdwgwddqdwdwdpwdwdwHw!

    Iwdw)pdwNdpiwdwd0wdwdwdrwdPdwdwd4wdwdwdwHS#3 2 solutions

    PS2475F

    w w w wdwdwdwdwwdwdwdwddwdwdw4wwdwdwdwddwhwdBdwwdpdwdr0$wdwIwdkH#2 3 solutionsEinstein Chess

    PS2476F

    w w w wdwdwdwdwwdwdwdwddwdw0wdKwdwdwdwddwdk1wdwwdwdN!wddwdwdwdwH#4 2 solutionsGrasshoppers

    FAIRY SOLUTIONS (July)PS2471F (Bowden) 1.Qb3 2.Kd3 3.Bd2 4.Be3

    5.Ke4 6.Ke5 7.Sxc7 8.Se6+ Rxe6. One batteryunloaded, another spiked, the wK shielded by a vitalpinning unit, and the black battery unspiked. ThebBb8 points to the graveyard, but there is lots ofgood strategy. Fun to solve! (C.C.Lytton). Cleversequence (CCF). Fine construction (M.Merkert).

    PS2472F (Tritten) 1.Bf1+ Kxf1-d3 2.Sc3 Rxc3-b5; 1.Sg3 Kxg3-f5 2.Ba6 Rxa6-d3. Exchange offunctions by the wRs and black minor pieces, withrotated echoed ideal mates, from only 6 pieces. Myonly gripe with Take & Make is that it seems to leadto much black slaughter by White (CCL). PleasingT&M miniature (RL). Curious mates (CCF).

    PS2473F (Satkus) 1.Kxd5-b4 Rxg7-g6 2.Bc3Rxd6-b7; 1.Kxd5-c3 Bxg7-g6 2.Bd4 Bxd3-e1.Reciprocal batteries, with double-check aspectsimpossible in orthodox chess, and preparatoryannihilation clearances for the bB. Difficult finalesto see, though the outlying wPb3 should have been ahint (CCL). More curious mates (CCF). With theTake&Make condition H#2 doesnt actually feel likea helpmate in 2, as its potentially 4 moves by eachside (MM).

    PS2474F(Parrinello) 1.Qxf8 Re3 2.Qxa3 Rxe5+3.Qc5+ Rxc5; 1.Qxh3 Bh6 2.Qxa3 Bd2+ 3.Qc3+Bxc3. Zilahi and matched strategy for pin-mates,

    though I was disappointed that the bR doesntimitate the bB and go via h6, following the Q(CCL). Circuits by the wQ with matching moves bythe R and B (CCF). Good work (RL). Solutions areindeed neatly matched; the realisation is a bit brutal,though (MM).

    PS2475F (Poissant) 1.Rb5=B Ra6=B 2.Bf1=SBxf1=R; 1.Rc5=B Ra7=B 2.Bg1=S Bf2=S; 1.Kg1Rc1=B 2.Re2=B Bxg5=R. Chameleon effect withparallel play in the first two lines. The third line wasvery difficult, but worth the effort, with a blackhideaway behind the wBf3 (CCL). Three goodEinstein mates (CCF).

    PS2476F(Rallo) 1.Ke4 Gd4 2.Kf5 Sf4 3.e4 Se64.Ge5 Sg7; 1.Ge6 Gd2 2.Ke3 Gf4 3.Ke4 Gd6 4.Kf5Sg3. Reflected echo with bK tempo in the 1.Ge6solution, highlighted by the try 1.Ke4 Kh4 2.Kf3

    Kh3 3.e4 Gd4 4.?? Sg1 (CCL). As JMR said, a neat

    miniature (CCF). First I had a look whether mate ispossible in the middle of the board (S covers 2squares, G 2, K 3, +2 blocks = 9), and it was not toohard to construct several such positions with bK onthe f-file, blocks along the e-file and the wSdelivering mate (MM).

    Parry-series-helpmate (Pser-H#n): as Ser-H#n, except that Black may check in the course of the series. Ifthis happens, White parries the check immediately and then the series resumes. There is no limit to the numberof checks allowed.

    Parry-series-selfmate (Pser-S#): White plays a series of consecutive moves (Black not moving at all) untilat the end of it White can force Black to mate in one. Check may be given in the course of the series, in whichBlack moves to parry the check before the series resumes. There is no limit to the number of checks allowed.

    Grasshopper (q): moves and captures on Q-lines by hopping over another unit of either colour (the hurdle)

    to the square immediately beyond it. A capture may be made on arrival, but the hurdle is not affected.Koeko(Klner Kontaktschach): the arrival square of any moving unit must be adjacent to a square occupied

    by another unit of either colour.

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    PS2549F Christopher Jones

    wdbdwdwddwHNdwdww0wIwdBdgwdw0wdww0wiwdwddPdwdpdwwdwdwdqddwdw4wdwHS#3 (b) c8=bR

    PS2550F Zlatko Mihajkoski(Macedonia)

    wdwdwdwd0pipdpdQwdwdw0wddpIwdwdwwdw0w1wddwdw4wdwwdwdwdwddwdwdwdwHS#3 2 solutions

    PS2551F Dan Meinking(USA)

    wdwdwdwddwdwdwdwwdwdwdwddwdwdwdwwdwdwdwddwdwdwdNwdwdwdw4IwdwdwdkPSer-H#12

    PS2552F Mark Kirtley(USA)

    KdwdwdwddPiwdwdwwdwdwdwddwdRdwdw

    wdwdbdwddwdwdwdwwdwdwdwddwdQdwdwPSer-S#5 2 solutions

    PS2553F Arthur Willmott(Australia)

    wdwdwdwddwdwdwdwQdwdwdwddwdwdwdw

    wHKdwdwddwdwiwdwwdbdrdwddw!wdwdwH#3 (b) BK>d6 (c) BK>f2(d) Gc1>g2 Grasshoppers

    PS2554F Vito Rallo(Italy)

    wdwdwdwddwdwdwdwwdwdwdnddwdwdwdk

    wdwdKdwddwdw)wdwwdwdwdwgdwdwdwdwHS#4 Koeko2 solutions

    FAIRY ORIGINALS PS2549-54F

    Solvers should certainly enjoy this months selectionof mainly helpselfmates and series-movers. Apologies to

    Christopher Jones, whose PS2549F has had to waitlonger than it should for publication. We sent ArthurWillmott congratulations in the November Problemistonhis recent 90th birthday, and its a pleasure to publishanother of his ingenious Grasshopper helpmates. Afurther pleasure for me was to meet Vito Rallo at theCongress in Jesi last August. From the solvers angle, thegood thing about Koeko is that the choice of moves islimited. Inevitably with these things, theres a drawback:the mating position can be very hard to spot. Have funanyway!

    JMR

    The Problemist Supplementis one of the

    two magazines produced for its membersby the British Chess Problem Society,which exists to promote the knowledge andenjoyment of chess compositions.Membership is by calendar year and isopen to chess enthusiasts in all countries.

    Membership subscriptions (due 1stJanuary) are 32.50 for Fellows and 25for members(12.50 for under-21s). Newmembers joining during the year pay aproportion of the subscription (exactamount to be negotiated with the

    Treasurer). Payments, in sterling toBCPS, should be sent to the AssistantTreasurer, Sally Lewis, 16 Cranford Close,Woodmancote, Cheltenham GL52 9QA([email protected]).

    Solutions to helpmates for solving (page 190)

    D(a) 1.Sg4 Kf5 2.Kxh4 Bf2; (b) 1.Sc4 Kd3 2.Kf4 Bb8.

    E1.Qc6 Re4 2.Kd5 Rh5; 1.Qc4 f4 2.Kd4 Bf2.