DESIGN OF STRAP BEAM

EXT COL INT COL

1. 0 LOADS INPUT

EXT COLUMN LOAD INTERIOR COLUMN LOADPw1 = 190.96 KN Pw2 = 287.82Mwy1 = 42.947 KN-m Mwy2 = 28.683

Pu1 = 242.51 KN Pu2 = 371.99Muy1 = 59.542 KN-m Muy2 = 40

2.0 CONSIDER WEIGHT OF FOOTING = 10 %

EXTERIOR COLUMN INTERIOR COLUMN

Service Column Load = 190.96 Service Column Load

Weight of Footing = 19.096 Weight of Footing

Total Concentrated Load = 210.056 Total Concentrated Load

3.0 FOOTING AREA

Total Combined Vertical Load Required Total Area of footingPw1 = 210.056 KN SBC = 100Pw2 = 316.602 KN

Arqd = 5.27Pwt = 526.658 KN

Length and Area of Exterior Footing Length and Area of Interior FootingA1 = 2.10 sq.m A2 = 3.17L = 1.45 m L = 1.78

L = 1.60 m L = 1.80A1 = 2.56 sq.m A2 3.24

COMBINED AREA Remark

A1 + A2 = 5.8 sq.m Aact > Arqd, ok!!

4.0 CENTROID OF FOOTING (WORKING LOAD)

CG OF LOADSxg 526.658 = P1x1 + P2x2 + Mwy1 + Mwy2

xg = 2.83 m from reference line

CG OF AREAxg 5.8 = A1x1 + A2x2

xg = 2.56 m from reference line

difference = -0.27 m

Ref line

Length of footing 1 = 1.6 Clear "d" bet. Col = 1.45

Centroid of column Load X = 2.83

P1 = 210.06

L1 /2 =0.8

R1 Pt = 526.658

X10.8 c to c of column = 3.15 m

4.85

5.0 SOLVING FOR STRAP BEAM FORCES (ULTIMATE FORCES)

EXTERIOR COLUMN

242.5 KN

0.8

M (KN-m) = 59.5V V (Shear)

V (Shear)

0.8

R1 = 210.91 KN

R1 = 210.91 KNM1 = 34.26 KN-mV1 = 31.60 KN

M = 34.26 KN-mV = 31.60 KN

DESIGN OF STRAP BEAM

INTERIOR COLUMN LOADKNKN-m

KNKN-m

INTERIOR COLUMN

= 287.82

= 28.782

= 316.602

Required Total Area of footingKpa

sq.m

Length and Area of Interior Footingsq.m

m

msq.m

Length of footing 2 = 1.8

P2 = 316.60

L2 /2 =0.9

R2

0.9

INTERIOR COLUMN

372.0 KN

0.9

M (KN-m) =40.0

0.9

R2 = 403.59 KN

R2 = 403.59 KNM2 = 11.56 KN-mV2 = 31.60 KN