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Transcript of Stat final presentation
Statistic Presentation
Ahmed Imran Hunjra
Subimtted to:
Arid Agricultural UniversityArid Agricultural UniversitySubmitted by:
SAAD ALIM.B.A 2nd SEMSTER
A data has been collected with the help of questionnaire from the students of different age, group at university of arid agriculture.
The questionnaire has been divided into two sections, which indicate the gender, course, CGPA and interest of the students.
The accumulative response is positive which shows that it is a good.
Consumer Purchase Intention (China Mobiles)
Q:1 Would you like to try such products?
Q:2 Would you buy such products if you happened to see it in a store?
Q:3 Would you actively seek out such products in a store in order to purchase it?
Q:4 I would favor such Marketing Campaign?
Q:5 It is good Marketing Campaign?
Q:6 Such Marketing Campaigns are beneficial for society?
Q:7 This marketing campaign has attractive contents?
Q:8 This marketing campaign has excellent execution?
Q:9 I like this campaign?
Questions
Techniques Frequency Distribution
Cumulative frequency distribution
Graphical representation of data
Measure of central tendency• Mean• Median• Mode• Percentile• Quartile
Measure of dispersion:• Range• Variance• Standard Deviation• Co-efficient of variance
Relative Measure• Z-Score• Outlier
Q:1 Would you like to try such products?
Would you like to try such products? Classes
Frequency Relative frequency
Percent frequency
Cumulative Frequency
Cumulative Percent
Strongly Disagree
3 0.06 6.0 3
6.0
Disagree 11 0.22 22.0 14 28.0Neutral 13 0.26 26.0 27 54.0Agree 17 0.34 34.0 44 88.0Strongly Agree
6 0.12 12.050
100.0
Total 50 1.0 100.0
•Frequency distribution :
Cross Tabulation With respect to class:
Would you like to try such products? * Class Crosstabulation
Questions
Class Total
BBA MBA MS MDM OTHERS
Strongly Disagree
0 3 0 0 0 3
Disagree 0 6 2 3 0 11
Neutral 2 5 1 2 3 13
Agree 0 15 0 2 0 17
Strongly Agree 0 4 0 2 0 6
Total 2 33 3 9 3 50
Bar Graph and Pie chart:
Histogram and Dot plot:
Interpretation:In the above we analyze the 50 student about their class who gave the opinion about the “Would you like to try such products” in it we collect the data from MBA, MDM, BBA, MS and Others And conclude that many student like the product.
Particulars Formulas Analysis
Mean 3.2400
Median Middle Value or Average middle Value 3.00
Mode Most Repeated Value 4.00
Percentile(m=64) 4.00
Quartile
Q1
Q2
Q3
25%
50%
75%
2.00
3.00
4.00
Five Number summary Minimum value
Q1
Q2
Q3
Maximum Value
1.00
2.00
3.00
4.00
5.00
Range range = xmaximum – xminimum4.00
Variance 1.247
Standard Deviation 1.1168
Co-efficient of Variance 34.50%
Z-score Give the below in the table
Outlier Analyze With the Help of Z-Score There is no outlier in the given output
-.21489 -.21489 -2.0056 1.57587 .68049
-.21489 -.21489 .68049 .68049 -1.11027
-.21489 .68049 -.21489 -.21489 -.21489
-.21489 -2.00565 1.57587 .68049 -1.11027
-.21489 -1.11027 -1.11027 -.21489 1.57587
-.21489 .68049 .68049 .68049 1.57587
-1.11027 .68049 .68049 .68049 -1.11027
.68049 1.57587 .68049 -1.11027 .68049
-1.1102 -1.11027 -2.00565 .68049 -.21489
-1.11027 .68049 1.57587 .68049 -1.11027
In the above we describe the opinion of the Student from which we collect the information about the “Would you like to try such products?” In the tabular and graphical form.
Now we go our next Question which is Q:2 Would you buy such products if you happened to see it in a store?
Frequency Distribution :
Would you buy such products if you happened to see it in a store?
Frequency
Relative Frequency
Percent frequency
Cumulative Frequency
Cumulative percent
Strongly Disagree 1 0.02 2 1 2
Disagree 5 0.10 10 6 12
Neutral 16 0.32 32 22 44
Agree 23 0.46 46 45 90
Strongly Agree 5 0.10 10 50 100
Total 50 1.00 100
Cross Tabulation With Respect to Class:
Questions
Class TotalBBA MBA MS MDM OTHERS
Strongly Disagree 0 1 0 0 0 1
Disagree 0 2 1 1 1 5
Neutral 1 11 2 2 0 16
Agree 1 14 0 6 2 23
Strongly Agree 0 5 0 0 0 5
Total 2 33 3 9 3 50
Bar Graph and Pie chart:
Histogram and Dot Plot:
Interpretation:In the above we analyze the 50 student about their class who gave the opinion about the “Would you buy such products if you happened to see it in a store?” in it we collect the data from MBA, MDM, BBA, MS and Others And conclude that many student like the product.
Particulars Formulas Analysis
Mean 3.5200
Geometric Mean
Harmonic mean
Median Middle Value or Average middle Value 4.00
Mode Most Repeated Value 4.00
Percentile(m=67) 4.00
Quartile
Q1
Q2
Q3
25%
50%
75%
3.00
4.00
4.00
Five Number summary Minimum value
Q1
Q2
Q3
Maximum Value
1.00
3.00
4.00
4.00
5.00
Range range = xmaximum – xminimum4.00
Variance 0.785
Standard Deviation .8861
Co-efficient of Variance 25.17%
Z-score Give the below in the table
Outlier Analyze With the Help of Z-Score There is no outlier in the given output
-.58679 -.58679 -1.71524 .54165 .54165
-.58679 .54165 1.67010 .54165 .54165
.54165 -2.84368 .54165 -.58679 -1.71524
-1.71524 -.58679 .54165 .54165 -.58679
.54165 .54165 -.58679 .5416 1.67010
.54165 .54165 .54165 .54165 -1.71524
.54165 1.67010 -.58679 -.58679 -.58679
.54165 -.58679 .54165 -.58679 -.58679
-.58679 -.58679 -1.71524 .54165 .54165
-.58679 1.67010 1.67010 .54165 .54165
Q:3 Would you actively seek out such products in a store in order to purchase it?
Would you actively seek out such products in a store in order to purchase it?
Question
Frequency RelativeFrequency
PercentFrequency
CumulativeFrequency
Cumulative Percent
Strongly Disagree
4 0.08 8.04
8.0
Disagree 8 0.16 16.0 12 24.0Neutral 17 0.34 34.0 29 58.0Agree 13 0.26 26.0 42 84.0Strongly agree 8 0.16 16.0 50 100.0Total 50 1.0 100.0
•Frequency Distribution:
Would you actively seek out such products in a store in order to purchase it? Questions
Class TotalBBA MBA MS MDM OTHERS
Strongly Disagree
0 3 1 0 0 4
Disagree 1 3 1 2 1 8Neutral 0 14 0 2 1 17Agree 1 9 0 2 1 13Strongly agree 0 4 1 3 0 8
Total 2 33 3 9 3 50
•Cross Tabulation:
•Bar graph and Pie chart:
•Histogram And Dot Plot:
Interpretation:The above graph and table shown the response of the students about the actively Seek out the goods. In the store or not and we analyze that Neutral Student are more in it which means they neither interested active seek out the Goods.
Particulars Formulas Analysis
Mean 3.2600
Harmonic mean
Median Middle Value or Average middle Value 3.00
Mode Most Repeated Value 3.00
Percentile(m=67) 3.00
Quartile
Q1
Q2
Q3
25%
50%
75%
2.7500
3.00
4.00
Five Number summary Minimum value
Q1
Q2
Q3
Maximum Value
1.00
2.7500
3.00
4.00
5.00
Range range = xmaximum – xminimum4.00
Variance 1.399
Standard Deviation 1.1572
Co-efficient of Variance 35.50%
Z-score Give the below in the table
Outlier Analyze With the Help of Z-Score There is no outlier in the given output
1.42993 -1.31993 .51331 -.40331 -.40331
-1.31993 .51331 -.40331 -.40331 -.40331
.51331 -1.31993 .51331 .51331 1.42993
-.40331 -.40331 1.42993 .51331 .51331
-.40331 .51331 .51331 1.42993 -2.23655
.51331 -.40331 .51331 -.40331 1.42993
1.42993 -.40331 -2.23655 -.40331 1.42993
-.40331 -.40331 -.40331 -.40331 1.42993
.51331 .51331 .51331 1.42993 -.40331
-1.31993 -2.23655 .51331 -1.31993 -.40331
Q:4 I would favor such Marketing Campaign.
I would favor such Marketing Campaign. Frequency Relative
FrequencyPercentFrequency
Cumulative Frequency
Cumulative Percent
strongly disagree
6 0.12 12.06
12.0
disagree 7 0.14 14.0 13 26.0Neutral 14 0.28 28.0 27 54.0Agree 14 0.28 28.0 41 82.0Strongly agree
9 0.18 18.050
100.0
Total 50 1.0 100.0
•Frequency Distribution:
I would favor such Marketing Campaign. * Class Cross tabulation
Question
Class TotalBBA MBA MS MDM OTHERS
strongly disagree 0 2 1 2 1 6disagree 1 4 1 0 1 7Neutral 0 10 0 4 0 14Agree 0 12 0 1 1 14Strongly agree 1 5 1 2 0 9
Total 2 33 3 9 3 50
•Cross Tabulation with Respect to Class:
•Bar Graph and Pie chart:
•Histogram and Dot Plot:
Particulars Formulas Analysis
Mean 3.2600
Geometric Mean
Harmonic mean
Median Middle Value or Average middle Value 3.00
Mode Most Repeated Value 3.00
Percentile(m=67) 3.0300
Quartile
Q1
Q2
Q3
25%
50%
75%
2.00
3.00
4.00
Five Number summary Minimum value
Q1
Q2
Q3
Maximum Value
1.00
2.00
3.00
4.00
5.00
Range range = xmaximum – xminimum4.00
Variance 1.584
Standard Deviation 1.2586
Co-efficient of Variance 38.61%
Z-score Give the below in the table
Outlier Analyze With the Help of Z-Score There is no outlier in the given output
Interpretation:In it we take the Suggestion from the Student about the Product, and the result is mostly agree or neutral. Which help us to makes the decision making.
1.38249 -1.00111 -1.00111 -.20658 -1.00111
-.20658 .58795 .58795 .58795 .58795
1.38249 -1.79564 -.20658 -.20658 .58795
-1.00111 -1.79564 1.38249 -1.00111 -.20658
-1.79564 -.20658 -1.79564 1.38249 1.38249
.58795 -.20658 -1.00111 -.20658 -1.79564
-.20658 1.38249 -.20658 1.38249 .58795
-.20658 -.20658 .58795 -.20658 1.38249
-1.79564 -.20658 .58795 .58795 .58795
-1.00111 .58795 .58795 .58795 1.38249
Q:5 It is good Marketing Campaign.
It is good Marketing Campaign.
Question:
Frequency Relative Frequency
Percent Frequency
Cumulative frequency
Cumulative Percent
strongly disagree
7 0.14 14.07
14.0
Disagree 5 0.10 10.0 12 24.0Neutral 10 0.20 20.0 22 44.0Agree 22 0.44 44.0 44 88.0Strongly Agree
6 0.12 12.050
100.0
Total 50 1.0 100.0
•Frequency Distribution:
It is good Marketing Campaign. * Class Cross tabulation
Question:
Class TotalBBA MBA MS MDM OTHERS
strongly disagree 1 4 0 2 0 7disagree 0 2 1 0 2 5Neutral 0 8 1 1 0 10Agree 1 15 1 4 1 22Strongly Agree 0 4 0 2 0 6
Total 2 33 3 9 3 50
•Cross tabulation With respect to Class:
Bar Graph And Pie chart:
•Histogram and Dot Plot:
Particulars Formulas Analysis
Mean 3.3000
Geometric Mean
Harmonic mean
Median Middle Value or Average middle Value 4.00
Mode Most Repeated Value 4.00
Percentile(m=43) 4.00
Quartile
Q1
Q2
Q3
25%
50%
75%
2.7500
4.00
4.00
Five Number summary Minimum value
Q1
Q2
Q3
Maximum Value
1.00
2.7500
4.00
4.00
5.00
Range range = xmaximum – xminimum4.00
Variance 1.520
Standard Deviation 1.2330
Co-efficient of Variance 37.36%
Z-score Give the below in the table
Outlier Analyze With the Help of Z-Score There is no outlier in the given output
Interpretation:In it we take the opinion from the students about the campaign of the product, and we conclude that many students agree from the marketing campaign about the product and we show it graph and table in the above.
.56770 -1.86530 -1.86530 -.24330 -.24330
-.24330 .56770 .56770 .56770 .56770
1.37870 -1.86530 .56770 .56770 .56770
-1.05430 -1.86530 -.24330 -.24330 .56770
-1.05430 .56770 .56770 .56770 1.37870
.56770 -1.05430 .56770 .56770 -1.86530
.56770 1.37870 .56770 .56770 -.24330
.56770 -1.86530 -1.86530 -.24330 1.37870
-1.05430 -1.05430 .56770 -.24330 1.37870
-.24330 1.37870 .56770 -.24330 .56770
Q:6 Such Marketing Campaigns are beneficial for society.
Such Marketing Campaigns are beneficial for society. Question:
Frequency Relative Frequency
PercentFrequency
C.F
Cumulative Percent
Strongly disagree
3 0.06 6.03
6.0
disagree 5 0.10 10.0 8 16.0Neutral 18 0.36 36.0 26 52.0Agree 15 0.30 30.0 41 82.0Strongly agree 9 0.18 18.0 50 100.0Total 50 1.00 100.0
Questions Class Total
BBA MBA MS MDM OTHERS
Strongly disagree 0 2 0 1 0 3
disagree 1 3 1 0 0 5
Neutral 0 12 1 3 2 18
Agree 0 11 1 2 1 15
Strongly agree 1 5 0 3 0 9
Total 2 33 3 9 3 50
•Frequency Distribution:
•Cross Tabulation:
•Bar Graph and pie chart:
•Dot Plot and Histogram:
Particulars Formulas Analysis
Mean 3.4400
Geometric Mean
Harmonic mean
Median Middle Value or Average middle Value 3.00
Mode Most Repeated Value 3.00
Percentile(m=67) 4.00
Quartile
Q1
Q2
Q3
25%
50%
75%
3.00
3.00
4.00
Five Number summary Minimum value
Q1
Q2
Q3
Maximum Value
1.00
3.00
3.00
4.00
5.00
Range range = xmaximum – xminimum4.00
Variance 1.190
Standard Deviation 1.091
Co-efficient of Variance 31.72%
Z-score Give the below in the table
Outlier Analyze With the Help of Z-Score There is no outlier in the given output
Interpretation:In the above we shows the reaction of students about Marketing Campaigns are beneficial for society and we conclude that many student are agree of such kind of marketing campaign.
1.42993 -1.31993 .51331 -.40331 -.40331
-1.31993 .51331 -.40331 -1.31993 -.40331
.51331 -1.31993 .51331 -.40331 -.40331
-.40331 -.40331 .51331 1.42993 1.42993
1.42993 .51331 .51331 -.40331 1.42993
.51331 -.40331 1.42993 -.40331 1.42993
-.40331 -.40331 .51331 -.40331 -2.23655
-.40331 -.40331 .51331 1.42993 .51331
.51331 -2.23655 -2.23655 .51331 1.42993
-1.31993 .51331 -.40331 .51331 -.40331
Q:7 This marketing campaign has attractive contents
This marketing campaign has attractive contents.
Questions Frequency Relative Frequency
Percent frequenc
y
Cumulative Frequency
Cumulative percent
Strongly disagree 2 0.04 4.0 2 2
disagree 6 0.12 12.0 8 16
Neutral 18 0.36 36.0 26 52
Agree 18 0.36 36.0 44 88
Strongly agree 6 0.12 12.0 50 100
Total 50 1.00 100.0
This marketing campaign has attractive contents. * Class Cross tabulation Questions: Class Total
BBA MBA MS MDM OTHERS
Strongly disagree
0 1 0 1 0 2
disagree 0 3 1 0 2 6Neutral 1 13 1 3 0 18agree 0 12 1 4 1 18Strongly agree 1 4 0 1 0 6
Total 2 33 3 9 3 50
Frequency Distribution:
Cross tabulation:
•Bar Graph and Pie chart
•Histogram and Dot plot:
Interpretation:In the above we take opinion from the students and in position of to take the decision that many student agree or strongly agree about the marketing campaign has attractive context.
Particulars Formulas Analysis
Mean 3.3400
Geometric Mean
Harmonic mean
Median Middle Value or Average middle Value 3.00
Mode Most Repeated Value 3.00
Percentile(m=87) 4.3700
Quartile
Q1
Q2
Q3
25%
50%
75%
3.00
3.00
4.00
Five Number summary Minimum value
Q1
Q2
Q3
Maximum Value
1.00
3.00
3.00
4.00
5.00
Range range = xmaximum – xminimum4.00
Variance .980
Standard Deviation .9897
Co-efficient of Variance 29.63%
Z-score Give the below in the table
Outlier Analyze With the Help of Z-Score There is no outlier in the given output
1.61658 -.40415 -1.41451 -.40415 -.40415
-.40415 1.61658 .60622 .60622 1.61658
-1.41451 -.40415 -1.41451 -.40415 .60622
.60622 .60622 -.40415 -.40415 1.61658
.60622 1.61658 .60622 -.40415 -.40415
.60622 .60622 .60622 -.40415 .60622
-1.41451 .60622 -.40415 -.40415 -2.42487
-1.41451 -.40415 .60622 -.40415 .60622
-.40415 -2.42487 -.40415 1.61658 .60622
.60622 -.40415 -.40415 .60622 .60622
Q:8 This marketing campaign has excellent execution.
This marketing campaign has excellent execution. Questions Frequency Relative
Frequency Percent
FrequencyCumulative Frequency
Cumulative Percent
strongly disagree 3 0.06 6.0 3 6
disagree 7 0.14 14.0 10 20
Neutral 13 0.26 26.0 23 46
Agree 17 0.34 34.0 40 80
Strongly agree 10 0.20 20.0 50 100
Total 50 1.00 100.0
This marketing campaign has excellent execution. * Class Cross tabulation
Questions: Class TotalBBA MBA MS MDM OTHERS
strongly disagree 1 1 0 1 0 3
disagree 0 1 2 2 2 7Neutral 1 10 1 1 0 13Agree 0 13 0 3 1 17Strongly agree 0 8 0 2 0 10
Total 2 33 3 9 3 50
Frequency Distribution:
Cross tabulation:
•Bar Graph and Pie chart:
•Histogram and Dot Plot:
Particulars Formulas Analysis
Mean 3.4800
Geometric Mean
Harmonic mean
Median Middle Value or Average middle Value 4.00
Mode Most Repeated Value 4.00
Percentile(m=31) 3.00
Quartile
Q1
Q2
Q3
25%
50%
75%
3.00
4.00
4.00
Five Number summary Minimum value
Q1
Q2
Q3
Maximum Value
1.00
3.00
4.00
4.00
5.00
Range range = xmaximum – xminimum4.00
Variance 1.316
Standard Deviation 1.1471
Co-efficient of Variance 32.96%
Z-score Give the below in the table
Outlier Analyze With the Help of Z-Score There is no outlier in the given output
Interpretation:In the above we plot the suggestion of the students about the marketing campaign has excellent execution. And at the end we conclude that many student are the favor of the Agree to the execution of the marketing.
-.41843 -2.16191 .45330 -.41843 .45330
-1.29017 1.32504 .45330 .45330 1.32504
-1.29017 -1.29017 -.41843 .45330 -.41843
.45330 -.41843 1.32504 -.41843 .45330
.45330 .45330 .45330 .45330 1.32504
.45330 1.32504 -.41843 .45330 -2.16191
-1.29017 1.32504 -.41843 1.32504 1.32504
-1.29017 .45330 1.32504 -.41843 .45330
.45330 -.41843 -1.29017 -1.29017 1.32504
-.41843 -2.16191 .45330 -.41843 -.41843
Q:9 I like this campaign.
I like this campaign.
Questions Frequency Relative Frequency
Percent Frequency
Cumulative
Frequency
Cumulative Percent
strongly disagree 5 0.10 10.0 5 10
Disagree 4 0.08 8.0 9 18
Neutral 14 0.28 28.0 23 46
Agree 16 0.32 32.0 39 78
strongly agree 11 0.22 22.0 50 100
Total 50 1.00 100.0
I like this campaign. * Class Cross tabulation
Questions Class TotalBBA MBA MS MDM OTHERS
strongly disagree 1 4 0 0 0 5Disagree 0 3 0 0 1 4Neutral 0 12 1 0 1 14Agree 1 9 2 3 1 16strongly agree 0 5 0 6 0 11
Total 2 33 3 9 3 50
Frequency Distribution:
•Cross tabulation:
•Bar Graph and Pie chart:
•Histogram and Dot Plot:
Particulars Formulas Analysis
Mean 3.4800
Geometric Mean
Harmonic mean
Median Middle Value or Average middle Value 4.00
Mode Most Repeated Value 4.00
Percentile(m=46) 3.4600
Quartile
Q1
Q2
Q3
25%
50%
75%
3.00
4.00
4.00
Five Number summary Minimum value
Q1
Q2
Q3
Maximum Value
1.00
3.00
4.00
4.00
5.00
Range range = xmaximum – xminimum4.00
Variance 1.479
Standard Deviation 1.2162
Co-efficient of Variance 34.95%
Z-score Give the below in the table
Outlier Analyze With the Help of Z-Score There is no outlier in the given output
Interpretation:In it we take the opinion of the student that the like the marketing campaign of the product or not, and at the end we conclude that many student are in the Favor of the Marketing and they like the such type of Marketing campaign.
.42756 -2.03911 -2.03911 .42757 .42756
-.39467 -1.21689 .42756 -.39467 1.24978
1.24978 -2.03911 -.39467 -.39467 .42756
-1.21689 -2.03911 1.24978 .42756 1.24978
-.39467 1.24978 1.24978 -.39467 .42756
.42756 -.39467 -.39467 -2.03911 1.24978
.42756 1.24978 -.39467 -.39467 -1.21689
-.39467 -.39467 1.24978 .42756 .42756
.42756 -.39467 -.39467 -1.21689 1.24978
.42756 .42756 .42756 -.39467 1.24978