Structural Eurocodes

5/25/2018 Structural Eurocodes

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Structural Eurocodes

EN 1993 Design of Steel

Structures

John J Murphy Chartered Engineer

Department of Civil, Structural & Environmental Engineering Cork Institute of Technology


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Department of Civil, Structural &Environmental Engineering Cork

Designers guide to Eurocode 3: Design of Steel Structures(L Gardner and D A Nethercot) Thomas Telford

Access Steel website that provides much information on design

to EC3

Access Steel is a unique electronic resource to ensure that the

European steel construction community takes maximum advantage

from the commercial opportunities arising from the Eurocodes.

With input from six leading institutes for steel construction in Europe,it provides harmonised information for clients, architects and

engineers on:

multi storey commercial buildings

single storey buildings

residential construction

fire safety engineering

http://www.access-steel.com/


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Partners

Steel Construction Institute (SCI) (UK)

Centre Technique Industriel de la Construction Metallique (CTICM ) (France)

Stalbyggnadsinstutet Swedish Institute of Steel Construction (SBI) (Sweden)

Rheinish-Westfalische Technische Hochschule Aachen (RWTH) (Germany)

Labein Tecnalia (Spain)

Profilarbed Research (PARE) (Luxembourg)

Sponsors

Arcelor-Mittal, Corus, Peiner Trger, Voest Alpine, Ruuki, Dillinger, SSAB


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EN 1993-1-1: General rules and rules for buildingsEN 1993-1-2: Structural fire design

EN 1993-1-3: Cold formed thin gauge members and sheeting

EN 1993-1-4: Structures in stainless steelEN 1993-1-5: Strength and stability of planar plated

structures without transverse loadingEN 1993-1-6: Strength and stability of shell structures

EN 1993-1-7: Strength and stability of plate structures loaded transversally

EN 1993-1-8: Design of jointsEN 1993-1-9: Fatigue strength

EN 1993-1-10: Fracture toughness assessment

EN 1993-1-11: Design of structures with tension components made of steel

EN 1993-1-12: Use of high strength steels


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IwItIWplWeliy,zAEC3

HJISZrx,yABS5950

tf,t

wdB,hVMNf

y

LTf

yf

yEC3

T,tdB,DVMPpcpbpyBS5950

Symbols


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Table 3.1: fy fu

Clause 3.2.6 E = 210000 N/mm2 G 81000 N/mm2, = 0.3

S275: t < 40 mm f y = 275 N/mm2

fu = 430 N/mm2

40 mm < t < 80 mm fy = 255 N/mm2 fu = 410 N/mm

2

Material properties taken from EN 10025-2, which gives additional

values for different thicknesses.

So for S275 16 mm < t < 40 mm fy = 265 N/mm2. Table 3.1 is asimplification of EN 10025-2.

5.5 Classification of cross sections

Table 5.2 { = (235/fy)} Class 1,2,3,4


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5 Structural Analysis

5.1.1 (2) Calculation model and basic assumptions should reflect

structural behaviour.

5.1.2 (2) Depending on joint behaviour simple, continuous, semi-

continuous

5.2.1 (3) First order analysis when cr = Fcr/FEd 10 elastic analysis15 plastic analysisFcr: Elastic critical buckling load FEd: Design load


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Ed

y

N

Af3.0


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5.2.2 Structural stability of frames

5.2.2 (3) b) Second order effects accounted for partially by

global analysis and partially through individual member

stability checks according to 6.3

5.2.2 (5) If cr 3, amplify all horizontal loads by

cr11

1

Second order effects likely to arise in unbraced structures

and in bracing design of braced structures

If cr

< 3, second order analysis is necessary


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( )m115.0 +

5.3 Imperfections

5.3.2 (3) a) Global initial sway imperfection: = 0 * h * m0: Initial value =1/200

h: Reduction factor for column height = 2/h (2/3 h 1)(h: structure height)

m: Reduction factor for number of columns in a row =

Recommendation (SCI) - use 0 i.e let h = m = 1.0


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which translates as NEd/Ncr 0.25

Use equivalent horizontal forces (EHFs) for

all load combinations

Ed

y

N

Af5.0


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6 Ultimate limit states

6.1 Material factors MM0 = 1.00 (cross-sections) M1 = 1.00 (Buckling)

M2 = 1.25 (Fracture) (1.1 in UK)

6.2.3 Tension

(1) NEd Nt,Rd(2) Npl,Rd = Afy/M0 gross section(3) Nu,Rd = 0.9Anetfu/M2 bolt holes

EN 1993-1-8: 4.13(2) For equal angle leg or unequal angle

connected (by welding) by its larger leg Aeff= Agross

EN 1993-1-8: 3.10.3(2) Nu,Rd formulae for resistance of angle

connected through one leg using 1,2 or 3+ bolts


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6.2.4 Compression

(1) NEd Nc,Rd(2) Nc,Rd = Afy/M0 (class 1,2,3)

Aefffy/M0 (class 4)

EN 1993-1-5 Clause 4.4:

Aeff is determined by excluding ineffective portion of

section.


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6.2.5 Bending moment

(1) MEd Mc,Rd

(2) Mc,Rd = Mpl,Rd = Wplfy/M0 (class 1,2)Wel,minfy/M0 (class 3)Weff,minfy/M0 (class 4)

(4) Fastener holes in tension flange may be ignored provided:

Af,net 0.9fu/ M2 Affy/ M0


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6.2.6 Shear(1) VEd Vc,Rd(2) Vpl,Rd = Av(fy/3)/M0(3) I section Av = A 2btf+ (tw + 2r)tfbut not less than hwtw(6) Shear buckling if hw/tw > 72/ may be conservatively taken as 1EN1993-1-5 Clause 5.1 Note 2: = 1.2 up to and including S460;

otherwise 16.2.8 Bending and shear

(2) VEd1

0.5Vpl,Rd

no effect on Mc,Rd(3) Reduced moment resistance: reduced design yield strength (1-)fy

2

,

12

=

Rdpl

Ed

V

V


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1,,

,

,,

,

+

RdzN

Edz

RdyN

Edy

M

M

M

M

6.2.9 Bending and axial force

6.2.9.1 Class 1 and 2 cross-sections

(4) Axial force can be ignored:yy axis: if NEd 0.25Npl,Rd and NEd 0.5hwtwfy/M0zz axis: if NEd hwtwfy/M0(5) Values of reduced moment capacities: MN,y,Rd, MN,z,Rd

(6)


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Conservative alternative for all sections: 6.2.1 (7)

1,

,

,

,++

Rdz

Edz

Rdy

Edy

Rd

Ed

M

M

M

M

N

NEq 6.2

As buckling is generally critical and will override Eq.

6.2, the more exact equations in 6.2.9 need not generally

be considered.


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6.3 Buckling resistance of members

Elastic buckling theory (Euler)Ncr =

2EI/l2 for ideal strut

This value is modified by various imperfections:

Geometric imperfections (initial curvature)

Eccentricity of loading

Residual stresses (locked-in due to differential cooling)

Non-homogeneity of material properties

End restraintsThese are taken into account in the Perry-Robertson formula


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EC3 provides solution for this equation. Effectively cr = fy

}{ EyEyEy

cr ++++=

2)2/))1(((2

)1(


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6.3.1 Uniform members in compression

6.3.1.1 Buckling resistance(1) NEd Nb,Rd

(3) Nb,Rd = Afy/ M1 (class 1,2,3)

Aefffy/ M1 (class 4)


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2.0

22

1

+

=22 )2.0(15,0 ++=

cr

y

N

Af=

cr

yeff

N

fA=

6.3.1.2 Buckling curves

(1)

(but 1)

(class 1,2,3)

: imperfection factor (Table 6.1) (Table 6.2)Ncr: Elastic critical buckling load

(chi) can also be obtained from Figure 6.4

(4) If

(class 4)

2.0 crEd NN 04.0( ) buckling effects can be ignored


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1

=

6.3.1.3 Slenderness for flexural buckling

fcr = Ncr/A = 2EI/Al2 = 2EAi2/Al2 = 2E/2

Lettingfcr =fy limiting slenderness 1 = (E/fy)0.5 = 93.9

= Lcr/iz

cr

y

N

Af

(ratio of actual slenderness to slenderness at boundary between

yielding and elastic buckling) =(E/fcr)0.5/ ((Efy)

0.5) = (fy/fcr)0.5

=

: non-dimensional slenderness


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5.0

2

2

2

2

+=

z

tcr

z

w

cr

zcr

EI

GIL

I

I

L

EIM

gg

z

tcr

z

w

wcr

zcr zCzC

EI

GIL

I

I

k

k

L

EICM 2

5.0

2

22

22

2

2

1

++

=

6.3.2 Uniform members in bending

Beam behaviour analogous to column behaviour

Beam subject to equal moments at each end

This is expanded to:

for other load situations.


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Mcr: Elastic critical buckling load

C1, C2, k, kw: constants

zg: Eccentricity of load relative to centroid of beam

(destabilizing load)

C1: depends on moment diagram

k, kw: depend on support conditions (generally 1)

C2: does not apply when zg = 0 (non destabilizing

loads)


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NCCI SN003a-EN-EU and NCCI SN006a-EN-EU (cantilevers)

provide information on calculation of Mcr.

Program to calculate Mcr

can be downloaded from

http://www.cticm.eu

The results for buckling and lateral torsional buckling are similar to

those in BS5950 (Annex C buckling (exact), Annex B lateraltorsional buckling)

6.3.2.1 Buckling resistance

(1) MEd Mb,Rd(3) Mb,Rd = LTWyfy/M1Wy = Wpl,y (class 1,2) Wy = Wel,y (class 3) Wy = Weff,y (class 4)


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22

1

LTLTLT

LT

+

=

222.015,0 LTLTLTLT ++=

cr

yy

LTM

fW

=

4.0LT crEd MM 16.0

6.3.2.2 Lateral torsional buckling curves General case(1)

(but 1)

LT: imperfection factor (Table 6.3) (Table 6.4)(3) LT can also be obtained from Figure 6.4

(4) If ( )buckling effects can be ignored


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NCCI SN002a: Simplified assessment of

119.0

1

z

LTC= where z = Lcr/iz, 1 = (E/fy)

1.3481.365pinned, central P

1.1271.132pinned, udl

2.552.752-1

2.572.927-.75

2.332.704-.5

2.052.281-.251.771.8790

1.621.563.25

1.311.323.5

1.141.141.75

1.001.0001

C1 (SN003a)C1 (Designers Guide) (= M1/M2)

C1 = 1.88 1.4 + 0.5 2 (C1 2.70)


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22

1

LTLTLT

LT

+=

2

1

LT

2

0,

2)(15,0 LTLTLTLTLT ++=

4.00, =LT

75.0=

6.3.2.3 Lateral torsional buckling curves for rolledsections or equivalent welded sections

(1) For members in bending (beams)

but 1 and


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2

)8.0(0.211(5.01 =

LTckf

LT: imperfection factor (Table 6.3) (Table 6.5)(2) LT,mod = LT/f ( 1)

kc: Table 6.6

6.3.2.3 used for rolled sections of standard dimensions

6.3.2.2 can be used for all sections including plate girders

(bigger than standard sections), castellated and cellularbeams

( 1)


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1,,

,

,

,

,,++

Rdzc

EdZ

yz

Rdb

Edy

yy

Rdyb

Ed

M

M

kM

M

kN

N

1,,

,

,

,

,,++

Rdzc

EdZ

zz

Rdb

Edy

zy

Rdzb

EdM

M

kM

M

kN

N

6.3.3 Uniform members in bending and compressionFor Class 1,2,3 sections, Equations 6.61 and 6.62 reduce to:

Eq. 6.61

Eq.6.62


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k values in Annex A, Annex B.

Annex A is more precise (French-Belgian)

Annex B is easier to use (Austrian-German)

Table B.3:

If =1 (uniform moment in column no lateral load on column)Cmy = Cmz = CmLT = 1

If =0 (M varies from 0 to Mmax no lateral load on column) Cmy= Cmz = CmLT = 0.6

Members susceptible to torsional deformations:

(Table B.2/ Table B.1)


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=

Rdzb

Ed

mLTRdzb

Ed

mLT

z

zy N

N

CN

N

CMAXk

,,,, )25.(

1.0

1,)25.0(

1.0

1

+

+=

yRdb

Edmy

Rdyb

Edymyyy

N

NC

N

NCMINk

,,,

8.01,)2.0(1

+

+=

Rdzb

Edmz

Rdzb

Edzmzzz

N

NC

N

NCMINk

,,,,

4.11,)6.02(1

kyz = 0.6kzz kzy = 0.6kyy

(Table B.2/ Table B.1) 4.0


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For columns in simple construction N generally dominates,

UC sections are less likely to buckle about yy axis Equation 6.62 likely to be critical.As N dominates, k values can be chosen conservatively

Access Steel (NCCI SN048b-EN-GB) suggests kzy= 1, kzz=

1.5 (conservatively)

15.1,,

,

,

,

,,

++

Rdzc

EdZ

Rdb

Edy

Rdzb

Ed

M

M

M

M

N

N


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7 Serviceability limit states

Deflections to be agreed with client BS5950 values proposed in

UK National Annex

Guidance is also provided in NCCI SN034a-EN-EU

Cantilever: Length/180Beams carrying plaster or other brittle finish: Span/360

Other beams: Span/200

Horizontal deflection limits also provided


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EN 1993-1-8 Design of Joints

Table 2.1 Partial safety factors for joints

Bolts, Plates in bearing, Welds M2 = 1.25 (UK: 1.5 for grade 4.6)Slip resistance at sls M3,ser = 1.1Preload of high strength bolts M7 = 1.1

2.5 Design Assumptions (1) Joints should be designed on the

basis of a realistic assumption of the distribution of internal

forces and moments.Identify a load path through the joint and

check all links in chain.


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2.7 Eccentricity at connections

Table 3.1 Bolt strength fy, fu

3 Connections made with bolts, rivets or pins

3.1.2 Preloaded bolts

Table 3.2

Bearing: Fv,Ed Fv,Rd Fv,Ed Fb,RdSlip (sls): Fv,Ed,ser Fv,Rd,ser Fv,Ed Fv,Rd Fv,Ed Fb,Rd(use grade 8.8 or 10.9)

Tension: Include prying action


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Table 3.3 End, edge distances (e) Spacings (p)

(d0 bolt hole diameter)

e1, p1: Parallel to load e2, p2: Perpendicular to load

3.6.1 (2) Preload in bolts: Fp,Cd = 0.7 fub As/ M7

(10) Single lap joints with one bolt row(12) Bolts through packing

Table 3.4 Design resistance

Shear resistance Fv,Rd = v fub As/ M2 v = 0.6 or 0.5Bearing resistance Fb,Rd = k1 ab fu d t/ M2ab = Min. (ad, fub/fu, 1) end bolts ad = e1/3do

inner bolts ad = p1/3do 0.25

k1 = Min. (2.8 e2/do -1.7, 2.5) edge bolts

k1 = Min. (1.4 e2/do -1.7, 2.5) inner bolts

Tension & Combined Shear and Tension also included


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3.8 Long joints

3.9 Design slip resistance Fs,Rd = (ksn)Fp,C)/ M3ks = 1 for bolts in normal holes (Table 3.6)

n is the number of friction surfaces: slip factor (Table 3.7)Class A: shot/ grit blasted, spray metallised with aluminium or zinc

based coating certified to provide a slip factor of 0.5

Class B: shot/ grit blasted, painted with alkali-zinc silicate paint toproduce a thickness of 50 80 mClass C: wire brushed or flame cleaned

Class D: untreated

3.10.2 Design for block tearing

(2) Veff,1,Rd = fu Ant/ M2 + (1/3)fy Anv/ M0 Eq 3.9

(3) Veff,2,Rd = 0.5 fu Ant/ M2 + (1/3)fy Anv/ M0 Eq 3.10


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Section 4 Welded connections

4.5.2 Effective throat thickness

4.5.3.2 Directional method

4.5.3.3 Simplified method for the design resistance of fillet weld

(1) Fw,Ed Fw,Rd(2) Fw,Rd = fvw,d * a (throat thickness) = 0.7 * leg length(3) fvw,d = fu/(3 * * M2) : Table 4.1 (= 0.85 for S275)

5 Analysis, classification and modelling

Table 5.1 Joint modelling

6 Structural Joints connecting H or I sections

Table 6.1 Basic joint components

Table 6.2 Design resistance of a T-stub


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=

2

,,

0,

1,

jd

Edj

fccjd

Edj

c

f

N

bhf

NMAXA

Column Base plate

6.2.8.2, Figure 6.19

6.2.5 Equivalent T-stub in compression

(3) FC,Rd = fjd * beff* leff(7) fjd = j FRdu/ (beff leff) j = EN 1992-1-1 Clause 3.1.6 (1) fcd = cc fck/ c; cc = 1, c = 1.5NCCI SN037a fjd = j * * fcd ( = 1.5)


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y

Mjd

pf

fct

03 =

Large projection

Short projection (when Ac,0 < 0.95bh) base plateSelect plate dimensions determine c (Figure 6.4)

Min. outstand: tf6.2.5(4)

y

Mjd

p

f

fct

03 =

EN 1993 1 5 Plated structural elements


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0.1

5.0

F

cr

ywwy

F

F

ftl=

w

wFcr

h

tEkF

3

9.0=

EN 1993-1-5 Plated structural elements

Section 6 Resistance to transverse forces (web bearing andbuckling)

Figure 6.1 kF6.2 Design resistance FRd =(fywLefftw)/ M1

Leff= Fly6.3 Length of stiff bearing

6.4 Reduction factor F =

6.5 Effective loaded length


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F

F

212

2

1

,2 mmtlmt

lm

tl fef

e

fe +++

++

csbut

hf

Etkl s

wyw

wFe +=

2

2

g

m1 = fyfbf/fywtw

m2 = 0.02 (hw/tf)2 if > 0.5,

ly is the minimum of:

6.6 Verification 1/)( 1

2 =

Mweffyw

Ed

tLf

F

0.50 if


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vveff 7.035.0, += yyeff 7.050.0, += zzeff 7.035.0, +=

Effective lengths

Truss members: EN 1993-1-1:

Annex BB.1.1: Lcr = L (for chord members)

Annex BB.1.2 (angles as web members):

Members in compression ends held in position (BS5950 in

absence of EC3 guidance)

1.0LNot restrained in direction at either end

0.85LRestrained in direction at one end

0.85LPartially restrained in direction at both ends

0.7LBoth ends effectively restrained in direction


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Members in bending compression flange laterallyrestrained, nominal torsional restraint against rotation

about longitudinal axis at supports (NCCI SN009a)

1.0Both flanges free to rotate on plan

0.85Compression flange partially restrained

against rotation on plan

0.8Both flanges partially restrained against

rotation on plan

0.75Compression flange fully restrainedagainst rotation on plan

0.7Both flanges fully restrained against

rotation on plan

KSupport conditions


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NCCI SN005a:

Simple construction assume loads applied at 100 mmfrom face of column (flange or web). Resulting moment

can be distributed between upper and lower levels in

accordance with stiffness


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End Plate NCCI: SN013, SN014

Use full depth end plate if VEd > 0.75 Vc,RdMin. number of bolts = VEd/75

Plate dimensions

14020010> 500 mm

901508, 10< 500 mm

Cross-centres(mm)

bp(mm)

tp(mm)

Beamdepth

Weld size (S275):

1086Leg length (mm)

75.54Throat (mm)

15129Beam web (mm)


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Bolts in shear: Shear resistance multiplied by 0.8 to account for

presence of some tension in bolts

End plate in shear (gross section): Shear resistance divided by

1.27 to allow for bending moment in plate

Weld design: Shear resistance divided by 1.27 to allow for

bending moment in plate

End plate in shear (block shear): may need to consider Veff,1,Rd(3.10.2 (2)) and Veff,2,Rd (3.10.2 (3))

End plate in bending when bolt cross-centre distance is large,

bending in plate reduces shear resistance

Beam web in shear to be checked for depth = plate depth


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Weld design a 0.39tw,b1

Ductility requirements:

py

ubp

f

fdt

,8.2


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