Statics- Force Vectors
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Transcript of Statics- Force Vectors
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8/9/2019 Statics- Force Vectors
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Statics(MCB 1053)
W02L1
TOC
• AOB
• week 2 outlook
• Chapter 2: Force Vectors
1Copyright © 2010 Pearson. (adapted by AAW)
AOB
• Week 1 Assignment (autodidactic):
– F2-5, 2-19, 2-24, F2-12, 2-39, 2-56, 2-58
• Online assignments
– for MasteringEngineering please use “official” UTP name & ID
– practice assignments up until 11:59pm Wed this week – graded online assignments start in week 2 onwards
– check the website regularly
• Tutorial
– tutorial signup: Sections 1, 3, 4 already full
– attend your own section only (for the entire semester)
• check for any announcements on UTP eLearning
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Week 2 outlook
• Chapter 2: Force Vectors
– scalars and vectors
– vector operation
– vector addition of forces – addition of a system of
coplanar forces
– position vectors
– force vectors directed
along a line
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• If the resultant force is required to act along the positive u axis andhave a magnitude of 5kN, determine the required magnitude of F B and its direction ! .
P2-8
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• The beam is to be hoisted using two chains. If the resultant force isto be 600 N directed along the positive y axis, determine themagnitudes of forces F A and F B acting on each chain and the angle ! .of F B so that the magnitude of F B is a minimum. F A acts 30o from the
y axis as shown.
P2-29
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Chapter Objectives
• to use Parallelogram or Triangle Laws to add forces & resolveinto components
• to express forces & vectors in Cartesian Vector Notation (CVN) - today’s lecture
• to use Dot Product to determine angle between two vectors andthe projection of one vector onto another vector
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Addition of a System of Coplanar Forces
• we can resolve a vector F into two components along twoperpendicular axes, x and y and write: F = F x + F y
• the x and y components are called rectangular components
• Scalar notation: since x and y axes are perpendicular: F x = F cos ! and F y = F sin !
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F y
• we can also define unit vectors i and j along the x and y axesrespectively
• these unit vectors are dimensionless and have a magnitude of 1
• Cartesian Vector Notation:
we write: F = F x i + F y j
Addition of a System of Coplanar Forces
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Addition of a System of Coplanar Forces
• Coplanar Force Resultants:
• Cartesian vector notation:
F1 = F 1 x i + F 1 y j
F2 = - F 2 x i + F 2 y j F3 = F 3 x i - F 3 y j
• resultant:
F R = ( F 1 x - F 2 x+ F 3 x ) i + ( F 1 y + F 2 y - F 3 y) j
• Scalar notation:
! F Rx = F 1 x - F 2 x+ F 3 x
" F Ry = F 1 y + F 2 y - F 3 y
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• Coplanar Force Resultants:
• generic case: F R = F Rx i + F Ry j
• magnitude of F R:
• direction:
Addition of a System of Coplanar Forces
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PF2-10
• If the resultant force acting on the bracket is to be 750 N directedalong the positive x axis, determine the magnitude of F and itsdirection ! .
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P2-49
• Determine the magnitude of the resultant force and its directionmeasured counterclockwise from the positive x axis.
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