Stat Chapter 4 c

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    Bayes Theorem

    Suppose we have estimatedprior probabilities for eventswe are concerned with, andthen obtain new information.

    We would like to a soundmethod to computed revised

    or posterior probabilities.Bayes theorem gives us a

    way to do this.

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    Probability Revision using Bayes

    Theorem

    PriorProbabilities

    NewInformation

    Application of

    Bayes Theorem

    PosteriorProbabilities

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    Application of Bayes Theorem

    Consider a manufacturing firm that receivesshipment of parts from two suppliers.

    Let A1 denote the event that a part is receivedfrom supplier 1; A2 is the event the part isreceived from supplier 2

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    We get 65 percent of our parts

    from supplier 1 and 35percent from supplier 2.

    Thus:

    P(A 1) = .65 and P(A 2) = .35

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    Quality levels differ between suppliersPercentageGood Parts

    PercentageBad Parts

    Supplier 1 98 2

    Supplier 2 95 5

    Let G denote that a part is good and B denotethe event that a part is bad. Thus we have thefollowing conditional probabilities:

    P (G | A1 ) = .98 and P (B | A2 ) = .02

    P (G | A2 ) = .95 and P (B | A2 ) = .05

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    Tree Diagram for Two-Supplier Example

    Step 1Supplier

    Step 2Condition

    ExperimentalOutcome

    A1

    A2

    G

    B

    G

    B

    (A1, G)

    (A1, B)

    (A2 , G)

    (A2 , B)

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    Each of the experimentaloutcomes is the intersection of 2

    events. For example, theprobability of selecting a partfrom supplier 1 that is good is

    given by:

    )|()()(),( 1111 AG P A P G A P G A P

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    Probability Tree for Two-Supplier Example

    6370.)|()()( 111 AG P A P G A P

    0130.)|()()( 111 A B P A P B A P

    3325.)|()()( 222 AG P A P G A P

    Step 1Supplier

    Step 2Condition

    Probability of Outcome

    P(A 1)

    P(A 2 )

    .65

    .35

    P(G | A 1 )

    P(B | A2 )

    P(B | A 2 )

    P(B | A 2 )

    .98

    .95

    .02

    .050175.)|()()( 222 AG P A P B A P

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    A bad part broke oneof our machines sowere through for the

    day. What is theprobability the partcame from suppler 1?

    We know from the law of conditional probability that:

    )()(

    )|( 11 B P B A P

    B A P

    Observe from the probability tree that:

    )|()()( 111 A B P A P B A P

    (4.14)

    (4.15)

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    The probability of selecting a badpart is found by adding togetherthe probability of selecting a bad

    part from supplier 1 and theprobability of selecting bad part

    from supplier 2.

    That is:

    )/()()|()(

    )()()(

    2211

    21

    A B P A P A B P A P

    B A P B A P B P (4.16)

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    Bayes Theorem for 2 events

    )|()()|()()|()()|(

    2211

    111 A B P A P A B P A P

    A B P A P B A P

    By substituting equations (4.15) and (4.16) into(4.14), and writing a similar result for P(B | A 2 ), weobtain Bayes theorem for the 2 event case:

    )|()()|()()|()(

    )|(2211

    222 A B P A P A B P A P

    A B P A P

    B A P

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    Do the Math

    4262.0305.0130.

    )05)(.35(.)02)(.65(.)02)(.65(.

    )|()()|()()|()()|(

    2211

    111 A B P A P A B P A P

    A B P A P B A P

    5738.0305.0175.

    )05)(.35(.)02)(.65(.)05)(.35(.

    )|()()|()()|()(

    )|(2211

    222 A B P A P A B P A P

    A B P A P B A P

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    Bayes Theorem

    )|()(...)|()()|()()|()(

    )|(2211 nn

    iii

    A B P A P A B P A P A B P A P

    A B P A P B A P

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    Tabular Approach to Bayes Theorem 2-Supplier Problem

    (1)

    EventsA i

    (2)Prior

    ProbabilitiesP(A i )

    (3)ConditionalProbabilities

    P(B | A 1 )

    (4)Joint

    ProbabilitiesP(A i B)

    (5)Posterior

    ProbabilitiesP(A i | B)

    A1 .65 .02 .0130 .0130/.0305=.4262

    A2 .35 .05 .0175 .0175/.0305

    =.57381.00 P(B)=.0305 1.0000

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    Using Excel to ComputePosterior Probabilities

    Prior Conditional Joint Posterior

    Events Probabilities Probabilities Probabilities Probabilities

    A 1 0.65 0.02 0.013 0.426229508

    A 2 0.35 0.05 0.0175 0.573770492

    0.0305 1.0000

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    Exercise 41, p. 187

    41. A consulting firm submitted a bid for a large consultingcontract. The firms management felt id had a 50 -50 changeof landing the project. However, the agency to which the bidwas submitted subsequently asked for additionalinformation. Past experience indicates that that for 75% ofsuccessful bids and 40% of unsuccessful bids the agency

    asked for additional information.a. What is the prior probability of the bid being successful

    (that is, prior to the request for additional information).

    b. What is the conditional probability of a request for

    additional information given that the bid will beultimately successful.

    c. Compute the posterior probability that the bid will besuccessful given a request for additional information.

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    Exercise 41, p. 187Let S 1 denote the event of successfully obtaining the project.

    S 2 is the event of not obtaining the project.B is the event of being asked for additional information about a bid.

    a. P(S 1 ) = .5

    b. P(B | S 1 ) = .75

    c. Use Bayes theorem to compute the posterior probability that arequest for information indicates a successful bid.

    652.575.375.

    )4)(.5(.)75)(.5(.)75)(.5(.

    )()()(

    )|(21

    11 BS P BS P

    BS P BS P